I have a Searches table for pets. I want to see the percentage of search per Animal-name.
My query is:
Select AVG(a.search_count) OVER (ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT
ROW)*100 AS Precentage
from (select [Animal-Name], count (*) as search_count
from dbo.Searches
group by [Animal-Name]
) as a
What I get from the second select (inside the from):
so what I need now is the percentage of search_count result for each animal-name.
any idea what is wrong with my query?
I think you want a simple ratio:
select [Animal-Name], count(*) as search_count,
count(*) * 1.0 / sum(count(*)) over () as ratio
from dbo.Searches
group by [Animal-Name];
The * 1.0 is because the code looks like SQL Server and SQL Server does integer arithmetic -- so 1 / 2 is 0 rather than 0.5.
Related
I am working on some car accident data and am stuck on how to get the data in the form I want.
select
sex_of_driver,
accident_severity,
count(accident_severity) over (partition by sex_of_driver, accident_severity)
from
SQL.dbo.accident as accident
inner join SQL.dbo.vehicle as vehicle on
accident.accident_index = vehicle.accident_index
This is my code, which counts the accidents had per each sex for each severity. I know I can do this with group by but I wanted to use a partition by in order to work out % too.
However I get a very large table (I assume for each row that is each sex/severity. When I do the following:
select
sex_of_driver,
accident_severity,
count(accident_severity) over (partition by sex_of_driver, accident_severity)
from
SQL.dbo.accident as accident
inner join SQL.dbo.vehicle as vehicle on
accident.accident_index = vehicle.accident_index
group by
sex_of_driver,
accident_severity
I get this:
sex_of_driver
accident_severity
(No column name)
1
1
1
1
2
1
-1
2
1
-1
1
1
1
3
1
I won't give you the whole table, but basically, the group by has caused the count to just be 1.
I can't figure out why group by isn't working. Is this an MS SQL-Server thing?
I want to get the same result as below (obv without the CASE etc)
select
accident.accident_severity,
count(accident.accident_severity) as num_accidents,
vehicle.sex_of_driver,
CASE vehicle.sex_of_driver WHEN '1' THEN 'Male' WHEN '2' THEN 'Female' end as sex_col,
CASE accident.accident_severity WHEN '1' THEN 'Fatal' WHEN '2' THEN 'Serious' WHEN '3' THEN 'Slight' end as serious_col
from
SQL.dbo.accident as accident
inner join SQL.dbo.vehicle as vehicle on
accident.accident_index = vehicle.accident_index
where
sex_of_driver != 3
and
sex_of_driver != -1
group by
accident.accident_severity,
vehicle.sex_of_driver
order by
accident.accident_severity
You seem to have a misunderstanding here.
GROUP BY will reduce your rows to a single row per grouping (ie per pair of sex_of_driver, accident_severity values. Any normal aggregates you use with this, such as COUNT(*), will return the aggregate value within that group.
Whereas OVER gives you a windowed aggregated, and means you are calculating it after reducing your rows. Therefore when you write count(accident_severity) over (partition by sex_of_driver, accident_severity) the aggregate only receives a single row in each partition, because the rows have already been reduced.
You say "I know I can do this with group by but I wanted to use a partition by in order to work out % too." but you are misunderstanding how to do that. You don't need PARTITION BY to work out percentage. All you need to calculate a percentage over the whole resultset is COUNT(*) * 1.0 / SUM(COUNT(*)) OVER (), in other words a windowed aggregate over a normal aggregate.
Note also that count(accident_severity) does not give you the number of distinct accident_severity values, it gives you the number of non-null values, which is probably not what you intend. You also have a very strange join predicate, you probably want something like a.vehicle_id = v.vehicle_id
So you want something like this:
select
sex_of_driver,
accident_severity,
count(*) as Count,
count(*) * 1.0 /
sum(count(*)) over (partition by sex_of_driver) as PercentOfSex
count(*) * 1.0 /
sum(count(*)) over () as PercentOfTotal
from
dbo.accident as accident a
inner join dbo.vehicle as v on
a.vehicle_id = v.vehicle_id
group by
sex_of_driver,
accident_severity;
How to calculate metrics between two tables? In addition, I noticed that when using FROM tbl1, tbl2, there are noises, the WHERE filters did not work, a total count(*) was returned
Query:
select
count(*) filter(WHERE tb_get_gap.system in ('LINUX','UNIX')) as gaps,
SUM(CAST(srvs AS INT)) filter(WHERE tb_getcountsrvs.type = 'LZ') as total,
100 - (( gaps / total ) * 100)
FROM tb_get_gap, tb_getcountsrvs
Error:
SQL Error [42703]: ERROR: column "gaps" does not exist
I need to count in the tb_get_gap table by fields = ('LINUX', 'UNIX'), then a SUM ()in thesrvs field in the
tb_getcountsrvs table by fields = 'LZ' in type, right after
making this formula 100 - ((gaps / total) * 100)
It would seem that you cannot define gaps and also use it in the same query. In SQL Server you would have to use the logic twice. Maybe a subquery would work better.
select 100 - (t.gaps / t.total) * 100)
from
(
select
count(*) filter(WHERE tb_get_gap.system in ('LINUX','UNIX')) as gaps,
SUM(CAST(srvs AS INT)) filter(WHERE tb_getcountsrvs.type = 'LZ') as total
FROM tb_get_gap, tb_getcountsrvs
) t
I have a table of names, where each row has the columns name, and occurrences.
