I am trying to convert date to number like below, not sure which function works better.
Database used is SQL Server.
Table details
create table test
(
id varchar(255),
call_date varchar(255)
);
insert into test('26203', '14-Aug-2020');
I need output as 4405726203 -- its concatenation of date (14-Aug-2014) + id (26203)
This is too long for a comment.
SQL Server allows you to convert a datetime to a float. That would be:
select cast(dte as float)
from (values (convert(datetime, '14-Aug-2020'))) v(dte)
However, the corresponding floating point value is 44055 (https://dbfiddle.uk/?rdbms=sqlserver_2019&fiddle=d142a64db0872e7572eb4fbd6d5d5fe7). It is a bit of mystery what your intention is.
You could subtract 2, but that seems arbitrary. You could calculate the number of days since 1899-12-30. But that also seems arbitrary.
In any case, once you figure out how to convert the date to the number you want, just use concat() to combine the values.
I have found the solution:
convert(varchar,CAST(CONVERT(datetime,call_date) as bigint)) + id
Under the hood, a SQL Server DateTime is a tuple of 2 32-bit integers:
The first integer is a count of days since since the epoch, which for SQL Server is 1 January 1900
The second integer is a count of milliseconds since start of day (00:00:00.000). Except that the count ticks up in 3- or 4-milliscond increments. Microsoft only knows why that decision was made.
You can get the count of days since the epoch with
convert( int, convert( date, t.call_date ) )
[wrap that in convert(varchar, ... ) to turn it into a string]
Looks like your id is already a varchar, so you can say:
select compound_key = convert(varchar,
convert(int,
convert(date,
call_date
)
)
)
+ t.id
from test t
I would suggest padding both fields with leading zeros to a fixed length so as to avoid possible collisions (assuming you're trying to generate a key here). Signed 32-bit integer overflows a 2.1 billion-ish, so 9 digits for each field is sufficient.
This works
select concat(datediff(d, 0, cast(call_date as date)), id)
from
(values ('26203','14-Aug-2020')) v(id, call_date);
Results
4405526203
Related
I'm working on a legacy database and need to parse info from one database to another, parsing it into the new database is easy enough but first I need to create the query to convert and cast the following in the legacy SQL Server database:
WorkedHours(NVARCHAR(10)) is in text format 07:30
I need to convert and cast this as a decimal ie 7.5
I have searched around for the answer to this but can not find anything that has worked, so thought I would put it out there to see if any of you has any ideas.
Edit - What I should of asked is. What is causing an error converting to an int from a character with a value of 0 when trying to trying to convert and cast a time to a decimal?
DATEDIFF(
MINUTE,
0,
CAST('07:30' AS TIME)
)
/
60.0
Works up to '23:59' only
EDIT:
Based on a comment elsewhere, you have some 'bad' values.
This may find them...
SELECT
*
FROM
yourTable
WHERE
TRY_CONVERT(TIME, worked_hours) IS NULL
And as such, this is a safer version of my expression....
DATEDIFF(
MINUTE,
0,
TRY_CONVERT(TIME, worked_hours)
)
/
60.0
(Returns NULL for values that failed to parse.)
There's no reason to pull out the date/time types. Just do some simple string parsing:
cast(left(right('0' + WorkedHours, 5), 2) as int)
+ cast(right(WorkedHours, 2) as int) / 60.00
This won't have any limitations on 24 hours or anything like that. It just assumes that you've got one or two digits before a colon and two digits after.
