I have two columns in two different tables.
First column is number like 0493484402 and second column is audit_detail like 'addr_mastersubscription has changed from 32488141893 to 32488141973'.
Audit detail column may have different type of string other than above. I have to check only in above type mentioned strings
I have to check whether first column value is present or not in second column at position of Second number.
If the number is not present I need that number as output
I am using oracel SQL developer
Second column datatype is clob and there is not comman filed in both table's
First column data type is varchar
Use REGEXP_LIKE:
SELECT *
FROM yourTable
WHERE REGEXP_LIKE (col2, ' to ' || col1 || '$');
You need to check the two conditions then you can use REGEXP_SUBSTR and REGEXP_LIKE as follows:
SELECT * FROM YOUR_TABLE
WHERE REGEXP_LIKE(SECOND_COLUMN, '^addr_mastersubscription has changed from [0-9]+ to [0-9]+$')
AND TO_NUMBER(FIRST_COLUMN) = TO_NUMBER(REGEXP_SUBSTR(SECOND_COLUMN,'[0-9]+$'))
This is how I understood the question.
Sample data (lines #1 - 9) contain additional ID column (unless you're planning to do cross join between those two tables) which is used to join taba and tabb.
regexp_substr looks for the second number in tabb's col column, which is compared to taba.col. I displayed whether it exists there or not; you can display whatever you want.
Query you might need begins at line #11.
SQL> with
2 taba (id, col) as
3 (select 1, '0493484402' from dual union all
4 select 2, '012345' from dual
5 ),
6 tabb (id, col) as
7 (select 1, 'addr_mastersubscription has changed from 32488141893 to 32488141973' from dual union all
8 select 2, 'nothing changed from 098776 to 012345' from dual
9 )
10 --
11 select a.id,
12 case when a.col = regexp_substr(b.col, '\d+', 1, 2) then a.col || ' exists in tabb'
13 else a.col || ' does not exist in tabb'
14 end result
15 from taba a join tabb b on a.id = b.id;
ID RESULT
---------- ---------------------------------
1 0493484402 does not exist in tabb
2 012345 exists in tabb
SQL>
You can use INSTR(), names itself defines in string where we can check if a particular string is available in the respective column.
Please use below query,
select t1.* from table1 t1
inner join table2 t2
on (instr(t1.first_column, t2.second_column) = 0);
instr(t1.first_column, t2.second_column) = 0 This condition provides you unmatching columns
instr(t1.first_column, t2.second_column) > 0 This condition provides you matching strings
Related
I'm trying to identify reference numbers contained in strings in a column. The table looks something like this:
col1 col2
1 fgREF1234fhjdREF1235hgkjREF1236
2 hREF1237hjdfREF1238djhfhs
Need to write an SQL query that identifies the 'REF' followed by the 4 digits and returns each in its own row.
The output should look like this:
col1 ref
1 REF1234
1 REF1235
1 REF1236
2 REF1237
2 REF1238
I have tried:
select
case when substr(substr(col2, instr(col2, 'REF'), 7), 1, 1) like 'R'
then substr(col2, instr(col2, 'R'), 7) else null end ref
from table
...but this will only identify the first match in the string.
I am using Oracle SQL but ideally the solution would be able to be converted to other SQL variants.
Any help would be much appreciated!
You can use regexp_substr delimited by connect by level <= regexp_count(col2,'REF') ( the appearance time of the pattern string REF within the strings col2 )
with t(col1,col2) as
(
select 1,'fgREF1234fhjdREF1235hgkjREF1236' from dual union all
select 2,'hREF1237hjdfREF1238djhfhs' from dual
)
select col1,
regexp_substr(col2,'REF[0-9]+',1,level) as ref
from t
connect by level <= regexp_count(col2,'REF')
and prior col1 = col1
and prior sys_guid() is not null;
Demo
You can use the below code to get the desired result :-
select x.col1, explode(x.ref) as ref from (
select col1,split(trim(regexp_replace(col2,'[^REF0-9]',' ')),' ') as ref
from inp
Is there a concept (with an implementation - in Oracle SQL for starters) which behaves like a 'universal' matcher ?
