Suppose there is one date in int format 20191229, I want to find end of month and check if it's end of month is of 31 days or 30 days in SQL Server
You can try this from the reference. The given answer will not work for the integer data type but it will work in the varchar datatype date value. Storing Date values in integer is not a good idea, so as suggested by Larnu change the data type in either date or varchar.
SELECT
Day(EOMONTH(Cast('20191229' as Date))) end_of_month;
If you want the amount of days within a month, as you need the days as an integer, you should go for this. This is the most robust built, but also the more complex one, as to make sure the Integer value is processed correctly:
SELECT DATEPART(DAY,EOMONTH(CAST(CAST('20191229' AS NCHAR(8)) AS DATE))) AS Days
Result:
Days
31
If you want to add an IF evaluation to your selected date(s), you can do this by add an IIF-clause where it evaluates whether or not the end of month is 31 or not. If you want to use a columnname instead of the date, just substitute #Date with the columnname. I've just added the variable #Date instead of '20191229' to make it more illustrative/understandable. You can change the True/false descriptions to whatever you like in the query.
DECLARE #Date AS int
SET #Date = '20191229'
SELECT
IIF (
DATEPART(DAY,EOMONTH(CAST(CAST(#Date AS NCHAR(8)) AS DATE))) = '31'
,'True'
,'False'
) AS Days
Output:
Days
True
Related
I am tring to add a year to a date if it is not before today. So in the statement below I would like to display 4/20/2018
declare #StartDate datetime
set #StartDate='4/20/2015'
select case when dateadd(year,1,#StartDate)> GETDATE() then
dateadd(year,1,#StartDate) else dATEADD(year,1,(datepart(year,GETDATE()))) end
I've changed the else clause so it works out the difference between the start date and today's date +1 to alter make '4/20/2015' become '4/20/2018'
declare #StartDate date
set #StartDate='4/20/2015'
select
case
when dateadd(year,1,#StartDate)> GETDATE() then dateadd(year,1,#StartDate)
else DATEADD(year,(datepart(year,GETDATE())+1-datepart(year,#StartDate)),#StartDate)
end
Also if you are not using the time part of a datetime data type it's best practice to use date instead as it only requires 3 bytes of storage rather than 8 for datetime.
More on date here: https://learn.microsoft.com/en-us/sql/t-sql/data-types/date-transact-sql
And a cheatsheet of sql data types here: https://sqlserverrider.files.wordpress.com/2013/04/pic116.png
Actually I have different date in SQL table when I pull those via SQL query, day of datetime field should have fixed day.
Example: (DD-MM-YYYY) day should be "7" > (7-MM-YYYY)
10-08-2007 > 07-08-2007
27-12-2013 > 07-12-2013
01-03-2017 > 07-03-2017
Can someone help me on this. Thanks in Advance.
Find the difference between 7 and the day of the original date and add that to the original date:
SELECT DATEADD(DAY, 7 - DAY(OriginalDate), OriginalDate)
Use DATEPART to take out the month and year parts. Cast those into varchar and concatenate with 07.
Query
select '07-' +
cast(DATEPART(mm, [date_column]) as varchar(2)) + '-' +
cast(DATEPART(yyyy, [date_column]) as varchar(4))
from your_table_name;
Assuming You might have to change the day number example
DECLARE #dayNum char(2)
SELECT #dayNum = '07'
select #dayNum + Right(convert(char(10),getdate(),105),8)
If that is not the case You could do this
select '07'+ Right(convert(char(10),'10-08-2007',105),8)
I'd go this way:
SELECT CONVERT(DATE,CONVERT(VARCHAR(6),GETDATE(),112)+'25',112);
CONVERT with format 112 will return the date as unseparated ISO (today we would get 20170407). Convert this to VARCHAR(6) will implicitly cut away the day's part (201704).
Now we add a day and use again CONVERT with 112, but now with DATE as target type.
