how to get this results for this? - sql

Write a SELECT statement that returns these columns from the db1.MyGuitarShop.Products table:
a) The DateAdded column
b) A column that uses the CAST function to return the DateAdded column with its date only (year, month, and day)
c) A column that uses the CAST function to return the DateAdded column with its full time only (hour, minutes, seconds, and milliseconds)
d) A column that uses the CAST function to return the DateAdded column with just the month and day
This is what I have currently:
SELECT
DateAdded,
CAST(DateAdded AS decimal(10, 1)) AS AddedDate,
CAST(DateAdded AS decimal(10)) AS AddedTime,
CAST(DateAdded AS int) AS AddedChar7
FROM MyGuitarShop.Products;


With CAST converting to a DATE and TIME is easy. But the third item is trickier and involves two separate CASTS's, followed by string concatenation.
Something like this shoul do the trick:
Note that I've subbed in a variable (#dt) just to make it simpler to demonstrate the concept.
DECLARE #dt DATETIME = GETDATE()
SELECT #dt
, CAST(#dt AS Date) AS AddedDate
, CAST(#dt AS Time) AS AddedTime
, CAST(MONTH(#dt) AS VARCHAR(4)) + CAST(DAY(#dt) AS VARCHAR(4)) AS AddedChar
Here is a fiddle


Another options would be to use CONVERT to convert the dates to text. It has the advantage of allowing you to choose a specific format for the results ...
https://learn.microsoft.com/en-us/sql/t-sql/functions/cast-and-convert-transact-sql?view=sql-server-ver15
SELECT
DateAdded,
CONVERT(varchar(128), DateAdded, 111) AS AddedDate,
CONVERT(varchar(128), DateAdded, 14) AS AddedTime,
CAST(DATEPART(MONTH, DateAdded) as varchar(2)) + '/' + CAST(DATEPART(DAY, DateAdded) as varchar(2)) AddedChar7
FROM (VALUES
(GETDATE())
)Products(DateAdded)


SELECT DateAdded
,Cast(DateAdded as date) Cast_YMD --Default for date is YMD
,Cast(DateAdded as time) Cast_HMSM -- Default for time is HMSM
,CAST(DateAdded as char(6)) Cast_MMDD --The 6 characters in the date field are month(as 3 char name Jan,Feb...) and day(as 2 digit)
FROM Products

Related

SQL Column Concatenation whilst keeping the datatype of first column [duplicate]

In an extract I am dealing with, I have 2 datetime columns. One column stores the dates and another the times as shown.
How can I query the table to combine these two fields into 1 column of type datetime?
Dates
2009-03-12 00:00:00.000
2009-03-26 00:00:00.000
2009-03-26 00:00:00.000
Times
1899-12-30 12:30:00.000
1899-12-30 10:00:00.000
1899-12-30 10:00:00.000

You can simply add the two.
if the Time part of your Date column is always zero
and the Date part of your Time column is also always zero (base date: January 1, 1900)
Adding them returns the correct result.
SELECT Combined = MyDate + MyTime FROM MyTable
Rationale (kudos to ErikE/dnolan)
It works like this due to the way the date is stored as two 4-byte
Integers with the left 4-bytes being the date and the right
4-bytes being the time. Its like doing $0001 0000 + $0000 0001 =
$0001 0001
Edit regarding new SQL Server 2008 types
Date and Time are types introduced in SQL Server 2008. If you insist on adding, you can use Combined = CAST(MyDate AS DATETIME) + CAST(MyTime AS DATETIME)
Edit2 regarding loss of precision in SQL Server 2008 and up (kudos to Martin Smith)
Have a look at How to combine date and time to datetime2 in SQL Server? to prevent loss of precision using SQL Server 2008 and up.

If the time element of your date column and the date element of your time column are both zero then Lieven's answer is what you need. If you can't guarantee that will always be the case then it becomes slightly more complicated:
SELECT DATEADD(day, 0, DATEDIFF(day, 0, your_date_column)) +
DATEADD(day, 0 - DATEDIFF(day, 0, your_time_column), your_time_column)
FROM your_table

This is an alternative solution without any char conversions:
DATEADD(ms, DATEDIFF(ms, '00:00:00', [Time]), CONVERT(DATETIME, [Date]))
You will only get milliseconds accuracy this way, but that would normally be OK. I have tested this in SQL Server 2008.

