The problem
Using PostgreSQL 13, I ran into a performance issue selecting the highest id from a view that joins two tables, depending on the select statement I execute.
Here's a sample setup:
CREATE TABLE test1 (
id BIGSERIAL PRIMARY KEY,
joincol VARCHAR
);
CREATE TABLE test2 (
joincol VARCHAR
);
CREATE INDEX ON test1 (id);
CREATE INDEX ON test1 (joincol);
CREATE INDEX ON test2 (joincol);
CREATE VIEW testview AS (
SELECT test1.id,
test1.joincol AS t1charcol,
test2.joincol AS t2charcol
FROM test1, test2
WHERE test1.joincol = test2.joincol
);
What I found out
I'm executing two statements which result in completely different execution plans and runtimes. The following statement executes in less than 100ms. As far as I understand the execution plan, the runtime is independent of the rowcount, since Postgres iterates the rows one by one (starting at the highest id, using the index) until a join on a row is possible and immediately returns.
SELECT id FROM testview ORDER BY ID DESC LIMIT 1;
However, this one takes over 1 second on average (depending on rowcount), since the two tables are "joined completely", before Postgres uses the index to select the highest id.
SELECT MAX(id) FROM testview;
Please refer to this sample on dbfiddle to check the explain plans:
https://www.db-fiddle.com/f/bkMNeY6zXqBAYUsprJ5eWZ/1
My real environment
On my real environment test1 contains only a hand full of rows (< 100), having unique values in joincol. test2 contains up to ~10M rows, where joincol always matches a value of test1's joincol. test2's joincol is not nullable.
The actual question
Why does Postgres not recognize that it could use an Index Scan Backward on row basis for the second select? Is there anything I could improve on the tables/indexes?
Queries not strictly equivalent
why does Postgres not recognize that it could use a Index Scan Backward on row basis for the second select?
To make the context clear:
max(id) excludes NULL values. But ORDER BY ... LIMIT 1 does not.
NULL values sort last in ascending sort order, and first in descending. So an Index Scan Backward might not find the greatest value (according to max()) first, but any number of NULL values.
The formal equivalent of:
SELECT max(id) FROM testview;
is not:
SELECT id FROM testview ORDER BY id DESC LIMIT 1;
but:
SELECT id FROM testview ORDER BY id DESC NULLS LAST LIMIT 1;
The latter query doesn't get the fast query plan. But it would with an index with matching sort order: (id DESC NULLS LAST).
That's different for the aggregate functions min() and max(). Those get a fast plan when targeting table test1 directly using the plain PK index on (id). But not when based on the view (or the underlying join-query directly - the view is not the blocker). An index sorting NULL values in the right place has hardly any effect.
We know that id in this query can never be NULL. The column is defined NOT NULL. And the join in the view is effectively an INNER JOIN which cannot introduce NULL values for id.
We also know that the index on test.id cannot contain NULL values.
But the Postgres query planner is not an AI. (Nor does it try to be, that could get out of hands quickly.) I see two shortcomings:
min() and max() get the fast plan only when targeting the table, regardless of index sort order, an index condition is added: Index Cond: (id IS NOT NULL)
ORDER BY ... LIMIT 1 gets the fast plan only with the exactly matching index sort order.
Not sure, whether that might be improved (easily).
db<>fiddle here - demonstrating all of the above
Indexes
Is there anything I could improve on the tables/indexes?
This index is completely useless:
CREATE INDEX ON "test" ("id");
The PK on test.id is implemented with a unique index on the column, that already covers everything the additional index might do for you.
There may be more, waiting for the question to clear up.
Distorted test case
The test case is too far away from actual use case to be meaningful.
In the test setup, each table has 100k rows, there is no guarantee that every value in joincol has a match on the other side, and both columns can be NULL
Your real case has 10M rows in table1 and < 100 rows in table2, every value in table1.joincol has a match in table2.joincol, both are defined NOT NULL, and table2.joincol is unique. A classical one-to-many relationship. There should be a UNIQUE constraint on table2.joincol and a FK constraint t1.joincol --> t2.joincol.
But that's currently all twisted in the question. Standing by till that's cleaned up.
