The following piece of code does its job : it gives me the top 10 results for each category.
SELECT *
FROM (
SELECT *, RANK() OVER (PARTITION BY "pera_id" ORDER BY "surface" DESC) AS rnk
FROM "testBadaBing"
) AS x
WHERE rnk <= 10
Now I'd like to add conditions so that the number of results may vary based on a criteria. Example : if "note" = 1, then I want to retain 1 result, else make it 3.
I tried something along the lines which you can see below using the CASE WHEN statement but as you might expect it doesn't work. Error returned :
1 - near "CASE": syntax error
SELECT *
CASE WHEN "note" = 1 THEN
SELECT *
FROM (
SELECT *, RANK() OVER (PARTITION BY "pera_id" ORDER BY "surface" DESC) AS rnk
FROM "testBadaBing"
) AS x
WHERE rnk <= 1
ELSE
SELECT *
FROM (
SELECT *, RANK() OVER (PARTITION BY "pera_id" ORDER BY "surface" DESC) AS rnk
FROM "testBadaBing"
) AS x
WHERE rnk <= 3
END
Do you have any ideas how to make this work? My knowledge of SQL is pretty limited. The code has to be SQLite/SpatiaLite compatible as I'm working in the QGIS environment. Thanks.
You can use boolean logic in the WHERE clause of the outer query:
SELECT *
FROM (
SELECT t.*,
RANK() OVER (PARTITION BY "pera_id" ORDER BY "surface" DESC) AS rnk
FROM "testBadaBing" t
) AS x
WHERE ("note" = 1 and rnk = 1) OR rnk <= 3
Related
SELECT * FROM
(
SELECT DISTINCT(TRUNC(receipt_dstamp))
FROM inventory
WHERE substr(location_id,1,3) = 'GI-'
ORDER BY 1 ASC
)
WHERE ROWNUM <= 5
Output:
Hi all, i've got this subeqery and in this case my oldest date is in row 1, i want to retrive only second from the last(from the top in this case) which is gonna be 01-SEP-21.
I was trying to play with ROWNUM and OVER but without any results, im getting blank output.
Thank you.
Full query:
SELECT TRUNC(receipt_dstamp) as old_putaway_date, COUNT(tag_id) as tag_old_putaway
FROM inventory
WHERE substr(location_id,1,3) = 'GI-'
AND TRUNC(receipt_dstamp) IN (
SELECT * FROM
(
SELECT DISTINCT(TRUNC(receipt_dstamp))
FROM inventory
WHERE substr(location_id,1,3) = 'GI-'
ORDER BY 1 ASC
)
WHERE ROWNUM = 1
)
GROUP BY TRUNC(receipt_dstamp);
You should be able to simplify the entire query to:
SELECT old_putaway_date,
COUNT(tag_id) as tag_old_putaway
FROM (
SELECT TRUNC(receipt_dstamp) as old_putaway_date,
tag_id,
DENSE_RANK() OVER (ORDER BY TRUNC(receipt_dstamp)) AS rnk
FROM inventory
WHERE substr(location_id,1,3) = 'GI-'
)
WHERE rnk = 3
GROUP BY
old_putaway_date;
You can use dense_rank() :
SELECT * FROM (
SELECT L.*,DENSE_RANK()
OVER (PARTITION BY L.TAG_OLD_PUTAWAY ORDER BY L.OLD_PUTAWAY_DATE DESC) RNK
FROM
(
SELECT TRUNC(receipt_dstamp) as old_putaway_date, COUNT(tag_id) as tag_old_putaway
FROM inventory
WHERE substr(location_id,1,3) = 'GI-'
AND TRUNC(receipt_dstamp) IN (
SELECT * FROM
(
SELECT DISTINCT(TRUNC(receipt_dstamp))
FROM inventory
WHERE substr(location_id,1,3) = 'GI-'
ORDER BY 1 ASC
)
WHERE ROWNUM = 1
)
GROUP BY TRUNC(receipt_dstamp)
) L
) WHERE RNK = 2
You are using an old Oracle syntax that is not standard compliant in the regard that it relies on a subquery result order. (Sub)query results are unordered data sets by definition, but Oracle lets this pass in order to make their ROWNUM work with it.
Oracle now supports the standard SQL FETCH clause, which you should use instead.
SELECT DISTINCT TRUNC(receipt_dstamp) AS receipt_date
FROM inventory
WHERE SUBSTR(location_id, 1, 3) = 'GI-'
ORDER BY receipt_date
OFFSET 2 ROWS
FETCH NEXT 1 ROW ONLY;
https://docs.oracle.com/en/database/oracle/oracle-database/19/sqlrf/SELECT.html#GUID-CFA006CA-6FF1-4972-821E-6996142A51C6
I need to select the data of all my customers with the records displayed in the image. But I need to get the most recent record only, for example I need to get the order # E987 for John and E888 for Adam. As you can see from the example, when I do the select statement, I get all the order records.
You don't mention the specific database, so I'll answer with a generic solution.
You can do:
select *
from (
select t.*,
row_number() over(partition by name order by order_date desc) as rn
from t
) x
where rn = 1
You can use analytical function row_number.
