I have two tables, a table with id, date, value and a table with all the dates of interest. I'd like to do a SQL query such that I get a new table exactly the same as my first table but not with NULL values per ID when a date is not present for a given ID.
Table 1.
id
date
value
1
2021-01-01
10
1
2021-02-01
8
1
2021-04-01
20
2
2021-02-01
5
2
2021-04-01
6
Table 2.
date
2020-12-01
2021-01-01
2021-02-01
2021-03-01
2021-04-01
2021-05-01
After I "merge" the two tables the result would be:
id
date
value
1
2020-12-01
NULL
1
2021-01-01
10
1
2021-02-01
8
1
2020-03-01
NULL
1
2021-04-01
20
1
2021-05-01
NULL
2
2020-12-01
NULL
2
2021-01-01
NULL
2
2021-02-01
5
2
2021-03-01
NULL
2
2021-04-01
6
2
2021-05-01
NULL
Which SQL query do I need to run to get such result?
SELECT
u.id,
d.date,
t.value
FROM
(
SELECT DISTINCT id FROM table1
)
u
CROSS JOIN
table2 d
LEFT JOIN
table1 t
ON t.id = u.id
AND t.date = d.date
Though, I'd refrain from using date and other potential keywords as column names.
Related
I have a table t with:
DATE
LOCATION
PRODUCT_ID
AMOUNT
2021-10-29
1
123
10
2021-10-30
1
123
9
2021-10-31
1
123
8
2021-10-29
1
456
100
2021-10-30
1
456
90
2021-10-31
1
456
80
2021-10-29
2
123
18
2021-10-30
2
123
17
2021-11-29
2
456
18
I need to find the AMOUNT of each PRODUCT_ID for each combination of LOCATION + PRODUCT_ID.
If a PRODUCT_ID has no entry for that day the AMOUNT is NULL.
So the result should look like:
DATE
LOCATION
PRODUCT_ID
AMOUNT
2021-10-31
1
123
8
2021-10-31
1
456
80
2021-10-31
2
123
NULL
2021-11-30
2
456
NULL
Sadly EXASOL has no LAST_DAY() or EOMONTH() function. How can I solve this?
You can get to the last day of the month using a date_trunc function in combination with date_add:
case
when t.date = date_add('day', -1, date_add('month', 1, date_trunc('month', t.date)))
then 'Y' else 'N' end as end_of_month
That being said, if you group your table for all combinations of locations and products, you will not get NULLs for products without sales on the last day of the month as shown in your output table.
When you group your data, any value that does not exist will simply not show up in your output table. If you want to force nulls to show up, you can create a new table that contains all combinations of products, locations, and hard-coded end of month dates.
Then, you can left join your old table with this new hard-coded table by date, location, and product. This method will give you the NULL values you expect.
I have these tables: Employee (id, name, number), Configuration (id, years, licence_days), Periods (id, start_date, end_date, configuration_id, employee_id, period_type):
Employee table:
id name number
---- ----- -------
1 Bob 355
2 John 467
3 Maria 568
4 Josh 871
configuration table:
id years licence_days
---- ----- ------------
1 1 8
2 3 16
3 5 24
Periods table:
id start_date end_date configuration_id employee_id period_type
---- ---------- ------- ---------------- ----------- -----------
1 2021-05-23 2021-05-31 1 1 vaccation
2 2021-05-24 2021-06-01 1 2 vaccation
3 2021-03-01 2021-03-17 2 2 vaccation
4 2021-05-05 2021-05-21 2 2 vaccation
5 2021-01-01 2021-01-17 2 4 vaccation
I want this result:
Result:
employee_id years licence_days max(end_date)
1 1 8 2021-05-31
1 3 16 null
1 5 24 null
2 1 8 2021-06-01
2 3 16 2021-05-21
2 5 24 null
3 1 8 null
3 3 16 null
3 5 24 null
4 1 8 null
4 3 16 2021-01-17
4 5 24 null
i.e., I want to select all Employees with all configuration, and for each one of that, the max end_date of the "vaccation" type (or null if it does not exists).
How can I do that
Oracle supports cross joins, right? So may be something like that?
SELECT e.employee_id, c.years, c.licence_days, max(p.end_date)
FROM Employee e
CROSS JOIN configuration c
LEFT JOIN Periods p
ON e.employee_id = p.employee_id
AND c.configuration_id = p.configuration_id
GROUP BY e.employee_id, c.years, c.licence_days
ORDER BY e.employee_id, c.years
#umberto-petrov chooses wisely with the ANSI CROSS JOIN syntax for a cartesian join. However, in the very weak probability that your requires output of configurations even where there is no employees, you can go with something like :
EDIT: Filtering the Periods join with 'vaccation' as asked in the comments.
