I want all the data from a table which is more than 6 months available in my table. So for that I wrote the below query but it wasn't giving the exact records.
Select * from changerequests where lastmodifiedon < sysdate - 180;
The issue is I was getting the records for 2nd april, 2020 which is not more than 6 months. Please suggest the query
If you want records that were last modified within the last 6 months, then you want the inequality condition the other way around:
where lastmodifiedon > sysdate - 180
Note that 180 days is not exactly 6 months. You might want to use add_months() for something more accurate:
where lastmodifiedon > add_months(sysdate, -12)
Related
I'm trying to figure out how to look for data in the last six months in the where statement of a SQL query in Databricks, but I'm having a lot of issues with the syntax.
Right now I have:
Select * from table
where datediff(add_months(date_column, -6), date_column) = 1
The query doesn't throw an error, but returns no results.
I think you're expecting the wrong thing from datediff. Datediff tells you the number of days between two dates. In your case, you're comparing your date_column to your date_column - 6 months. That's always going to be 6 months or ~180 days.
Try this.
WHERE date_column > DATEADD(MONTH, -6, CURRENTDATE())
AKA, where your date column is greater than the current date minus 6 months.
I am trying to write a logic to find a person membership is going to expiring in next 30days. Can, some one help me to write a query in hive?
I tried using:
select * from db where expiringdate > current_date;
But is showing all the records greater than current date. But I need only for next 30 days
You want two inequality conditions on the expiration date:
select *
from db
where expiringdate > current_date -- later than today
and expiringdate < add_months(current_date, 1) -- not later than one month from now
Or if you want exactly 30 days rather than one month, use date_add(current_date, 3).
I apologize, I am new at SQL. I am using BigQuery. I have a field called "last_engaged_date", this field is a datetime value (2021-12-12 00:00:00 UTC). I am trying to perform a count on the number of records that were "engaged" 12 months ago, 18 months ago, and 24 months ago based on this field. At first, to make it simple for myself, I was just trying to get a count of the number of records per year, something like:
Select count(id), year(last_engaged_date) as last_engaged_year
from xyz
group by last_engaged_year
order by last_engaged_year asc
I know that there are a lot of things wrong with this query but primarily, BQ says that "Year" is not a valid function? Either way, What I really need is something like:
Date() - last_engaged_date = int(# of months)
count if <= 12 months as "12_months_count" (# of records where now - last engaged date is less than or equal to 12 months)
count if <= 18 months as "18_months_count"
count if <= 24 months as "24_months_count"
So that I have a count of how many records for each last_engaged_date period there are.
I hope this makes sense. Thank you so much for any ideas
[How to] Return the number of months between now and datetime value [in BigQuery] SQL
The simples way is just to use DATE_DIFF function as in below example
date_diff(current_date(), date(last_engaged_date), month)
I want to write a SQL query in Oracle database for:
A priceindex(field name) have around 120(say) records each day and I have to display the priceindex name and today's date, if the avg of last 7 days record count is greater than Todays record count for the priceindex(group by priceindex).
Basically, There will be 56 priceindex and each should have around 120 records each day and is dump to database each day from external site. So want to make sure all records are downloaded to the database everyday.
Except for the clarification I requested in a Comment to your question (having to do with "how can we know today's final count, when today is not over yet), the problem can be solved along the following lines. Not tested since you didn't provide sample data.
From your table, select only the rows where the relevant DATE is between "today" - 7 and "today" (so there are really EIGHT days: the seven days preceding today, and today). Then group by PRICEINDEX. Count total rows for each group, and count rows just for "today". The rows for "today" should be less than 1/8 times the total count (this is easy algebra: this is equivalent to being less than 1/7 times the count of OTHER days).
Such conditions, at the group level, must be in the HAVING clause.
select priceindex
from your_table
where datefield >= trunc(sysdate) - 7 and datefield < trunc(sysdate) + 1
group by priceindex
having count(case when datefield >= trunc(sysdate) then 1 end) < 1/8 * count(*)
;
EDIT The OP clarified that the query runs every day at midnight; this means that "today" should actually mean "yesterday" (the day that just ended). In Oracle, and probably in all of computing, midnight belongs to the day that BEGINS at midnight, not the one that ends at midnight. The time-of-day at midnight is 00:00:00 (beginning of the new day), not 24:00:00.
So, the query above will have to be changed slightly:
select priceindex
from your_table
where datefield >= trunc(sysdate) - 8 and datefield < trunc(sysdate)
group by priceindex
having count(case when datefield >= trunc(sysdate) - 1 then 1 end)
< 1/8 * count(*)
;
How do I get last 2 months of data from Hive?
Here is my attempt:
select (date_add(FROM_UNIXTIME(UNIX_TIMESTAMP(), 'yyyy-MM-dd'),
2 - month(FROM_UNIXTIME(UNIX_TIMESTAMP(), 'yyyy-MM-dd'))
));
This results in 2015-05-30. The results should be like: if Today is '2015-06-03', then the result of last two months should be like: '2015-04-01'. Notice that I put the first day of the month for the results. What am I doing wrong here? Thanks!
Extra Notes:
In SQL is it pretty easy to get:
select * from date_field >= DATEADD(MONTH, -2, GETDATE());
date_add adds days, not months. The below line evaluates to -4
2 - month(FROM_UNIXTIME(UNIX_TIMESTAMP(), 'yyyy-MM-dd'))
So you are basically subtracting 4 days from '2015-06-03', which is why you get the result '2015-05-30'.
As far as I know, there is no direct way to subtract months in Hive. Solutions you could consider:
Subtract 60 days, but that won't give you accurate results.
Write a custom UDF to return the date 2 months ago.
Calculate the date in a script, and pass it to hive.