hope you can help me with this. so i have one table that contains value
user_id
Monday.
Tuesday
Wednesday
aa11
100
164
284
bb22.
223
143
346
and another table that contains count
user_id
Monday.
Tuesday
Wednesday
aa11
2
3
4
bb22
5
2
3
how can i combine both so it looks like this?
user_id
type
Monday.
Tuesday
Wednesday
aa11
value
100
164
284
aa11
count
2
3
4
bb22.
value
223
143
346
bb22
count
5
2
3
is it even a good practice to pivot long like this or should i just pivot wide so there would be columns monday_value, monday_count, tuesday_value, tuesday_count, etc?
Simple union? :
select * from (
select user_id, 'value' as type,Monday.,Tuesday,Wednesday
from table1
union all
select user_id, 'count' as type,Monday.,Tuesday,Wednesday
from table2
) t
You can use simple way as given in answer by #eshirvana.
Or as per your ask, if you want to do it horizontally you can do it following way:
WITH week_value AS
(
SELECT 1 as user, 100 as monday
UNION ALL SELECT 2 as user, 200 as monday
),
week_count as (
SELECT 1 as user, 10 as monday
UNION ALL SELECT 2 as user, 2 as monday
)
select A.user, A.monday as monday_value, B.monday as monday_count
from week_value as A
FULL JOIN week_count as B on A.user = B.user
Related
I have a table which contain _id, underSubheadId, wefDate, price.
Whenever a product is created or price is edited an entry is made in this table also.
What I want is if I enter a date, I get the latest price of all distinct UnderSubheadIds before the date (or on that date if no entry found)
_id underHeadId wefDate price
1 1 2016-11-01 5
2 2 2016-11-01 50
3 1 2016-11-25 500
4 3 2016-11-01 20
5 4 2016-11-11 30
6 5 2016-11-01 40
7 3 2016-11-20 25
8 5 2016-11-15 52
If I enter 2016-11-20 as date I should get
1 5
2 50
3 25
4 30
5 52
I have achieved the result using ROW NUMBER function in SQL SERVER, but I want this result in Sqlite which don't have such function.
Also if a date like 2016-10-25(which have no entries) is entered I want the price of the date which is first.
Like for 1 we will get price as 5 as the nearest and the 1st entry is 2016-11-01.
This is the query for SQL SERVER which is working fine. But I want it for Sqlite which don't have ROW_NUMBER function.
select underSubHeadId,price from(
select underSubHeadId,price, ROW_NUMBER() OVER (Partition By underSubHeadId order by wefDate desc) rn from rates
where wefDate<='2016-11-19') newTable
where newTable.rn=1
Thank You
This is a little tricky, but here is one way:
select t.*
from t
where t.wefDate = (select max(t2.wefDate)
from t t2
where t2.underSubHeadId = t.underSubHeadId and
t2.wefdate <= '2016-11-20'
);
select underHeadId, max(price)
from t
where wefDate <= "2016-11-20"
group by underHead;
I have a table with duplicate item's ...
I need show the list of all columns without duplicate item's
for example i have this table:
ID CODE RANK TIME
1 12345 2 10:00
2 12345 2 11:00
3 98765 3 20:00
4 98765 3 22:00
5 66666 2 10:00
6 55555 5 11:00
result , i need :
ID CODE RANK TIME
1 12345 2 10:00
3 98765 3 20:00
5 66666 2 10:00
6 55555 5 11:00
The time column in not Important , only one of them most be show ...
try this:
SELECT * FROM myTable WHERE ID IN(SELECT MIN(ID) FROM myTable GROUP BY Code)
If there is no specific way the ID should show (just like the time column), and the ID and TIME column are always sorted that way,this should work.
SELECT MIN(id), code, rank, MIN(time)
FROM table
GROUP BY code, rank
So you only want rows where the CODE is not duplicated in the table.
SELECT "CODE"
FROM table1
GROUP BY "CODE"
HAVING COUNT(*) = 1
This will return the distinct CODE-s. Based on them - as they are unique - you can self-join it to fetch the whole rows:
SELECT *
FROM table1
WHERE "CODE" IN (
SELECT "CODE"
FROM table1
GROUP BY "CODE"
HAVING COUNT(*) = 1
)
I think you are looking for the DISTINCT clause;
SELECT DISTINCT
column_1,
column_2
FROM
tbl_name;
I've got a table something like..
[DateValueField][Hour][Value]
2014-09-01 1 200
...
2014-09-01 24 400
2014-09-02 1 220
...
2014-09-02 24 200
...
I need the same value for each DateValueField based on the average Value for Hour between 6-12 for example but have that display for all hours, not just 6-12. For instance...
[DateValueField][Hour][Value]
2014-09-01 1 300
...
2014-09-01 24 300
2014-09-02 1 190
...
2014-09-02 24 190
...
