I have the following table:
Date Number
-----------------------------
2018-01-01 10
2018-01-04 5
2018-01-10 10
2018-01-20 5
2018-02-01 8
2018-02-03 2
2018-02-28 10
I want to have the following result:
WeekNumber Year SumOfNumber
-----------------------------------------------
1 2018 15
2 2018 10
3 2018 5
5 2018 10
9 2018 10
Week day Start from Monday to Sunday.
The result should be inserted into a Table.
Does anyone have an idea for this?
Thank you
Use ISO_WEEK in DATEPART() function
select
DATEPART(ISO_WEEK, date) WeekNumber, year(date) Year, sum(Number) SumOfNumber
from table
group by DATEPART(ISO_WEEK, date), year(date)
Related
In SQL Server, I have maintained following details.
S.No
Vehicle_ID
Start Date
Failed Date
Total Run years
1
1
2011-01-01
2013-12-31
3
2
1
2014-01-01
2015-12-31
2
3
1
2016-01-01
2019-12-31
4
4
1
2020-01-01
2022-12-31
3
5
2
2011-01-01
2015-12-31
5
6
2
2016-01-01
2022-12-31
7
8
3
2013-01-01
2016-12-31
4
10
3
2017-01-01
2021-12-31
5
I would like to calculate year on year Run_time from cumulative Run_time
Required result like this:
Year
Run Years
2011
2
2012
2
2013
3
2014
3
2015
3
2016
3
2017
3
2018
3
2019
3
2020
3
2021
3
2022
2
Year column first year is MIN year from Start Date
Year column end year is MAX year from Failed Date
First of all we can generate list of relevant years using GENERATE_SERIES
SELECT value [Year]
FROM GENERATE_SERIES(
(SELECT YEAR(MIN(StartDate)) FROM Cars),
(SELECT YEAR(MAX(EndDate)) FROM Cars)
)
After this we can JOIN YEARS table with our data group it by Year ad get count:
WITH YEARS AS (
SELECT value [Year]
FROM GENERATE_SERIES(
(SELECT YEAR(MIN(StartDate)) FROM Cars),
(SELECT YEAR(MAX(EndDate)) FROM Cars)
)
) SELECT [Year], COUNT(*)
FROM YEARS
JOIN Cars ON [Year] BETWEEN YEAR(StartDate) AND YEAR(EndDate)
GROUP BY [Year]
And test above queries on:
https://sqlize.online/sql/mssql2022/9ae8b354190c9cf2d19739bf9b9a9816/
Iam trying to extract only the last dates of every month in a year.
SELECT
*
FROM
UNNEST(GENERATE_DATE_ARRAY('2018-04-30', '2027-03-31', INTERVAL 1 MONTH)) AS example
ORDER BY 1 ASC
I am getting
1 2018-04-30
2 2018-05-30
3 2018-06-30
4 2018-07-30
5 2018-08-30
6 2018-09-30
7 2018-10-30
8 2018-11-30
9 2018-12-30
10 2019-01-30
EXPECTATION:
31/01/2013
28/02/2013
31/03/2013
30/04/2013
31/05/2013
30/06/2013
31/07/2013
31/08/2013
30/09/2013
31/10/2013
30/11/2013
31/12/2013
31/01/2014
28/02/2014
31/03/2014
30/04/2014
31/05/2014
30/06/2014
31/07/2014
31/08/2014
30/09/2014
31/10/2014
30/11/2014
31/12/2014
31/01/2015
28/02/2015
You could generate an array of the first day of each month and then subtract one day to get the last day of the previous month:
SELECT DATE_SUB(example, INTERVAL 1 DAY)
FROM UNNEST(GENERATE_DATE_ARRAY('2018-05-1', '2027-04-01', INTERVAL 1 MONTH)) AS example
Consider below approach
SELECT LAST_DAY(example, MONTH) last_day_of_month
FROM UNNEST(GENERATE_DATE_ARRAY('2018-04-30', '2027-03-31', INTERVAL 1 MONTH)) AS example
My data looks like below, and I need to show the ids where interval between date1 and date2 are part of a given month/year parameter.
