I made a select and it looks like this
SELECT name,class_name
FROM students
INNER JOIN classes on classes.id = students.id
and I get a table like
| name | class_name |
| -------- | -------------- |
| Daniel | Math |
| Johnny | Physics |
| Johnny | Math |
| Andrew | English |
...
How am I supposed to split the table to get the first two classes each student attends (students can attend more than two classes or a single class)
Example:
| name | class_1 | class_2 |
| -------- | -------------- | ---------|
| Daniel | Math | |
| Johnny | Math | Physics |
| Andrew | English | |
...
I was thinking of transposing the table, however, I don't know how to actually do it or if it's a good approach.
I concatenated every different class for each student in a single column with commas as separators (because classes can contain spaces, for example, "Computer Science") then I split the single column into the two required classes.
WITH part
AS (SELECT NAME,
class_name
FROM students
INNER JOIN classes
ON classes.id = students.id),
ans
AS (SELECT NAME,
Array_to_string(Array_agg(class_name), ',') AS cl
FROM part
GROUP BY NAME)
SELECT NAME,
Split_part(cl, ',', 1) AS class_1,
Split_part(cl, ',', 2) AS class_2
FROM ans
Related
I have the following data:
select * from art_skills_table;
+----+------+---------------------------+
| ID | Name | skills |
+----+------+---------------------------|
| 1 | Anna | ["painting","photography"]|
| 2 | Bob | ["drawing","sculpting"] |
| 3 | Cat | ["pastel"] |
+----+------+---------------------------+
select * from computer_table;
+------+------+-------------------------+
| ID | Name | skills |
+------+------+-------------------------+
| 1 | Anna | ["word","typing"] |
| 2 | Cat | ["code","editing"] |
| 3 | Bob | ["excel","code"] |
+------+------+-------------------------+
I would like to write an SQL statement which results in the following table.
+------+------+-----------------------------------------------+
| ID | Name | skills |
+------+------+-----------------------------------------------+
| 1 | Anna | ["painting","photography","word","typing"] |
| 2 | Bob | ["drawing","sculpting","excel","code"] |
| 3 | Cat | ["pastel","code","editing"] |
+------+------+-----------------------------------------------+
I've tried something like SELECT * from art_skills_table LEFT JOIN computer_table ON name. However it doesn't give what I need. I've read about array_cat but I'm having a bit of trouble implementing it.
if the skills column from both tables are arrays, then you should be able to get away with this:
SELECT a.ID, a.name, array_cat(a.skills, c.skills)
FROM art_skills_table a LEFT JOIN computer_table c
ON c.id = a.id
That said, While you used LEFT join in your sample, I think either an INNER or FULL (OUTER) join might serve you better.
First, i wondered why the data are stored in such a model.
Was of the opinion that NoSQL databases lack ability for joins and ...
... a semantic triple would be in the form of subject–predicate–object.
... a Key-value (KV) stores use associative arrays.
... a relational database would be normalized.
A few information about the use case would have helped.
Nevertheless, you can select the data with CONCAT and REPLACE for the desired form.
SELECT art_skills_table.ID, computer_table.name,
CONCAT(
REPLACE(art_skills_table.skills, '}',','),
REPLACE(computer_table.skills, '{','')
)
FROM art_skills_table JOIN computer_table ON art_skills_table.ID = computer_table.ID
The query returns the following result:
+----+------+--------------------------------------------+
| ID | Name | Skills |
+----+------+--------------------------------------------+
| 1 | Anna | {"painting","photography","word","typing"} |
| 2 | Cat | {"drawing","sculpting","code","editing"} |
| 3 | Bob | {"pastel","excel","code"} |
+----+------+--------------------------------------------+
I've used the ID for the JOIN, even though Bob has different values.
The JOIN should probably be done over the name.
JOIN computer_table ON art_skills_table.Name = computer_table.Name
BTW, you need to tell us what SQL engine you're running on.
I am trying to filter a set of tables that includes an M:N junction table in Android Room (SQLite).
An image can have many subjects. I'd like to allow filtering by a subject, so that I get a row with complete image information (including all subjects). So if an image had (National Park, Yosemite) filtering for either would result in one row with both keywords. Unless I messed something up, a typical join will result in multiple rows such that matching Yosemite would get the right image, but you'd be lacking National Park. I came up with this:
SELECT *,
(SELECT GROUP_CONCAT(name)
FROM meta_subject_junction
JOIN subject
ON subject.id = meta_subject_junction.subjectId
WHERE meta_subject_junction.metaId = meta.id) AS keywords,
(SELECT documentUri
FROM image_parent
WHERE meta.parentId = image_parent.id ) AS parentUri
FROM meta
Now this gets me the complete rows, but I think at this point I'd need to:
WHERE keywords LIKE(%YOSEMITE%)
and I think the LIKE is less than ideal, not to mention an imprecise match. Is there a better way to accomplish this? Thanks, this is bending my novice SQL brain.
