Iam trying to extract only the last dates of every month in a year.
SELECT
*
FROM
UNNEST(GENERATE_DATE_ARRAY('2018-04-30', '2027-03-31', INTERVAL 1 MONTH)) AS example
ORDER BY 1 ASC
I am getting
1 2018-04-30
2 2018-05-30
3 2018-06-30
4 2018-07-30
5 2018-08-30
6 2018-09-30
7 2018-10-30
8 2018-11-30
9 2018-12-30
10 2019-01-30
EXPECTATION:
31/01/2013
28/02/2013
31/03/2013
30/04/2013
31/05/2013
30/06/2013
31/07/2013
31/08/2013
30/09/2013
31/10/2013
30/11/2013
31/12/2013
31/01/2014
28/02/2014
31/03/2014
30/04/2014
31/05/2014
30/06/2014
31/07/2014
31/08/2014
30/09/2014
31/10/2014
30/11/2014
31/12/2014
31/01/2015
28/02/2015
You could generate an array of the first day of each month and then subtract one day to get the last day of the previous month:
SELECT DATE_SUB(example, INTERVAL 1 DAY)
FROM UNNEST(GENERATE_DATE_ARRAY('2018-05-1', '2027-04-01', INTERVAL 1 MONTH)) AS example
Consider below approach
SELECT LAST_DAY(example, MONTH) last_day_of_month
FROM UNNEST(GENERATE_DATE_ARRAY('2018-04-30', '2027-03-31', INTERVAL 1 MONTH)) AS example
Related
I need to get last 6 weeks data from some table, right now the logic that I use is this
WEEK([date column]) BETWEEN WEEK(NOW()) - 6 AND WEEK(NOW())
It run as I want, but January is near and I realize that this query will not working as it is. I try to run my query on 15th January 2022, I only get data from 1st January to 15th January when I use my logic.
TGL MINGGU_KE
2022-01-01 | 1
2022-01-02 | 2
2022-01-03 | 2
2022-01-04 | 2
2022-01-05 | 2
2022-01-06 | 2
2022-01-07 | 2
2022-01-08 | 2
2022-01-09 | 3
2022-01-10 | 3
2022-01-11 | 3
2022-01-12 | 3
2022-01-13 | 3
2022-01-14 | 3
2022-01-15 | 3
Can I get the last 6 weeks data including last year?
This is my dbfiddle: https://dbfiddle.uk/o9BeAFJF
You can round the dates to the first day of the week using ROUND, TRUNC or THIS_WEEK
WITH
SEARCH_WEEK (TGL) AS (
VALUES date '2020-12-01'
UNION ALL
SELECT tgl + 1 DAY FROM SEARCH_WEEK WHERE tgl < CURRENT date
),
BASE_DATE (base_date) AS (
VALUES date '2022-01-15'
),
OPTIONS (OPTION, OPTION_BASE_DATE) AS (
SELECT OPTION, option_base_date FROM base_date CROSS JOIN LATERAL (
VALUES
('ROUND D', ROUND(base_date, 'D')),
('ROUND IW', ROUND(base_date, 'IW')),
('ROUND W', ROUND(base_date, 'W')),
('ROUND WW', ROUND(base_date, 'WW')),
('TRUNC D', TRUNC(base_date, 'D')),
('TRUNC IW', TRUNC(base_date, 'IW')),
('TRUNC W', TRUNC(base_date, 'W')),
('TRUNC WW', TRUNC(base_date, 'WW')),
('THIS_WEEK', THIS_WEEK(base_date)),
('THIS_WEEK + 1 DAY', THIS_WEEK(base_date) + 1 DAY)
) a (OPTION, OPTION_BASE_DATE)
)
SELECT
OPTION,
MIN(TGL) BEGIN,
max(tgl) END,
dayname(MIN(TGL)) day_BEGIN,
dayname(max(tgl)) day_end,
days_between(max(tgl), min(tgl)) + 1 duration_in_days
FROM
SEARCH_WEEK
CROSS JOIN options
WHERE
TGL BETWEEN option_base_date - 35 DAYS AND option_base_date + 6 DAYS
GROUP BY OPTION
OPTION
BEGIN
END
DAY_BEGIN
DAY_END
DURATION_IN_DAYS
ROUND D
2021-12-12
2022-01-22
Sunday
Saturday
42
ROUND IW
2021-12-13
2022-01-23
Monday
Sunday
42
ROUND W
2021-12-11
2022-01-21
Saturday
Friday
42
ROUND WW
2021-12-11
2022-01-21
Saturday
Friday
42
THIS_WEEK
2021-12-05
2022-01-15
Sunday
Saturday
42
THIS_WEEK + 1 DAY
2021-12-06
2022-01-16
Monday
Sunday
42
TRUNC D
2021-12-05
2022-01-15
Sunday
Saturday
42
TRUNC IW
2021-12-06
2022-01-16
Monday
Sunday
42
TRUNC W
2021-12-11
2022-01-21
Saturday
Friday
42
TRUNC WW
2021-12-11
2022-01-21
Saturday
Friday
42
fiddle
you can use dateadd to get first day of week six weeks ago like this:
Select * from tableName
where [dateColumn] between dateadd(WEEK,-6,getdate()) and getdate()
You can use DATEADD to get last 6 weeks of data as follows:
Select * from [TableName] where [DateColumn] between
DATEADD(WEEK,-6,GETDATE()) and GETDATE();
I want to take the value that falls between the current day (today) and yesterday but only when after 9 am yesterday and before 9 am today. The current day must be only on Tuesday - Friday. But, if the current day is Monday, it will take value from Friday after 9 am to Monday before 9 am.
Samples
+---------+------------------------------+
| ID | registration_started_at |
+---------+------------------------------+
| 1 | 2021-05-13 07:00:00.000 |
| 2 | 2021-05-13 11:00:00.000 |
| 3 | 2021-05-14 08:00:00.000 |
| 4 | 2021-05-14 10:00:00.000 |
| 5 | 2021-05-15 12:00:00.000 |
| 6 | 2021-05-16 13:00:00.000 |
| 7 | 2021-05-17 08:00:00.000 |
| 8 | 2021-05-17 10:00:00.000 |
+---------+------------------------------+
So let say when the current_day (today) is Friday (14 May 2021),
When I run the query it must return
Desired Result 1
+---------+------------------------------+
| ID | registration_started_at |
+---------+------------------------------+
| 2 | 2021-05-13 11:00:00.000 |
| 3 | 2021-05-14 08:00:00.000 |
+---------+------------------------------+
But when current_day (today) is Monday (17 May 2021) it should return
Desired Result 2
+---------+------------------------------+
| ID | registration_started_at |
+---------+------------------------------+
| 4 | 2021-05-14 10:00:00.000 |
| 5 | 2021-05-15 12:00:00.000 |
| 6 | 2021-05-16 13:00:00.000 |
| 7 | 2021-05-17 08:00:00.000 |
+---------+------------------------------+
I only manage to get the desired result 1 with this query and I think this still not correct tho for desired result 2
SELECT ID,
DATETIME(registration_started_at, 'Asia/Jakarta') as registration_started_at
FROM `table`
WHERE
DATETIME_DIFF(CURRENT_DATETIME('Asia/Jakarta'), DATETIME(registration_started_at, 'Asia/Jakarta'), week) = 0
AND DATE(DATETIME_ADD(DATETIME(registration_started_at, 'Asia/Jakarta'), INTERVAL -9 HOUR)) = CURRENT_DATE('Asia/Jakarta') - 1
---------edit 1
Using the Mr. Caius Jard answer
WHERE
(DATETIME(registration_started_at, 'Asia/Jakarta') BETWEEN (
(CASE
WHEN EXTRACT(
DAYOFWEEK
FROM CURRENT_DATE('Asia/Jakarta')
) = 2 -- if Monday
THEN DATETIME_ADD(
CURRENT_DATETIME('Asia/Jakarta'),
INTERVAL -63 HOUR
) -- then 63 hours back from midnight today
ELSE DATETIME_ADD(
CURRENT_DATETIME('Asia/Jakarta'),
INTERVAL -15 HOUR
)
END)
) -- else 15 hours back from midnight today
AND DATETIME_ADD(
CURRENT_DATETIME('Asia/Jakarta'),
INTERVAL 9 HOUR
)) -- 9am today
It returns the 63 hours before today's time for Monday or 15 hours before today's time if not Monday, which is incorrect because if I run the query on 15.00 it only returns value from 00.00 today
I think this captures the logic you want:
WHERE DATETIME(registration_started_at, 'Asia/Jakarta') < DATETIME_ADD(DATETIME(DATE(CURRENT_DATETIME('Asia/Jakarta'))), INTERVAL 9 HOUR) AND
(EXTRACT(DAYOFWEEK, DATE(CURRENT_DATETIME('Asia/Jakarta'))) = 2 AND
DATETIME(registration_started_at, 'Asia/Jakarta') > DATETIME_ADD(DATETIME_ADD(DATETIME(DATE(CURRENT_DATETIME('Asia/Jakarta'))), INTERVAL 9 HOUR), INTERVAL -3 DAY) OR
DATETIME(registration_started_at, 'Asia/Jakarta') > DATETIME_ADD(DATETIME_ADD(DATETIME(DATE(CURRENT_DATETIME('Asia/Jakarta'))), INTERVAL 9 HOUR), INTERVAL -1 DAY)
)
What are the important components of this?
