I am having trouble with the ambiquity of this statement:
http://activemq.apache.org/how-do-i-preserve-order-of-messages.html
If you have multiple consumers on a single queue the consumers will compete for messages and ActiveMQ will load balance across them, so order will be lost.
Does this mean that if I one producer (P1) publshing on a single topic (T1) and four subscribers to that topic (S1,S2,S3, S4). All above using AMQP.
Is there is no guarantee that the message order from P1 would be seen by S1 in that same order by itself?
And each other subscriber would not necessarily see the order than P1 actually sent?).
Note, I am talking about jms pub/sub here via topic://
[If I add more producers but each one has its own topic queue, would that also effect the order on the other queues?]
I would not expect this, but the statement from the website is giving us some concerns here.
The documentation is actually fairly clear:
ActiveMQ will preserve the order of messages sent by a single producer to all consumers on a topic. If there is a single consumer on a queue then the order of messages sent by a single producer will be preserved as well.
Since you are asking about Topics the first sentence pretty much nails it down for you, for Topics, order is preserved when there is one producer. Each subscriber on a Topic sees each message sent and sees it in the order it was sent (barring any priority based reordering). Only when you are talking about Queues (not Topics) does the ordering become more complex.
For a Queue you are no longer doing pub/sub you are doing point-to-point and in that case multiple subscribers compete for messages from the Queue and thus you no longer have an order guarantee since each consumer will be taking some messages and depending on prefetch they will take them in some batches which you cannot predict.
Related
I know that achieving round-robin behaviour in a topic exchange can be tricky or impossible so my question in fact is if there is anything I can make out of RabbitMQ or look away to other message queues that support that.
Here's a detailed explanation of my application requirements:
There will be one producer, let's call it P
There (potentially) will be thousands of consumers, let's call them Cn
Each consumer can "subscribe" to 1 or more topic exchange and multiple consumers can be subscribed to the same topic
Every message published into the topic should be consumed by only ONE consumer
Use case #1
Assume:
Topics
foo.bar
foo.baz
Consumers
Consumer C1 is subscribed to topic #
Consumer C2 is subscribed to topic foo.*
Consumer C3 is subscribed to topic *.bar
Producer P publishes the following messages:
publish foo.qux: C1 and C2 can potentially consume this message but only one receives it
publish foo.bar: C1, C2 and C3 can potentially consume this message but only one receives it
Note
Unfortunately I can't have a separate queue for each "topic" therefore using the Direct Exchange doesn't work since the number of topic combinations can be huge (tens of thousands)
From what I've read, there is no out-of-the box solution with RabbitMQ. Does anybody know a workaround or there's another message queue solution that would support this, ex. Kafka, Kinesis etc.
Thank you
There appears to be a conflation of the role of the exchange, which is to route messages, and the queue, which is to provide a holding place for messages waiting to be processed. Funneling messages into one or more queues is the job of the exchange, while funneling messages from the queue into multiple consumers is the job of the queue. Round robin only comes into play for the latter.
Fundamentally, a topic exchange operates by duplicating messages, one for each queue matching the topic published with the message. Therefore, any expectation of round-robin behavior would be a mistake, as it goes against the very definition of the topic exchange.
All this does is to establish that, by definition, the scenario presented in the question does not make sense. That does not mean the desired behavior is impossible, but the terms and topology may need some clarifying adjustments.
Let's take a step back and look at the described lifetime for one message: It is produced by exactly one producer and consumed by one of many consumers. Ordinarily, that is the scenario addressed by a direct exchange. The complicating factor in this is that your consumers are selective about what types of messages they will consume (or, to put it another way, your producer is not consistent about what types of messages it produces).
Ordinarily in message-oriented processing, a single message type corresponds to a single consumer type. Therefore, each different type of message would get its own corresponding queue. However, based on the description given in this question, a single message type might correspond to multiple different consumer types. One issue I have is the following statement:
Unfortunately I can't have a separate queue for each "topic"
On its face, that statement makes no sense, because what it really says is that you have arbitrarily many (in fact, an unknown number of) message types; if that were the case, then how would you be able to write code to process them?
So, ignoring that statement for a bit, we are led to two possibilities with RabbitMQ out of the box:
Use a direct exchange and publish your messages using the type of message as a routing key. Then, have your various consumers subscribe to only the message types that they can process. This is the most common message processing pattern.
Use a topic exchange, as you have, and come up with some sort of external de-duplication logic (perhaps memcached), where messages are checked against it and discarded if another consumer has started to process it.
Now, neither of these deals explicitly with the round-robin requirement. Since it was not explained why or how this was important, it is assumed that it can be ignored. If not, further definition of the problem space is required.
