This used to work with a column type of DATEIME but now it won't with DATE.
CONVERT(BIGINT,ev.StartDate) * -1
Is there anyway to get a BIGINT value from a DATE column?
You can cast the startdate as datetime for conversion.
CONVERT(BIGINT,CAST(ev.StartDate as DATETIME)) * -1
Yet another option. This will even flip the sign for you
Example
Declare #YourTable table (StartDate date)
Insert Into #YourTable values ('2017-05-30')
Select DateDiff(DAY,StartDate,-1)
From #YourTable
Returns
-42884
First, dates in SQL Server are counted by days from the year 1900. A big int starts to be useful at about 2.1 billion. That corresponds to a year in the range of 5.8 million. Do you really have dates that large?
Of course, casting to an int is not permitted. You can cast datetime values . . . but are there other ways?
One simple way is:
select 1 + datediff(day, 0, datecol)
The "+ 1" is needed so the value matches the actual conversion. (You can use "-1" instead of "0" instead.)
Or, perhaps you want Unix time in seconds or milliseconds. For that:
select datediff_big(ms, '1970-01-01', datecol)
You might require to convert to varchar and then bigint
select Convert(bigint,convert(varchar(10),ev.StartDate,112))*(-1)
Related
I am trying to convert date to number like below, not sure which function works better.
Database used is SQL Server.
Table details
create table test
(
id varchar(255),
call_date varchar(255)
);
insert into test('26203', '14-Aug-2020');
I need output as 4405726203 -- its concatenation of date (14-Aug-2014) + id (26203)
This is too long for a comment.
SQL Server allows you to convert a datetime to a float. That would be:
select cast(dte as float)
from (values (convert(datetime, '14-Aug-2020'))) v(dte)
However, the corresponding floating point value is 44055 (https://dbfiddle.uk/?rdbms=sqlserver_2019&fiddle=d142a64db0872e7572eb4fbd6d5d5fe7). It is a bit of mystery what your intention is.
You could subtract 2, but that seems arbitrary. You could calculate the number of days since 1899-12-30. But that also seems arbitrary.
In any case, once you figure out how to convert the date to the number you want, just use concat() to combine the values.
I have found the solution:
convert(varchar,CAST(CONVERT(datetime,call_date) as bigint)) + id
Under the hood, a SQL Server DateTime is a tuple of 2 32-bit integers:
The first integer is a count of days since since the epoch, which for SQL Server is 1 January 1900
The second integer is a count of milliseconds since start of day (00:00:00.000). Except that the count ticks up in 3- or 4-milliscond increments. Microsoft only knows why that decision was made.
You can get the count of days since the epoch with
convert( int, convert( date, t.call_date ) )
[wrap that in convert(varchar, ... ) to turn it into a string]
Looks like your id is already a varchar, so you can say:
select compound_key = convert(varchar,
convert(int,
convert(date,
call_date
)
)
)
+ t.id
from test t
I would suggest padding both fields with leading zeros to a fixed length so as to avoid possible collisions (assuming you're trying to generate a key here). Signed 32-bit integer overflows a 2.1 billion-ish, so 9 digits for each field is sufficient.
This works
select concat(datediff(d, 0, cast(call_date as date)), id)
from
(values ('26203','14-Aug-2020')) v(id, call_date);
Results
4405526203
I have date formats that are as follows:
Date_str
19-12-2007
31-7-2009
3-1-2010
31-11-2009
etc.
I can't do the following:
CONCAT(RIGHT(Date_str,4),SUBSTRING(Date_str,3,3),LEFT(2))
because as you can see above, the dates are not the same length. Is there a way in SQL Server to extract the date as datetime/date?
I also tried
Convert(datetime, Date_str)
but it just threw an error:
The conversion of a varchar data type to a datetime data type resulted
in an out-of-range value.
If 2012+, I would use Try_Convert(). This will return bogus dates as NULL.
Example
Declare #YourTable Table ([Date_str] varchar(50))
Insert Into #YourTable Values
('19-12-2007')
,('31-7-2009')
,('3-1-2010')
,('31-11-2009')
Select *
,try_convert(date,Date_Str,105)
from #YourTable
Returns
Date_str (No column name)
19-12-2007 2007-12-19
31-7-2009 2009-07-31
3-1-2010 2010-01-03
31-11-2009 NULL -- Notice 11/31 is NOT a date
See https://learn.microsoft.com/en-us/sql/t-sql/functions/cast-and-convert-transact-sql for date formats
You probably need
CONVERT(DateTime, Date_str, 105)
As I mentioned in the comments, the only realistic solution is to convert that string into a proper date-typed column. The current format doesn't allow date sorting, or search for a range of dates, eg to find entries in the last week, or between one date and the other.