If you have to filter for some employee ids, change ON 1 = 1 by ON Employee.id IN (id1, id2, ...). It still keeps every configurations but only takes employees that match the ids.
SELECT Employee.employee_id,
Configuration.years,
Configuration.licence_days,
MAX(Configuration.end_date) max_end_date
FROM Configuration LEFT JOIN Employee ON 1 = 1
LEFT JOIN Periods ON Periods.configuration_id = Configuration.id
AND Periods.employee_id = Employee.id
AND Periods.period_type = 'vaccation'
GROUP BY Employee.employee_id,
Configuration.years,
Configuration.licence_days
ORDER BY Employee.employee_id,
Configuration.years,
Configuration.licence_days
We start from configuration to take every records from this one at least, then made a LEFT CARTESIAN JOIN with Employee and finally a full LET JOIN on Periods for both. That way , if there is no employees, this will output configuration_id and NULL for years, licence_days and max end_date.
I'm trying to find the min and max date within a subgroup of another group. Here's example 'data'
ID Type Date
1 A 7/1/2015
1 B 1/1/2015
1 A 8/5/2014
22 B 3/1/2015
22 B 9/1/2014
333 A 8/1/2015
333 B 4/1/2015
333 B 3/29/2014
333 B 2/28/2013
333 C 1/1/2013
What I'd like to identify is - within an ID, what is the min/max Date for each block of similar Type? So for ID # 333 I want the below info:
A: min & max = 8/1/2015
B: min = 2/28/2013
max = 4/1/2015
C: min & max = 1/1/2013
I'm having trouble figuring out how to identify only uninterrupted groupings of Type within a grouping of ID. For ID #1, I need to keep the two 'A' Types with separate min/max dates because they were split by a Type 'B', so I can't just pull the min date of all Type A's for ID #1, it has to be two separate instances.
What I've tried is something like the below two lines, but neither of these accurately captures the case mentioned above for ID #1 where Type B interrupts Type A.
Max(Date) OVER (Partition By ID, Type)
or this:
Row_Number() OVER (Partition By ID, Type ORDER BY Date DESC)
,then selecting Row #1 for max date, and date ASC w/ row #1 for min date
Thank you for any insight you can provide!
If I understand right, you want the min/max values for an id/type grouped using a descending date sort, but the catch is that you want them based on clusters within the id by time.
What you can do is use CONDITIONAL_CHANGE_EVENT to tag the rows on change of type, then use that in your GROUP BY on a standard min/max aggregation.
This would be the intermediate step towards getting to what you want:
select ID, Type, Date,
CONDITIONAL_CHANGE_EVENT(Type) OVER( PARTITION BY ID ORDER BY Date desc) cce
from mytable
group by ID, Type, Date
order by ID, Date desc, Type
ID Type Date cce
1 A 2015-07-01 00:00:00 0
1 B 2015-01-01 00:00:00 1
1 A 2014-08-05 00:00:00 2
22 B 2015-03-01 00:00:00 0
22 B 2014-09-01 00:00:00 0
333 A 2015-08-01 00:00:00 0
333 B 2015-04-01 00:00:00 1
333 B 2014-03-29 00:00:00 1
333 B 2013-02-28 00:00:00 1
333 C 2013-01-01 00:00:00 2
Once you have them grouped using CCE, you can do an aggregate on this to get the min/max you are looking for grouping on cce. You can play with the order by at the bottom, this ordering seem to make the most sense to me.