This expressoin:
DATETIME_ADD(DATETIME(DATE(CURRENT_DATETIME('Asia/Jakarta'))), INTERVAL 9 HOUR)
Returns 9:00 on the current date in Jakarata. No matter what, you want registration_started_at before that date/time.
This expression
EXTRACT(DAYOFWEEK, DATE(CURRENT_DATETIME('Asia/Jakarta')))
Returns the current day of the week, with 2 for Monday.
These expressions:
DATETIME_ADD(DATETIME_ADD(DATETIME(DATE(CURRENT_DATETIME('Asia/Jakarta'))), INTERVAL 9 HOUR), INTERVAL -3 DAY)
DATETIME_ADD(DATETIME_ADD(DATETIME(DATE(CURRENT_DATETIME('Asia/Jakarta'))), INTERVAL 9 HOUR), INTERVAL -1 DAY)
Just subtract 1 or 3 days from the current 9:00 datetime.
Perhaps something like:
WHERE
registration_started_at
BETWEEN
CASE WHEN EXTRACT(DAYOFWEEK FROM CURRENT_DATE()) = 2 -- if Monday
THEN DATETIME_ADD(CURRENT_DATE(), INTERVAL -63 HOUR)) -- then 63 hours back from midnight today
ELSE DATETIME_ADD(CURRENT_DATE(), INTERVAL -15 HOUR)) END -- else 15 hours back from midnight today
AND
DATETIME_ADD(CURRENT_DATE(), INTERVAL 9 HOUR)) -- 9am today
Never used bigquery, so it might need some fiddling, but the basic idea is that we ask via case when what the current day is and use it to change how much we go back in time
Using Mr. Caius Jard idea, I am able to make it works. I just need to cast CURRENT_DATE to DATETIME() to take the today's 00:00
WHERE
(DATETIME(registration_started_at, 'Asia/Jakarta') BETWEEN (
(CASE
WHEN EXTRACT(
DAYOFWEEK
FROM CURRENT_DATE('Asia/Jakarta')
) = 2 -- if Monday
THEN DATETIME_ADD(
DATETIME(CURRENT_DATE('Asia/Jakarta')),
INTERVAL -63 HOUR
) -- then 63 hours back from midnight today
ELSE DATETIME_ADD(
DATETIME(CURRENT_DATE('Asia/Jakarta')),
INTERVAL -15 HOUR
)
END)
) -- else 15 hours back from midnight today
AND DATETIME_ADD(
DATETIME(CURRENT_DATE('Asia/Jakarta')),
INTERVAL 9 HOUR
)) -- 9am today
I have a table that is currently in the following format
ID
Title
CreatedOn
1
Test 1
2021-04-26 08:00:00
2
Test 2
2021-04-26 10:00:00
3
Test 3
2021-04-27 09:00:00
4
Test 4
2021-04-28 14:00:00
5
Test 5
2021-04-28 16:00:00
6
Test 6
2021-04-28 12:00:00
7
Test 7
2021-04-29 13:00:00
8
Test 8
2021-04-30 06:00:00
9
Test 9
2021-05-17 10:00:00
10
Test 10
2021-05-18 19:00:00
11
Test 11
2021-05-18 23:00:00
12
Test 12
2021-05-19 16:00:00
13
Test 13
2021-05-20 07:00:00
14
Test 14
2021-05-21 14:00:00
15
Test 15
2021-05-21 10:00:00
16
Test 16
2021-04-30 10:00:00
What I would like to do is a query that would tell me how many requests have been Monday to Friday per hour. So aggregate all the data into just rows of Monday to Friday.