This is a very good problem, and good testcase.
I tested it in postgres 9.3 perhaps 13 is can it more more fast.
I used Occam's Razor and i excluded some possiblities
View (without view is slow to)
JOIN can filter some rows (unfortunatly in your test not, but more length md5 5-6 yes)
Other basic equivalent select statements not solve yout problem (inner query or exists)
I achieved to use just index, but because the tables isn't bigger than indexes it was not the solution.
I think
CREATE INDEX on "test" ("id");
is useless, because PK!
If you change this
CREATE INDEX on "test" ("joincol");
to this
CREATE INDEX ON TEST (joincol, id);
Than the second query use just indexes.
After you run this
REINDEX table test;
REINDEX table test2;
VACUUM ANALYZE test;
VACUUM ANALYZE test2;
you can achive some performance tuning. Because you created indexes before inserts.
I think the reason is the two aim of DB.
First aim optimalize just some row. So run Nested Loop. You can force it with limit x.
Second aim optimalize whole table. Run this query fast for whole table.
In this situation postgres optimalizer didn't notice that simple MAX can run with NESTED LOOP. Or perhaps postgres cannot use limit in aggregate clause (can run on whole partial select, what is filtered with query).
And this is very expensive. But you have possiblities to write there other aggregates, like SUM, MIN, AVG stb.
Perhaps can help you the Window functions too.
Related
This question already has an answer here:
Does a SELECT query always return rows in the same order? Table with clustered index
(1 answer)
Closed 8 years ago.
I am unable to get clear cut answers on this contentious question .
MSDN documentation mentions
Clustered
Clustered indexes sort and store the data rows in the table or view
based on their key values. These are the columns included in the
index definition. There can be only one clustered index per table,
because the data rows themselves can be sorted in only one order.
The only time the data rows in a table are stored in sorted order is
when the table contains a clustered index. When a table has a
clustered index, the table is called a clustered table. If a table
has no clustered index, its data rows are stored in an unordered
structure called a heap.
While I see most of the answers
Does a SELECT query always return rows in the same order? Table with clustered index
http://sqlwithmanoj.com/2013/06/02/clustered-index-do-not-guarantee-physically-ordering-or-sorting-of-rows/
answering negative.
What is it ?
Just to be clear. Presumably, you are talking about a simple query such as:
select *
from table t;
First, if all the data on the table fits on a single page and there are no other indexes on the table, it is hard for me to imagine a scenario where the result set is not ordered by the primary key. However, this is because I think the most reasonable query plan would require a full-table scan, not because of any requirement -- documented or otherwise -- in SQL or SQL Server. Without an explicit order by, the ordering in the result set is a consequence of the query plan.
That gets to the heart of the issue. When you are talking about the ordering of the result sets, you are really talking about the query plan. And, the assumption of ordering by the primary key really means that you are assuming that the query uses full-table scan. What is ironic is that people make the assumption, without actually understanding the "why". Furthermore, people have a tendency to generalize from small examples (okay, this is part of the basis of human intelligence). Unfortunately, they see consistently that results sets from simple queries on small tables are always in primary key order and generalize to larger tables. The induction step is incorrect in this example.
What can change this? Off-hand, I think that a full table scan would return the data in primary key order if the following conditions are met:
Single threaded server.
Single file filegroup
No competing indexes
No table partitions
I'm not saying this is always true. It just seems reasonable that under these circumstances such a query would use a full table scan starting at the beginning of the table.
Even on a small table, you can get surprises. Consider:
select NonPrimaryKeyColumn
from table
The query plan would probably decide to use an index on table(NonPrimaryKeyColumn) rather than doing a full table scan. The results would not be ordered by the primary key (unless by accident). I show this example because indexes can be used for a variety of purposes, not just order by or where filtering.
If you use a multi-threaded instance of the database and you have reasonably sized tables, you will quickly learn that results without an order by have no explicit ordering.
And finally, SQL Server has a pretty smart optimizer. I think there is some reluctance to use order by in a query because users think it will automatically do a sort. SQL Server works hard to find the best execution plan for the query. IF it recognizes that the order by is redundant because of the rest of the plan, then the order by will not result in a sort.
