For example, I would like to query from the first 10 rows, how could I achieve that. (Not get the first 10 of the query results).
I tried using 'limit' first then 'where' but it doesn't work.
If I understand correctly you first want to fetch 10 rows of one query, then search within those 10 rows for data. To do that you can use a subquery:
SELECT *
FROM (SELECT *
FROM YOUR_TABLE yt
ORDER BY yt.SOME_COLUMN
LIMIT 10) sq
WHERE sq.SOME_OTHER_COLUMN > 25;
Best of luck.
Based on your sort criteria you can create a SQL like this
SELECT column1, column2, ...
FROM your table
ORDER BY sort column
LIMIT 10
This will give you the top 10 rows from your table based on your sort column
Related
I'm not sure if it's even possible. Let's say, I have a table A having 100 records. I want to select top five records and also return a total number of elements in this table in one query. How can I do this?
You can add the count as an additional column using window functions:
select a.*, count(*) over () as records_in_table
from a
order by <whatever> -- however you define "top five"
fetch first 5 rows only;
I would like to display a table of results. The data is sourced from a SQL query on an Oracle database. I would like to show the results one page (say, 10 records) at a time, minimising the actual data being sent to the front-end.
At the same time, I would like to show the total number of possible results (say, showing 1-10 of 123), and to allow for pagination (say, to calculate that 10 per page, 123 results, therefore 13 pages).
I can get the total number of results with a single count query.
SELECT count(*) AS NUM_RESULTS FROM ... etc.
and I can get the desired subset with another query
SELECT * FROM ... etc. WHERE ? <= ROWNUM AND ROWNUM < ?
But, is there a way to get all the relevant details in one single query?
Update
Actually, the above query using ROWNUM seems to work for 0 - 10, but not for 10 - 20, so how can I do that too?
ROWNUM is a bit tricky to use.
The ROWNUM pseudocolumn always starts with 1 for the first result that actually gets fetched. If you filter for ROWNUM>10, you will never fetch any result and therefore will not get any.
If you want to use it for paging (not that you really should), it requires nested subqueries:
select * from
(select rownum n, x.* from
(select * from mytable order by name) x
)
where n between 3 and 5;
Note that you need another nested subquery to get the order by right; if you put the order by one level higher
select * from
(select rownum n, x.* from mytable x order by name)
where n between 3 and 5;
it will pick 3 random(*) rows and sort them, but that is ususally not what you want.
(*) not really random, but probably not what you expect.
See http://use-the-index-luke.com/sql/partial-results/window-functions for more effient ways to implement pagination.
You can use inner join on your table and fetch total number of result in your subquery. The example of an query is as follows:
SELECT E.emp_name, E.emp_age, E.emp_sal, E.emp_count
FROM EMP as E
INNER JOIN (SELECT emp_name, COUNT(*) As emp_count
FROM EMP GROUP BY emp_name) AS T
ON E.emp_name = T.emp_name WHERE E.emp_age < 35;
Not sure exactly what you're after based on your question wording, but it seems like you want to see your specialized table of all records with a row number between two values, and in an adjacent field in each record see the total count of records. If so, you can try selecting everything from your table and joining a subquery of a COUNT value as a field by saying where 1=1 (i.e. everywhere) tack that field onto the record. Example:
SELECT *
FROM table_name LEFT JOIN (SELECT COUNT(*) AS NUM_RESULTS FROM table_name) ON 1=1
WHERE ? <= ROWNUM AND ROWNUM < ?
I have a table that contains a number of items with ids, if I clicked on one of these ids I'd like to display the one I clicked, followed by 9 random entries.
The following query will select 10 rows randomly:
SELECT column FROM table ORDER BY RAND() LIMIT 10
How do I first display the item of my choice, and then the 9 items that were chosen at random?
What is the suitable query for this problem ??
Sounds like you just want a union.
SELECT column FROM table LIMIT 1
UNION ALL
SELECT column
FROM table
ORDER BY RAND()
LIMIT 9
Two things you may want to consider. First, if you don't put a nonrandom order by on the first query there is no guarantee what you will get as your first row or even that it is consistent. Also, you could end up selecting the same first row twice. To avoid that you can try:
SELECT column FROM table ORDER BY SOME_COLUMN LIMIT 1
UNION ALL
SELECT column
FROM table
WHERE COLUMN NOT IN(SELECT column FROM table ORDER BY SOME_COLUMN LIMIT 1)
ORDER BY RAND()
LIMIT 9
I would suggest using multiple conditions in the order by:
SELECT `column`
FROM `table`
ORDER BY (id = SELECTEDID) DESC, RAND()
LIMIT 10;
This will ensure two things. First, your selected row will be first (because of he order by). And second, you will get nine other rows in the 10.