One thing to keep in mind: The day you add must be two-digit. You can achieve this with
DECLARE #int INT=7;
SELECT REPLACE(STR(#int,2),' ','0');
Use DATEFROMPARTS: Updated ONLY works from 2012 - OP has tagged SQL-Server 2008
select DATEFROMPARTS ( year('10-08-2007'), month('10-08-2007'), 7 )
Assuming that your field is of datetime datatype and your fixed day is of integer type.
select datetimecolumn+(yourparamfixedday-datepart(dd,datetimecolumn))
I need help. Pervasive DB stored dates in days. For example 719311 would be the amount of days from 01/01/0001 to May 28 1970. So May 28 1970 is the date represented in pervasive when looking at 719311.
You can use SQL Servers dateadd feature for this. However the values in Pervasive are much too large to add to the base date of 0 (1900-01-01).
To work around that I used the known integer/date provided and calculated the delta between 0001-01-01 and 1900-01-01 - which is 693597. This value is static, and can be subtracted from each Pervasive value and used in the dateadd. The result can then be added to 1900-01-01.
-- GET BASE DATE OF 0
SELECT CONVERT(DATETIME,0)
-- CALCULATE DIFF FROM 0 TO A KNOWN DATE...
SELECT DATEDIFF(DD,0,'1970-05-28')
--SUBTRACT ABOVE DIFF FROM KNOWN INTEGER FOR SAID DATE... THIS IS OUR DELTA
SELECT 719311-25714
-- ADD THE INTEGER OF SAID DATE, MINUS THE ABOVE DELTA TO 0 TO CONFIRM WE GET THE KNOWN DATE.
SELECT DATEADD(DD,719311-693597,0)
-- USING VARIABLES, LEAVE #DELTA AS A STATIC VALUE, JUST UPDATE #PERVASIVE
DECLARE #PERVASIVE INT, #DELTA INT
SET #PERVASIVE=719312
SET #DELTA=693597
SELECT DATEADD(DD,#PERVASIVE-#DELTA,0)
select datediff(day,'0001-01-01','1753-01-01') + 2
select 719311 - 639907 -- sql
select dateadd(day,79404,'1753-01-01')
dateadd() function cannot work with a date older than '1753-01-01', so you need the 719311 days minus the 639907 days. The difference you can than plug into the dateadd() function.
You should get this 1970-05-28 00:00:00.000
Another alternative is add days to a date datatype.
When I add 719311 days to '0001-01-01' I get '1970-05-30'
To get '1970-05-28' I have to remove 2 of those days.
select dateadd(day,719311-2,convert(date,'00010101'))
returns '1970-05-28'
I need to get the last day of month with input of month and year. For example, with input 06/2016 it will return 30. I use SQL Server 2005. Thanks for any help.
Suppose your input is VARCHAR in the form of MM/YYYY.
Use RIGHT and LEFT to get the year and month respectively. Then use DATEFROMPARTS to generate the starting date. Next, use EOMONTH to get the last day of the month. Finally use DAY to extract the day part.
DECLARE #input VARCHAR(7) = '06/2016'
SELECT
DAY(
EOMONTH(
DATEFROMPARTS(CAST(RIGHT(#input,4) AS INT),CAST(LEFT(#input, 2) AS INT),1)
)
)
The above only works for SQL Server 2012+.
For SQL Server 2005, you can use DATEADD to generate the dates:
SELECT
DAY( -- Day part
DATEADD(DAY, -1, -- Last day of the month
DATEADD(MONTH, CAST(LEFT(#input, 2) AS INT), -- Start of next month
DATEADD(YEAR, CAST(RIGHT(#input, 4) AS INT) - 1900, 0) -- Start of the year
)
)
)
Reference:
Some Common Date Routines
You would do something like this:
select eomonth(getdate(), 0);
If you want it formatted as MM/YYYY then you'd do this:
select format(eomonth(getdate(), 0), 'MM/yyyy');
Pardon me for tossing-in a response that is not specific to "SQL Server," nor thence to "2005," but the generalized way to compute the answer that you seek is as follows:
Break down the input that you have, e.g. 06/2016, into two parts. Call 'em #MONTH and #YEAR. Define a third value, #DAY, equal to 1.
