Pivoting Multiple Attributres and grouping them as a 'single' attribute (many to one) - sql

Question

So I Have a table called Value that's associated with different 'Fields'. Note that some of these fields have similar 'names' but they are named differently. Ultimately I want these 'similar names' to be pivoted/grouped as the same field name in the result set
VALUE_ID VALUE_TX FIELD_NAME Version_ID
1 Yes Adult 1
2 18 Age 1
3 Black Eye Color 1
4 Yes Is_Adult 2
5 25 Years_old 2
6 Brown Color_of_Eyes 2
I have a table called Submitted that looks like the following:
Version_ID Version_Name
1 TEST_RUN
2 REAL_RUN
I need a result set that Looks like this:
Submitted_Name Adult? Age Eye_Color
TEST_RUN Yes 18 Black
REAL_RUN Yes 25 Brown
I've tried the following:
SELECT * FROM (
select value_Tx, field_name, version_id
from VALUE
)
PIVOT (max (value_tx) for field_name in (('Adult', 'Is_Adult') as 'Adult?', ('Age', 'Years_old') as 'Age', ('Eye Color', 'Color_of_Eyes') as 'Eye_Color')
);
What am I doing wrong? Please let me know if I need to add any additional details / data.
Thanks in advance!
The error message that I am getting is the following:
ORA-00907: missing right parenthesis

Answer 1

I would change the field names in the subquery:
SELECT *
FROM (select value_Tx,
(case when field_name in ('Adult', 'Is_Adult') then 'Adult?'
field_name in ('Age', 'Years_old') then 'Age'
field_name in ('Eye Color', 'Color_of_Eyes') then 'Eye_Color'
else field_name
end) as field_name, version_id
from VALUE
)
PIVOT (max(value_tx) for field_name in ('Adult?', 'Age', 'Eye_Color'));

Answer 2

You can use double quotes for column aliasing within the pivot clause's part, and I think decode function suits well for this question. You can consider using the following query :
with value( value_id, value_tx, field_name, version_id ) as
(
select 1 ,'Yes' ,'Adult' ,1 from dual union all
select 2 ,'18' ,'Age' ,1 from dual union all
select 3 ,'Black','Eye_Color' ,1 from dual union all
select 4 ,'Yes' ,'Is_Adult' ,2 from dual union all
select 5 ,'25' ,'Years_old' ,2 from dual union all
select 6 ,'Brown','Color_of_Eyes',2 from dual
), Submitted( version_id, version_name ) as
(
select 1 ,'TEST_RUN' from dual union all
select 2 ,'REAL_RUN' from dual
)
select * from
(
select s.version_name as "Submitted_Name", v.value_Tx,
decode(v.field_name,'Adult','Is_Adult','Age','Years_old','Eye_Color',
'Color_of_Eyes',v.field_name) field_name
from value v
join Submitted s
on s.version_id = v.version_id
group by decode(v.field_name,'Adult','Is_Adult','Age','Years_old','Eye_Color',
'Color_of_Eyes',v.field_name),
v.value_Tx, s.Version_Name
)
pivot(
max(value_tx) for field_name in ( 'Is_Adult' as "Adult?", 'Years_old' as "Age",
'Color_of_Eyes' as "Eye_Color" )
);
Submitted_Name Adult? Age Eye_Color
REAL_RUN Yes 25 Brown
TEST_RUN Yes 18 Black
I think, better to solve as much as shorter way, as an example, using modular arithmetic would even be better as below :
select *
from
(
select s.version_name as "Submitted_Name", v.value_Tx, mod(v.value_id,3) as value_id
from value v
join Submitted s
on s.version_id = v.version_id
group by v.value_Tx, s.version_name, mod(v.value_id,3)
)
pivot(
max(value_tx) for value_id in ( 1 as "Adult?", 2 as "Age", 0 as "Eye_Color" )
)
Demo