This should work in SQL Server and an example-string "1101:56" (1101h & 56 minutes) | in general from 0h to >24h:
-- Take all hours before ":" and all Minutes (2 digits) after ":" and convert it to decimal.
select convert(decimal,left('1101:56',CHARINDEX(':','1101:56')-1)) + ( convert(decimal,right('1101:56',2))/60 );
-- with column-placeholder "time_str_from_table"
select convert(decimal,left(time_str_from_table,CHARINDEX(':',time_str_from_table)-1)) + ( convert(decimal,right(time_str_from_table,2))/60 );
If the source table have NULL-Values, than use "ISNULL" with substitution-value "0.0":
-- with column-placeholder "time_str_from_table"
select isnull( ( convert(decimal,left(time_str_from_table,CHARINDEX(':',time_str_from_table)-1)) + ( convert(decimal,right(time_str_from_table,2))/60) ), 0.0);
I have an INT64 column called "Date" which contains many different numbers like: "20210209" or "20200305". I want to turn those numbers into a date with this format: MM-YYYY (so in these cases, 02-2021 and 03-2020). Ultimately I want to sum all the data in each month together. The problem is that BigQuery can't convert INT64 to date, only to strings. I'm not sure if I should convert to a string and then to a date or if there is a better way.
Although converting to a string then a date both works and is very concise, over large enough numbers of rows (which may be the case in Big Query) you may be better off using integer maths and using DATE(year, month, day)...
https://cloud.google.com/bigquery/docs/reference/standard-sql/date_functions#date
SELECT
DATE(
DIV( 20210209 , 10000), -- Which gives 2021
DIV(MOD(20210209, 10000), 100), -- Which gives 02
MOD(20210209, 100) -- Which gives 09
)
You can convert the value to a string and use parse_date():
select parse_date('%Y%m%d', cast(20210209 as string))
Another option
select date,
regexp_replace('' || date, r'(\d{4})(\d{2})(\d{2})', r'\2-\1') as MM_YYYY
from your_table
if applied to sample data in your question - output is
Yet another option
select date,
format_date('%m-%Y', parse_date('%Y%m%d', '' || date)) as MM_YYYY
from your_table
with same output
I've got a column that shows the date as a decimal such as 101118 for 10-11-18 and 90118 for 09-01-18. I am trying to create a simple report that would give me all reservations yesterday.
So for example
Select playerid, datereservationmade
from dbo.lms
normally there is very simple and I would just do
Select playerid, datereservationmade
from dbo.lms
where datereservationmade >= dateadd(day,datediff(day,1,GETDATE()),0)
AND datereservationmade < dateadd(day,datediff(day,0,GETDATE()),0)
That does not work in this case because the datereservationmade field is a decimal and if its a month 1-9 it leaves off the 0 and makes it a 5 digit decimal then if its 10-12 it is a 6 digit decimal.
Someone please help me figure out how to convert this!
If at all possible, you really should fix your schema so that dates are actually being stored as dates.
If you need to work with the decimal data type, you can use something like the following...
IF OBJECT_ID('tempdb..#TestData', 'U') IS NOT NULL
BEGIN DROP TABLE #TestData; END;
CREATE TABLE #TestData (
decimal_date DECIMAL(6, 0) NOT NULL
);
INSERT #TestData (decimal_date) VALUES (101118), (90118), (101718);
--==============================================
SELECT
td.decimal_date,
dd.date_date
FROM
#TestData td
CROSS APPLY ( VALUES (RIGHT('0' + CONVERT(VARCHAR(6), td.decimal_date), 6)) ) cd (char_date)
CROSS APPLY ( VALUES (CONVERT(DATE, STUFF(STUFF(cd.char_date, 5, 0, '/'), 3, 0, '/'), 1)) ) dd (date_date)
WHERE
dd.date_date = CONVERT(DATE, DATEADD(DAY, -1, GETDATE()));
Convert the decimal to varchar(6) by adding a zero in front and getting the RIGHT 6 characters.
Then convert the string to a date from its parts, which are substrings in your varchar(6). This is made easier in SQL Server 2012 with the DATEFROMPARTS function.
Using the DATEFROMPARTS, as Tab Alleman suggested, you might get something like this:
-- Example of the arithmetic
SELECT 101118 / 10000 AS Month, (101118 % 10000) / 100 AS Day, (101118 % 100) AS Year
-- Using the math in DATEFROMPARTS
SELECT DATEFROMPARTS((101118 % 100) + 2000, 101118 / 10000, (101118 % 10000) / 100 )
However, I'm skeptical that you've provided all the correct information. What happens on January first? Your decimal value won't start with zero (as you stated). Will your day always pad with zero? If not, then 1119 won't produce the same result as 10119. If, however, your day does start with zero, then the equation above should work fine.
