My data looks like below, and I need to show the ids where interval between date1 and date2 are part of a given month/year parameter.
Eg.: for July 2018 I need ids from 1 to 7.
date1 date2 id
---------- ---------- --------
2017-11-01 2018-08-28 1
2018-06-05 2018-07-05 2
2018-06-05 2019-05-07 3
2018-06-05 2018-08-08 4
2018-07-01 2018-07-31 5
2018-07-07 2018-07-15 6
2018-07-27 2018-08-05 7
2018-06-01 2018-06-07 8
2018-08-03 2018-09-01 9
solution is quite simple
SELECT
id
FROM
YOUR_TABLE
WHERE
date1<=YOUR_DATE_END_OF_MONTH AND date2>=YOUR_DATE_START_OF_MONTH
e.g. for July 2018
SELECT
id
FROM
YOUR_TABLE
WHERE
date1<='2018-07-31' AND date2>='2018-07-01'
or if you do not need to calculate first end day of the month (but this do not use any indexes if exists on date1 and date2)
SELECT
id
FROM
YOUR_TABLE
WHERE
EXTRACT(YEAR FROM date1)*12 + EXTRACT(MONTH FROM date1)<=2018*12 + 7
AND EXTRACT(YEAR FROM date2)*12 + EXTRACT(MONTH FROM date2)>=2018*12 + 7
Related
Iam trying to extract only the last dates of every month in a year.
SELECT
*
FROM
UNNEST(GENERATE_DATE_ARRAY('2018-04-30', '2027-03-31', INTERVAL 1 MONTH)) AS example
ORDER BY 1 ASC
I am getting
1 2018-04-30
2 2018-05-30
3 2018-06-30
4 2018-07-30
5 2018-08-30
6 2018-09-30
7 2018-10-30
8 2018-11-30
9 2018-12-30
10 2019-01-30
EXPECTATION:
31/01/2013
28/02/2013
31/03/2013
30/04/2013
31/05/2013
30/06/2013
31/07/2013
31/08/2013
30/09/2013
31/10/2013
30/11/2013
31/12/2013
31/01/2014
28/02/2014
31/03/2014
30/04/2014
31/05/2014
30/06/2014
31/07/2014
31/08/2014
30/09/2014
31/10/2014
30/11/2014
31/12/2014
31/01/2015
28/02/2015
You could generate an array of the first day of each month and then subtract one day to get the last day of the previous month:
SELECT DATE_SUB(example, INTERVAL 1 DAY)
FROM UNNEST(GENERATE_DATE_ARRAY('2018-05-1', '2027-04-01', INTERVAL 1 MONTH)) AS example
Consider below approach
SELECT LAST_DAY(example, MONTH) last_day_of_month
FROM UNNEST(GENERATE_DATE_ARRAY('2018-04-30', '2027-03-31', INTERVAL 1 MONTH)) AS example
I have the following table:
Date Number
-----------------------------
2018-01-01 10
2018-01-04 5
2018-01-10 10
2018-01-20 5
2018-02-01 8
2018-02-03 2
2018-02-28 10
I want to have the following result:
WeekNumber Year SumOfNumber
-----------------------------------------------
1 2018 15
2 2018 10
3 2018 5
5 2018 10
9 2018 10
Week day Start from Monday to Sunday.
The result should be inserted into a Table.
Does anyone have an idea for this?
Thank you
Use ISO_WEEK in DATEPART() function
select
DATEPART(ISO_WEEK, date) WeekNumber, year(date) Year, sum(Number) SumOfNumber
from table
group by DATEPART(ISO_WEEK, date), year(date)
I have a table
ID Value Date
1 10 2017-10-02 02:50:04.480
2 20 2017-10-01 07:28:53.593
3 30 2017-09-30 23:59:59.000
4 40 2017-09-30 23:59:59.000
5 50 2017-09-30 02:36:07.520
I compare Value with previous date. But, I don't need compare result between first day in current month and last day in previous month. For this table, I don't need to compare result between 2017-10-01 07:28:53.593 and 2017-09-30 23:59:59.000 How it can be done?
Result table for this example:
ID Value Date Diff
1 10 2017-10-02 02:50:04.480 10
2 20 2017-10-01 07:28:53.593 NULL
3 30 2017-09-30 23:59:59.000 10
4 40 2017-09-29 23:59:59.000 10
5 50 2017-09-28 02:36:07.520 NULL
You can use this.