This worked for me
CAST(Tbl.date as DATETIME) + CAST(Tbl.TimeFrom AS TIME)
(on SQL 2008 R2)

If you're not using SQL Server 2008 (i.e. you only have a DateTime data type), you can use the following (admittedly rough and ready) TSQL to achieve what you want:
DECLARE #DateOnly AS datetime
DECLARE #TimeOnly AS datetime
SET #DateOnly = '07 aug 2009 00:00:00'
SET #TimeOnly = '01 jan 1899 10:11:23'
-- Gives Date Only.
SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, #DateOnly))
-- Gives Time Only.
SELECT DATEADD(Day, -DATEDIFF(Day, 0, #TimeOnly), #TimeOnly)
-- Concatenates Date and Time parts.
SELECT
CAST(
DATEADD(dd, 0, DATEDIFF(dd, 0, #DateOnly)) + ' ' +
DATEADD(Day, -DATEDIFF(Day, 0, #TimeOnly), #TimeOnly)
as datetime)
It's rough and ready, but it works!

If both of your fields are datetime then simply adding those will work.
eg:
Declare #d datetime, #t datetime
set #d = '2009-03-12 00:00:00.000';
set #t = '1899-12-30 12:30:00.000';
select #d + #t
If you used Date & Time datatype then just cast the time to datetime
eg:
Declare #d date, #t time
set #d = '2009-03-12';
set #t = '12:30:00.000';
select #d + cast(#t as datetime)

This was my solution which ignores the date value of the time column
CAST(Tbl.date as DATETIME) + CAST(CAST(Tbl.TimeFrom AS TIME) as DATETIME)
Hope this helps others

Convert the first date stored in a datetime field to a string, then convert the time stored in a datetime field to string, append the two and convert back to a datetime field all using known conversion formats.
Convert(datetime, Convert(char(10), MYDATETIMEFIELD, 103) + ' ' + Convert(char(8), MYTIMEFIELD, 108), 103)

Convert both field into DATETIME :
SELECT CAST(#DateField as DATETIME) + CAST(#TimeField AS DATETIME)
and if you're using Getdate() use this first:
DECLARE #FechaActual DATETIME = CONVERT(DATE, GETDATE());
SELECT CAST(#FechaActual as DATETIME) + CAST(#HoraInicioTurno AS DATETIME)

I had many errors as stated above so I did it like this
try_parse(concat(convert(date,Arrival_date),' ',arrival_time) as datetime) AS ArrivalDateTime
It worked for me.

Finding this works for two dates where you want time from one and date from the other:
declare #Time as datetime = '2021-11-19 12:34'
declare #Date as datetime = '2021-10-10'
SELECT #time + datediff(day, #Time, #Date)

DECLARE #Dates table ([Date] datetime);
DECLARE #Times table ([Time] datetime);
INSERT INTO #Dates VALUES('2009-03-12 00:00:00.000');
INSERT INTO #Dates VALUES('2009-03-26 00:00:00.000');
INSERT INTO #Dates VALUES('2009-03-30 00:00:00.000');
INSERT INTO #Times VALUES('1899-12-30 12:30:00.000');
INSERT INTO #Times VALUES('1899-12-30 10:00:00.000');
INSERT INTO #Times VALUES('1899-12-30 10:00:00.000');
WITH Dates (ID, [Date])
AS (
SELECT ROW_NUMBER() OVER (ORDER BY [Date]), [Date] FROM #Dates
), Times (ID, [Time])
AS (
SELECT ROW_NUMBER() OVER (ORDER BY [Time]), [Time] FROM #Times
)
SELECT Dates.[Date] + Times.[Time] FROM Dates
JOIN Times ON Times.ID = Dates.ID
Prints:
2009-03-12 10:00:00.000
2009-03-26 10:00:00.000
2009-03-30 12:30:00.000