This used to work with a column type of DATEIME but now it won't with DATE.
CONVERT(BIGINT,ev.StartDate) * -1
Is there anyway to get a BIGINT value from a DATE column?
You can cast the startdate as datetime for conversion.
CONVERT(BIGINT,CAST(ev.StartDate as DATETIME)) * -1
Yet another option. This will even flip the sign for you
Example
Declare #YourTable table (StartDate date)
Insert Into #YourTable values ('2017-05-30')
Select DateDiff(DAY,StartDate,-1)
From #YourTable
Returns
-42884
First, dates in SQL Server are counted by days from the year 1900. A big int starts to be useful at about 2.1 billion. That corresponds to a year in the range of 5.8 million. Do you really have dates that large?
Of course, casting to an int is not permitted. You can cast datetime values . . . but are there other ways?
One simple way is:
select 1 + datediff(day, 0, datecol)
The "+ 1" is needed so the value matches the actual conversion. (You can use "-1" instead of "0" instead.)
Or, perhaps you want Unix time in seconds or milliseconds. For that:
select datediff_big(ms, '1970-01-01', datecol)
You might require to convert to varchar and then bigint
select Convert(bigint,convert(varchar(10),ev.StartDate,112))*(-1)
I got a column called DateOfBirth in my csv file with Excel Date Serial Number Date
Example:
36464
37104
35412
When i formatted cells in excel these are converted as
36464 => 1/11/1999
37104 => 1/08/2001
35412 => 13/12/1996
I need to do this transformation in SSIS or in SQL. How can this be achieved?
In SQL:
select dateadd(d,36464,'1899-12-30')
-- or thanks to rcdmk
select CAST(36464 - 2 as SmallDateTime)
In SSIS, see here
http://msdn.microsoft.com/en-us/library/ms141719.aspx
The marked answer is not working fine, please change the date to "1899-12-30" instead of "1899-12-31".
select dateadd(d,36464,'1899-12-30')
You can cast it to a SQL SMALLDATETIME:
CAST(36464 - 2 as SMALLDATETIME)
MS SQL Server counts its dates from 01/01/1900 and Excel from 12/30/1899 = 2 days less.
tldr:
select cast(#Input - 2e as datetime)
Explanation:
Excel stores datetimes as a floating point number that represents elapsed time since the beginning of the 20th century, and SQL Server can readily cast between floats and datetimes in the same manner. The difference between Excel and SQL server's conversion of this number to datetimes is 2 days (as of 1900-03-01, that is). Using a literal of 2e for this difference informs SQL Server to implicitly convert other datatypes to floats for very input-friendly and simple queries:
select
cast('43861.875433912' - 2e as datetime) as ExcelToSql, -- even varchar works!
cast(cast('2020-01-31 21:00:37.490' as datetime) + 2e as float) as SqlToExcel
-- Results:
-- ExcelToSql SqlToExcel
-- 2020-01-31 21:00:37.490 43861.875433912
this actually worked for me
dateadd(mi,CONVERT(numeric(17,5),41869.166666666664)*1440,'1899-12-30')
(minus 1 more day in the date)
referring to the negative commented post
SSIS Solution
The DT_DATE data type is implemented using an 8-byte floating-point number. Days are represented by whole number increments, starting with 30 December 1899, and midnight as time zero. Hour values are expressed as the absolute value of the fractional part of the number. However, a floating point value cannot represent all real values; therefore, there are limits on the range of dates that can be presented in DT_DATE. Read more
From the description above you can see that you can convert these values implicitly when mapping them to a DT_DATE Column after converting it to a 8-byte floating-point number DT_R8.
Use a derived column transformation to convert this column to 8-byte floating-point number:
(DT_R8)[dateColumn]
Then map it to a DT_DATE column
Or cast it twice:
(DT_DATE)(DT_R8)[dateColumn]
You can check my full answer here:
Is there a better way to parse [Integer].[Integer] style dates in SSIS?