What I mean is; I know NULL is not equal to anything - including NULL.
Which is why you have to be careful to 'IS NULL' rather than '=NULL' in SQL expressions.
I also know it is useful to use the NVL (in Oracle) function to detect a NULL and replace it with something in the output.
However: what you replace the NULL with using NVL has to match the datatype of the underlying column; otherwise you'll (rightly) get an error.
An example:
I have a table with a NULLABLE column 'name' of type VARCHAR2; and this contains a NULL row.
I can fetch out the NULL and replace it with an NVL like this:
SELECT NVL(name, 'NullyMcNullFace’) from my_table;
Great.
But if the column happens to a NUMBER (say 'age'), then I have to change my NVL:
SELECT NVL(age, 32) from my_table;
Also great.
Now if the column happens to be a DATE (say 'somedate'), then I have to change my NVL again:
SELECT NVL(somedate, sysdate) from my_table;
What I'm getting at here : is that in order to deal with NULLs you have to replace with a specific something ; and that specific something has to 'fit' the data-type.
So is there a construct/concept of (for want of a better word) like 'ANY' here.
Where 'ANY' would fit into a column of any datatype (like NULL), but (unlike NULL and unlike all other specific values) would match ANYTHING (including NULL - ? probably urghhh dunno).
So that I could do:
SELECT NVL(whatever_column, ANY) from my_table;
I think the answer is probably no; and probably 'go away, NULLs are bad enough - never mind this monster you have half-thought of'.
No, there's no "universal acceptor" value in SQL that is equal to everything.
What you can do is raise the NVL into your comparison. Like if you're trying to do a JOIN:
SELECT ...
FROM my_table AS m
JOIN other_table AS o ON o.name = NVL(m.name, o.name)
So if m.name is NULL, then the join will compare o.name to o.name, which is of course always true.
For other uses of NULL, you might have to use another technique that suits the situation.
Adressing the question in the comment on Bill Karwin's answer:
I want to output a 1 if the NEW and OLD value differ and a 0 if they are the same. But (for my purposes) I want to also return 0 for two NULLS.
select
Case When (:New = :Old) or
(:New is NULL and :Old is NULL) then 0
Else
1
End
from dual
In a WHERE CLAUSE you can put a condition like this,
WHERE column1 LIKE NVL(any_column_or_param, '%')
Perhaps DECODE() would suit your purpose here?
WITH t1 AS (SELECT 1 ID, NULL val FROM dual UNION ALL
SELECT 2 ID, NULL val FROM dual UNION ALL
SELECT 3 ID, 1 val FROM dual UNION ALL
SELECT 4 ID, 2 val FROM dual UNION ALL
SELECT 5 ID, 5 val FROM dual),
t2 AS (SELECT 1 ID, NULL val FROM dual UNION ALL
SELECT 2 ID, 3 val FROM dual UNION ALL
SELECT 3 ID, 1 val FROM dual UNION ALL
SELECT 4 ID, 4 val FROM dual UNION ALL
SELECT 6 ID, 5 val FROM dual)
SELECT t1.id t1_id,
t1.val t1_val,
t2.id t2_id,
t2.val t2_val,
DECODE(t1.val, t2.val, 0, 1) different_vals
FROM t1
FULL OUTER JOIN t2 ON t1.id = t2.id
ORDER BY COALESCE(t1.id, t2.id);
T1_ID T1_VAL T2_ID T2_VAL DIFFERENT_VALS
---------- ---------- ---------- ---------- --------------
1 1 0
2 2 3 1
3 1 3 1 0
4 2 4 4 1
5 5 1
6 5 1
I want the server to give me the results of a query in the order I send it.
So if I write:
SELECT * FROM table WHERE column in (9,1,8)
I would like it to give me the results in the order: 9,1,8
One method uses left join:
select t.*
from (select 9 as c, 1 as priority union all select 1, 2 union all select 8, 3
) vals left join
table t
on t.column = vals.c
order by vals.priority;
Note: This is generic syntax. The specific syntax for the subquery may differ depending on the database.
Another method uses case in the order by:
select t.*
from table t
where t.column in (9, 1, 8)
order by (case column when 9 then 1 when 1 then 2 when 8 then 3 end);
Once again, this can be simplified in some databases, say by using special functions.
