I am trying to delete ALL empty paragraphs at the start of a Word file. I am using the following to delete just the FIRST paragraph but I need to delete all empty paragraphs in a row, so that if you have 5 empty lines, they will all be deleted.
here is the code:
Dim MyRange As Range
Set MyRange = ActiveDocument.Paragraphs(1).Range
If MyRange.Text = vbCr Then MyRange.Delete
I've tried adding a loop and for statement, but to no avail.
thanks in advance.
Collapse to the start of the document, then extend the range whilst 'empty characters' are found.
Here is your starter for 10
Dim MyRange As Range
Set MyRange = ActiveDocument.Paragraphs(1).Range
MyRange.Collapse direction:=wdCollapseStart
MyRange.MoveEndWhile cset:=" " & vbCrLf ' & any other invisible characters that may be present
MyRange.Delete
Each paragraph must have at least one character - the paragraph mark itself. So all we need to do is to check if the paragraph contains only 1 character.
Simple like this:
Sub ClearEmptyPargraphAtStartOfDocument()
While (ActiveDocument.Paragraphs(1).Range.Characters.Count = 1)
ActiveDocument.Paragraphs(1).Range.Delete
Wend
End Sub
This seems to work for me
Public Sub SOCheck()
Dim MyRange As Range, CarryOn As Boolean
CarryOn = True
While CarryOn
Set MyRange = ActiveDocument.Paragraphs(1).Range
If MyRange.Text = vbCr Then
MyRange.Delete
Else
CarryOn = False
End If
Wend
'MsgBox "Done"
End Sub
It's just a loop around your own code
Related
I have been using the following macro to pull out items in parenthesis to comments in word:
'
' CommentBubble Macro
'
'
Dim myRange As Range
Set myRange = ActiveDocument.Content
searchtext = "\(*\)"
With myRange.Find
.MatchWildcards = True
Do While .Execute(findText:=searchtext, Forward:=True) = True
If Len(myRange.Text) > 4 Then
ActiveDocument.Comments.Add myRange, myRange.Text
myRange.Text = ""
End If
Loop
End With
End Sub
The reason I have the length of the text be > 4 is because these are legal documents and I don't want to isolate strings that have things like "in the following conditions: (i) condition 1, (ii) condition 2, etc."
However, here is a snippet of text for which the above code breaks:
This is sample text (with some additional text) that does stuff (with more stuff) and represents 39.4% of shares on the effective date (before giving effect, with some conditions such as ( some stuff (i) and some stuff (ii) with final stuff) and more final stuff) which is subject to (some conditions here) and conclude here.
If you run this you will get the following result:
This is sample text that does stuff and represents 39.4% of shares on the effective date and some stuff (ii) with final stuff) and more final stuff) which is subject to and conclude here.
As you can see the nested parenthesis cause some trouble. Any advice?
Thanks!
You are trying to match parentheses which in Word is a difficult and thankless task as Word only sees opening and closing parentheses as individual characters and not automatically matched by word. The code below finds matching parentheses, eliminates trailing spaces, habdles the case of no parentheses being present, and errors out if you have unbalanced errors. I've left in debugging statements so that you can uncomment them to see what is happening.
Option Explicit
Public Sub ttest()
Dim myRange As Word.Range
Set myRange = ActiveDocument.StoryRanges(wdMainTextStory)
myRange.Collapse direction:=wdCollapseStart
Set myRange = NextParenRange(myRange)
Do Until myRange Is Nothing
DoEvents
Debug.Print myRange.Text
Dim myDupRange As Word.Range
Set myDupRange = myRange.Duplicate
myRange.Collapse direction:=wdCollapseEnd
If myDupRange.Characters.Last.Next.Text = " " Then myDupRange.MoveEnd Count:=1
myDupRange.Delete
Set myRange = NextParenRange(myRange)
Loop
End Sub
Public Function NextParenRange(ByVal ipRange As Word.Range) As Word.Range
Const OpenP As String = "("
Const CloseP As String = ")"
Dim myRange As Word.Range
Set myRange = ipRange.Duplicate
'If myRange.Start <> myRange.End Then myRange.Collapse direction:=wdCollapseStart
'exit if no parentheses exist
'Debug.Print myRange.Start
If myRange.MoveUntil(cset:=OpenP) = 0 Then
Set NextParenRange = Nothing
Exit Function
Else
'Debug.Print myRange.Start
Dim myParenCount As Long
myParenCount = 1
myRange.MoveEnd Count:=1
End If
Do Until myParenCount = 0
' allows VBA to respond to a break key press
DoEvents
' if we run out of parentheses before we get back to zero then flag an error
If myRange.MoveEndUntil(cset:=OpenP & CloseP) = 0 Then
VBA.Err.Raise 17, "Unbalanced parentheses in document"
End If
myRange.MoveEnd Count:=1
'Debug.Print myRange.Characters.Last.Text
'Debug.Print myRange.Characters.Last.Next.Text
myParenCount = myParenCount + IIf(myRange.Characters.Last.Text = OpenP, 1, -1)
Loop
Set NextParenRange = myRange.Duplicate
End Function
Within a Word docx: I'm trying to add a bookmark to each sentence. For example, at first sentence would be bookmark "bmarkpg01" and second sentence would be bookmark ""bmarkpg01ln01col01"". My code adds only one bookmark to first sentence and doesn't loop through to end of document.