And, of course you want to guarantee the ordering of results, you need order by in the outermost query. Even a query like this:
select *
from (select top 100 t.* from t order by col1) t
Does not guarantee that the results are ordered in the final result set. You really need to do:
select *
from (select top 100 t.* from t order by col1) t
order by col1;
to guarantee the results in a particular order. This behavior is documented here.
Without ORDER BY, there is no default sort order even if you have clustered index
in this link there is a good example :
CREATE SCHEMA Data AUTHORIZATION dbo
GO
CREATE TABLE Data.Numbers(Number INT NOT NULL PRIMARY KEY)
GO
DECLARE #ID INT;
SET NOCOUNT ON;
SET #ID = 1;
WHILE #ID < 100000 BEGIN
INSERT INTO Data.Numbers(Number)
SELECT #ID;
SET #ID = #ID+1;
END
CREATE TABLE Data.WideTable(ID INT NOT NULL
CONSTRAINT PK_WideTable PRIMARY KEY,
RandomInt INT NOT NULL,
CHARFiller CHAR(1000))
GO
CREATE VIEW dbo.WrappedRand
AS
SELECT RAND() AS random_value
GO
CREATE ALTER FUNCTION dbo.RandomInt()
RETURNS INT
AS
BEGIN
DECLARE #ret INT;
SET #ret = (SELECT random_value*1000000 FROM dbo.WrappedRand);
RETURN #ret;
END
GO
INSERT INTO Data.WideTable(ID,RandomInt,CHARFiller)
SELECT Number, dbo.RandomInt(), 'asdf'
FROM Data.Numbers
GO
CREATE INDEX WideTable_RandomInt ON Data.WideTable(RandomInt)
GO
SELECT TOP 100 ID FROM Data.WideTable
OUTPUT:
1407
253
9175
6568
4506
1623
581
As you have seen, the optimizer has chosen to use a non-clustered
index to satisfy this SELECT TOP query.
Clearly you cannot assume that your results are ordered unless you
explicitly use ORDER BY clause.
One must specify ORDER BY in the outermost query in order to guarantee rows are returned in a particular order. The SQL Server optimizer will optimize the query and data access to improve performance which may result in rows being returned in a different order. Examples of this are allocation order scans and parallelism. A relational table should always be viewed as an unordered set of rows.
I wish the MSDN documentation were clearer about this "sorting". It is more correct to say that SQL Server b-tree indexes provide ordering by 1) storing adjacent keys in the same page and 2) linking index pages in key order.
SQL Fiddle: http://sqlfiddle.com/#!3/23cf8
In this query, when I have an In clause on an Id, and then also select other columns, the In is evaluated first, and then the Details column and other columns are pulled in via a RID Lookup:
--In production and in SQL Fiddle, Details is grabbed via a RID Lookup after the In clause is evaluated
SELECT [Id]
,[ForeignId]
,Details
--Generate a numbering(starting at 1)
--,Row_Number() Over(Partition By ForeignId Order By Id Desc) as ContactNumber --Desc because older posts should be numbered last
FROM SupportContacts
Where foreignId In (1,2,3,5)
With this query, the Details are being pulled in via a Table Scan.
With NumberedContacts AS
(
SELECT [Id]
,[ForeignId]
--Generate a numbering(starting at 1)
,Row_Number() Over(Partition By ForeignId Order By Id Desc) as ContactNumber --Desc because older posts should be numbered last
FROM SupportContacts
Where ForeignId In (1,2,3,5)
)
Select nc.[Id]
,nc.[ForeignId]
,sc.[Details]
From NumberedContacts nc
Inner Join SupportContacts sc on nc.Id = sc.Id
Where nc.ContactNumber <= 2 --Only grab the last 2 contacts per ForeignId
;
In SqlFiddle, the second query actually gets a RID Lookup, whereas in production with a million records it produces a Table Scan (the IN clause eliminates 99% of the rows)
Otherwise the query plan shown in SQL Fiddle is identical, the only difference being that for the second query the RID Lookup in SQL Fiddle, is a Table Scan in production :(
I would like to understand possibilities that would cause this behavior? What kinds of things would you look at to help determine the cause of it using a table scan here?