I'd like to calculate the percentage of a certain name from the table.
How can I do that in one query?
You can get it by using SUM(occurrences):
select
name,
100.0 * sum(occurrences) / (select sum(occurrences) from users) as percentage
from
users
where name = 'Bob'
Try this:
SELECT name, cast(sum(occurance) as float) /
(select sum(occurance) from test) * 100 percentage FROM test
where name like '%dog%'
Demo here
It is not very elegant due to the subquery in the field list but this will do the job if you want it in one query:
SELECT
`name`,
(CAST(SUM(`occurance`) AS DOUBLE)/CAST((SELECT SUM(`occurance`) FROM `user`) AS DOUBLE)) as `percent`
FROM
`user`
WHERE
`name`='miroslav';
Example Fiddle
Hope this helps,
I think conditional aggregation is the best approach:
select sum(case when name = #name then occurrences else 0 end) / sum(occurrences) as ratio
from t;
If you want an actual percentage between 0 and 100 multiply by 100.
I have one table and I want to calculate the percentage of one column
I tried to do so in two ways.
but I am actually face with error.
The error is 'syntax error at or near "select"'
This is my code in below:
WITH total AS
(
select krs_name,count(fclass) as cluster
FROM residentioal
GROUP BY krs_name
)
SELECT total.cluster,
total.krs_name
(select count(fclass)
FROM residentioal
where fclass='village'
or fclass='hamlet'
or fclass='suburb'
or fclass='island'
AND krs_name = total.krs_name
)::float / count(fclass) * 100 as percentageofonline
FROM residentioal, total
WHERE residentioal.krs_name = total.krs_name
GROUP BY total.krs_name total.krs_name
My table has 5437 rows in which there is 8 group of krs_name and in the other column namely fclass, there is 6 group. Therefore I want to calculate the percentage of 4 groups from fclass for each krs_name . thus, i have to first query the count(fclass) group by krs_name and then query the count of fclass where fclass is equal to my condition group by krs_name and finally count(fclass) "with condition" / count(fclass) "total fclass" * 100 goup by krs_name?
I'm using Postgresql 9.1.
The problem is in this line:
SELECT total.cluster, total.krs_name (
The open paren makes no sense.
But, this seems to do what you want and it is much simpler:
SELECT r.krs_name, COUNT(*) as total,
AVG( (fclass in ('village', 'hamlet', 'suburb', 'island'))::int ) * 100 as percentageofonline
FROM residentioal r
GROUP BY r.krs_name
I have a postgresql query like this:
with r as (
select
1 as reason_type_id,
rarreason as reason_id,
count(*) over() count_all
from
workorderlines
where
rarreason != 0
and finalinsdate >= '2012-12-01'
)
select
r.reason_id,
rt.desc,
count(r.reason_id) as num,
round((count(r.reason_id)::float / (select count(*) as total from r) * 100.0)::numeric, 2) as pct
from r
left outer join
rtreasons as rt
on
r.reason_id = rt.rtreason
and r.reason_type_id = rt.rtreasontype
group by
r.reason_id,
rt.desc
order by r.reason_id asc
This returns a table of results with 4 columns: the reason id, the description associated with that reason id, the number of entries having that reason id, and the percent of the total that number represents.
This table looks like this:
What I would like to do is only display the top 10 results based off the total number of entries having a reason id. However, whatever is leftover, I would like to compile into another row with a description called "Other". How would I do this?
with r2 as (
...everything before the select list...
dense_rank() over(order by pct) cause_rank
...the rest of your query...
)
select * from r2 where cause_rank < 11
union
select
NULL as reason_id,
'Other' as desc,
sum(r2.num) over() as num,
sum(r2.pct) over() as pct,
11 as cause_rank
from r2
where cause_rank >= 11
As said above Limit and for the skipping and getting the rest use offset... Try This Site
Not sure about Postgre but SELECT TOP 10... should do the trick if you sort correctly
However about the second part: You might use a Right Join for this. Join the TOP 10 Result with the whole table data and use only the records not appearing on the left side. If you calculate the sum of those you should get your "Sum of the rest" result.
I assume that vw_my_top_10 is the view showing you the top 10 records. vw_all_records shows all records (including the top 10).
Like this:
SELECT SUM(a_field)
FROM vw_my_top_10
RIGHT JOIN vw_all_records
ON (vw_my_top_10.Key = vw_all_records.Key)
WHERE vw_my_top_10.Key IS NULL