Further details
meta
+----+----------+--+
| id | name | |
+----+----------+--+
| 1 | yosemite | |
| 2 | bryce | |
| 3 | flowers | |
+----+----------+--+
subject
+----+---------------+--+
| id | name | |
+----+---------------+--+
| 1 | National Park | |
| 2 | Yosemite | |
| 3 | Tulip | |
+----+---------------+--+
junction
+--------+-----------+
| metaId | subjectId |
+--------+-----------+
| 1 | 1 |
| 1 | 2 |
| 2 | 1 |
| 3 | 3 |
+--------+-----------+
Although I may have done something wrong, as far as I can tell Android Room doesn't like:
+----+-----------+---------------+
| id | name | subject |
+----+-----------+---------------+
| 1 | yosemite | National Park |
| 1 | yosemite | Yosemite |
+----+-----------+---------------+
so I'm trying to reduce the rows:
+----+-----------+-------------------------+
| id | name | subject |
+----+-----------+-------------------------+
| 1 | yosemite | National Park, Yosemite |
+----+-----------+-------------------------+
which the above query does. However, I also want to query for a subject. So that National Park filter will yield:
+----+-----------+-------------------------+
| id | name | subject |
+----+-----------+-------------------------+
| 1 | yosemite | National Park, Yosemite |
| 2 | bryce | National Park |
+----+-----------+-------------------------+
I'd like to be more precise/efficient than LIKE with the already 'concat' subject. Most of my attempts end up with no results in Room (multi-row) or reducing the subject to only the filter keyword.
Update
Here's a test I've been using to compare the actual SQL results from a query to what Android Room ends up with:
http://sqlfiddle.com/#!7/0ac11/10/0
That join query is interpreted as four objects in Android Room, so I'm trying to reduce the rows, but retain the full subject results while filtering for any image containing the subject keyword.
If you want multiple keywords, then where and group by and having can be used:
select image_id
from image_subject
where subject_id in ('a', 'b', 'c') -- whatever
group by image-id
having count(distinct subject_id) = 3; -- same count as in `where`
This gets the result I need, though I'd love to hear a better option if this is particularly inefficient.
SELECT meta.*,
(SELECT GROUP_CONCAT(name)
FROM junction
JOIN subject
ON subject.id = junction.subjectId
WHERE junction.metaId = meta.id) AS keywords,
junction.subjectId
FROM meta
LEFT JOIN junction ON junction.metaId = meta.id
WHERE subjectId IN (1,2)
GROUP BY meta.id
+----+----------+------------------------+-----------+
| id | name | keywords | subjectId |
+----+----------+------------------------+-----------+
| 1 | yosemite | National Park,Yosemite | 2 |
| 2 | bryce | National Park | 1 |
+----+----------+------------------------+-----------+
http://sqlfiddle.com/#!7/86a76/13
I have two tables I am using at work to help me gain experience in writing SQL queries. One table contains a list of Applications and has three columns -
Application_Name, Application_Contact_ID and Business_Contact_ID. I then have a separate table called Contacts with two columns - Contact_ID and Contact_Name. I am trying to write a query that will list the Application_Name and Contact_Name for both the Applications_Contact_ID and Business_Contact_ID columns instead of the ID number itself.
I understand I need to JOIN the two tables but I haven't quite figured out how to formulate the correct statement. Help Please!
APPLICATIONS TABLE:
+------------------+------------------------+---------------------+
| Application_Name | Application_Contact_ID | Business_Contact_ID |
+------------------+------------------------+---------------------+
| Adobe | 23 | 23 |
| Word | 52 | 14 |
| NotePad++ | 44 | 989 |
+------------------+------------------------+---------------------+
CONTACTS TABLE:
+------------+--------------+
| Contact_ID | Contact_Name |
+------------+--------------+
| 23 | Tim |
| 52 | John |
| 14 | Jen |
| 44 | Carl |
| 989 | Sam |
+------------+--------------+
What I am trying to get is:
+------------------+--------------------------+-----------------------+
| Application_Name | Application_Contact_Name | Business_Contact_Name |
+------------------+--------------------------+-----------------------+
| Adobe | Tim | Tim |
| Word | John | Jen |
| NotePad++ | Carl | Sam |
+------------------+--------------------------+-----------------------+
I've tried the below but it is only returning the name for one of the columns:
SELECT Application_Name, Application_Contact_ID, Business_Contact_ID, Contact_Name
FROM Applications
JOIN Contact ON Contact_ID = Application_Contact_ID
This is a pretty critical and 101 part of SQL. Consider reading this other answer on a different question, which explains the joins in more depth. The trick to your query, is that you have to join the CONTACTS table twice, which is a bit hard to visualize, because you have to go there for both the application_contact_id and business_contact_id.
There are many flavors of joins (INNER, LEFT, RIGHT, etc.), which you'll want to familiarize yourself with for the future reference. Consider reading this article at the very least: https://www.techonthenet.com/sql_server/joins.php.