You could use CASE expression in order you want, something like:
select *
from table_name
where column_name in (9,1,8)
order by case column_name
when 9 then 1
when 1 then 2
when 8 then 3 end
, column_name -- optional, but here could go another column if you want to have custom order
You can do in Oracle SQL if you have
SELECT Column_name
FROM user_tab_columns
where table_name = 'MY_TABLE'
and Column_id in (9,1,8)
SELECT *
FROM table
WHERE column IN (9, 1, 8)
ORDER BY CASE WHEN column = 9 THEN 1
WHEN column = 1 THEN 2
WHEN column = 8 THEN 3
END
I have an issue where in my data I will have a record returned where a column value will look like
-- query
Select col1 from myTable where id = 23
-- result of col1
111, 104, 34, 45
I want to feed these values to an in clause. So far I have tried:
-- Query 2 -- try 1
Select * from mytableTwo
where myfield in (
SELECT col1
from myTable where id = 23)
-- Query 2 -- try 2
Select * from mytableTwo
where myfield in (
SELECT '''' +
Replace(col1, ',', ''',''') + ''''
from myTable where id = 23)
-- query 2 test -- This works and will return data, so I verify here that data exists
Select * from mytableTwo
where myfield in ('111', '104', '34', '45')
Why aren't query 2 try 1 or 2 working?
You don't want an in clause. You want to use like:
select *
from myTableTwo t2
where exists (select 1
from myTable t
where id = 23 and
', '+t.col1+', ' like '%, '+t2.myfield+', %'
);
This uses like for the comparison in the list. It uses a subquery for the value. You could also phrase this as a join by doing:
select t2.*
from myTableTwo t2 join
myTable t
on t.id = 23 and
', '+t.col1+', ' like '%, '+t2.myfield+', %';
However, this could multiply the number of rows in the output if there is more than one row with id = 23 in myTable.
If you observe closely, Query 2 -- try 1 & Query 2 -- try 2 are considered as single value.
like this :
WHERE myfield in ('111, 104, 34, 45')
which is not same as :
WHERE myfield in ('111', '104', '34', '45')
So, If you intend to filter myTable rows from MyTableTwo, you need to extract the values of fields column data to a table variable/table valued function and filter the data.
I have created a table valued function which takes comma seperated string and returns a table value.
you can refer here T-SQL : Comma separated values to table
Final code to filter the data :
DECLARE #filteredIds VARCHAR(100)
-- Get the filter data
SELECT #filteredIds = col1
FROM myTable WHERE id = 23
-- TODO : Get the script for [dbo].[GetDelimitedStringToTable]
-- from the given link and execute before this
SELECT *
FROM mytableTwo T
CROSS APPLY [dbo].[GetDelimitedStringToTable] ( #filteredIds, ',') F
WHERE T.myfield = F.Value
Please let me know If this helps you!
I suppose col is a character type, whose result would be like like '111, 104, 34, 45'. If this is your situation, it's not the best of the world (denormalized database), but you can still relate these tables by using character operators like LIKE or CHARINDEX. The only gotcha is to convert the numeric column to character -- the default conversion between character and numeric is numeric and it will cause a conversion error.
Since #Gordon, responded using LIKE, I present a solution using CHARINDEX:
SELECT *
FROM mytableTwo tb2
WHERE EXISTS (
SELECT 'x'
FROM myTable tb1
WHERE tb1.id = 23
AND CHARINDEX(CONVERT(VARCHAR(20), tb2.myfield), tb1.col1) > 0
)
I have two similar tables in oracle in two different databases.
For example : my table name is EMPLOYEE and primary key is employee id. The same table with same columns(say 50 columns are is avlbl in two databases and two databases are linked.
