Problem description
Let the tables C and V have those values
>> Table V <<
| UnID | BillID | ProductDesc | Value | ... |
| 1 | 1 | 'Orange Juice' | 3.05 | ... |
| 1 | 1 | 'Apple Juice' | 3.05 | ... |
| 1 | 2 | 'Pizza' | 12.05 | ... |
| 1 | 2 | 'Chocolates' | 9.98 | ... |
| 1 | 2 | 'Honey' | 15.98 | ... |
| 1 | 3 | 'Bread' | 3.98 | ... |
| 2 | 1 | 'Yogurt' | 8.55 | ... |
| 2 | 1 | 'Ice Cream' | 7.05 | ... |
| 2 | 1 | 'Beer' | 9.98 | ... |
| 2 | 2 | 'League of Legends RP' | 40.00 | ... |
>> Table C <<
| UnID | BillID | ClientName | ... |
| 1 | 1 | 'Alexander' | ... |
| 1 | 2 | 'Tom' | ... |
| 1 | 3 | 'Julia' | ... |
| 2 | 1 | 'Tom' | ... |
| 2 | 2 | 'Alexander' | ... |
Table C have the values of each product, which is associated with a bill number. Table V has the relationship between the client name and the bill number. However, the bill number has a counter that is dependent on the UnId, which is the store unity ID. That being said, each store has it`s own Bill number 1, number 2, etc. Also, the number of bills from each store are not equal.
Solution description
I'm trying to make select between the C left join V without sucess. Because each BillID is dependent on the UnID, I have to make the join considering the concatenation between those two columns.
I've used this script, but it gives me an error.
SELECT
SUM(C.Value),
V.ClientName
FROM
C
LEFT JOIN
V
ON
CONCAT(C.UnID, C.BillID) = CONCAT(V.UnID, V.BillID)
GROUP BY
V.ClientName
and SQL server returns me this 'CONCAT' is not a recognized built-in function name.
I'm using Microsoft SQL Server 2008 R2
Is the use of CONCAT wrong? Or is it the way I tried to SELECT? Could you give me a hand?
[OBS: The tables I've present you are just for the purpose of explaining my difficulties. That being said, if you find any errors in the explanation, please let me know to correct them.]
You should be joining on the equality of the UnID and BillID columns in the two tables:
SELECT
c.ClientName,
COALESCE(SUM(v.Value), 0) AS total
FROM C c
LEFT JOIN V v
ON c.UnID = v.UnID AND
c.BillID = v.BillID
GROUP BY
c.ClientName;
In theory you could try joining on CONCAT(UnID, BillID). However, you could run into problems. For example, UnID = 1 with BillID = 23 would, concatenated together, be the same as UnID = 12 and BillID = 3.
Note: We wrap the sum with COALESCE, because should a given client have no entries in the V table, the sum would return NULL, which we then replace with zero.
concat is only available in sql server 2012.
Here's one option.
SELECT
SUM(C.Value),
V.ClientName
FROM
C
LEFT JOIN
V
ON
cast(C.UnID as varchar(100)) + cast(C.BillID as varchar(100)) = cast(V.UnID as varchar(100)) + cast(V.BillID as varchar(100))
GROUP BY
V.ClientName
I have a 1 table in a db that stored Incoming, Outgoing and Net values for various Account Codes over time. Although there is a date field the sequence of events per Account Code is based on the "Version" number where 0 = original record for each Account Code and it increments by 1 after each change to that Account Code.
The Outgoing and Incoming values are stored in the db as cumulative values rather than the individual transaction value but I am looking for a way to Select * From this table and return the individual amounts as opposed to the cumulative.
Below are test scripts of table and data, and also 2 examples.
If i Select where code = '123' in the test table I currently get this (values are cumulative);
+------+------------+---------+---------+---------+-----+
| Code | Date | Version | Incoming| Outgoing| Net |
+------+------------+---------+---------+---------+-----+
| 123 | 01/01/2018 | 0 | 100 | 0 | 100 |
| 123 | 07/01/2018 | 1 | 150 | 0 | 150 |
| 123 | 09/01/2018 | 2 | 150 | 100 | 50 |
| 123 | 14/01/2018 | 3 | 200 | 100 | 100 |
| 123 | 18/01/2018 | 4 | 200 | 175 | 25 |
| 123 | 23/01/2018 | 5 | 225 | 175 | 50 |
| 123 | 30/01/2018 | 6 | 225 | 225 | 0 |
+------+------------+---------+---------+---------+-----+
This is what I would like to see (each individual transaction);
+------+------------+---------+----------+----------+------+
| Code | Date | Version | Incoming | Outgoing | Net |
+------+------------+---------+----------+----------+------+
| 123 | 01/01/2018 | 0 | 100 | 0 | 100 |
| 123 | 07/01/2018 | 1 | 50 | 0 | 50 |
| 123 | 09/01/2018 | 2 | 0 | 100 | -100 |
| 123 | 14/01/2018 | 3 | 50 | 0 | 50 |
| 123 | 18/01/2018 | 4 | 0 | 75 | -75 |
| 123 | 23/01/2018 | 5 | 25 | 0 | 25 |
| 123 | 30/01/2018 | 6 | 0 | 50 | -50 |
+------+------------+---------+----------+----------+------+
If I had the individual transaction values and wanted to report on the cumulative, I would use an OVER PARTITION BY, but is there an opposite to that?