To combine date from a datetime column and time from another datetime column this is the best fastest solution for you:
select cast(cast(DateColumn as date) as datetime) + cast(TimeColumn as datetime) from YourTable

SELECT CAST(CAST(#DateField As Date) As DateTime) + CAST(CAST(#TimeField As Time) As DateTime)

Another way is to use CONCATand CAST, be aware, that you need to use DATETIME2(x) to make it work. You can set x to anything between 0-7 7 meaning no precision loss.
DECLARE #date date = '2018-03-12'
DECLARE #time time = '07:00:00.0000000'
SELECT CAST(CONCAT(#date, ' ', #time) AS DATETIME2(7))
Returns 2018-03-12 07:00:00.0000000
Tested on SQL Server 14

simply concatenate both , but cast them first as below
select cast(concat(Cast(DateField as varchar), ' ', Cast(TimeField as varchar)) as datetime) as DateWithTime from TableName;

select s.SalesID from SalesTbl s
where cast(cast(s.SaleDate as date) as datetime) + cast(cast(s.SaleCreatedDate as time) as datetime) between #FromDate and #ToDate

The existing answers do not address the datetime2 datatype so I will add mine:
Assuming that you want to add a time value to a datetime2 value where:
The datetime2 value could contain non-zero time component and/or fractional seconds
The time value could contain the value 23:59:59.9999999 which is 86,399.9999999 seconds, 86,399,999,999.9 microseconds or 86,399,999,999,900 nanoseconds¹
Due to the limitations of dateadd function¹ you must add them in two steps:
Convert the time value to seconds and use dateadd(second, ...)
Extract the nanoseconds from the time value and use dateadd(nanosecond, ...) to add them to the date calculated above
declare #dv datetime2 = '2000-01-01 12:34:56.7890123';
declare #tv time = '23:59:59.9999999';
select dateadd(
nanosecond,
datepart(nanosecond, #tv),
dateadd(
second,
datepart(hour, #tv) * 60 * 60 + datepart(minute, #tv) * 60 + datepart(second, #tv),
#dv
)
);
-- 2000-01-02 12:34:56.7890122
¹ Nanosecond values might not fit in int datatype which dateadd function expects.

SELECT CAST(your_date_column AS date) + CAST(your_time_column AS datetime) FROM your_table
Works like a charm

I ran into similar situation where I had to merge Date and Time fields to DateTime field. None of the above mentioned solution work, specially adding two fields as the data type for addition of these 2 fields is not same.
I created below solution, where I added hour and then minute part to the date. This worked beautifully for me. Please check it out and do let me know if you get into any issues.
;with tbl
as
(
select StatusTime = '12/30/1899 5:17:00 PM', StatusDate = '7/24/2019 12:00:00 AM'
)
select DATEADD(MI, DATEPART(MINUTE,CAST(tbl.StatusTime AS TIME)),DATEADD(HH, DATEPART(HOUR,CAST(tbl.StatusTime AS TIME)), CAST(tbl.StatusDate as DATETIME)))
from tbl
Result: 2019-07-24 17:17:00.000

Converting a FLOAT into DATE in SQL?

I wanted to know how to properly convert FLOAT value into a DATE?
The data we receive has a value oriented as such: YYYYMM ex. 201911 (today's Year + Month). However, all the values passing under the YYYYMM column signifies the first of the month ex. 201911 = 11/01/2019.
RIGHT([DATE],2) + '/01/' + LEFT([DATE],4) AS [DATE]
When I try converting it, it doesn't put it in a date format because I tried using it in a DATEADD function and it errored on the field I converted.