SELECT * ,
LEAD(Value) OVER( PARTITION BY DATEPART(YEAR,[Date]), DATEPART(MONTH,[Date]) ORDER BY ID ) - Value AS Diff
FROM MyTable
ORDER BY ID
you can use a query like below
select *,
diff=LEAD(Value) OVER( PARTITION BY Month(Date),Year(Date) ORDER BY Date desc)-Value
from t
order by id asc
see working demo
I have the following table in HANA :
vehicle_id time roaming_time parking_time
1 Sep 01,2016 3:09:03 AM 3 9
2 Sep 01,2016 3:12:03 AM 6 8
1 Sep 01,2016 9:10:03 AM 10 6
4 Sep 01,2016 10:09:03 AM 9 3
1 Sep 01,2016 10:10:03 AM 10 10
4 Sep 01,2016 12:09:03 AM 3 9
from these information I wanted to know that what is the sum of roaming_time and sum of parking_time for each hour from all the vehicles and want the output in the format:
time roaming_time parking_time
____ _____________ ____________
2016-09-01 00:00:00 3 9
2016-09-01 01:00:00 6 8
2016-09-01 02:00:00 9 6
2016-09-01 03:00:00 3 6
2016-09-01 04:00:00 12 3
2016-09-01 05:00:00 15 8
2016-09-01 06:00:00 18 4
2016-09-01 07:00:00 8 3
2016-09-01 08:00:00 9 4
2016-09-01 09:00:00 6 6
2016-09-01 10:00:00 6 9
........
2016-09-01 23:00:00 3 12
I need to group the following query which gives all the sum by hour wise and get the expected result:
select sum(roaming_time) as roaming_time,sum(parking_time) as parking_time
from time>='2016-09-01 00:00:00'
time>='2016-09-01 23:59:59'
I do not know how to do the grouping by hour in HANA. Any help is appreciated
Here is one method . . . it converts the time to a date and hour format:
select to_varchar(time, 'YYYY-MM-DD'), hour(time),
sum(roaming_time) as roaming_time, sum(parking_time) as parking_time from t
group by date(time), hour(time)
order by to_varchar(time, 'YYYY-MM-DD'), hour(time);
Use a group by clause with SERIES_ROUND(). Avoid date() and hour() and similar data/time functions on large data sets as they tend to be slower.
select SERIES_ROUND(time, 'INTERVAL 1 HOUR') as time,
sum(roaming_time) as roaming_time, sum(parking_time) as parking_time from t
group by SERIES_ROUND(time, 'INTERVAL 1 HOUR')
order by SERIES_ROUND(time, 'INTERVAL 1 HOUR');
Another approach is to convert it to a string, especially if no further time calculations are required.
This could look like this:
select to_varchar(time, 'DD.MM.YYYY HH24') as parking_hour ,
sum(roaming_time) as roaming_time, sum(parking_time) as parking_time from t
group by to_varchar(time, 'DD.MM.YYYY HH24') as parking_hour
order byto_varchar(time, 'DD.MM.YYYY HH24') as parking_hour;
Please help me how can I break a date range into quarters of a year.Ex date range 1st Jan 2012 to 31st October 2013 should give me a result set of all 8 quarters.The results should be in following format, I am using SQL server 2008 :
Quarter Month start Month end
1 Jan-12 Mar-12
2 Apr-12 Jun-12
3 Jul-12 Sep-12
4 Oct-12 Dec-12
1 Jan-13 Mar-13
2 Apr-13 Jun-13
3 Jul-13 Sep-13
4 Oct-13 Oct-13
You'd need to look at the DATEPART(QUARTER,date) and break them up that way. Something akin to this:
select datepart(year, dateTarget) as theYear, num as theQuarter, min(dateTarget) as startDate, max(dateTarget) as endDate
from numbers
join dates on datepart(quarter, dateper) = num
where num between 1 and 4
group by datepart(year, dateTarget),num
Where the dates table is the table you're looking at, and numbers is, well, a numbers table (something I find pretty useful to just have around).
This gives you quarter start dates for 12 quarrters:
with calendar as (
select
--DATEFROMPARTS(year(getdate()),1,1) as [start],
convert(datetime, convert(char(4), year(getdate()))+'0101') as [start],
qtrsBack = 1
union all
select
dateadd(mm,-3,[start]),
qtrsBack+1
from calendar
where qtrsback < 12
)
select * from calendar
producing:
start qtrsBack
---------- -----------
2013-01-01 1
2012-10-01 2
2012-07-01 3
2012-04-01 4
2012-01-01 5
2011-10-01 6
2011-07-01 7
2011-04-01 8
2011-01-01 9
2010-10-01 10
2010-07-01 11
2010-04-01 12