I have one direct exchange. There is also one queue, bound to this exchange.
I have two consumers for that queue. The consumers are manually ack'ing the messages once they've done the corresponding processing.
The messages are logically ordered/sorted, and should be processed in that order. Is it possible to enforce that all messages are received and processed sequentially accross consumer A and consumer B? In other words, prevent A and B from processing messages at the same time.
Note: the consumers are not sharing the same connection and/or channel. This means I cannot use <channel>.basicQoS(1);.
Rationale of this question: both consumers are identicall. If one goes down, the other queue starts processing messages and everything keeps working without any required intervention.
One approach to handling failover in a case where you want redundant consumers but need to process messages in a specific order is to use the exclusive consumer option when setting up the bind to the queue, and to have two consumers who keep trying to bind even when they can't get the exclusive lock.
The process is something like this:
Consumer A starts first and binds to the queue as an exclusive consumer. Consumer A begins processing messages from the queue.
Consumer B starts next and attempts to bind to the queue as an exclusive consumer, but is rejected because the queue already has an exclusive consumer.
On a recurring basis, consumer B attempts to get an exclusive bind on the queue but is rejected.
Process hosting consumer A crashes.
Consumer B attempts to bind to the queue as an exclusive consumer, and succeeds this time. Consumer B starts processing messages from the queue.
Consumer A is brought back online, and attempts an exclusive bind, but is rejected now.
Consumer B continues to process messages in FIFO order.
While this approach doesn't provide load sharing, it does provide redundancy.
Even though this is already answered. May be this can help others.
RabbitMQ has a feature known as Single Active Consumer, which matches your case.
We can have N consumers attached to a Queue but only 1 (one) of them will be actively consuming messages from the Queue. Fail-over happens only when active consumer fails.
Kindly take a look at the link https://www.rabbitmq.com/consumers.html#single-active-consumer
Thank you
Usually the point of a MQ system is to distribute workload. Of course, there are some situations where processing of message N depends on result of processing the message N-1, or even the N-1 message itself.
If A and B can't process messages at the same time, then why not just have A or just B? As I see it, you are not saving anything with having 2 consumers in a way that one can work only when the other one is not...
In your case, it would be best to have one consumer but to actually do the parallelisation (not a word really) on the processing part.
Just to add that RMQ is distributing messages evenly to all consumers (in round-robin fashion) regardless on any criteria. Of course this is when prefetch is set to 1, which by default it is. More info on that here, look for "fair dispatch".
I need to implement sequential message processing on multiple consumers, but only one message per time on the queue. I have a lot of queues, but all of them are sequential and I need multiple consumers support for load balancing and redundancy. Anybody can tell whether it is real or not to limit number of unacknowledged message to 1 per queue?
Anybody can tell whether it is real or not to limit number of unacknowledged message to 1 per queue?
this isn't possible with multiple consumers. you can limit the number of unacknowledged messages using prefetch limit for a single channel, but not across multiple channels / consumers. it is tied to the channel of the consumer, not the queue.
the only way you can achieve this is with a single consumer and a single queue, using prefetch.
even then, you have no guarantee that the messages will arrive in the queue in the correct order.
(this is a fundamental difficulty with distributed systems of any kind, not a rabbitmq limitation)
look at the Message Sequencer and Resequencer patterns to try and put the messages back in order.
but even then, you're going to run into difficulty.
you'll also want to read up on idempotency so you don't re-process a message that has already been processed.
You should be able to configure your consumer to consume only X message(s) at time and same for your channel. Take a look at QOS or Consumer Prefetch
https://www.rabbitmq.com/consumer-prefetch.html
Here is an example, where multi-consumers will acknoledge only one message and channel allow only one message to be acknoledged (whatever how much consumers a plugged on it)
Channel channel = ...;
Consumer consumer1 = ...;
Consumer consumer2 = ...;
channel.basicQos(1, false); // Per consumer limit
channel.basicQos(1, true); // Per channel limit
channel.basicConsume("my-queue1", false, consumer1);
channel.basicConsume("my-queue2", false, consumer2);
Here, a consumer can acknoledge only one message each time, and the channel can only have one unacknoledged message. You didn't mention which language you use so you'll problably have to adapt this example.
I need to choose a new Queue broker for my new project.
This time I need a scalable queue that supports pub/sub, and keeping message ordering is a must.
