Changing date format from day of year format (DDDYYYY) to Date Format (MM/DD/YYYY) - sql

Trying to convert data thats in DDDYYYY (i.e. 1112014) to a standard date format (Feb-02-2014). How would i go about doing this? I know how to do the inverse operation but I was unable to find any examples online of how to convert from DDDYYYY format to MM/DD/YYYY format.
Below is my attempt:
select to_date(to_char(1112018, 'DDDYYYY'), 'MM/DD/YYYY') from dual;

Related

correct to_char date syntax to have trailing zeroes after milliseconds

My current query in oracle sql for getting a timestamp format is TO_CHAR(c2.start_on,'DD-MM-YY HH:MI:SS.FF PM'), it outputs the timestamp like this 25-11-20 07:00:13.36 PM
However I want it to display the date in this way 25-11-20 07:00:13.360000000 PM
What should I add in the timestamp format for this to be possible ?
I have tried doing it like this HH:MI:SS.FM00000 as suggested here
but it gives me the error. ORA-01821: date format not recognized
what is the correct way to get the date in the desired format ?
If you want fractional seconds, you don't want a DATE, you want a TIMESTAMP. So here's a timestamp formatted with 6 digits of precision
select to_char(systimestamp, 'HH:MI:SS.FF6') from dual;
If you have a date, you could convert it to a TIMESTAMP (using CAST AS TIMESTAMP), but better to look at updating your data model to use the proper type for the source column as starters.

Convert date to YYYY-MM-DDThh:mm:ss.sssZ format in Postgresql

I want to convert the date format to YYYY-MM-DDThh:mm:ss.SSSXXXZ (ISO 8601).
Getting 2021-02-10T04:02:55.55SXXXZ and it's wrong. I need it as 2021-02-10T04:02:55.55S000000Z.
select to_char(now(), 'YYYY-MM-DDThh:mm:ss.SSSXXXZ')
For ISO 8601 date format you can use below query:
select to_char(now(), 'YYYY-MM-DD"T"HH24:MI:SS"Z"')
Output:
"2021-02-10T12:09:17Z"
Is it your desired format?

How to convert a VARCHAR to a date in ORACLE SQL?

I have that field in my table:
2020-01-16T10:55:16..296518000
How to convert this Varchar into a date in format 'YYYY-MM-DD' ?
I tried:
select TRUNC(to_date(DATE_UPDATED ,'YYYY-MM-DD hh24:mi:ss')) from JOB_SCHEDULE_TBL
but I'm getting an error:
ORA-01830: date format picture ends before converting entire input string
Just use substr():
select to_date(SUBSTR(DATE_UPDATED, 1, 10) ,'YYYY-MM-DD')
The trunc() is unnecessary.
You are confusing the format of DATE with what you are seeing on the screen. A DATE data type has no "format". It's Oracle's internal, binary format. Even when you SELECT TO_DATE ..., the result is going to get displayed by the client, and to do so the client will have to peform (under the covers) a TO_CHAR on the resulting DATE. And that implied to_char will use the current system/session/ settings for TNS_DATE_FORMAT.

convert MM/DD/YYYY to YYYYMMDD in redshift

I have a requirement to convert MM/DD/YYYY to YYYYMMDD in amazon redshift database.
My result of this query gives me some weird result. Can some one please help me.
select to_date ('07/17/2017','YYYYMMDD');
0007-07-20
If you just wish to convert the hard-coded string into a DATE:
select to_date('07/17/2017', 'MM/DD/YYYY')
If you have a column already formatted as DATE, then use:
to_char(fieldname, 'YYYYMMDD')
Combining the two concepts:
select to_char(to_date('07/17/2017', 'MM/DD/YYYY'), 'YYYYMMDD')
TO_DATE - converts a date represented in a character string to a DATE data type.
TO_CHAR - converts a time stamp or numeric expression to a character-string data format.
select to_char(sysdate,'YYYYMMDD');
If I’ve made a bad assumption please comment and I’ll refocus my answer.

How do i convert date time format in informatica

I want to map a datetime mm/dd/yyyy hh24:mi:ss attribute in flatfile to Teradata table date yyyy-mm-dd attribute using informatica.
When I added to_date(date_field, 'yyyy-mm-dd') I'm encountering oracle fatal error. When I tried with to_date(to_char(date_field, 'yyyy-mm-dd')) it is giving invalid string input to to_date().
Can anyone help?
In Informatica, the format that you specify under to_date() function should be same as your source data format and not your target format.
So in your case, to_date function should be like this:
to_date (date_field, 'mm/dd/yyyy hh24:mi:ss')
This is because your flat file date has a format of mm/dd/yyyy hh24:mi:ss (Ensure that all the records in this column in your flat file date are really in this format - else you will encounter error)
Do not worry about target date format as long as the target column is a date datatype. By nature, date datatype does not have a format, it's only the display that needs format.