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I have a set of strings like this:
CAP BCP0018 36
MFP ACZZ1BD 265
LZP FEI-12 3
I need to extract only the last values from the right and before the space, like:
36
265
3
how will the select statement look like? I tried using the below statement, but it did not work.
select CHARINDEX(myField, ' ', -1)
FROM myTable;
Perhaps the simplest method in SQL Server is:
select t.*, v.value
from t cross apply
(select top (1) value
from string_split(t.col, ' ')
where t.col like concat('% ', val)
) v;
This is perhaps not the most performant method. You probably would use:
select right(t.col, charindex(' ', reverse(t.col)) - 1)
Note: If there are no spaces, then to prevent an error:
select right(t.col, charindex(' ', reverse(t.col) + ' ') - 1)
Since you have mentioned CHARINDEX() in question, I am assuming you are using SQL Server.
Try below
declare #table table(col varchar(100))
insert into #table values('CAP BCP0018 36')
insert into #table values('MFP ACZZ1BD 265')
insert into #table values('LZP FE-12 3')
SELECT REVERSE(LEFT(REVERSE(col),CHARINDEX(' ',REVERSE(col)) - 1)) FROM #table
Functions used
CHARINDEX ( expressionToFind , expressionToSearch ) : returns position of FIRST occurence of an expression inside another expression.
LEFT ( character_expression , integer_expression ) : Returns the left part of a character string with the specified number of characters.
REVERSE ( string_expression ) : Returns the reverse order of a string value
I want to get sub string
in between two operators like = and ,
I tried something like CHARINDEX and LEFT to get the value but i got output in terms of
CN=Khushwant Khatri
but my output should be only Khushwant Khatri
SELECT left([String_value],CHARINDEX(',',([String_value]),0)-1) from trim_string
My string look like
CN=Khushwant Khatri,OU=TestMig,DC=valjha,DC=vedantaresource,DC=local
CN=Raghav Tare,OU=EXECUTIVE,OU=EXUDR,DC=HZL01,DC=vedantaresource,DC=local
CN=D K Chodankar,OU=Users,OU=AD LotusSync,DC=SGL01,DC=vedantaresource,DC=local
as you can see string has variable length
i want only CN value my output should look like
Khushwant Khatri
Raghav Tare
D K Chodankar
You may try this. First you need to find the position of your first =, since name will start from there, then need to find the length of your name which is separated by ,. So we find the index of next , and substract it from the length of string till =. Remaining string is your name as expected.
I am considering that your first value 'CN=' may vary for some condition.
declare #str varchar(max) = 'CN=Khushwant Khatri,OU=TestMig,DC=valjha,DC=vedantaresource,DC=local'
select substring( #str, charindex('=',#str)+1, (charindex(',',#str) - (charindex('=',#str) +1) ))
As per given table structure details please find the below code snippet.
Create table trim_string ( string_value nvarchar(max) )
Insert into trim_string ( string_value )
values ( 'CN=Khushwant Khatri,OU=TestMig,DC=valjha,DC=vedantaresource,DC=local' )
, ( 'CN=Raghav Tare,OU=EXECUTIVE,OU=EXUDR,DC=HZL01,DC=vedantaresource,DC=local' )
, ( 'CN=D K Chodankar,OU=Users,OU=AD LotusSync,DC=SGL01,DC=vedantaresource,DC=local' )
----- this is your query section
; with cte as (
select string_value , substring( string_value, charindex('=',string_value)+1, (charindex(',',string_value) - (charindex('=',string_value) +1) )) newvalue
from trim_string )
---- you may store them in temptable
select * into #temp from cte
----or
---- for selection
select * from cte
----or
----- use to update
update cte set string_value = newvalue
select * from trim_string
As per the comments discussion please try this.
; with cte as (
select string_value , substring( string_value, charindex('=',string_value)+1, (charindex(',',string_value) - (charindex('=',string_value) +1) )) newvalue
from trim_string )
select * from cte
This should give you all of the strings record of your table, with Name is fetched in new column as newvalue.