If your value is YYYYMM, then one simple method is to convert to a string and then a date:
select convert(date, convert(varchar(255), yyyymm) + '01')
Or, use datefromparts():
select datefromparts(floor(yyyymm / 100), yyyymm % 100, 1)

Please check this :
DECLARE #Date AS FLOAT;
SET #Date = 201911;
SELECT CONVERT(VARCHAR, CAST(CAST(LEFT(#Date,4) AS VARCHAR(4)) + '/01' + '/' + CAST(RIGHT(#Date,2) AS VARCHAR(2)) AS DATE) , 103) As CREATEDDATE
Will output 11/01/2019

Subtract substring days from date

I'm trying to come up with a Select statement that would return the DATE column minus the number of days in the DAYS column.
This is the query I tried:
SELECT
DATEADD(DAY, -+(REPLACE(ISNULL(DAYS,0), 'DAYS', '')), DATE)
FROM
T
It throws an error
Operand data type varchar is invalid for minus operator

dateadd(day, -1*convert(int, coalesce(replace([DAYS], ' days', ''),'0')), [DATE])

Something like
DECLARE
#Days VARCHAR(25) = '23 DAYS',
#Date DATE = '2018-10-23';
SELECT DATEADD(Day, - CAST(REPLACE(#Days , 'DAYS', '') AS INT), #Date )
If you are using SQL Server 2012+
SELECT DATEADD(Day, - ISNULL(TRY_CAST(REPLACE(#Days , 'DAYS', '') AS INT), 0), #Date )

I think you need to get the number, cast it to integer as negative and use dateadd like below:
SELECT dateadd(DAY,cast('-'+substring([DAYS], 1,charindex(' ',[DAYS])) as int),[DATE])
FROM T

You can use this:
Use CHARINDEX to get the number of days and convert to int
and then minus it from date column
select DATEADD(DAY,-CAST(SUBSTRING(days,1,CHARINDEX(' ',days)) AS INT),DATE),* from #table

The DATEADD function expects an integer for its second parameter argument.
By REPLACING 'DAYS' with an empty string, you are still left with a varchar containing a number and the blank space that was between that number and the word "DAYS".
RTRIM this result and CAST it as an Integer, and you should be good to go.
Oh, and you also need to put ,DATE inside the DATEADD()'s parenthesis.

Convert Decimal or Varchar into Date

I have 2 fields.
Birth= Datatype Decimal(12,4) & Date = Datatype Date
Birth Date
19650101 2015-07-09
how do i get a result that looks like this
i want the result to be like this
Birth Date
1965-01-01 2015-07-09
where the Birth is a Date datatype and not a decimal (12,4)

To convert the number 19650101 to a date use
CONVERT(DATETIME, CAST(Birth AS VARCHAR(8)), 112)
To get the number of years (to one decimal) you could do:
ROUND(
DATEDIFF(day,
CONVERT(DATETIME, CAST(Birth AS VARCHAR(8)), 112),
[Date])/365.25
,1)
Which won't be exact but should be close enough to tenths of a year.

You can use this:
-- Create demo data
CREATE TABLE #dates(birth int, date date)
INSERT INTO #dates(birth,date)
VALUES(19650101,N'2015-07-09')
-- Your work
SELECT CONVERT(date,CONVERT(nvarchar(max),birth),112) as birth, date,
DATEDIFF(year,
CONVERT(date,CONVERT(nvarchar(max),birth),112),
date
) as years
FROM #dates
-- Cleanup
DROP TABLE #dates
This depends on the exact format you provides (19650101).

Here is one way to do this conversion.
cast(cast(FLOOR(birth) as CHAR(8)) as DATE)

I think you don't need to round. Just convert your decimal value and put "-" like below : )
select left(birth,4) +'-' +
substring(convert(nvarchar,birth),5,2)+'-'+
substring(convert(nvarchar,birth),7,2)

How to combine date from one field with time from another field - MS SQL Server

In an extract I am dealing with, I have 2 datetime columns. One column stores the dates and another the times as shown.
How can I query the table to combine these two fields into 1 column of type datetime?
Dates
2009-03-12 00:00:00.000
2009-03-26 00:00:00.000
2009-03-26 00:00:00.000
Times
1899-12-30 12:30:00.000
1899-12-30 10:00:00.000
1899-12-30 10:00:00.000