Parsing with CONVERT or TRY_PARSE means that no indexes can be used to speed up queries. Each time :
WHERE CONVERT(Date, Date_str, 105) > '20170101'
is used, the server will have to scan the entire table to convert the data, then filter the rows.
If you can't change the type of the field itself, you can create a persisted computed column that returns the value as a date and add indexes to it. You'll be able to use that column for indexed querying:
alter table SomeTable add date2 as TRY_convert(Actual_Date,date_str,105) PERSISTED
create index IX_SomeTable_ActualDate on SomeTable (Actual_Date)
This will allow you to perform sorting without tricks:
SELECT *
FROM SomeTable
ORDER BY Actual_Date
Or run range queries that take advantage of the IX_SomeTable_ActualDate index:
SELECT *
FROM SomeTable
Where Actual_Date Between DATEADD(d,-7,GETDATE()) AND GETDATE()
If you have 1000 rows, you could get 1000 times better performance.
Existing applications won't even notice the change. Newer queries and applications will be able to take advantage of indexing and sorting
I had a similar problem: my column (<my_date_field>) had date values in the form of
2021-01
2021-02
2021-10
2021-12
and so on, with data type of nvarchar(4000), and I always ran into the Conversion failed when converting date and/or time from character string. error (when trying e.g. CAST(<my_date_field> AS DATE) or CAST(CAST(<my_date_field> AS VARCHAR(7)) AS DATE) etc.)
I was able to convert them to date with the following code:
SELECT
CONVERT(date, <my_date_field> + '-01') AS first_day_of_month
FROM my_table
which resulted in
2021-08-01
2021-07-01
2021-06-01
2021-05-01
I am trying to compare L.LoanDueDate (which is a smalldatetime) to the return value of ufnARCUGetLatestProcessDate() (which is an int) to see how many days the loan due date is past the last process date.
I receive an
Arithmetic overflow error converting expression to data type smalldatetime
error and can't seem to figure it out. Any help would be useful. Thank you in advance.
CAST(L.LoanDueDate - CAST(CAST((SELECT ProcessDate FROM ufnARCUGetLatestProcessDate()) AS VARCHAR(10)) AS smalldatetime) AS INT)
You can't compare an int to a smalldatetime. You need to compare two dates and for that you'd have to use datediff.
I was able to figure out the issue. DigCamare's comment on DATEDIFF reminded me that is what I needed to do even though you can cast a int to a smalldatetime so you can compare it.
DATEDIFF(d,L.LoanDueDate,CONVERT(smalldatetime,convert(varchar(10),(SELECT ProcessDate FROM ufnARCUGetLatestProcessDate()))))
You can cast the date column to int. It will give you the aproximate (rounded) date, without the time part, as an int.
Edit:
This will give you the date as a number for you to compare:
SELECT FLOOR(CAST(L.LoanDueDate as float)) -
(SELECT ProcessDate FROM ufnARCUGetLatestProcessDate()) AS myValue
FROM ...
The key is to cast the date to number and not the number to date.
Just wanted to add the following. This is what I am using to do a simple int to smalldatetime conversion. Hope it helps other people.
(SELECT CAST(CAST(ProcessDate AS VARCHAR(10)) AS SMALLDATETIME) FROM ufnARCUGetLatestProcessDate())
I got a column called DateOfBirth in my csv file with Excel Date Serial Number Date
Example:
36464
37104
35412
When i formatted cells in excel these are converted as
36464 => 1/11/1999
37104 => 1/08/2001
35412 => 13/12/1996
I need to do this transformation in SSIS or in SQL. How can this be achieved?
In SQL:
select dateadd(d,36464,'1899-12-30')
-- or thanks to rcdmk
select CAST(36464 - 2 as SmallDateTime)
In SSIS, see here
http://msdn.microsoft.com/en-us/library/ms141719.aspx
The marked answer is not working fine, please change the date to "1899-12-30" instead of "1899-12-31".
select dateadd(d,36464,'1899-12-30')
You can cast it to a SQL SMALLDATETIME:
CAST(36464 - 2 as SMALLDATETIME)
MS SQL Server counts its dates from 01/01/1900 and Excel from 12/30/1899 = 2 days less.