For example I have:
create table a (i int);
Assume there are 10k rows.
I want to count 0's in the last 20 rows.
Something like:
select count(*) from (select i from a limit 20) where i = 0;
Is that possible to make it more efficient? Like a single SQL statement or something?
PS. DB is SQLite3 if that matters at all...
UPDATE
PPS. No need to group by anything in this instance, assume the table that is literally 1 column (and presumably the internal DB row_ID or something). I'm just curious if this is possible to do without the nested selects?
You'll need to order by something in order to determine the last 20 rows. When you say last, do you mean by date, by ID, ...?
Something like this should work:
select count(*)
from (
select i
from a
order by j desc
limit 20
) where i = 0;
If you do not remove rows from the table, you may try the following hacky query:
SELECT COUNT(*) as cnt
FROM A
WHERE
ROWID > (SELECT MAX(ROWID)-20 FROM A)
AND i=0;
It operates with ROWIDs only. As the documentation says: Rows are stored in rowid order.
You need to remember to order by when you use limit, otherwise the result is indeterminate. To get the latest rows added, you need to include a column with the insertion date, then you can use that. Without this column you cannot guarantee that you will get the latest rows.
To make it efficient you should ensure that there is an index on the column you order by, possibly even a clustered index.
I'm afraid that you need a nested select to be able to count and restrict to last X rows at a time, because something like this
SELECT count(*) FROM a GROUP BY i HAVING i = 0
will count 0's, but in ALL table records, because a LIMIT in this query will basically have no effect.
However, you can optimize making COUNT(i) as it is faster to COUNT only one field than 2 or more (in this case your table will have 2 fields, i and rowid, that is automatically created by SQLite in PKless tables)
What is the most efficient way to select the first and last element only, from a column in SQLite?
The first and last element from a row?
SELECT column1, columnN
FROM mytable;
I think you must mean the first and last element from a column:
SELECT MIN(column1) AS First,
MAX(column1) AS Last
FROM mytable;
See http://www.sqlite.org/lang_aggfunc.html for MIN() and MAX().
I'm using First and Last as column aliases.
if it's just one column:
SELECT min(column) as first, max(column) as last FROM table
if you want to select whole row:
SELECT 'first',* FROM table ORDER BY column DESC LIMIT 1
UNION
SELECT 'last',* FROM table ORDER BY column ASC LIMIT 1
The most efficient way would be to know what those fields were called and simply select them.
SELECT `first_field`, `last_field` FROM `table`;
Probably like this:
SELECT dbo.Table.FirstCol, dbo.Table.LastCol FROM Table
You get minor efficiency enhancements from specifying the table name and schema.
First: MIN() and MAX() on a text column gives AAAA and TTTT results which are not the first and last entries in my test table. They are the minimum and maximum values as mentioned.
I tried this (with .stats on) on my table which has over 94 million records:
select * from
(select col1 from mitable limit 1)
union
select * from
(select col1 from mitable limit 1 offset
(select count(0) from mitable) -1);
But it uses up a lot of virtual machine steps (281,624,718).
Then this which is much more straightforward (which works if the table was created without WITHOUT ROWID) [sql keywords are in capitals]:
SELECT col1 FROM mitable
WHERE ROWID = (SELECT MIN(ROWID) FROM mitable)
OR ROWID = (SELECT MAX(ROWID) FROM mitable);
That ran with 55 virtual machine steps on the same table and produced the same answer.
min()/max() approach is wrong. It is only correct, if the values are ascending only. I needed something liket this for currency rates, which are random raising and falling.
This is my solution:
select st.*
from stats_ticker st,
(
select min(rowid) as first, max(rowid) as last --here is magic part 1
from stats_ticker
-- next line is just a filter I need in my case.
-- if you want first/last of the whole table leave it out.
where timeutc between datetime('now', '-1 days') and datetime('now')
) firstlast
WHERE
st.rowid = firstlast.first --and these two rows do magic part 2
OR st.rowid = firstlast.last
ORDER BY st.rowid;
magic part 1: the subselect results in a single row with the columns first,last containing rowid's.
magic part 2 easy to filter on those two rowid's.
This is the best solution I've come up so far. Hope you like it.
We can do that by the help of Sql Aggregate function, like Max and Min. These are the two aggregate function which help you to get last and first element from data table .
Select max (column_name ), min(column name) from table name
Max will give you the max value means last value and min will give you the min value means it will give you the First value, from the specific table.