I want to compare these two tables column by column and find out which records are not matching. i want the specific column in each row in two tables that are not matching.
select *
from
(
( select * from TableInSchema1
minus
select * from TableInSchema2)
union all
( select * from TableInSchema2
minus
select * from TableInSchema1)
)
should do the trick if you want to solve this with a query
As an alternative which saves from full scanning each table twice and also gives you an easy way to tell which table had more rows with a combination of values than the other:
SELECT col1
, col2
-- (include all columns that you want to compare)
, COUNT(src1) CNT1
, COUNT(src2) CNT2
FROM (SELECT a.col1
, a.col2
-- (include all columns that you want to compare)
, 1 src1
, TO_NUMBER(NULL) src2
FROM tab_a a
UNION ALL
SELECT b.col1
, b.col2
-- (include all columns that you want to compare)
, TO_NUMBER(NULL) src1
, 2 src2
FROM tab_b b
)
GROUP BY col1
, col2
HAVING COUNT(src1) <> COUNT(src2) -- only show the combinations that don't match
Credit goes here: http://asktom.oracle.com/pls/apex/f?p=100:11:0::::P11_QUESTION_ID:1417403971710
It won't be fast, and there will be a lot for you to type (unless you generate the SQL from user_tab_columns), but here is what I use when I need to compare two tables row-by-row and column-by-column.
The query will return all rows that
Exists in table1 but not in table2
Exists in table2 but not in table1
Exists in both tables, but have at least one column with a different value
(common identical rows will be excluded).
"PK" is the column(s) that make up your primary key.
"a" will contain A if the present row exists in table1.
"b" will contain B if the present row exists in table2.
select pk
,decode(a.rowid, null, null, 'A') as a
,decode(b.rowid, null, null, 'B') as b
,a.col1, b.col1
,a.col2, b.col2
,a.col3, b.col3
,...
from table1 a
full outer
join table2 b using(pk)
where decode(a.col1, b.col1, 1, 0) = 0
or decode(a.col2, b.col2, 1, 0) = 0
or decode(a.col3, b.col3, 1, 0) = 0
or ...;
Edit
Added example code to show the difference described in comment.
Whenever one of the values contains NULL, the result will be different.
with a as(
select 0 as col1 from dual union all
select 1 as col1 from dual union all
select null as col1 from dual
)
,b as(
select 1 as col1 from dual union all
select 2 as col1 from dual union all
select null as col1 from dual
)
select a.col1
,b.col1
,decode(a.col1, b.col1, 'Same', 'Different') as approach_1
,case when a.col1 <> b.col1 then 'Different' else 'Same' end as approach_2
from a,b
order
by a.col1
,b.col1;
col1 col1_1 approach_1 approach_2
==== ====== ========== ==========
0 1 Different Different
0 2 Different Different
0 null Different Same <---
1 1 Same Same
1 2 Different Different
1 null Different Same <---
null 1 Different Same <---
null 2 Different Same <---
null null Same Same
Try to use 3rd party tool, such as SQL Data Examiner which compares Oracle databases and shows you differences.
Using the minus operator was working but also it was taking more time to execute which was not acceptable.
I have a similar kind of requirement for data migration and I used the NOT IN operator for that.
The modified query is :
select *
from A
where (emp_id,emp_name) not in
(select emp_id,emp_name from B)
union all
select * from B
where (emp_id,emp_name) not in
(select emp_id,emp_name from A);
This query executed fast. Also you can add any number of columns in the select query.
Only catch is that both tables should have the exact same table structure for this to be executed.
SELECT *
FROM (SELECT table_name, COUNT (*) cnt
FROM all_tab_columns
WHERE owner IN ('OWNER_A')
GROUP BY table_name) x,
(SELECT table_name, COUNT (*) cnt
FROM all_tab_columns
WHERE owner IN ('OWNER_B')
GROUP BY table_name) y
WHERE x.table_name = y.table_name AND x.cnt <> y.cnt;
Used full outer join -- But it will not show - if its not matched -
SQL> desc aaa - its a table
Name Null? Type
A1 NUMBER
B1 VARCHAR2(10)
SQL> desc aaav -its a view
Name Null? Type
A1 NUMBER
B1 VARCHAR2(10)
SQL> select a.column_name,b.column_name from dba_tab_columns a full outer join dba_tab_columns b on a.column_name=b.column_name where a.TABLE_NAME='AAA' and B.table_name='AAAV';
COLUMN_NAME COLUMN_NAME
A1 A1
B1 B1