How can I influence it to use a RID Lookup there?
From looking at operation costs in the actual execution plan, I believe I can get the second query very close in performance to the first query if I can get it to use a RID Lookup. If I don't select the Detail column, then the performance of both queries is very close in production. It is only after adding other columns like Detail that performance degrades significantly for the second query. When I put it in SQL Fiddle and saw that the execution plan used an RID Lookup, I was surprised but slightly confused...
It doesn't have a clustered index because in testing with different clustered indexes, there was slightly worse performance for this and other queries. That was before I began adding other columns like Details though, and I can experiment with that more, but would like to have a understanding of what is going on now before I start shooting in the dark with random indexes.
What if you would change your main index to include the Details column?
If you use:
CREATE NONCLUSTERED INDEX [IX_SupportContacts_ForeignIdAsc_IdDesc]
ON SupportContacts ([ForeignId] ASC, [Id] DESC)
INCLUDE (Details);
then neither a RID lookup nor a table scan would be needed, since your query could be satisfied from just the index itself....
The differences in the query plans will be dependent on the types of indexes that exist and the statistics of the data for those tables in the different environments.
The optimiser uses the statistics (histograms of data frequency, mostly) and the available indexes to decide which execution plan is going to be the quickest.
So, for example, you have noticed that the performance degrades when the 'Details' column is included. This is an almost sure sign that either the 'Details' column is not part of an index, or if it is part of an index, the data in that column is mostly unique such that the index accesses would be equivalent (or almost equivalent) to a table scan.
Often when this situation arises, the optimiser will choose a table scan over the index access, as it can take advantage of things like block reads to access the table records faster than perhaps a fragmented read of an index.
To influence the path that will be chose by the optimiser, you would need to look at possible indexes that could be added/modified to make an index access more efficient, but this should be done with care as it can adversely affect other queries as well as possibly degrading insert performance.
The other important activity you can do to help the optimiser is to make sure the table statistics are kept up to date and refreshed at a frequency that is appropriate to the rate of change of the frequency distribution in the table data
If it's true that 99% of the rows would be omitted if it performed the query using the relevant index + RID then the likeliest problem in your production environment is that your statistics are out of date and the optimiser doesn't realise that ForeignID in (1,2,3,5) would limit the result set to 1% of the total data.
Here's a good link for discovering more about statistics from Pinal Dave: http://blog.sqlauthority.com/2010/01/25/sql-server-find-statistics-update-date-update-statistics/
As for forcing the optimiser to follow the correct path WITHOUT updating the statistics, you could use a table hint - if you know the index that your plan should be using which contains the ID and ForeignID columns then stick that in your query as a hint and force SQL optimiser to use the index:
http://msdn.microsoft.com/en-us/library/ms187373.aspx
FYI, if you want the best performance from your second query, use this index and avoid the headache you're experiencing altogether:
create index ix1 on SupportContacts(ForeignID, Id DESC) include (Details);
I have an index on a nullable column and I want to select all it's values like this:
SELECT e.ename
FROM emp e;
In the explain plan I see a FULL TABLE SCAN (even a hint didn't help)
SELECT e.ename
FROM emp e
WHERE e.ename = 'gdoron';
Does use the index...
I googled and found out there are no null entries in indexes, thus the first query can't use the index.
My question is simple: why there aren't null entries in indexes?
By default, relational databases ignore NULL values (because the relational model says that NULL means "not present"). So, Index does not store NULL value, consequently if you have null condition in SQL statement, related index is ignored (by default).
But you can suprass this problem, check THIS or THIS article.
If you're getting all of the rows from the table, why do you think it should use the index? A full table scan is the most efficient means to return all of the values. It has nothing to do with the nulls not being in the index and everything to do with the optimizer choosing the most efficient means of retrieving the data.