I've tried a for each loop to attempt each sent in sentences and each bmark in bookmark.
Sub tryAddBmarkatSentence()
Dim myRange As Range
Set myRange = ActiveDocument.Content
Dim bmark As Bookmark
Application.ScreenUpdating = False
For Each MySent In ActiveDocument.Sentences
For Each bmark In ActiveDocument.Bookmarks
ActiveDocument.Bookmarks.Add Name:="pmark" & bmark.Range.Information(wdActiveEndAdjustedPageNumber), Range:=myRange 'bmark name would have added info of page, line, and col number. here as example is pagenumber.
Next
Next
End Sub
EXPECTED RESULT: Within entire document, each sentence has a corresponding bookmark and bookmark name ("bmarkpg01ln01col01", "bmarkpg01ln02col10", etc.)
ACTUAL RESULTS: only one bookmark is added to the first sentence of the document.
The following works for me, as far as the requirements in the question go.
Please remember to put Option Explicit at the top of a code page. This will force you to declare ("Dim") variables, but will also save time and trouble as it will prevent typos and warn you of other problems.
A Sentence in Word returns a Range object, so the code below delares MySent As Range. This provides the target Range for the Bookmarks.Add method.
If you won't be doing anything else with the bookmark, it's not strictly necessary to Set bkm = when adding the bookmark. I left it in since it is declared in the code in the question.
It's not necessary to loop the collection of bookmarks - espeicially since there aren't any - they're being added.
I've added some code for naming the bookmarks, as well.
Sub tryAddBmarkatSentence()
Dim doc As Word.Document
Dim MySent As Word.Range
Dim bmark As Bookmark
Application.ScreenUpdating = False
Set doc = ActiveDocument
For Each MySent In doc.Sentences
Set bmark = doc.Bookmarks.Add(Name:="bmark" & _
MySent.Information(wdActiveEndAdjustedPageNumber) & "_" &_
MySent.Information(wdFirstCharacterLineNumber) & "_" & _
MySent.Information(wdFirstCharacterColumnNumber), Range:=MySent)
'bmark name would have added info of page, line, and col number. here as example is pagenumber.
Next
End Sub
u can try like this
Sub tryAddBmarkatSentence()
Dim myRange As Range
Set myRange = ActiveDocument.Content
Dim bmark As Bookmark
Application.ScreenUpdating = False
For Each MySent In ActiveDocument.Sentences
ActiveDocument.Bookmarks.Add ... and the rest of the code.
//i dont know how you define witch bookmark is to asign to that sentence
Next
End Sub
I have a code like so:
Sub MoveToBeginningSentence()
Application.ScreenUpdating = False
Dim selectedWords As Range
Dim selectedText As String
Const punctuation As String = " & Chr(145) & "
On Error GoTo ErrorReport
' Cancel macro when there's no text selected
Selection.Cut
Selection.MoveLeft Unit:=wdSentence, Count:=1, Extend:=wdMove
Selection.MoveRight Unit:=wdCharacter, Count:=1, Extend:=wdExtend
Set selectedWords = Selection.Range
selectedText = selectedWords
If InStr(selectedText, punctuation) = 0 Then
Selection.MoveLeft Unit:=wdSentence, Count:=1, Extend:=wdMove
Selection.Paste
Else
Selection.MoveLeft Unit:=wdSentence, Count:=1, Extend:=wdMove
Selection.Paste
Selection.Paste
Selection.Paste
Selection.Paste
End If
ErrorReport:
End Sub
Basically, it help me move whatever text I have selected to the beginning of the sentence in Word. If there's no quotation mark, then paste once. If there is a quote mark, paste 4 times.