tldr:
select cast(#Input - 2e as datetime)
Explanation:
Excel stores datetimes as a floating point number that represents elapsed time since the beginning of the 20th century, and SQL Server can readily cast between floats and datetimes in the same manner. The difference between Excel and SQL server's conversion of this number to datetimes is 2 days (as of 1900-03-01, that is). Using a literal of 2e for this difference informs SQL Server to implicitly convert other datatypes to floats for very input-friendly and simple queries:
select
cast('43861.875433912' - 2e as datetime) as ExcelToSql, -- even varchar works!
cast(cast('2020-01-31 21:00:37.490' as datetime) + 2e as float) as SqlToExcel
-- Results:
-- ExcelToSql SqlToExcel
-- 2020-01-31 21:00:37.490 43861.875433912
this actually worked for me
dateadd(mi,CONVERT(numeric(17,5),41869.166666666664)*1440,'1899-12-30')
(minus 1 more day in the date)
referring to the negative commented post
SSIS Solution
The DT_DATE data type is implemented using an 8-byte floating-point number. Days are represented by whole number increments, starting with 30 December 1899, and midnight as time zero. Hour values are expressed as the absolute value of the fractional part of the number. However, a floating point value cannot represent all real values; therefore, there are limits on the range of dates that can be presented in DT_DATE. Read more
From the description above you can see that you can convert these values implicitly when mapping them to a DT_DATE Column after converting it to a 8-byte floating-point number DT_R8.
Use a derived column transformation to convert this column to 8-byte floating-point number:
(DT_R8)[dateColumn]
Then map it to a DT_DATE column
Or cast it twice:
(DT_DATE)(DT_R8)[dateColumn]
You can check my full answer here:
Is there a better way to parse [Integer].[Integer] style dates in SSIS?
Found this topic helpful so much so created a quick SQL UDF for it.
CREATE FUNCTION dbo.ConvertExcelSerialDateToSQL
(
#serial INT
)
RETURNS DATETIME
AS
BEGIN
DECLARE #dt AS DATETIME
SELECT #dt =
CASE
WHEN #serial is not null THEN CAST(#serial - 2 AS DATETIME)
ELSE NULL
END
RETURN #dt
END
GO
I had to take this to the next level because my Excel dates also had times, so I had values like this:
42039.46406 --> 02/04/2015 11:08 AM
42002.37709 --> 12/29/2014 09:03 AM
42032.61869 --> 01/28/2015 02:50 PM
(also, to complicate it a little more, my numeric value with decimal was saved as an NVARCHAR)
The SQL I used to make this conversion is:
SELECT DATEADD(SECOND, (
CONVERT(FLOAT, t.ColumnName) -
FLOOR(CONVERT(FLOAT, t.ColumnName))
) * 86400,
DATEADD(DAY, CONVERT(FLOAT, t.ColumnName), '1899-12-30')
)
In postgresql, you can use the following syntax:
SELECT ((DATE('1899-12-30') + INTERVAL '1 day' * FLOOR(38242.7711805556)) + (INTERVAL '1 sec' * (38242.7711805556 - FLOOR(38242.7711805556)) * 3600 * 24)) as date
In this case, 38242.7711805556 represents 2004-09-12 18:30:30 in excel format
In addition of #Nick.McDermaid answer I would like to post this solution, which convert not only the day but also the hours, minutes and seconds:
SELECT DATEADD(s, (42948.123 - FLOOR(42948.123))*3600*24, dateadd(d, FLOOR(42948.123),'1899-12-30'))
For example
42948.123 to 2017-08-01 02:57:07.000
42818.7166666667 to 2017-03-24 17:12:00.000
You can do this if you just need to display the date in a view:
CAST will be faster than CONVERT if you have a large amount of data, also remember to subtract (2) from the excel date:
CAST(CAST(CAST([Column_With_Date]-2 AS INT)AS smalldatetime) AS DATE)
If you need to update the column to show a date you can either update through a join (self join if necessary) or simply try the following:
You may not need to cast the excel date as INT but since the table I was working with was a varchar I had to do that manipulation first. I also did not want the "time" element so I needed to remove that element with the final cast as "date."
UPDATE [Table_with_Date]
SET [Column_With_Excel_Date] = CAST(CAST(CAST([Column_With_Excel_Date]-2 AS INT)AS smalldatetime) AS DATE)
If you are unsure of what you would like to do with this test and re-test! Make a copy of your table if you need. You can always create a view!