#A.B.Cade: It's possible that the optimizer could choose to use the index, but not likely. Let's say you've got a table with an indexed table with 100 rows, but only 10 values. If the optimizer uses the index, it has to get the 10 rows from the index, then expand it to 100 rows, whereas, with the full-table scan, it gets all 100 rows from the get-go. Here's an example:
create table test1 (blarg varchar2(10));
create index ak_test1 on test1 (blarg);
insert into test1
select floor(level/10) from dual connect by level<=100;
exec dbms_stats.gather_table_stats('testschema','test1');
exec dbms_stats.gather_index_stats('testschema','ak_test1');
EXPLAIN PLAN FOR
select * from test1;
My point is largely that this question is based largely on a flawed premise: that index-scans are intrinsically better that full-table scans. That is not always true, as this scenario demonstrates.
Should be noted, Bitmap-Indexes include rows that have NULL values.
But you should not create Bitmap-Index just because you like to have NULL values in
your index. Bitmap-Index indexes are intended for their use-case (see documentation)!
If you use them wrong, then your over-all performance may suffer significantly.
I am not sure the first query is pertinent in terms of index usage, at least the second could.
Anyway, while it is true that you cannot index a column containing a null value, there are ways to do it like for example:
create index MY_INDEX on emp(ename, 1);
notice the , 1) at the end which does the trick.
I have a SQL table readings something like:
id int
client_id int
device_id int
unique index(client_id, device_id)
I do not understand why the following query is so slow:
SELECT client_id FROM `readings` WHERE device_id = 10 ORDER BY client_id DESC LIMIT 1
My understanding with the index is that mysql keeps an ordered list (one property of a btree) of each row in the table sorted first by client_id and then by device_id. When I execute an explain on this query it says that it will use the index, but that it will need to look at every row. This makes sense since in the worst case, there may only be one row with device_id = 10 and that may also be the row with the smallest client_id and thus at the end of it's search. However, in practice, this is not true. My table has ~10 million rows, and rows with device_id = 10 are spread fairly evenly throughout that table. Why then doesn't MySQL start at the end of the index and scan until it finds the first row with device_id = 10, stop and return that value? It does not seem possible that this is what is happening since the query takes ~30 seconds to execute.
Is it that my unique key is implemented as a hash somehow and thus not accessible in a list form? PHPMyAdmin is telling me that it is implemented as a b-tree, which makes me think that it should be able to do the scan as I mentioned above and quit with the first instance.
Where is my error and how can I make this query execute more quickly?
Thanks
Try switching the column order in the index:
unique index(device_id, client_id)
Since you are filtering on device_id, you would want that to be the first column in the index.
First, I'm assuming that you have good statistics for this table. If not, you'll want to analyze the table to make sure the optimizer can figure out what the best option is.
Here's another approach you could try that might work better. I could be that MySQL is not understanding your intent well enough to optimize correctly:
SELECT MAX(client_id) from readings where device_id = 10
Otherwise you could modify the index to be by device_id first, then client_id. Or you could add another index by just device_id.
You have a compound index on (client_id, device_id), these will(more or less) be concatenated for the purpose of indexing and the index will only be considered if you use the
first of the column(s). Your query is using 'device_id' which is the last of them, you could provide a separate index on that column, or swap the columns around in the index.
Also, check the output of EXPLAIN on your queries.
How can I make an ORDER BY clause with a small LIMIT (ie 20 rows at a time) return quickly, when I can't use an index to satisfy the ordering of rows?
Let's say I would like to retrieve a certain number of titles from a table 'node' (simplified below). I'm using MySQL by the way.
node_ID INT(11) NOT NULL auto_increment,
node_title VARCHAR(127) NOT NULL,
node_lastupdated INT(11) NOT NULL,
node_created INT(11) NOT NULL
But I need to limit the rows returned to only those a particular user has access to. Many users have access large numbers of nodes. I have this information pre-calculated in a big lookup table (an attempt to make things easier) where the primary key covers both columns and the presence of a row means that usergroup has access to that node:
viewpermission_nodeID INT(11) NOT NULL,
viewpermission_usergroupID INT(11) NOT NULL
My query therefore contains something like
FROM
node
INNER JOIN viewpermission ON
viewpermission_nodeID=node_ID
AND viewpermission_usergroupID IN (<...usergroups of current user...>)
... and I also use a GROUP BY or a DISTINCT so that a node is only returned once even if two of the user's 'usergroups' both have access to that node.