The problem is regardless of whether there's any quotation there or not, it will only paste once. If I set the macro to detect any other character, it will work fine. But every single time I try to force it to detect smart quotations, it will fail.
Is there any way to fix it?
Working with the Selection object is always a bit chancy; on the whole, it's better to work with a Range object. You can have only one Selection; you can have as many Ranges as you need.
Because your code uses the Selection object it's not 100% clear what the code does. Based on my best guess, I put together the following example which you can tweak if it's not exactly right.
At the beginning, I check whether there's something in the selection, or it's a blinking insertion point. If no text is selected, the macro ends. This is better than invoking Error handling, then not handling anything: If other problems crop up in your code, you wouldn't know about them.
A Range object is instantiated for the selection - there's no need to "cut" it, as you'll see further along. Based on this, the entire sentence is also assigned to a Range object. The text of the sentence is picked up, then the sentence's Range is "collapsed" to its starting point. (Think of this like pressing the left arrow on the keyboard.)
Now the sentence's text is checked for the character Chr(145). If it's not there, the original selection's text (including formatting) is added at the beginning of the sentence. If it's there, then it's added four times.
Finally, the original selection is deleted.
Sub MoveToBeginningSentence()
Application.ScreenUpdating = False
Dim selectedText As String
Dim punctuation As String
punctuation = Chr(145) ' ‘ "smart" apostrophe
Dim selRange As word.Range
Dim curSentence As word.Range
Dim i As Long
' Cancel macro when there's no text selected
If Selection.Type = wdSelectionIP Then Exit Sub
Set selRange = Selection.Range
Set curSentence = selRange.Sentences(1)
selectedText = curSentence.Text
curSentence.Collapse wdCollapseStart
If InStr(selectedText, punctuation) = 0 Then
curSentence.FormattedText = selRange.FormattedText
Else
For i = 1 To 4
curSentence.FormattedText = selRange.FormattedText
curSentence.Collapse wdCollapseEnd
Next
End If
selRange.Delete
End Sub
Please check out this code.
Sub MoveToBeginningSentence()
' 19 Jan 2018
Dim Rng As Range
Dim SelText As String
Dim Repeats As Integer
Dim i As Integer
With Selection.Range
SelText = .Text ' copy the selected text
Set Rng = .Sentences(1) ' identify the current sentence
End With
If Len(SelText) Then ' Skip when no text is selected
With Rng
Application.ScreenUpdating = False
Selection.Range.Text = "" ' delete the selected text
Repeats = IIf(IsQuote(.Text), 4, 1)
If Repeats = 4 Then .MoveStart wdCharacter, 1
For i = 1 To Repeats
.Text = SelText & .Text
Next i
Application.ScreenUpdating = True
End With
Else
MsgBox "Please select some text.", _
vbExclamation, "Selection is empty"
End If
End Sub
Private Function IsQuote(Txt As String) As Boolean
' 19 Jan 2018
Dim Quotes
Dim Ch As Long
Dim i As Long
Quotes = Array(34, 147, 148, -24143, -24144)
Ch = Asc(Txt)
' Debug.Print Ch ' read ASCII code of first character
For i = 0 To UBound(Quotes)
If Ch = Quotes(i) Then Exit For
Next i
IsQuote = (i <= UBound(Quotes))
End Function
The approach taken is to identify the first character of the selected sentence using the ASC() function. For a normal quotation mark that would be 34. In my test I came up with -24143 and -24144 (opening and closing). I couldn't identify Chr(145) but found MS stating that curly quotation marks are Chr(147) and Chr(148) respectively. Therefore I added a function that checks all of them. If you enable the line Debug.Print Ch in the function the character code actually found will be printed to the immediate window. You might add more character codes to the array Quotes.
The code itself doesn't consider spaces between words. Perhaps Word will take care of that, and perhaps you don't need it.
You need to supply InStr with the starting position as a first parameter:
If InStr(1, selectedText, punctuation) = 0 Then
Also
Const punctuation As String = " & Chr(145) & "
is going to search for space-ampersand-space-Chr(145)-space-ampersand-space. If you want to search for the smart quote character then use
Const punctuation As String = Chr(145)
Hope that helps.
I'm new to VBA and would greatly appreciate some help on a problem.