So the query should return
Day
Hour
Count
Monday
08:00
1
Monday
10:00
2
Tuesday
10:00
1
Tuesday
19:00
1
Tuesday
23:00
1
Wednesday
14:00
1
Wednesday
16:00
2
Wednesday
12:00
1
etc.. How do I achieve this?
So far I have the following
SELECT
DATENAME(WEEK, CreatedOn) AS Week,
DATEPART(Hour, CreatedOn) AS Hour,
COUNT(*) AS Requests
FROM [Enterprise32].[dbo].[nav_EmailEstimateRequests]
where CreatedOn > '2021-01-01'
GROUP BY DATENAME(WK, CreatedOn),DATEPART(Hour, CreatedOn)
ORDER BY DATENAME(WK, CreatedOn);
But the above query returns each week so Week 1 up until Week 21. Please guide me in the right direction.
Thank you!
You want weekday for the date part:
SELECT DATENAME(WEEKDAY, CreatedOn) AS Weekday,
DATEPART(Hour, CreatedOn) AS Hour,
COUNT(*) AS Requests
FROM [Enterprise32].[dbo].[nav_EmailEstimateRequests]
WHERE CreatedOn > '2021-01-01'
GROUP BY DATENAME(WEEKDAY, CreatedOn), DATEPART(Hour, CreatedOn), DATEPART(WEEKDAY, CreatedOn)
ORDER BY DATEPART(WEEKDAY, CreatedOn), Hour;
Note: I included DATEPART(weekday, ) in the GROUP BY, so you could use it in the ORDER BY.
My data looks like below, and I need to show the ids where interval between date1 and date2 are part of a given month/year parameter.
Eg.: for July 2018 I need ids from 1 to 7.
date1 date2 id
---------- ---------- --------
2017-11-01 2018-08-28 1
2018-06-05 2018-07-05 2
2018-06-05 2019-05-07 3
2018-06-05 2018-08-08 4
2018-07-01 2018-07-31 5
2018-07-07 2018-07-15 6
2018-07-27 2018-08-05 7
2018-06-01 2018-06-07 8
2018-08-03 2018-09-01 9
solution is quite simple
SELECT
id
FROM
YOUR_TABLE
WHERE
date1<=YOUR_DATE_END_OF_MONTH AND date2>=YOUR_DATE_START_OF_MONTH
e.g. for July 2018
SELECT
id
FROM
YOUR_TABLE
WHERE
date1<='2018-07-31' AND date2>='2018-07-01'
or if you do not need to calculate first end day of the month (but this do not use any indexes if exists on date1 and date2)
SELECT
id
FROM
YOUR_TABLE
WHERE
EXTRACT(YEAR FROM date1)*12 + EXTRACT(MONTH FROM date1)<=2018*12 + 7
AND EXTRACT(YEAR FROM date2)*12 + EXTRACT(MONTH FROM date2)>=2018*12 + 7
I have the following table:
Date Number
-----------------------------
2018-01-01 10
2018-01-04 5
2018-01-10 10
2018-01-20 5
2018-02-01 8
2018-02-03 2
2018-02-28 10
I want to have the following result:
WeekNumber Year SumOfNumber
-----------------------------------------------
1 2018 15
2 2018 10
3 2018 5
5 2018 10
9 2018 10
Week day Start from Monday to Sunday.
The result should be inserted into a Table.
Does anyone have an idea for this?
Thank you
Use ISO_WEEK in DATEPART() function
select
DATEPART(ISO_WEEK, date) WeekNumber, year(date) Year, sum(Number) SumOfNumber
from table
group by DATEPART(ISO_WEEK, date), year(date)