USERS
ID TIMEMODIFIED
1 1400481271
2 1400481489
3 1400486453
4 1400486525
5 1401777484
I have timemodified field, From timemodified, I need to get the rows of last 4 weeks by taking from today's date.
SELECT id FROM USERS
WHERE FROM_UNIXTIME(timemodified,'%d-%m-%Y') >= curdate()
AND FROM_UNIXTIME(timemodified,'%d-%m-%Y') < curdate()-1
Your times are already in Unix timestamp format. Bear in mind that it'll be far more efficient to compare [TIMEMODIFIED] against the current date converted to a Unix timestamp. In addition, you don't need to check any upper bound unless [TIMEMODIFIED] can be in the future.
Try:
-- 60x60x24x7x4 = 2419200 seconds in four weeks
SET #unix_four_weeks_ago = UNIX_TIMESTAMP(curdate()) - 2419200;
SELECT id FROM USERS
WHERE timemodified >= #unix_four_weeks_ago;
NB. Four weeks ago (i.e. today – 28 days) was 1,437,696,000 (24th July) at the time of this answer. The latest record in the sample you provided has a timestamp going back to the 3rd June 2014, and so none of these records will be returned by the query.
Related
I apologize, I am new at SQL. I am using BigQuery. I have a field called "last_engaged_date", this field is a datetime value (2021-12-12 00:00:00 UTC). I am trying to perform a count on the number of records that were "engaged" 12 months ago, 18 months ago, and 24 months ago based on this field. At first, to make it simple for myself, I was just trying to get a count of the number of records per year, something like:
Select count(id), year(last_engaged_date) as last_engaged_year
from xyz
group by last_engaged_year
order by last_engaged_year asc
I know that there are a lot of things wrong with this query but primarily, BQ says that "Year" is not a valid function? Either way, What I really need is something like:
Date() - last_engaged_date = int(# of months)
count if <= 12 months as "12_months_count" (# of records where now - last engaged date is less than or equal to 12 months)
count if <= 18 months as "18_months_count"
count if <= 24 months as "24_months_count"
So that I have a count of how many records for each last_engaged_date period there are.
I hope this makes sense. Thank you so much for any ideas
[How to] Return the number of months between now and datetime value [in BigQuery] SQL
The simples way is just to use DATE_DIFF function as in below example
date_diff(current_date(), date(last_engaged_date), month)
Need help to get the data of particular format
We have a table which have a data which of production now we need to select the data of each day with particular time period which is differentiate between three shift A,B,C.
In our table we have a datetime column which capture's each seconds data now that data we need in shiftwise like 6am to 2pm is of A shift production count and 2pm to 10pm of shift B and 10pm to 6 am of shift C.
here i am getting the data for single day where i have written the below query which is working good.
select distinct(count(PRD_SERIAL_NUMBER)),(select convert(date,getdate())) as date,'B' as shift_name
from table_name
where status=02
and LAST_UPDATED_DATE
between (SELECT FORMAT(GETDATE(),'yyyy-MM-dd 14:01:00.000')) and
(SELECT FORMAT(GETDATE()-26,'yyyy-MM-dd 22:01:00.000'))
refer below output image 1
Here i am getting the count for single day and for upcoming days i have solution but now the question arise is i have a past 4 Month data which i need to get in datewise and shiftwise count and for the column prd_serial_number have duplicate entries so it should be in distinct.
please refer below image 2 for required output format
So in my query, I simply need to narrow down the results by whoever's status was last updated 3 weeks ago.
The line:
AND DATE_ADD(user_status_updated, INTERVAL - 21 DAY)
returns the results as an interval from now and 21 days from now. I am only interested in the exact date 21 days ago, but cannot find the right function to use.
I am writing automatic emails and part of this project is to check daily for users that have been inactive for 3 weeks, so it will always be a matter of NOW() minus 21 days. But I don't want the interval, I want the exact 21 days ago since last updated results.
Ok I found my solution.
WHERE user_status_updated= DATE_SUB(DATE(NOW()), INTERVAL 21 DAY)
The user_status_updated is a DATETIME field
Have table: item (int) and timestamp (datetime).
Need to know if there are any records with timestamp after last 6 AM.
Example:
At 5 AM it should check if there are any records from after 6 AM
yesterday. AT 7 AM it should check if there are any records from
after 6 AM today
This could be done of course by making a variable with datepart as:
if time now is < 6 AM datepart should be yesterday if time now
is >= 6 AM datepart should be today
but there must be a simpler way ?
This expression should always return the most recent 06:00 in the past:
select DATEADD(hour,
(DATEDIFF(hour,'2014-01-01T06:00:00',CURRENT_TIMESTAMP)/24)*24,
'2014-01-01T06:00:00')
It works by asking how many hours have happened since some arbitrary, known, 6AM. We then round this number down to the closest multiple of 24 (by dividing and multiplying with integer maths), and add this number back onto the same, arbitrary, 6AM
I want to perform an operation in crystal report.
I have a db table contains a date column.
I want to filter and get the rows having data created in last week(last sunday to last saturday = 7 days).For example if today is 24th August Wednesday, then I need data from 14th August(Sunday) to 20th August(Saturday).
Basically I want to find 2 dates and filter the date column.
Date1 = Date(CurrentDate)-Day(7 + WeekDayinNum(CurrentDate)) ; (Ex:for my example it will be 10)
Date2 = Date(CurrentDate)-Day(WeekDayinNum(CurrentDate))
I do not know the Date APIs properly,can anybody help me in this.
This is a common enough date range that CR provides it for you. In your record selection formula, you can just add {table.date} in LastFullWeek
From CR, "LastFullWeek specifies a range of Date values that includes all dates from Sunday to Saturday of the previous week."
Add this to the record selection formula:
{table.date_field} IN Last7Days
If today is Sunday(1) you want rows that are between 7 and 1 days old,
If today is Monday(2) you want rows that are between 8 and 2 days old,
If today is Tuesday(3) you want rows that are between 9 and 3 days old,
etc.
SELECT *
FROM `tablename`
WHERE `somedatefield` >= DATE_SUB(NOW(),INTERVAL (DAYOFWEEK(NOW()) + 6) DAY)
AND `somedatefield` <= DATE_SUB(NOW(),INTERVAL (DAYOFWEEK(NOW())) DAY)