Typecast this into a date-value ... "June 1, 2016."
Now, using the date-handling functions that you're sure to have, "first add one month, then subtract one day."
One thing that you must be very careful of, when designing code like this, is to be certain(!) that your code for decoding 06/2016 works for every(!) value that actually occurs in that database, or that it can be relied upon to fail.
try this,
declare #input varchar(20)='06/2016'
set #input=#input+'/01'
declare #dtinput datetime=#input
select dateadd(day,-1,dateadd(month,datediff(month,0,#dtinput)+1,0))
--OR in sql server 2012
select eomonth(#dtinput)
I am trying to find a data with specific where clause of date and month but I am receiving an error can anyone help me with this?
select *
from my_data
where date BETWEEN '11-20' AND '12-15'
MS SQL Server Management Studio
I am receving an error
Conversion failed when converting date and/or time from character string
Most databases support functions to extract components of dates. So, one way of doing what you want is to convert the values to numbers and make a comparison like this:
where month(date) * 100 + day(date) between 1120 and 1215
The functions for extracting date parts differ by database, so your database might have somewhat different methods for doing this.
The conversion is failing because you are not specifying a year. If you were to specify '11-20-2015' your query would work just insert whatever year you need.
SELECT *
FROM my_data
WHERE date BETWEEN '11-20-2015' AND '12-15-2015'
Alternatively if you wanted data from that range of dates for multiple years I would use a while loop to insert information in a # table then read from that table, depending on the amount of data this could be quick or sloooowww here is an example.
DECLARE #mindatestart date, #mindateend date, #maxdatestart date
SET #mindatestart = '11-20-2010'
SET #mindateend = '12-15-2010'
SET #maxdatestart = '11-20-2015'
SELECT top 0 *, year = ' '
INTO #mydata
FROM my_data
WHILE #mindatestart < #maxdatestart
BEGIN
INSERT INTO #mydata
SELECT *, YEAR(#mindatestart)
FROM my_data
where date between #mindatestart and #mindateend
SET #mindatestart = DATEADD(Year, 1, #mindatestart)
SET #mindateend = DATEADD(Year, 1, #mindateend)
END
This will loop and insert the data from 2010-2015 for those date ranges and add a extra column on the end so you can call the data and order by year if you want like this
SELECT * FROM #mydata order by YEAR
Hopefully some part of this helps!
FROM THE COMMENT BELOW
SELECT *
FROM my_data
WHERE DAY(RIGHT(date, 5)) between DAY(11-20) and DAY(12-15)
The reason '11-20' doesn't work is because its a character string which is why you have to input it between ' ' What the Month() function does is take whatever you put between the () and convert it to an integer. Which is why you're not getting anything back using the method in the first answer, the '-Year' from the table date field is being added into the numeric value where your value is just being converted from 11-20 you can see by using these queries
SELECT MONTH(11-20) --Returns 12
SELECT MONTH(11-20-2015) -- Returns 6
SELECT MONTH(11-20-2014) -- Returns 6
Using RIGHT(Date, 5) you only get Month-day, then you date the day value of that so DAY(RIGHT(DATE, 5) and you should get something that in theory should fall within those date ranges despite the year. However I'm not sure how accurate the data will be, and its a lot of work just to not add an additional 8 characters in your original query.
Since you only care about month and day, but not year, you need to use DATEPART to split up the date. Try this:
select *
from my_data
WHERE 1=1
AND (DATEPART(m, date) >= 11 AND DATEPART(d,date) >= 20)
AND (DATEPART(m, date) <= 12 AND DATEPART(d,date) <= 15)