I am not looking to redesign the create table or the process in which it is stored, I am just looking for a way to report on this from our MI environment.
Note: I've added other random Account Codes into this to emphasis how the data is not ordered by Code or Version, but by Date.
thanks in advance for any help.
USE [tempdb];
IF EXISTS ( SELECT *
FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_NAME = 'Table1'
AND TABLE_SCHEMA = 'dbo')
DROP TABLE [dbo].[Table1];
GO
CREATE TABLE [dbo].[Table1]
(
[Code] CHAR(3)
,[Date] DATE
,[Version] CHAR(3)
,[Incoming] DECIMAL(20,2)
,[Outgoing] DECIMAL(20,2)
,[Net] DECIMAL(20,2)
);
GO
INSERT INTO [dbo].[Table1] VALUES
('123','2018-01-01','0','100','0','100'),
('456','2018-01-02','0','50','0','50'),
('789','2018-01-03','0','0','0','0'),
('456','2018-01-04','1','100','0','100'),
('456','2018-01-05','2','150','0','150'),
('789','2018-01-06','1','50','50','0'),
('123','2018-01-07','1','150','0','150'),
('456','2018-01-08','3','200','0','200'),
('123','2018-01-09','2','150','100','50'),
('789','2018-01-10','2','0','0','0'),
('456','2018-01-11','4','225','0','225'),
('789','2018-01-12','3','75','25','50'),
('987','2018-01-13','0','0','50','-50'),
('123','2018-01-14','3','200','100','100'),
('654','2018-01-15','0','100','0','100'),
('456','2018-01-16','5','250','0','250'),
('987','2018-01-17','1','50','50','0'),
('123','2018-01-18','4','200','175','25'),
('789','2018-01-19','4','100','25','75'),
('987','2018-01-20','2','150','125','25'),
('321','2018-01-21','0','100','0','100'),
('654','2018-01-22','1','0','0','0'),
('123','2018-01-23','5','225','175','50'),
('321','2018-01-24','1','100','50','50'),
('789','2018-01-25','5','100','50','50'),
('987','2018-01-26','3','150','150','0'),
('456','2018-01-27','6','250','250','0'),
('456','2018-01-28','7','270','250','20'),
('321','2018-01-29','2','100','100','0'),
('123','2018-01-30','6','225','225','0'),
('987','2018-01-31','4','175','150','25')
;
GO
SELECT *
FROM [dbo].[Table1]
WHERE [Code] = '123'
GO;
USE [tempdb];
IF EXISTS ( SELECT *
FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_NAME = 'Table1'
AND TABLE_SCHEMA = 'dbo')
DROP TABLE [dbo].[Table1];
GO;
}
Just use lag():
select Evt, Date, Version,
(Loss - lag(Loss, 1, 0) over (partition by evt order by date)) as incoming,
(Rec - lag(Rec, 1, 0) over (partition by evt order by date)) as outgoing,
(Net - lag(Net, 1, 0) over (partition by evt order by date)) as net
from [dbo].[Table1];
We have a table like this:
+----+-------+-----------------+----------------+-----------------+----------------+-----------------+
| ID | Name | RecievedService | FirstZoneTeeth | SecondZoneTeeth | ThirdZoneTeeth | FourthZoneTeeth |
+----+-------+-----------------+----------------+-----------------+----------------+-----------------+
| 1 | John | SomeService1 | 13 | | 4 | |
+----+-------+-----------------+----------------+-----------------+----------------+-----------------+
| 2 | John | SomeService1 | 34 | | | |
+----+-------+-----------------+----------------+-----------------+----------------+-----------------+
| 3 | Steve | SomeService3 | | | | 2 |
+----+-------+-----------------+----------------+-----------------+----------------+-----------------+
| 4 | Steve | SomeService4 | | | | 12 |
+----+-------+-----------------+----------------+-----------------+----------------+-----------------+
Every digit in zones is a tooth (dental science) and it means "John" has got "SomeService1" twice for tooth #3.