Found this topic helpful so much so created a quick SQL UDF for it.
CREATE FUNCTION dbo.ConvertExcelSerialDateToSQL
(
#serial INT
)
RETURNS DATETIME
AS
BEGIN
DECLARE #dt AS DATETIME
SELECT #dt =
CASE
WHEN #serial is not null THEN CAST(#serial - 2 AS DATETIME)
ELSE NULL
END
RETURN #dt
END
GO
I had to take this to the next level because my Excel dates also had times, so I had values like this:
42039.46406 --> 02/04/2015 11:08 AM
42002.37709 --> 12/29/2014 09:03 AM
42032.61869 --> 01/28/2015 02:50 PM
(also, to complicate it a little more, my numeric value with decimal was saved as an NVARCHAR)
The SQL I used to make this conversion is:
SELECT DATEADD(SECOND, (
CONVERT(FLOAT, t.ColumnName) -
FLOOR(CONVERT(FLOAT, t.ColumnName))
) * 86400,
DATEADD(DAY, CONVERT(FLOAT, t.ColumnName), '1899-12-30')
)
In postgresql, you can use the following syntax:
SELECT ((DATE('1899-12-30') + INTERVAL '1 day' * FLOOR(38242.7711805556)) + (INTERVAL '1 sec' * (38242.7711805556 - FLOOR(38242.7711805556)) * 3600 * 24)) as date
In this case, 38242.7711805556 represents 2004-09-12 18:30:30 in excel format
In addition of #Nick.McDermaid answer I would like to post this solution, which convert not only the day but also the hours, minutes and seconds:
SELECT DATEADD(s, (42948.123 - FLOOR(42948.123))*3600*24, dateadd(d, FLOOR(42948.123),'1899-12-30'))
For example
42948.123 to 2017-08-01 02:57:07.000
42818.7166666667 to 2017-03-24 17:12:00.000
You can do this if you just need to display the date in a view:
CAST will be faster than CONVERT if you have a large amount of data, also remember to subtract (2) from the excel date:
CAST(CAST(CAST([Column_With_Date]-2 AS INT)AS smalldatetime) AS DATE)
If you need to update the column to show a date you can either update through a join (self join if necessary) or simply try the following:
You may not need to cast the excel date as INT but since the table I was working with was a varchar I had to do that manipulation first. I also did not want the "time" element so I needed to remove that element with the final cast as "date."
UPDATE [Table_with_Date]
SET [Column_With_Excel_Date] = CAST(CAST(CAST([Column_With_Excel_Date]-2 AS INT)AS smalldatetime) AS DATE)
If you are unsure of what you would like to do with this test and re-test! Make a copy of your table if you need. You can always create a view!
Google BigQuery solution
Standard SQL
Select Date, DATETIME_ADD(DATETIME(xy, xm, xd, 0, 0, 0), INTERVAL xonlyseconds SECOND) xaxsa
from (
Select Date, EXTRACT(YEAR FROM xonlydate) xy, EXTRACT(MONTH FROM xonlydate) xm, EXTRACT(DAY FROM xonlydate) xd, xonlyseconds
From (
Select Date
, DATE_ADD(DATE '1899-12-30', INTERVAL cast(FLOOR(cast(Date as FLOAT64)) as INT64) DAY ) xonlydate
, cast(FLOOR( ( cast(Date as FLOAT64) - cast(FLOOR( cast(Date as FLOAT64)) as INT64) ) * 86400 ) as INT64) xonlyseconds
FROM (Select '43168.682974537034' Date) -- 09.03.2018 16:23:28
) xx1
)
For those looking how to do this in excel (outside of formatting to a date field) you can do this by using the Text function https://exceljet.net/excel-functions/excel-text-function
i.e.
A1 = 132134
=Text(A1,"MM-DD-YYYY") will result in a date
This worked for me because sometimes the field was a numeric to get the time portion.
Command:
dateadd(mi,CONVERT(numeric(17,5),41869.166666666664)*1440,'1899-12-31')