select id, type, min(date), max(date)
from (
select ID, Type, Date,
CONDITIONAL_CHANGE_EVENT(Type) OVER( PARTITION BY ID ORDER BY Date desc) cce
from mytable
group by ID, Type, Date
) x
group by id, type, cce
order by id, 3 desc, 4 desc;
id type min max
1 A 2015-07-01 00:00:00 2015-07-01 00:00:00
1 B 2015-01-01 00:00:00 2015-01-01 00:00:00
1 A 2014-08-05 00:00:00 2014-08-05 00:00:00
22 B 2014-09-01 00:00:00 2015-03-01 00:00:00
333 A 2015-08-01 00:00:00 2015-08-01 00:00:00
333 B 2013-02-28 00:00:00 2015-04-01 00:00:00
333 C 2013-01-01 00:00:00 2013-01-01 00:00:00
I have following tables:
TABLE ITEMS Contains
ITEM_ID ITEM
-------------------
1 Food
2 Medical
3 Shopping
4 Others
TABLE EXPENSE_DURATION Contains
E_ID NAME FROM_DATE TO_DATE
----------------------------------------------------------------
1 FEB_2012 1-Feb-2013 12:00:00 AM 28-Feb-2013 12:00:00 AM
2 MAR_2012 1-Mar-2013 12:00:00 AM 31-Mar-2013 12:00:00 AM
TABLE AMOUNT_FOR_EXPENSE Contains
AFE_ID E_ID ITEM_LIST AMOUNT
------------------------------------
1 1 1,2,3,4 5000
2 2 1,2,3,4 6000
TABLE EXPENSE Contains
EXPENSE_ID E_ID ITEM_ID DATE AMOUNT
---------------------------------------------------------------------
1 1 1 1-Feb-2013 12:00:00 AM 250
2 1 2 1-Feb-2013 12:00:00 AM 450
3 1 3 1-Feb-2013 12:00:00 AM 300
4 1 4 1-Feb-2013 12:00:00 AM 100
5 1 1 2-Feb-2013 12:00:00 AM 4500
6 1 2 2-Feb-2013 12:00:00 AM 3500
7 1 3 2-Feb-2013 12:00:00 AM 2000
8 1 4 2-Feb-2013 12:00:00 AM 1500
Now I want to make one stored Procedure that gives me expense_summary. I am passing Just E_ID as parameter to this stored procedure.
As a result I need one table contains respective summary.
Example: E_ID=1
Result:
TOTAL_OUT TOTAL_IN SUMMARY (IN-OUT)
12600 5000 -7600
I know only
SELECT SUM(AMOUNT) FROM EXPENSE WHERE E_ID=1
Result > 12600
And
SELECT AMOUNT FROM AMOUNT_FOR_EXPENSE WHERE E_ID=1
Result > 5000
I Know this two separate queries but I don’t know how to merge them and how to perform subtraction in select query with joins.
Please help to make select query / stored procedure so that I can generate result as I need.
You can use the following query to get the result:
select e.e_id,
e.Total_out,
a.amount Total_in,
(e.Total_out - a.amount) * -1 Summary
from
(
select sum(amount) Total_out,
e_id
from expense
group by e_id
) e
left join AMOUNT_FOR_EXPENSE a
on e.e_id = a.e_id
where e.e_id = 1
See SQL Fiddle with Demo
try this
SELECT SUM(AMOUNT),AMOUNT FROM EXPENSE ,AMOUNT_FOR_EXPENSE WHERE E_ID=1
I have this in my table
TempTable
Id Date
1 1-15-2010
2 2-14-2010
3 3-14-2010
4 4-15-2010
i would like to change every record so that they have all same day, that is the 15th
like this
TempTable
Id Date
1 1-15-2010
2 2-15-2010 <--change to 15
3 3-15-2010 <--change to 15
4 4-15-2010
what if i like on the 30th?
the records should be
TempTable
Id Date
1 1-30-2010
2 2-28-2010 <--change to 28 because feb has 28 days only
3 3-30-2010 <--change to 30
4 4-30-2010
thanks
You can play some fun tricks with DATEADD/DATEDIFF:
create table T (
ID int not null,
DT date not null
)
insert into T (ID,DT)
select 1,'20100115' union all
select 2,'20100214' union all
select 3,'20100314' union all
select 4,'20100415'
SELECT ID,DATEADD(month,DATEDIFF(month,'20100101',DT),'20100115')
from T
SELECT ID,DATEADD(month,DATEDIFF(month,'20100101',DT),'20100130')
from T
Results:
ID
----------- -----------------------
1 2010-01-15 00:00:00.000
2 2010-02-15 00:00:00.000
3 2010-03-15 00:00:00.000
4 2010-04-15 00:00:00.000
ID
----------- -----------------------
1 2010-01-30 00:00:00.000
2 2010-02-28 00:00:00.000
3 2010-03-30 00:00:00.000
4 2010-04-30 00:00:00.000
Basically, in the DATEADD/DATEDIFF, you specify the same component to both (i.e. month). Then, the second date constant (i.e. '20100130') specifies the "offset" you wish to apply from the first date (i.e. '20100101'), which will "overwrite" the portion of the date your not keeping. My usual example is when wishing to remove the time portion from a datetime value:
SELECT DATEADD(day,DATEDIFF(day,'20010101',<date column>),'20100101')
You can also try something like
UPDATE TempTable
SET [Date] = DATEADD(dd,15-day([Date]), DATEDIFF(dd,0,[Date]))
We have a function that calculates the first day of a month, so I just addepted it to calculate the 15 instead...