I have parameter YEAR and MONTH, for example 2021 and 9
How do I get the last date of that month, in that year?
For example, with the values mentioned before, I should receive:
30.09.2021.
Why not literraly ?
select LAST_DAY(SYSDATE) from dual
with your parameters
select LAST_DAY(to_date('01'||:month||:year,'ddmmyyyy')) from dual;
Related
I'm trying to create three columns based on date in seconds format.
My user.updated_at = 1521533490
I would like to get year, month and day separately and put these formatted values to columns for example:
year -> 2018, month -> 11, day -> 23
Does someone know how can I do that in pgSQL?
I would like to get year, month and day separately and put these formated values to columns
Don't do that.
Use a single column of type date or timestamp, depending on your application. Not every combination of your three columns will be a valid date. But every value in a single column of type date will be a valid date.
If you need the parts of a date separately, use PostgreSQL's date/time functions.
Try this approche to get differents arguments, then you can do whatever you want:
SELECT to_timestamp(1521533490); //2018-03-20T08:11:30.000Z
SELECT to_char(to_timestamp(1521533490), 'HH'); // 08 Hour
SELECT to_char(to_timestamp(1521533490), 'MI'); // 11 Minutes
SELECT to_char(to_timestamp(1521533490), 'SS'); // 30 Seconds
SELECT to_char(to_timestamp(1521533490), 'DD'); // 20 Day
SELECT to_char(to_timestamp(1521533490), 'Mon'); // MAR Month
SELECT to_char(to_timestamp(1521533490), 'YYYY'); // 2018 Year
Use the EXTRACT function.
SELECT to_timestamp(updated_at) "Date",
EXTRACT(YEAR FROM (to_timestamp(updated_at))) "Year",
EXTRACT(MONTH FROM (to_timestamp(updated_at))) "Month",
EXTRACT(DAY FROM (to_timestamp(updated_at))) "Day"
FROM users
Output
Date Year Month Day
2018-03-20T08:11:30Z 2018 3 20
SQL Fiddle: http://sqlfiddle.com/#!15/afe0e/15/0
More information on the EXTRACT function.
The following query returns
select to_char( trunc(sysdate) - numtoyminterval(level - 1, 'month'), 'mon-yy') as month from dual connect by level <= 12
last 12 months according to today's date(i.e. 2-Jan-18).
Say if today's date is 29-DEC-17 it gives oracle sql error:
ORA-01839: date not valid for month specified
(since on subtracting there would be a date in the result as '29-FEB-17' which is not possible). So on specific dates this error would pop-up. How do you suggest to overcome this?
I prefer ADD_MONTHS (TRUNC of a date literal is stupid, but I left it as you'd have SYSDATE anyway, wouldn't you?):
SQL> select to_char(add_months(trunc(date '2017-12-29'), -level), 'dd-mon-yy',
2 'nls_Date_language = english') as month
3 from dual
4 connect by level <= 12;
MONTH
------------------
29-nov-17
29-oct-17
29-sep-17
29-aug-17
29-jul-17
29-jun-17
29-may-17
29-apr-17
29-mar-17
28-feb-17
29-jan-17
29-dec-16
12 rows selected.
SQL>
This behavior of INTERVAL YEAR TO MONTH is as documented, see Datetime/Interval Arithmetic
You should consider function ADD_MONTHS:
If date is the last day of the month or if the resulting month has
fewer days than the day component of date, then the result is the last
day of the resulting month. Otherwise, the result has the same day
component as date.
It depends on your requirements what you consider as "right". In fact "one month" does not have a fixed duration.
I have a query which uses needs to know how many days passed since 1st of January in the current year.
Which means that if the query runs for example in:
2nd Jan 2017 than it should return 2 (as 2 days passed since 1st Jan
2017).
10th Feb 2016 than it should return 41 (as 41 days passed since 1st
Jan 2016).
basically it needs to take Current Year from Curent Date and count the days since 1/1/(Year).
i have the current year with: SELECT EXTRACT(year FROM CURRENT_DATE);
I created the 1st of Jan with:
select (SELECT EXTRACT(year FROM CURRENT_DATE)::text || '-01-01')::date
How do I get the difference from this date to Current_Date?
Basically this question can be Given two dates, how many days between them?
Something like age(timestamp '2016-01-01', timestamp '2016-06-15') isn't good because I need the result only in days. while age gives in years,months and days.
An easier approach may be to extract the day of year ("doy") field from the date:
db=> SELECT EXTRACT(DOY FROM CURRENT_DATE);
date_part
-----------
41
And if you need it as a number, you could just cast it:
db=> SELECT EXTRACT(DOY FROM CURRENT_DATE)::int;
date_part
-----------
41
Note: The result 41 was produced by running the query today, February 9th.
Given two dates, how many days between them
Just subtract one from the other.
In your case you could just round the current_date to the start of the year and subtract that from the current date:
select current_date - date_trunc('year', current_date)::date
The ::date cast is necessary to get the result as an integer, otherwise the result will be an interval.
Another solution is to use DATEDIFF
SELECT DATE_PART('day', now()::timestamp - '2016-01-01 00:00:00'::timestamp);
How do I determine how many days in a month, from the first to the current day (could be anywhere into the month). So if I have a field that gives 6/01/12 5:32:13 PM and 6/07/12 5:33:04 PM how do I get the difference?
I think something like this should do it:
SELECT TRUNC(SYSDATE) - TRUNC(SYSDATE,'MONTH') + 1 FROM DUAL
SELECT EXTRACT(DAY FROM sysdate) FROM dual;
What is the correct expression to use for todays date plus 1 year.
I assume it starts with Now()+ but im unsure from there
This page has lots of great examples, including:
=DateAdd(DateInterval.Month, 6, Parameters!StartDate.Value)
From that and the example before it, it looks like you want:
=DateAdd(DateInterval.Year, 1, Today())
this should be what your looking for:
--midnight last day of last month
select DateAdd(mm,-0,(DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE()),0))))
--midnight last day of this month
select DateAdd(mm,+1,(DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE()),0))))
--midnight last day of last month 1 year ago
select DateAdd(yy,-1,(DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE()),0))))
--midnight last day of this month 1 year ago
select DateAdd(yy,-1,DateAdd(mm,+1,(DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE()),0)))))