+----+------+-----------------+----------------+-----------------+----------------+-----------------+
| ID | Name | RecievedService | FirstZoneTeeth | SecondZoneTeeth | ThirdZoneTeeth | FourthZoneTeeth |
+----+------+-----------------+----------------+-----------------+----------------+-----------------+
| 1 | John | SomeService1 | 13 | | 4 | |
+----+------+-----------------+----------------+-----------------+----------------+-----------------+
| 2 | John | SomeService1 | 34 | | | |
+----+------+-----------------+----------------+-----------------+----------------+-----------------+
Note that Steve has received services twice for tooth #2 (4th Zone) but services are not one.
I'd write some code that gives me a table with duplicate rows (Checking the only patient and received service)(using "group by" clause") but I need to check zones too.
I've tried this:
select ROW_NUMBER() over(order by vv.ID_sick) as RowNum,
bb.Radif,
bb.VCount as 'Count',
vv.ID_sick 'ID_Sick',
vv.ID_service 'ID_Service',
sick.FNamesick + ' ' + sick.LNamesick as 'Sick',
serv.NameService as 'Service',
vv.Mab_Service as 'MabService',
vv.Mab_daryafti as 'MabDaryafti',
vv.datevisit as 'DateVisit',
vv.Zone1,
vv.Zone2,
vv.Zone3,
vv.Zone4,
vv.ID_dentist as 'ID_Dentist',
dent.FNamedentist + ' ' + dent.LNamedentist as 'Dentist',
vv.id_do as 'ID_Do',
do.FNamedentist + ' ' + do.LNamedentist as 'Do'
from visiting vv inner join (
select ROW_NUMBER() OVER(ORDER BY a.ID_sick ASC) AS Radif,
count(a.ID_sick) as VCount,
a.ID_sick,
a.ID_service
from visiting a
group by a.ID_sick, a.ID_service, a.Zone1, a.Zone2, a.Zone3, a.Zone4
having count(a.ID_sick)>1)bb
on vv.ID_sick = bb.ID_sick and vv.ID_service = bb.ID_service
left join InfoSick sick on vv.ID_sick = sick.IDsick
left join infoService serv on vv.ID_service = serv.IDService
left join Infodentist dent on vv.ID_dentist = dent.IDdentist
left join infodentist do on vv.id_do = do.IDdentist
order by bb.ID_sick, bb.ID_service,vv.datevisit
But this code only returns rows with all tooths repeated. What I want is even one tooth repeats ...
How can I implement it?
I need to check characters in zones.
**Zone's datatype is varchar
This is a bad datamodel for what you are trying to do. By storing the teeth as a varchar, you have kind of decided that you are not interested in single teeth, but only in the group of teeth. Now, however, you are trying to investigate on single teeth.
You'd want a datamodel like this:
service
+------------+--------+-----------------+
| service_id | Name | RecievedService |
+------------+--------+-----------------+
| 1 | John | SomeService1 |
+------------+--------+-----------------+
| 3 | Steve | SomeService3 |
+------------+--------+-----------------+
| 4 | Steve | SomeService4 |
+------------+-------+-----------------+
service_detail
+------------+------+-------+
| service_id | zone | tooth |
+------------+------+-------+
| 1 | 1 | 1 |
| 1 | 1 | 3 |
| 1 | 3 | 4 |
+------------+------+-------+
| 1 | 1 | 3 |
| 1 | 1 | 4 |
+------------+------+-------+
| 3 | 4 | 2 |
+------------+------+-------+
| 4 | 4 | 1 |
| 4 | 4 | 2 |
+------------+------+-------+
What you can do with the given datamodel is to create such table on-the-fly using a recursive query and string manipulation:
with unpivoted(service_id, name, zone, teeth) as
(
select recievedservice, name, 1, firstzoneteeth
from mytable where len(firstzoneteeth) > 0
union all
select recievedservice, name, 2, secondzoneteeth
from mytable where len(secondzoneteeth) > 0
union all
select recievedservice, name, 3, thirdzoneteeth
from mytable where len(thirdzoneteeth) > 0
union all
select recievedservice, name, 4, fourthzoneteeth
from mytable where len(fourthzoneteeth) > 0
)
, service_details(service_id, name, zone, tooth, teeth) as
(
select
service_id, name, zone, substring(teeth, 1, 1), substring(teeth, 2, 10000)
from unpivoted
union all
select
service_id, name, zone, substring(teeth, 1, 1), substring(teeth, 2, 10000)
from service_details
where len(teeth) > 0
)
, duplicates(service_id, name) as
(
select distinct service_id, name
from service_details
group by service_id, name, zone, tooth
having count(*) > 1
)
select m.*
from mytable m
join duplicates d on d.service_id = m.recievedservice and d.name = m.name;
A lot of work and a rather slow query due to a bad datamodel, but still feasable.
Rextester demo: http://rextester.com/JVWK49901