Use SUBSTRING() as
SELECT SUBSTRING(S, 4, CHARINDEX(',', S)-4),
S
FROM
(
VALUES
('CN=Khushwant Khatri,OU=TestMig,DC=valjha,DC=vedantaresource,DC=local'),
('CN=Raghav Tare,OU=EXECUTIVE,OU=EXUDR,DC=HZL01,DC=vedantaresource,DC=local'),
('CN=D K Chodankar,OU=Users,OU=AD LotusSync,DC=SGL01,DC=vedantaresource,DC=local')
) T(S);
Try this:
select substring(#t,charindex('=',#t)+1,charindex(',',#t)-4)
I am not exactly sure what you want. Alse working with CHARINDEX is a bit unclear.
But I was thinking that maybe this piece of query can help you to find what you want in your string better.
DECLARE #string VARCHAR(MAX) = 'CN=Khushwant Khatri,OU=TestMig,DC=valjha,DC=vedantaresource,DC=local,
,CN=Raghav Tare,OU=EXECUTIVE,OU=EXUDR,DC=HZL01,DC=vedantaresource,DC=local
,CN=D K Chodankar,OU=Users,OU=AD LotusSync,DC=SGL01,DC=vedantaresource,DC=local'
SELECT *
FROM (
SELECT -- this part is based on what your question looks it want.
CASE WHEN LEN(X.value)>2 THEN X.value END AS Value
FROM
(
SELECT value
FROM string_split(REPLACE(#string,',','='),'=') -- might help more than CHARINDEX
) X
) Y
WHERE Y.Value IS NOT NULL
I have to make a query to a base using as a comparison a string like this 12345678, but the value to compare is this way12.345.678, if I do the following query it does not return anything.
SELECT * FROM TABLA WHERE CAMPO = '12345678'
Where CAMPO would have the value of (12.345.678), if I replace = with a like, it does not return the data either
SELECT * FROM TABLA WHERE CAMPO like '12345678%'
SELECT * FROM TABLA WHERE CAMPO like '%12345678'
SELECT * FROM TABLA WHERE CAMPO like '%12345678%'
None of the 3 previous consultations works for me, how can I make this query?
The value can be of either 7, 8 or 9 numbers and the. It has to be every 3 from the end to the beginning
Use REPLACE() function to replace all the dots '.' as
SELECT *
FROM(
VALUES ('12.345.678'),
('23.456.789')
) T(CAMPO)
WHERE REPLACE(CAMPO, '.', '') = '12345678';
Your query should be
SELECT * FROM TABLA WHERE REPLACE(CAMPO, '.', '') = '12345678';
You can compare the string without the dots to a REPLACE(StringWithDots, '.','')
I recommend you to convert the number to numeric
So you can use < and > operators and all functions that require you to have a number...
the best way to achieve this is to make sure you remove any unecessary dots and convert the commas to dots. like this
CONVERT(NUMERIC(10, 2),
REPLACE(
REPLACE('7.000,45', '.', ''),
',', '.'
)
)
I hope this will help you out.
A SARGABLE solution would be to write a function that takes your target value ('12345678') and inserts the separators ('.') every third character from right to left. The result ('12.345.678') can then be used in a where clause and benefit from an index on CAMPO.
The following code demonstrates an approach without creating a user-defined function (UDF). Instead, a recursive common table expression (CTE) is used to process the input string three characters at a time to build the dotted target string. The result is used in a query against a sample table.
To see the results from the recursive CTE replace the final select statement with the commented select immediately above it.
-- Sample data.
declare #Samples as Table ( SampleId Int Identity, DottedDigits VarChar(20) );
insert into #Samples ( DottedDigits ) values
( '1' ), ( '12' ), ( '123' ), ( '1.234' ), ( '12.345' ),
( '123.456' ), ( '1.234.567' ), ( '12.345.678' ), ( '123.456.789' );
select * from #Samples;
-- Query the data.
declare #Target as VarChar(15) = '12345678';
with
Target as (
-- Get the first group of up to three characters from the tail of the string ...
select
Cast( Right( #Target, 3 ) as VarChar(20) ) as TargetString,
Cast( Left( #Target, case when Len( #Target ) > 3 then Len( #Target ) - 3 else 0 end ) as VarChar(20) ) as Remainder
union all
-- ... and concatenate the next group with a dot in between.
select
Cast( Right( Remainder, 3 ) + '.' + TargetString as VarChar(20) ),
Cast( Left( Remainder, case when Len( Remainder ) > 3 then Len( Remainder ) - 3 else 0 end ) as VarChar(20) )
from Target
where Remainder != ''
)
-- To see the intermediate results replace the final select with the line commented out below:
--select TargetString from Target;
select SampleId, DottedDigits
from #Samples
where DottedDigits = ( select TargetString from Target where Remainder = '' );
An alternative approach would be to add a indexed computed column to the table that contains Replace( CAMPO, '.', '' ).