Select * from
(Select t.*,
Row_number() over (partition by customer_id order by order_date desc) as rn
From your_table t) t
Where rn = 1
Or you can use not exists as follows:
Select *
From yoir_table t
Where not exists
(Select 1 from your_table tt
Where t.customer_id = tt.custome_id
And tt.order_date > t.order_date)
You can do it with a subquery that finds the last order date.
SELECT t.*
FROM yoir_table t
JOIN (SELECT tt.custome_id,
MAX(tt.order_date) MaxOrderDate
FROM yoir_table tt
GROUP BY tt.custome_id) AS tt
ON t.custome_id = tt.custome_id
AND t.order_date = tt.MaxOrderDate
This question is best explained with an image and the script I have currently... How can I extract a FULL one row per assignment, with the lowest rank, and if there are 2 rows with a denserank as 1, then choose either of them?...
select *
,Dense_RANK() over (partition by [Assignment] order by [Text] desc) as
[DenseRank]
from [dbo].[CLEANSED_T3B_Step1_Res_Withdups____CP]
select * from
(
select *
,Dense_RANK() over (partition by [Assignment] order by [Text] desc, NewID()
) as [DenseRank] from [dbo].[CLEANSED_T3B_Step1_Res_Withdups____CP]
) as A
where A.[DenseRank] = 1
Second script is working perfectly!
SELECT * INTO
[dbo].[CLEANSED_T3B_Step1_COMPLETED]
from
(
select *
,Dense_RANK() over (partition by [Assignment] order by
left([Text],1) desc , [Diff_Doc_Clearing_Date] desc , [Amount] asc
as [DenseRank]
from [dbo].[CLEANSED_T3B_Step1_Res_Withdups____CP]
)
as A
where A.[DenseRank] = 1
No longer need just a random first Tied '1st place', now need to get the one with the highest day diff and then also the highest amount after. SO have adapted everything in this version 3.
It seems you don't want to use DENSE_RANK but ROW_NUMBER.
with cte as(
select t.*, rn = row_number() over(partition by assignment order by [text] desc)
from tablename t
)
select * from cte
where rn = 1
Order by 'newid()' as the 'tie-breaker'
Order by [Text],Newid()
I'm trying to set ROW_NUMBER()... as an alias so I can reference it in the OFFSET. e.g. OFFSET some_alias - 1. I need to get a single row including the ROW_NUMBER() from a larger query. Here's my working code (gets correct ROW_NUMBER(), but isn't offset by the right amount):
WITH FirstQuery AS (
SELECT "RepInitials", COUNT("OrderStatus"), ROW_NUMBER()OVER(ORDER BY COUNT("OrderStatus") DESC)
FROM "tblBulkSalesQuery"
WHERE "OrderStatus" = 'CMC'
GROUP BY "RepInitials"
)
SELECT "RepInitials", COUNT("OrderStatus"), ROW_NUMBER()OVER(ORDER BY COUNT("OrderStatus") DESC)
FROM "tblBulkSalesQuery"
WHERE "OrderStatus" = 'CMC'
GROUP BY "RepInitials"
LIMIT 1
OFFSET 1;
select *
from (
SELECT "RepInitials",
COUNT("OrderStatus") as order_status_count,
ROW_NUMBER() OVER (ORDER BY COUNT("OrderStatus") DESC) as rn
FROM "tblBulkSalesQuery"
WHERE "OrderStatus" = 'CMC'
GROUP BY "RepInitials"
) as t
where rn = 1
Edit:
The t is an alias for the nested select ("derived table"). PostgreSQL requires each derived table to get it's own "name" and that can only be done by assigning a alias.
It's pretty much the same as:
with t as (
... here goes the real select ...
)
select *
from t
where rn = 1;
I am querying a data system with an OLEDB interface that supports SQL92. My query problem is equivalent to the one solved here: SQL Query to find earliest date dependent on column value changing,
but the solution provided there and copied below is too advanced for SQL92:
SELECT JobCodeId, MIN(LastEffectiveDate) AS mindate
FROM (
SELECT *,
prn - rn AS diff
FROM (
SELECT *,
ROW_NUMBER() OVER (PARTITION BY JobCodeID
ORDER BY LastEffectiveDate) AS prn,
ROW_NUMBER() OVER (ORDER BY LastEffectiveDate) AS rn
FROM #tmp
) q
) q2
GROUP BY
JobCodeId, diff
ORDER BY
mindate
What would a SQL92-compliant version of this solution look like?
Use:
SELECT JobCodeId,
MIN(LastEffectiveDate) AS mindate
FROM (SELECT *,
prn - rn AS diff
FROM (SELECT *,
(SELECT CASE WHEN COUNT(*) = 0 THEN 1 ELSE COUNT(*) END
FROM #tmp t
WHERE t.JobCodeID = r.JobCodeID
AND t.LastEffectiveDate <= x.LastEffectiveDate) AS prn,
(SELECT COUNT(*) + 1
FROM #tmp t
WHERE t.LastEffectiveDate <= x.LastEffectiveDate) AS rn
FROM #tmp x) q
) q2
GROUP BY JobCodeId, diff
ORDER BY mindate