You can simply add the two.
if the Time part of your Date column is always zero
and the Date part of your Time column is also always zero (base date: January 1, 1900)
Adding them returns the correct result.
SELECT Combined = MyDate + MyTime FROM MyTable
Rationale (kudos to ErikE/dnolan)
It works like this due to the way the date is stored as two 4-byte
Integers with the left 4-bytes being the date and the right
4-bytes being the time. Its like doing $0001 0000 + $0000 0001 =
$0001 0001
Edit regarding new SQL Server 2008 types
Date and Time are types introduced in SQL Server 2008. If you insist on adding, you can use Combined = CAST(MyDate AS DATETIME) + CAST(MyTime AS DATETIME)
Edit2 regarding loss of precision in SQL Server 2008 and up (kudos to Martin Smith)
Have a look at How to combine date and time to datetime2 in SQL Server? to prevent loss of precision using SQL Server 2008 and up.

If the time element of your date column and the date element of your time column are both zero then Lieven's answer is what you need. If you can't guarantee that will always be the case then it becomes slightly more complicated:
SELECT DATEADD(day, 0, DATEDIFF(day, 0, your_date_column)) +
DATEADD(day, 0 - DATEDIFF(day, 0, your_time_column), your_time_column)
FROM your_table

This is an alternative solution without any char conversions:
DATEADD(ms, DATEDIFF(ms, '00:00:00', [Time]), CONVERT(DATETIME, [Date]))
You will only get milliseconds accuracy this way, but that would normally be OK. I have tested this in SQL Server 2008.

This worked for me
CAST(Tbl.date as DATETIME) + CAST(Tbl.TimeFrom AS TIME)
(on SQL 2008 R2)

If you're not using SQL Server 2008 (i.e. you only have a DateTime data type), you can use the following (admittedly rough and ready) TSQL to achieve what you want:
DECLARE #DateOnly AS datetime
DECLARE #TimeOnly AS datetime
SET #DateOnly = '07 aug 2009 00:00:00'
SET #TimeOnly = '01 jan 1899 10:11:23'
-- Gives Date Only.
SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, #DateOnly))
-- Gives Time Only.
SELECT DATEADD(Day, -DATEDIFF(Day, 0, #TimeOnly), #TimeOnly)
-- Concatenates Date and Time parts.
SELECT
CAST(
DATEADD(dd, 0, DATEDIFF(dd, 0, #DateOnly)) + ' ' +
DATEADD(Day, -DATEDIFF(Day, 0, #TimeOnly), #TimeOnly)
as datetime)
It's rough and ready, but it works!

If both of your fields are datetime then simply adding those will work.
eg:
Declare #d datetime, #t datetime
set #d = '2009-03-12 00:00:00.000';
set #t = '1899-12-30 12:30:00.000';
select #d + #t
If you used Date & Time datatype then just cast the time to datetime
eg:
Declare #d date, #t time
set #d = '2009-03-12';
set #t = '12:30:00.000';
select #d + cast(#t as datetime)

This was my solution which ignores the date value of the time column
CAST(Tbl.date as DATETIME) + CAST(CAST(Tbl.TimeFrom AS TIME) as DATETIME)
Hope this helps others

Convert the first date stored in a datetime field to a string, then convert the time stored in a datetime field to string, append the two and convert back to a datetime field all using known conversion formats.
Convert(datetime, Convert(char(10), MYDATETIMEFIELD, 103) + ' ' + Convert(char(8), MYTIMEFIELD, 108), 103)

Convert both field into DATETIME :
SELECT CAST(#DateField as DATETIME) + CAST(#TimeField AS DATETIME)
and if you're using Getdate() use this first:
DECLARE #FechaActual DATETIME = CONVERT(DATE, GETDATE());
SELECT CAST(#FechaActual as DATETIME) + CAST(#HoraInicioTurno AS DATETIME)

I had many errors as stated above so I did it like this
try_parse(concat(convert(date,Arrival_date),' ',arrival_time) as datetime) AS ArrivalDateTime
It worked for me.