Google BigQuery solution
Standard SQL
Select Date, DATETIME_ADD(DATETIME(xy, xm, xd, 0, 0, 0), INTERVAL xonlyseconds SECOND) xaxsa
from (
Select Date, EXTRACT(YEAR FROM xonlydate) xy, EXTRACT(MONTH FROM xonlydate) xm, EXTRACT(DAY FROM xonlydate) xd, xonlyseconds
From (
Select Date
, DATE_ADD(DATE '1899-12-30', INTERVAL cast(FLOOR(cast(Date as FLOAT64)) as INT64) DAY ) xonlydate
, cast(FLOOR( ( cast(Date as FLOAT64) - cast(FLOOR( cast(Date as FLOAT64)) as INT64) ) * 86400 ) as INT64) xonlyseconds
FROM (Select '43168.682974537034' Date) -- 09.03.2018 16:23:28
) xx1
)
For those looking how to do this in excel (outside of formatting to a date field) you can do this by using the Text function https://exceljet.net/excel-functions/excel-text-function
i.e.
A1 = 132134
=Text(A1,"MM-DD-YYYY") will result in a date
This worked for me because sometimes the field was a numeric to get the time portion.
Command:
dateadd(mi,CONVERT(numeric(17,5),41869.166666666664)*1440,'1899-12-31')
I have two tables where column [date] is type of DATETIME2(0).
I have to compare two records only by theirs Date parts (day+month+year), discarding Time parts (hours+minutes+seconds).
How can I do that?
Use the CAST to the new DATE data type in SQL Server 2008 to compare just the date portion:
IF CAST(DateField1 AS DATE) = CAST(DateField2 AS DATE)
A small drawback in Marc's answer is that both datefields have been typecast, meaning you'll be unable to leverage any indexes.
So, if there is a need to write a query that can benefit from an index on a date field, then the following (rather convoluted) approach is necessary.
The indexed datefield (call it DF1) must be untouched by any kind of function.
So you have to compare DF1 to the full range of datetime values for the day of DF2.
That is from the date-part of DF2, to the date-part of the day after DF2.
I.e. (DF1 >= CAST(DF2 AS DATE)) AND (DF1 < DATEADD(dd, 1, CAST(DF2 AS DATE)))
NOTE: It is very important that the comparison is >= (equality allowed) to the date of DF2, and (strictly) < the day after DF2. Also the BETWEEN operator doesn't work because it permits equality on both sides.
PS: Another means of extracting the date only (in older versions of SQL Server) is to use a trick of how the date is represented internally.
Cast the date as a float.
Truncate the fractional part
Cast the value back to a datetime
I.e. CAST(FLOOR(CAST(DF2 AS FLOAT)) AS DATETIME)
Though I upvoted the answer marked as correct. I wanted to touch on a few things for anyone stumbling upon this.
In general, if you're filtering specifically on Date values alone. Microsoft recommends using the language neutral format of ymd or y-m-d.
Note that the form '2007-02-12' is considered language-neutral only
for the data types DATE, DATETIME2, and DATETIMEOFFSET.
To do a date comparison using the aforementioned approach is simple. Consider the following, contrived example.
--112 is ISO format 'YYYYMMDD'
declare #filterDate char(8) = CONVERT(char(8), GETDATE(), 112)
select
*
from
Sales.Orders
where
CONVERT(char(8), OrderDate, 112) = #filterDate
In a perfect world, performing any manipulation to the filtered column should be avoided because this can prevent SQL Server from using indexes efficiently. That said, if the data you're storing is only ever concerned with the date and not time, consider storing as DATETIME with midnight as the time. Because:
When SQL Server converts the literal to the filtered column’s type, it
assumes midnight when a time part isn’t indicated. If you want such a
filter to return all rows from the specified date, you need to ensure
that you store all values with midnight as the time.
Thus, assuming you are only concerned with date, and store your data as such. The above query can be simplified to:
--112 is ISO format 'YYYYMMDD'
declare #filterDate char(8) = CONVERT(char(8), GETDATE(), 112)
select
*
from
Sales.Orders
where
OrderDate = #filterDate
You can try this one
CONVERT(DATE, GETDATE()) = CONVERT(DATE,'2017-11-16 21:57:20.000')
I test that for MS SQL 2014 by following code
select case when CONVERT(DATE, GETDATE()) = CONVERT(DATE,'2017-11-16 21:57:20.000') then 'ok'
else '' end
You may use DateDiff and compare by day.
DateDiff(dd,#date1,#date2) > 0
It means #date2 > #date1
For example :
select DateDiff(dd, '01/01/2021 10:20:00', '02/01/2021 10:20:00')
has the result : 1
For Compare two date like MM/DD/YYYY to MM/DD/YYYY .
Remember First thing column type of Field must be dateTime.
Example : columnName : payment_date dataType : DateTime .
after that you can easily compare it.
Query is :
select * from demo_date where date >= '3/1/2015' and date <= '3/31/2015'.
It very simple ......
It tested it.....