My problem is that there seems to be no way for an ORDER BY clause which sorts results by created or last updated date to use an index, because the rows being returned depend on values in the other viewpermission table.
Therefore MySQL would need to find all rows which match the criteria, then sort them all itself. If there are one million rows for a particular user, and we want to view, say, the latest 100 or rows 100-200 when ordered by last update, the DB would need to figure out which one million rows the user can see, sort this whole result set itself, before it can return those 100 rows, right?
Is there any creative way to get around this? I've been thinking along the lines of:
Somehow add dates into the viewpermission lookup table so that I can build an index containing the dates as well as the permissions. It's a possibility I guess.
Edit: Simplified question
Perhaps I can simplify the question by rewriting it like this:
Is there any way to rewrite this query or create an index for the following such that an index can be used to do the ordering (not just to select the rows)?
SELECT nodeid
FROM lookup
WHERE
usergroup IN (2, 3)
GROUP BY
nodeid
An index on (usergroup) allows the WHERE part to be satisfied by an index, but the GROUP BY forces a temporary table and filesort on those rows. An index on (nodeid) does nothing for me, because the WHERE clause needs an index with usergroup as its first column. An index on (usergroup, nodeid) forces a temporary table and filesort because the GROUP BY is not the first column of the index that can vary.
Any solutions?
Can I answer my own question?
I believe I have found that the only way to do what I describe is for my lookup table to have rows for every possible combination of usergroups a person may want to be a member of.
To pick a simplified example, instead of doing this:
SELECT id FROM ids WHERE groups IN(1,2) ORDER BY id
If you need to use the index both to select rows and to order them, you have to abstract that IN(1,2) so that it is constant rather than a range, ie:
SELECT id FROM ids WHERE grouplist='1,2' ORDER BY id
Of course instead of using the string '1,2' you could have a foreign key there, etc. The point being that you'd have to have a row not just for each group but for each combination of multiple groups.
So, there is my answer.
Anyway, for my application, I feel that maintaining a lookup for all possible combinations of usergroups for each node is not worth it. For my purposes, I predict that most nodes are visible to most users, so I feel that it is acceptable to simply to make the GROUP BY use the index, as the filtering doesn't need it so badly.
In other words, the approach I'll take for my original query may be something like:
SELECT
<fields>
FROM
node
INNER JOIN viewpermission ON
viewpermission_nodeID=node_ID
AND viewpermission_usergroupID IN (<...usergroups of current user...>)
FORCE INDEX(node_created_and_node_ID)
GROUP BY
node_created, node_ID
GROUP BY can use an index if it starts at the left most column of the index and it is in the first non-const non-system table to be processed. The join then deals with the entire list (which is already ordered), and only those not visible to the current user (which will be a small proportion) are removed by the INNER JOIN.
Copy the value you are going to order by into to viewpermission table and add it to your index.
You could use a trigger to maintain that value from the other table.
select * from
(
select *
FROM node
INNER JOIN viewpermission
ON viewpermission_nodeID=node_ID
AND viewpermission_usergroupID IN (<...usergroups of current user...>)
) a
order by a.node_lastupdated desc
The inner query gives you the filtered subset, which I understand is substantially smaller than the whole set. Only the smaller has to be sorted.
MySQL has problems when you use GROUP BY and ORDER BY in the same query. That causes a filesort, and that's probably the biggest penalty for performance.
You can eliminate the need for a DISTINCT (or GROUP BY) by using a non-correlated subquery instead of a JOIN.
SELECT * FROM node
WHERE node_id IN (
SELECT viewpermission_nodeID
FROM viewpermission
WHERE viewpermissiong_usergroupID IN ( <...usergroups...> )
)
ORDER BY node_lastupdated DESC
LIMIT 100;
There's no need to sort or do a DISTINCT on the subquery, since IN (1, 1, 2, 3) is the same as IN (1, 3, 2).
Note that MySQL can use only one index per table in a given query, so it'll try to make the best choice between an index on node_id and an index on node_lastupdated. It can't use both, and even if you made a compound index it wouldn't help in this case.
Remember to analyze different solutions with EXPLAIN.