Finding this works for two dates where you want time from one and date from the other:
declare #Time as datetime = '2021-11-19 12:34'
declare #Date as datetime = '2021-10-10'
SELECT #time + datediff(day, #Time, #Date)

DECLARE #Dates table ([Date] datetime);
DECLARE #Times table ([Time] datetime);
INSERT INTO #Dates VALUES('2009-03-12 00:00:00.000');
INSERT INTO #Dates VALUES('2009-03-26 00:00:00.000');
INSERT INTO #Dates VALUES('2009-03-30 00:00:00.000');
INSERT INTO #Times VALUES('1899-12-30 12:30:00.000');
INSERT INTO #Times VALUES('1899-12-30 10:00:00.000');
INSERT INTO #Times VALUES('1899-12-30 10:00:00.000');
WITH Dates (ID, [Date])
AS (
SELECT ROW_NUMBER() OVER (ORDER BY [Date]), [Date] FROM #Dates
), Times (ID, [Time])
AS (
SELECT ROW_NUMBER() OVER (ORDER BY [Time]), [Time] FROM #Times
)
SELECT Dates.[Date] + Times.[Time] FROM Dates
JOIN Times ON Times.ID = Dates.ID
Prints:
2009-03-12 10:00:00.000
2009-03-26 10:00:00.000
2009-03-30 12:30:00.000

To combine date from a datetime column and time from another datetime column this is the best fastest solution for you:
select cast(cast(DateColumn as date) as datetime) + cast(TimeColumn as datetime) from YourTable

SELECT CAST(CAST(#DateField As Date) As DateTime) + CAST(CAST(#TimeField As Time) As DateTime)

Another way is to use CONCATand CAST, be aware, that you need to use DATETIME2(x) to make it work. You can set x to anything between 0-7 7 meaning no precision loss.
DECLARE #date date = '2018-03-12'
DECLARE #time time = '07:00:00.0000000'
SELECT CAST(CONCAT(#date, ' ', #time) AS DATETIME2(7))
Returns 2018-03-12 07:00:00.0000000
Tested on SQL Server 14

simply concatenate both , but cast them first as below
select cast(concat(Cast(DateField as varchar), ' ', Cast(TimeField as varchar)) as datetime) as DateWithTime from TableName;

select s.SalesID from SalesTbl s
where cast(cast(s.SaleDate as date) as datetime) + cast(cast(s.SaleCreatedDate as time) as datetime) between #FromDate and #ToDate

The existing answers do not address the datetime2 datatype so I will add mine:
Assuming that you want to add a time value to a datetime2 value where:
The datetime2 value could contain non-zero time component and/or fractional seconds
The time value could contain the value 23:59:59.9999999 which is 86,399.9999999 seconds, 86,399,999,999.9 microseconds or 86,399,999,999,900 nanoseconds¹
Due to the limitations of dateadd function¹ you must add them in two steps:
Convert the time value to seconds and use dateadd(second, ...)
Extract the nanoseconds from the time value and use dateadd(nanosecond, ...) to add them to the date calculated above
declare #dv datetime2 = '2000-01-01 12:34:56.7890123';
declare #tv time = '23:59:59.9999999';
select dateadd(
nanosecond,
datepart(nanosecond, #tv),
dateadd(
second,
datepart(hour, #tv) * 60 * 60 + datepart(minute, #tv) * 60 + datepart(second, #tv),
#dv
)
);
-- 2000-01-02 12:34:56.7890122
¹ Nanosecond values might not fit in int datatype which dateadd function expects.

SELECT CAST(your_date_column AS date) + CAST(your_time_column AS datetime) FROM your_table
Works like a charm

I ran into similar situation where I had to merge Date and Time fields to DateTime field. None of the above mentioned solution work, specially adding two fields as the data type for addition of these 2 fields is not same.
I created below solution, where I added hour and then minute part to the date. This worked beautifully for me. Please check it out and do let me know if you get into any issues.
;with tbl
as
(
select StatusTime = '12/30/1899 5:17:00 PM', StatusDate = '7/24/2019 12:00:00 AM'
)
select DATEADD(MI, DATEPART(MINUTE,CAST(tbl.StatusTime AS TIME)),DATEADD(HH, DATEPART(HOUR,CAST(tbl.StatusTime AS TIME)), CAST(tbl.StatusDate as DATETIME)))
from tbl
Result: 2019-07-24 17:17:00.000