If the table containing IDs like 12.345.678 is big (contains many records), I would add a computed field that removes the dots (and if this ID does never contain any alphanumeric characters other than dots and has no significant leading zeros then also cast it in an INT or BIGINT) and persist it and lay an index over it. That way you loose a little time when inserting the record but are querying it with maximum speed and therefore saving processor power.
I have a column u_manualdoc which contains the values are like this CGY DR# 7405. I want to remove the CGY DR#.
Here's the code:
select u_manualdoc, cardcode, cardname from ODLN
I want only the 7405 number. Thanks!
Try this:
--sample data you provided in comments
declare #tbl table(codes varchar(20))
insert into #tbl values
('CGY PST - 58277') , ('CGY RMC PST # 58083'), ('CGY DR # 7443'), ('CSI # 1304'), ('PO# 0568 , 0570'), ('CGY DR# 7446')
--actual query that you can apply to your table
select SUBSTRING(codes, PATINDEX('%[0-9]%', codes), len(codes)) from #tbl
The key point here is to use patindex, which searches for a pattern and returns index where such pattern occur. I specified %[0-9]% which means that we search for any digit - it will return first occurrence of a digit. Now- since this would be our starting point to substring, we pass it to such function. Third parameter of substring is length. Since we want the rest of a string, len function makes sure that we get that :)
Applying to your naming:
select SUBSTRING(u_manualdoc, PATINDEX('%[0-9]%', u_manualdoc), len(u_manualdoc)),
cardcode,
cardname
from ODLN
You should use string functions charindex,len and substring to get it.
See the code below.
select SUBSTRING(u_manualdoc,CHARINDEX('#',u_manualdoc)+1,LEN(u_manualdoc)- CHARINDEX('#',u_manualdoc))
EDIT
In addition to the other answers, you can use this simple method:
select
substring(
u_manualdoc,
len(u_manualdoc) - patindex('%[^0-9]%', reverse(u_manualdoc)) + 2,
len(u_manualdoc)
),
cardcode, cardname
from ODLN
In this example, patindex finds the first non-digit (as specified by ^[0-9]) from the right side of the string, and then uses that as the starting point of the substring.
This will work on all of your sample strings (including 'PO# 0568 , 0570 CGY DR# 7446').
Or use SQL Server Regex, which lets you use more powerful regular expressions within your queries.
TRY THIS
DECLARE #table TABLE(DirtyCol VARCHAR(100));
INSERT INTO #table
VALUES('AB ABCDE # 123'), ('ABCDE# 123'), ('AB: ABC# 123 AB: ABC# 123'), ('AB#'), ('AB # 1 000 000'), ('AB # 1`234`567'), ('AB # (9)(876)(543)');
WITH tally
AS (
SELECT TOP (100) N = ROW_NUMBER() OVER(ORDER BY ##spid)
FROM sys.all_columns),
data
AS (
SELECT DirtyCol,
Col
FROM #table
CROSS APPLY
(
SELECT
(
SELECT C+''
FROM
(
SELECT N,
SUBSTRING(DirtyCol, N, 1) C
FROM tally
WHERE N <= DATALENGTH(DirtyCol)
) [1]
WHERE C BETWEEN '0' AND '9'
ORDER BY N FOR XML PATH('')
)
) p(Col)
WHERE p.Col IS NOT NULL)
SELECT DirtyCol,
CAST(Col AS INT) IntCol
FROM data;
Thank you in advance.
I want to remove string after . including ., but length is variable and string can be of any length.