Eg.: for July 2018 I need ids from 1 to 7.
date1 date2 id
---------- ---------- --------
2017-11-01 2018-08-28 1
2018-06-05 2018-07-05 2
2018-06-05 2019-05-07 3
2018-06-05 2018-08-08 4
2018-07-01 2018-07-31 5
2018-07-07 2018-07-15 6
2018-07-27 2018-08-05 7
2018-06-01 2018-06-07 8
2018-08-03 2018-09-01 9
solution is quite simple
SELECT
id
FROM
YOUR_TABLE
WHERE
date1<=YOUR_DATE_END_OF_MONTH AND date2>=YOUR_DATE_START_OF_MONTH
e.g. for July 2018
SELECT
id
FROM
YOUR_TABLE
WHERE
date1<='2018-07-31' AND date2>='2018-07-01'
or if you do not need to calculate first end day of the month (but this do not use any indexes if exists on date1 and date2)
SELECT
id
FROM
YOUR_TABLE
WHERE
EXTRACT(YEAR FROM date1)*12 + EXTRACT(MONTH FROM date1)<=2018*12 + 7
AND EXTRACT(YEAR FROM date2)*12 + EXTRACT(MONTH FROM date2)>=2018*12 + 7
I have a table
ID Value Date
1 10 2017-10-02 02:50:04.480
2 20 2017-10-01 07:28:53.593
3 30 2017-09-30 23:59:59.000
4 40 2017-09-30 23:59:59.000
5 50 2017-09-30 02:36:07.520
I compare Value with previous date. But, I don't need compare result between first day in current month and last day in previous month. For this table, I don't need to compare result between 2017-10-01 07:28:53.593 and 2017-09-30 23:59:59.000 How it can be done?
Result table for this example:
ID Value Date Diff
1 10 2017-10-02 02:50:04.480 10
2 20 2017-10-01 07:28:53.593 NULL
3 30 2017-09-30 23:59:59.000 10
4 40 2017-09-29 23:59:59.000 10
5 50 2017-09-28 02:36:07.520 NULL
You can use this.
SELECT * ,
LEAD(Value) OVER( PARTITION BY DATEPART(YEAR,[Date]), DATEPART(MONTH,[Date]) ORDER BY ID ) - Value AS Diff
FROM MyTable
ORDER BY ID
you can use a query like below
select *,
diff=LEAD(Value) OVER( PARTITION BY Month(Date),Year(Date) ORDER BY Date desc)-Value
from t
order by id asc
see working demo
Please help me how can I break a date range into quarters of a year.Ex date range 1st Jan 2012 to 31st October 2013 should give me a result set of all 8 quarters.The results should be in following format, I am using SQL server 2008 :
Quarter Month start Month end
1 Jan-12 Mar-12
2 Apr-12 Jun-12
3 Jul-12 Sep-12
4 Oct-12 Dec-12
1 Jan-13 Mar-13
2 Apr-13 Jun-13
3 Jul-13 Sep-13
4 Oct-13 Oct-13
You'd need to look at the DATEPART(QUARTER,date) and break them up that way. Something akin to this:
select datepart(year, dateTarget) as theYear, num as theQuarter, min(dateTarget) as startDate, max(dateTarget) as endDate
from numbers
join dates on datepart(quarter, dateper) = num
where num between 1 and 4
group by datepart(year, dateTarget),num
Where the dates table is the table you're looking at, and numbers is, well, a numbers table (something I find pretty useful to just have around).
This gives you quarter start dates for 12 quarrters:
with calendar as (
select
--DATEFROMPARTS(year(getdate()),1,1) as [start],
convert(datetime, convert(char(4), year(getdate()))+'0101') as [start],
qtrsBack = 1
union all
select
dateadd(mm,-3,[start]),
qtrsBack+1
from calendar
where qtrsback < 12
)
select * from calendar
producing:
start qtrsBack
---------- -----------
2013-01-01 1
2012-10-01 2
2012-07-01 3
2012-04-01 4
2012-01-01 5
2011-10-01 6
2011-07-01 7
2011-04-01 8
2011-01-01 9
2010-10-01 10
2010-07-01 11
2010-04-01 12