Query I'm trying is...
select DateValueField, Hour,
(select avg(Value) as Value from MyTable where Hour
between 6 and 12) as Value from MyTable
where DateValueField between '2014' and '2015'
group by DateValueField, Hour
order by DateValueField, Hour
But it gives me the Value as an average of ALL Values but I need it averaged out for that particular day between the hours I specify.
I'd appreciate some help/advice. Thanks!
You can use a derived table to get the average value between hours 6 and 12 grouped by date and then join that to your original table
select t1.DateValueField, t1.Hour, t2.avg_value
from MyTable t1
join (
select DateValueField, avg(Value) avg_value
from MyTable
where hour between 6 and 12
group by DateValueField
) t2 on t2.DateValueField = t1.DateValueField
order by t1.DateValueField, t1.Hour
Note: You may want to use a left join if some of your dates don't have values between hours 6 and 12 but you still want to retrieve all rows from MyTable.
I've been trying to build an sql query that finds from (table) the most recent date for selected id's that fulfill the condition where 'type' is in hierarchy 'vegetables'. My goal is to be able to get the whole row once max(date) and hierarchy conditions are met for each id.
Example values
ID DATE PREFERENCE AGE
123 1/3/2013 carrot 14
123 1/3/2013 apple 12
123 1/2/2013 carrot 14
124 1/5/2013 carrot 13
124 1/3/2013 apple 13
124 1/2/2013 carrot 14
125 1/4/2013 carrot 13
125 1/3/2013 apple 14
125 1/2/2013 carrot 13
I tried the following
SELECT *
FROM table
WHERE date in
(SELECT max(date) FROM (table) WHERE id in (123,124,125))
and preference in
(SELECT preference FROM (hierarchy_table)
WHERE hierarchy = vegetables))
and id in (123,24,125)
but it doesn't give me the most recent date for each id that meets the hierarchy conditions. (ex. in this scenario I would only get id 124)
Thank you in advance!
SELECT max(date) FROM (table) WHERE id in (123,124,125)
is giving you the max date from all dates, you need to group them.
Try replacing with:
SELECT max(date) FROM (table) GROUP BY id
This way you will get the max date for each id
I figured this out. Please see the query below as an example:
SELECT * FROM (table) t
WHERE t.date in
(SELECT max(date) FROM table sub_t where t.ID = sub_t.ID and (date !> (currentdate))
and preference in
(SELECT preference FROM (hierarchy_table) WHERE hierarchy ='vegetables')
and ID in ('124')
Change:
max(date)
To:
-- if your date data is in mm/dd/yyyy
max( str_to_date( date, '%m/%d/%Y' ) )
OR
-- if your date data is in dd/mm/yyyy
max( str_to_date( date, '%d/%m/%Y' ) )
I have this in my table
TempTable
Id Date
1 1-15-2010
2 2-14-2010
3 3-14-2010
4 4-15-2010
i would like to change every record so that they have all same day, that is the 15th
like this
TempTable
Id Date
1 1-15-2010
2 2-15-2010 <--change to 15
3 3-15-2010 <--change to 15
4 4-15-2010
what if i like on the 30th?
the records should be
TempTable
Id Date
1 1-30-2010
2 2-28-2010 <--change to 28 because feb has 28 days only
3 3-30-2010 <--change to 30
4 4-30-2010
thanks
You can play some fun tricks with DATEADD/DATEDIFF:
create table T (
ID int not null,
DT date not null
)
insert into T (ID,DT)
select 1,'20100115' union all
select 2,'20100214' union all
select 3,'20100314' union all
select 4,'20100415'
SELECT ID,DATEADD(month,DATEDIFF(month,'20100101',DT),'20100115')
from T
SELECT ID,DATEADD(month,DATEDIFF(month,'20100101',DT),'20100130')
from T
Results:
ID
----------- -----------------------
1 2010-01-15 00:00:00.000
2 2010-02-15 00:00:00.000
3 2010-03-15 00:00:00.000
4 2010-04-15 00:00:00.000
ID
----------- -----------------------
1 2010-01-30 00:00:00.000
2 2010-02-28 00:00:00.000
3 2010-03-30 00:00:00.000
4 2010-04-30 00:00:00.000
Basically, in the DATEADD/DATEDIFF, you specify the same component to both (i.e. month). Then, the second date constant (i.e. '20100130') specifies the "offset" you wish to apply from the first date (i.e. '20100101'), which will "overwrite" the portion of the date your not keeping. My usual example is when wishing to remove the time portion from a datetime value:
SELECT DATEADD(day,DATEDIFF(day,'20010101',<date column>),'20100101')
You can also try something like
UPDATE TempTable
SET [Date] = DATEADD(dd,15-day([Date]), DATEDIFF(dd,0,[Date]))
We have a function that calculates the first day of a month, so I just addepted it to calculate the 15 instead...