1)Example:
Input:- SCC0204.X and FRK0005.X and RF0023.X and ADF1010.A and HGT9010.V
Output: SCC0204 and FRK0005 and RF0023 and ADF1010.A and HGT9010.V
I tried using the charindex but as the length keeps on changing i wasn't able to do it. I want to trim the values with ending with only X
Any help will be greatly appreciated.
Assuming there is only one dot
UPDATE TABLE
SET column_name = left(column_name, charindex('.', column_name) - 1)
For SELECT
select left(column_name, charindex('.', column_name) - 1) AS col
from your_table
Hope this helps. The code only trims the string when the value has a decimal "." in it and if that value is equal to .X
;WITH cte_TestData(Code) AS
(
SELECT 'SCC0204.X' UNION ALL
SELECT 'FRK0005.X' UNION ALL
SELECT 'RF0023.X' UNION ALL
SELECT 'ADF1010.A' UNION ALL
SELECT 'HGT9010.V' UNION ALL
SELECT 'SCC0204' UNION ALL
SELECT 'FRK0005'
)
SELECT CASE
WHEN CHARINDEX('.', Code) > 0 AND RIGHT(Code,2) = '.X'
THEN SUBSTRING(Code, 1, CHARINDEX('.', Code) - 1)
ELSE Code
END
FROM cte_TestData
If the criteria is only to replace remove .X then probably this should also work
;WITH cte_TestData(Code) AS
(
SELECT 'SCC0204.X' UNION ALL
SELECT 'FRK0005.X' UNION ALL
SELECT 'RF0023.X' UNION ALL
SELECT 'ADF1010.A' UNION ALL
SELECT 'HGT9010.V' UNION ALL
SELECT 'SCC0204' UNION ALL
SELECT 'FRK0005'
)
SELECT REPLACE (Code,'.X','')
FROM cte_TestData
Use LEFT String function :
DECLARE #String VARCHAR(100) = 'SCC0204.XXXXX'
SELECT LEFT(#String,CHARINDEX('.', #String) - 1)
I think your best bet here is to create a function that parses the string and uses regex. I hope this old post helps:
Perform regex (replace) in an SQL query
However, if the value you need to trim is constantly ".X", then you should use
select replace(string, '.x', '')
Please check the below code. I think this will help you.
DECLARE #String VARCHAR(100) = 'SCC0204.X'
IF (SELECT RIGHT(#String,2)) ='.X'
SELECT LEFT(#String,CHARINDEX('.', #String) - 1)
ELSE
SELECT #String
Update: I just missed one of the comments where the OP clarifies the requirement. What I put together below is how you would deal with a requirement to remove everything after the first dot on strings ending with X. I leave this here for reference.
;WITH cte_TestData(Code) AS
(
SELECT 'SCC0204.X' UNION ALL -- ends with '.X'
SELECT 'FRK.000.X' UNION ALL -- ends with '.X', contains multiple dots
SELECT 'RF0023.AX' UNION ALL -- ends with '.AX'
SELECT 'ADF1010.A' UNION ALL -- ends with '.A'
SELECT 'HGT9010.V' UNION ALL -- ends with '.V'
SELECT 'SCC0204.XF' UNION ALL -- ends with '.XF'
SELECT 'FRK0005' UNION ALL -- totally clean
SELECT 'ABCX' -- ends with 'X', not dots
)
SELECT
orig_string = code,
newstring =
SUBSTRING
(
code, 1,
CASE
WHEN code LIKE '%X'
THEN ISNULL(NULLIF(CHARINDEX('.',code)-1, -1), LEN(code))
ELSE LEN(code)
END
)
FROM cte_TestData;
FYI - SQL Server 2012+ you could simplify this code like this:
SELECT
orig_string = code,
newstring =
SUBSTRING(code, 1,IIF(code LIKE '%X', ISNULL(NULLIF(CHARINDEX('.',code)-1, -1), LEN(code)), LEN(code)))
FROM cte_TestData;
With SUBSTRING you can achieve your requirements by below code.
SELECT SUBSTRING(column_name, 0, CHARINDEX('.', column_name)) AS col
FROM your_table
If you want to remove fixed .X from string you can also use REPLACE function.
SELECT REPLACE(column_name, '.X', '') AS col