SELECT t1.application_name Application_Name,
t2.contact_name Application_Contact_name,
t3.contact_name Business_Contact_name
FROM applications t1
INNER JOIN contacts ON t2 t1.Application_Contact_ID = t2.contact_id -- join contacts for appName
INNER JOIN contacts ON t3 t1.business_Contact_ID = t3.contact_id; -- join contacts for busName
Here are the two tables i have: [all columns in both tables are of type "text"], Table name and the column names are in bold fonts.
Names
--------------------------------
Name | DoB | Team |
--------------------------------
Harry | 3/12/85 | England
Kevin | 8/07/86 | England
James | 5/05/89 | England
Scores
------------------------
ScoreName | Score
------------------------
James-1 | 120
Harry-1 | 30
Harry-2 | 40
James-2 | 56
End result i need is a table that has the following
NameScores
---------------------------------------------
Name | DoB | Team | ScoreData
---------------------------------------------
Harry | 3/12/85 | England | "{"ScoreName":"Harry-1", "Score":"30"}, {"ScoreName":"Harry-2", "Score":"40"}"
Kevin | 8/07/86 | England | null
James | 5/05/89 | England | "{"ScoreName":"James-1", "Score":"120"}, {"ScoreName":"James-2", "Score":"56"}"
I need to do this using a single SQL command which i will use to create a materialized view.
I have gotten as far as realising that it will involve a combination of string_agg, JOIN and JSON, but haven't been able to crack it fully. Please help :)
I don't think the join is tricky. The complication is building the JSON object:
select n.name, n.dob, n.team,
json_agg(json_build_object('ScoreName', s.name,
'Score', s.score)) as ScoreData
from names n left join
scores s
ons.name like concat(s.name, '-', '%')
group by n.name, n.dob, n.team;
Note: json_build_object() was introduced in Postgres 9.4.
EDIT:
I think you can add a case statement to get the simple NULL:
(case when s.name is null then NULL
else json_agg(json_build_object('ScoreName', s.name,
'Score', s.score))
end) as ScoreData
Use json_agg() with row_to_json() to aggregate scores data into a json value:
select n.*, json_agg(row_to_json(s)) "ScoreData"
from "Names" n
left join "Scores" s
on n."Name" = regexp_replace(s."ScoreName", '(.*)-.*', '\1')
group by 1, 2, 3;
Name | DoB | Team | ScoreData
-------+---------+---------+---------------------------------------------------------------------------
Harry | 3/12/85 | England | [{"ScoreName":"Harry-1","Score":30}, {"ScoreName":"Harry-2","Score":40}]
James | 5/05/89 | England | [{"ScoreName":"James-1","Score":120}, {"ScoreName":"James-2","Score":56}]
Kevin | 8/07/86 | England | [null]
(3 rows)
I have three tables like this:
Person table:
person_id | name | dob
--------------------------------
1 | Naveed | 1988
2 | Ali | 1985
3 | Khan | 1987
4 | Rizwan | 1984
Address table:
address_id | street | city | state | country
----------------------------------------------------
1 | MAJ Road | Karachi | Sindh | Pakistan
2 | ABC Road | Multan | Punjab | Pakistan
3 | XYZ Road | Riyadh | SA | SA
Person_Address table:
person_id | address_id
----------------------
1 | 1
2 | 2
3 | 3
Now I want to get all records of Person_Address table but also with their person and address records like this by one query:
person_id| name | dob | address_id | street | city | state | country
----------------------------------------------------------------------------------
1 | Naveed | 1988 | 1 | MAJ Road | Karachi | Sindh | Pakistan
2 | Ali | 1985 | 2 | ABC Road | Multan | Punjab | Pakistan
3 | Khan | 1987 | 3 | XYZ Road | Riyadh | SA | SA
How it is possible using zend? Thanks
The reference guide is the best starting point to learn about Zend_Db_Select. Along with my example below, of course:
//$db is an instance of Zend_Db_Adapter_Abstract
$select = $db->select();
$select->from(array('p' => 'person'), array('person_id', 'name', 'dob'))
->join(array('pa' => 'Person_Address'), 'pa.person_id = p.person_id', array())
->join(array('a' => 'Address'), 'a.address_id = pa.address_id', array('address_id', 'street', 'city', 'state', 'country'));
It's then as simple as this to fetch a row:
$db->fetchRow($select);
In debugging Zend_Db_Select there's a clever trick you can use - simply print the select object, which in turn invokes the toString method to produce SQl:
echo $select; //prints SQL
I'm not sure if you're looking for SQL to do the above, or code using Zend's facilities. Given the presence of "sql" and "joins" in the tags, here's the SQL you'd need:
SELECT p.person_id, p.name, p.dob, a.address_id, street, city, state, country
FROM person p
INNER JOIN Person_Address pa ON pa.person_id = p.person_id
INNER JOIN Address a ON a.address_id = pa.address_id
Bear in mind that the Person_Address tells us that there's a many-to-many relationship between a Person and an Address. Many Persons may share an Address, and a Person may have more than one address.
The SQL above will show ALL such relationships. So if Naveed has two Address records, you will have two rows in the result set with person_id = 1.