I have table such as
column
abcx sample 6.5oz
bbcd sku 2ct
tty 80z
rre pool 65g box
How can I create a new column in my select statement that would just give me what the size of each row value is? ( 6.50z, 2ct, 80z, 65g)
desired output:
size
6.5oz
2ct
90z
65g
The question is not specified precisely.
Here's a solution assuming you're interested in "a sequence of digits, possibly containing a dot, immediately followed by a sequence of lowercase letters".
If so, this should do it:
select col, regexp_substr(col, '[\\d\\.]+[a-z]+') from test;
If this is not what you're looking for, please make the question very specific
Related
Hi i have string in BigQuery column like this
cancellation_amount: 602000
after_cancellation_transaction_amount: 144500
refund_time: '2022-07-31T06:05:55.215203Z'
cancellation_amount: 144500
after_cancellation_transaction_amount: 0
refund_time: '2022-08-01T01:22:45.94919Z'
i already using this logic to get cancellation_amount
regexp_extract(file,r'.*cancellation_amount:\s*([^\n\r]*)')
but the output only amount 602000, i need the output 602000 and 144500 become different column
Appreciate for helping
If your lines in the input (which will eventually become columns) are fixed you can use multiple regexp_extracts to get all the values.
SELECT
regexp_extract(file,r'cancellation_amount:\s*([^\n\r]*)') as cancellation_amount
regexp_extract(file,r'. after_cancellation_transaction_amount:\s*([^\n\r]*)') as after_cancellation_transaction_amount
FROM table_name
One issue I found with your regex expression is that .*cancellation_amount won't match after_cancellation_transaction_amount.
There is also a function called regexp_extract_all which returns all the matches as an array which you can later explode into columns, but if you have finite values separating them out in different columns would be a easier.
Here is my problem statement:
I have single column table having the data like as :
ROW-1>> 7302-2210177000-XXXX-XXXXXX-XXX-XXXXXXXXXX-XXXXXX-XXXXXX-U-XXXXXXXXX-XXXXXX
ROW-2>> 0311-1130101-XXXX-000000-XXX-XXXXXXXXXX-XXXXXX-XXXXXX-X-XXXXXXXXX-WIPXXX
Here i want to separate these values from '-' and load into a new table. There are 11 segments in this string separated by '-', therefore, 11 columns. The problem is:
A. The length of these values are changing, however, i have to keep it as the length of these values in the standard format or the length which it has
e.g 7302- (should have four values, if the value less then that then keep that value eg. 73 then it should populate 73.
Therefore, i have to separate as well as mentation the integrity. The code which i am writing is :
select
SUBSTR(PROFILE_ID,1,(case when length(instr(PROFILE_ID,'-')<>4) THEN (instr(PROFILE_ID,'-') else SUBSTR(PROFILE_ID,1,4) end)
)AS [RQUIRED_COLUMN_NAME]
from [TABLE_NAME];
getting right parenthesis error
Please help.
I used the regex_substr SQL function to solve the above issue. Here below is an example:
select regex_substr('7302-2210177000-XXXX-XXXXXX-XXX-XXXXXXXXXX-XXXXXX-XXXXXX-U-XXXXXXXXX-XXXXXX ROW-2>> 0311-1130101-XXXX-000000-XXX-XXXXXXXXXX-XXXXXX-XXXXXX-X-XXXXXXXXX-WIPXXX',[^-]+,1,1);
Output is: 7302 --which is the 1st segment of the string
Similarly, the send string segment which is separated by "-" in the string can be obtained by just replacing the 1 with 2 in the above query at the end.
Example : select regex_substr('7302-2210177000-XXXX-XXXXXX-XXX-XXXXXXXXXX-XXXXXX-XXXXXX-U-XXXXXXXXX-XXXXXX ROW-2>> 0311-1130101-XXXX-000000-XXX-XXXXXXXXXX-XXXXXX-XXXXXX-X-XXXXXXXXX-WIPXXX',[^-]+,1,2);
output: 2210177000 which is the 2nd segment of the string
I'm trying to take a regular expression and split it by a pre-determined character, and then extract the final value of the returned list.
