I am struggling with a conversion from DD/MM/YYYY format into YYYY-MM-DD in NETEZZA.
I was trying some variants but it didn't worked:
SELECT REVERSE(contract_end_date)
from JNK_TABLE (was tried to revers and after do a To_DATE)
SELECT RIGHT(contract_end_date)
from JNK_TABLE
Any help will be good.
How about converting to a date?
select to_date(contract_end_date, 'DD/MM/YYYY')
Then, fix the data model so that dates are stored as dates.
Once you have it as a date, you can control the format by converting to a string:
select to_char(contract_end_date, 'YYYY-MM-DD')
If you want to find dates that have errors in the day where the day is 0, then try:
select contract_end_date
from t
where contract_end_date like '0/%' or
contract_end_date like '00/%';
Related
I need to convert sysdate in YYYYMM format to validate the expiry date, this is the query I have written but am facing the below error.
select to_char (to_date(sysdate,'MM/DD/YYYY'),'YYYYMM') from dual;
ORA-01858: a non-numeric character was found where a numeric was expected
There is no reason to convert sysdate to a date. So just use:
select to_char(sysdate, 'YYYYMM')
If you wanna to format the date, try "DATE_FORMAT" way:
SELECT DATE_FORMAT('2011-11-11 13:14:01','%m%Y')
or you wanna to get the difference between the expired date and sysdate,you may try "DATEDIFF":
SELECT DATEDIFF('2001-01-01','2001-02-02') -> -32
I'm having issues in my WHERE clause selecting data from a specific day to today's date. The day/time format in my date column is '7/2/2020 3:12:08 PM'.
I've tested a couple options but keep getting this error - 'literal does not match format string'.
Any idea's of how I can select all data from March 1, 2020 to current date?
Thanks!
In Oracle date columns are not strings, they are exactly in date datatype, so you don't need to convert/cast it. Just use simple date literals:
https://docs.oracle.com/en/database/oracle/oracle-database/19/sqlrf/Literals.html#GUID-8F4B3F82-8821-4071-84D6-FBBA21C05AC1
select * from table where your_date_columg >= date'2015-12-31'
or with to_date function for your string:
select * from table
where
your_date_columg >= to_date('2019-11-25 13:57:52',
'yyyy-mm-dd hh24:mi:ss')
I have that field in my table:
2020-01-16T10:55:16..296518000
How to convert this Varchar into a date in format 'YYYY-MM-DD' ?
I tried:
select TRUNC(to_date(DATE_UPDATED ,'YYYY-MM-DD hh24:mi:ss')) from JOB_SCHEDULE_TBL
but I'm getting an error:
ORA-01830: date format picture ends before converting entire input string
Just use substr():
select to_date(SUBSTR(DATE_UPDATED, 1, 10) ,'YYYY-MM-DD')
The trunc() is unnecessary.
You are confusing the format of DATE with what you are seeing on the screen. A DATE data type has no "format". It's Oracle's internal, binary format. Even when you SELECT TO_DATE ..., the result is going to get displayed by the client, and to do so the client will have to peform (under the covers) a TO_CHAR on the resulting DATE. And that implied to_char will use the current system/session/ settings for TNS_DATE_FORMAT.
Trying to convert data thats in DDDYYYY (i.e. 1112014) to a standard date format (Feb-02-2014). How would i go about doing this? I know how to do the inverse operation but I was unable to find any examples online of how to convert from DDDYYYY format to MM/DD/YYYY format.
Below is my attempt:
select to_date(to_char(1112018, 'DDDYYYY'), 'MM/DD/YYYY') from dual;
I have a requirement to convert MM/DD/YYYY to YYYYMMDD in amazon redshift database.
My result of this query gives me some weird result. Can some one please help me.
select to_date ('07/17/2017','YYYYMMDD');
0007-07-20
If you just wish to convert the hard-coded string into a DATE:
select to_date('07/17/2017', 'MM/DD/YYYY')
If you have a column already formatted as DATE, then use:
to_char(fieldname, 'YYYYMMDD')
Combining the two concepts:
select to_char(to_date('07/17/2017', 'MM/DD/YYYY'), 'YYYYMMDD')
TO_DATE - converts a date represented in a character string to a DATE data type.
TO_CHAR - converts a time stamp or numeric expression to a character-string data format.
select to_char(sysdate,'YYYYMMDD');
If I’ve made a bad assumption please comment and I’ll refocus my answer.