I have long Word documents where I need to apply standard comments to the same set of keywords, but only in selected sections of the document. The following macro worked to find a keyword and apply a comment (from question here https://superuser.com/questions/547710/macro-to-insert-comment-bubbles-in-microsoft-word):
Sub label_items()
'
' label_items Macro
'
'
Do While Selection.Find.Execute("keyword1") = True
ActiveDocument.Comments.Add range:=Selection.range, Text:="comment for keyword 1"
Loop
End Sub
The two modifications are:
1) only apply the comments to user selected text, not the whole document. I tried a "With Selection.Range.Find" approach but I don't think comments can be added this way (??)
2) repeat this for 20+ keywords in the selected text. The keywords aren't totally standard and have names like P_1HAI10, P_1HAI20, P_2HAI60, P_HFS10, etc.
EDIT: I have tried to combine code from similar questions ( Word VBA: finding a set of words and inserting predefined comments and Word macro, storing the current selection (VBA)) but my current attempt (below) only runs for the first keyword and comment and runs over the entire document, not just the text I have highlighted/selected.
Sub label_items()
'
' label_items Macro
'
Dim selbkup As range
Set selbkup = ActiveDocument.range(Selection.range.Start, Selection.range.End)
Set range = selbkup
Do While range.Find.Execute("keyword 1") = True
ActiveDocument.Comments.Add range, "comment for keyword 1"
Loop
Set range = selbkup
Do While range.Find.Execute("keyword 2") = True
ActiveDocument.Comments.Add range, "comment for keyword 2"
Loop
'I would repeat this process for all of my keywords
End Sub
I've combed through previous questions and the Office Dev Center and am stuck. Any help/guidance is greatly appreciated!
It's a matter of adding a loop and a means of Finding the next keyword you're looking for. There are a few suggestions in the code example below, so please adjust it as necessary to fit your requirements.
Option Explicit
Sub label_items()
Dim myDoc As Document
Dim targetRange As Range
Set myDoc = ActiveDocument
Set targetRange = Selection.Range
'--- drop a bookmark to return the cursor to it's original location
Const RETURN_BM = "OrigCursorLoc"
myDoc.Bookmarks.Add Name:=RETURN_BM, Range:=Selection.Range
'--- if nothing is selected, then search the whole document
If Selection.Start = Selection.End Then
Selection.Start = 0
targetRange.Start = 0
targetRange.End = myDoc.Range.End
End If
'--- build list of keywords to search
Dim keywords() As String
keywords = Split("SMS,HTTP,SMTP", ",", , vbTextCompare)
'--- search for all keywords within the user selected range
Dim i As Long
For i = 0 To UBound(keywords)
'--- set the cursor back to the beginning of the
' originally selected range
Selection.GoTo What:=wdGoToBookmark, Name:=RETURN_BM
Do
With Selection.Find
.Forward = True
.Wrap = wdFindStop
.Text = keywords(i)
.Execute
If .Found Then
If (Selection.Start < targetRange.End) Then
Selection.Comments.Add Selection.Range, _
Text:="Found the " & keywords(i) & " keyword"
Else
Exit Do
End If
Else
Exit Do
End If
End With
Loop
Next i
'--- set the cursor back to the beginning of the
' originally selected range
Selection.GoTo What:=wdGoToBookmark, Name:=RETURN_BM
End Sub
In my code below, when the word isn't there, all the table contente is deleted. How to fix it? Text is in Cell(1,1) for multiple tables.
Sub DeleteText()
StartWord = "Orientation:"
For Each oTbl In ActiveDocument.Tables
Set oRng = oTbl.Range
With oRng
.Find.Execute Findtext:=StartWord & "*", MatchWildcards:=True
.MoveStart wdCharacter, 0
.MoveEndUntil vbCr
.Delete
End With
Next
End Sub
First of all you need to add if statement which will check if your text is found. You will find that in the code below. However, I also improved the way you delete the whole content of cell where your text is found. My solution is better in situation when you have more lines/paragraphs/sentences in the cell.
Sub DeleteText_Improved()
Dim StartWord As String
Dim oTbl As Table
Dim oRng As Range
StartWord = "Mauris"
For Each oTbl In ActiveDocument.Tables
Set oRng = oTbl.Range
With oRng
.Find.Execute Findtext:=StartWord & "*", MatchWildcards:=True
If .Find.Found Then
'how to select whole cell range
oTbl.Cell(.Information(wdEndOfRangeRowNumber), _
.Information(wdEndOfRangeColumnNumber)).Range.Delete
End If
End With
Next
End Sub
Final remark- your code is working only for the first occurrence of the word you search for. It will not remove other cells where the word appears.