For example, my string may take the form:
name
WAYNE.ROONEY.226
ROSS.BARKLEY.HELLO.113
ADAM.A122
Pythonically, what I'm trying to do is:
for x in list:
my_val = x.split('.')[-1] #Return the last element of the list when split on .
e.g. desired output:
name value
WAYNE.ROONEY.226 226
ROSS.BARKLEY.HELLO.113 113
ADAM.A122 A122
Can anyone provide me any pointers in either Hive or Impala please?
If I can create this as a view, ideally, that would be perfect, but am also happy with generating actual output with it and then re-uploading to a table
Thank you!
For Hive:
select regexp_extract(NAME, '\\.([^\\.]+)$', 1) as VALUE
from WHATEVER
And pleeeease [edit] learn the power of regular expressions...
What I am trying to do is get a range of cube numbers within our building. The issue being the the cube number data type is nvarchar. I know its what messing me up but I have no control over the DB also all of our cube numbers are prefaced with a couple of chars such as AA-1 through AA-255 (thus the nvarchar). My question is this why does the below work:
Select
PCName,
CubeNumer
From
thisTable
where
CubeNumber like 'AA-[1-9]'
The above will give me the PCNames for AA-1 through AA-9 but when I do the following:
...
where CubeNumber like 'AA-[1-20]'
it gives me AA-1 and AA-2. I see the 1 and 2 there, I get its not seeing it as a 20. So is it possible to get that range to work, or any range beside 1-9 to work with that syntax?
Regex is a string comparison and therefore will will look for specific strings. Your pattern of 'AA-[1-20]' is looking for anything that starts with AA- and then numbers 1 through 2, or 0. The correct way would be to do 'AA-[0-9]*'
If your cubes always start with AA-, you could also do a replace and then cast to convert the cube numbers to actual numbers and then do a BETWEEN query.
CAST(REPLACE(CubeNumber,'AA-','') as INT) BETWEEN 1 AND 20;
I found a weird problem with MySQL select statement having "IN" in where clause:
I am trying this query:
SELECT ads.*
FROM advertisement_urls ads
WHERE ad_pool_id = 5
AND status = 1
AND ads.id = 23
AND 3 NOT IN (hide_from_publishers)
ORDER BY rank desc
In above SQL hide_from_publishers is a column of advertisement_urls table, with values as comma separated integers, e.g. 4,2 or 2,7,3 etc.
As a result, if hide_from_publishers contains same above two values, it should return only record for "4,2" but it returns both records
Now, if I change the value of hide_for_columns for second set to 3,2,7 and run the query again, it will return single record which is correct output.
Instead of hide_from_publishers if I use direct values there, i.e. (2,7,3) it does recognize and returns single record.
Any thoughts about this strange problem or am I doing something wrong?
There is a difference between the tuple (1, 2, 3) and the string "1, 2, 3". The former is three values, the latter is a single string value that just happens to look like three values to human eyes. As far as the DBMS is concerned, it's still a single value.
If you want more than one value associated with a record, you shouldn't be storing it as a comma-separated value within a single field, you should store it in another table and join it. That way the data remains structured and you can use it as part of a query.
You need to treat the comma-delimited hide_from_publishers column as a string. You can use the LOCATE function to determine if your value exists in the string.
Note that I've added leading and trailing commas to both strings so that a search for "3" doesn't accidentally match "13".
select ads.*
from advertisement_urls ads
where ad_pool_id = 5
and status = 1
and ads.id = 23
and locate(',3,', ','+hide_from_publishers+',') = 0
order by rank desc
You need to split the string of values into separate values. See this SO question...
Can Mysql Split a column?
As well as the supplied example...
http://blog.fedecarg.com/2009/02/22/mysql-split-string-function/
Here is another SO question:
MySQL query finding values in a comma separated string
And the suggested solution:
http://dev.mysql.com/doc/refman/5.0/en/string-functions.html#function_find-in-set