I read Alexis comment: He writes:
"Indeed, we think RabbitMQ provides stronger ordering than Kafka"
I read the message ordering section in rabbitmq docs:
"Messages can be returned to the queue using AMQP methods that feature
a requeue
parameter (basic.recover, basic.reject and basic.nack), or due to a channel
closing while holding unacknowledged messages...With release 2.7.0 and later
it is still possible for individual consumers to observe messages out of
order if the queue has multiple subscribers. This is due to the actions of
other subscribers who may requeue messages. From the perspective of the queue
the messages are always held in the publication order."
If I need to handle messages by their order, I can only use rabbitMQ with an exclusive queue to each consumer?
Is RabbitMQ still considered a good solution for ordered message queuing?
Well, let's take a closer look at the scenario you are describing above. I think it's important to paste the documentation immediately prior to the snippet in your question to provide context:
Section 4.7 of the AMQP 0-9-1 core specification explains the
conditions under which ordering is guaranteed: messages published in
one channel, passing through one exchange and one queue and one
outgoing channel will be received in the same order that they were
sent. RabbitMQ offers stronger guarantees since release 2.7.0.
Messages can be returned to the queue using AMQP methods that feature
a requeue parameter (basic.recover, basic.reject and basic.nack), or
due to a channel closing while holding unacknowledged messages. Any of
these scenarios caused messages to be requeued at the back of the
queue for RabbitMQ releases earlier than 2.7.0. From RabbitMQ release
2.7.0, messages are always held in the queue in publication order, even in the presence of requeueing or channel closure. (emphasis added)
So, it is clear that RabbitMQ, from 2.7.0 onward, is making a rather drastic improvement over the original AMQP specification with regard to message ordering.
With multiple (parallel) consumers, order of processing cannot be guaranteed.
The third paragraph (pasted in the question) goes on to give a disclaimer, which I will paraphrase: "if you have multiple processors in the queue, there is no longer a guarantee that messages will be processed in order." All they are saying here is that RabbitMQ cannot defy the laws of mathematics.
Consider a line of customers at a bank. This particular bank prides itself on helping customers in the order they came into the bank. Customers line up in a queue, and are served by the next of 3 available tellers.
This morning, it so happened that all three tellers became available at the same time, and the next 3 customers approached. Suddenly, the first of the three tellers became violently ill, and could not finish serving the first customer in the line. By the time this happened, teller 2 had finished with customer 2 and teller 3 had already begun to serve customer 3.
Now, one of two things can happen. (1) The first customer in line can go back to the head of the line or (2) the first customer can pre-empt the third customer, causing that teller to stop working on the third customer and start working on the first. This type of pre-emption logic is not supported by RabbitMQ, nor any other message broker that I'm aware of. In either case, the first customer actually does not end up getting helped first - the second customer does, being lucky enough to get a good, fast teller off the bat. The only way to guarantee customers are helped in order is to have one teller helping customers one at a time, which will cause major customer service issues for the bank.
It is not possible to ensure that messages get handled in order in every possible case, given that you have multiple consumers. It doesn't matter if you have multiple queues, multiple exclusive consumers, different brokers, etc. - there is no way to guarantee a priori that messages are answered in order with multiple consumers. But RabbitMQ will make a best-effort.
Message ordering is preserved in Kafka, but only within partitions rather than globally. If your data need both global ordering and partitions, this does make things difficult. However, if you just need to make sure that all of the same events for the same user, etc... end up in the same partition so that they are properly ordered, you may do so. The producer is in charge of the partition that they write to, so if you are able to logically partition your data this may be preferable.
I think there are two things in this question which are not similar, consumption order and processing order.
Message Queues can -to a degree- give you a guarantee that messages will get consumed in order, they can't, however, give you any guarantees on the order of their processing.
The main difference here is that there are some aspects of message processing which cannot be determined at consumption time, for example:
As mentioned a consumer can fail while processing, here the message's consumption order was correct, however, the consumer failed to process it correctly, which will make it go back to the queue. At this point the consumption order is intact, but the processing order is not.
If by "processing" we mean that the message is now discarded and finished processing completely, then consider the case when your processing time is not linear, in other words processing one message takes longer than the other. For example, if message 3 takes longer to process than usual, then messages 4 and 5 might get consumed and finish processing before message 3 does.
So even if you managed to get the message back to the front of the queue (which by the way violates the consumption order) you still cannot guarantee they will also be processed in order.
If you want to process the messages in order:
Have only 1 consumer instance at all times, or a main consumer and several stand-by consumers.
Or don't use a messaging queue and do the processing in a synchronous blocking method, which might sound bad but in many cases and business requirements it is completely valid and sometimes even mission critical.
There are proper ways to guarantuee the order of messages within RabbitMQ subscriptions.
If you use multiple consumers, they will process the message using a shared ExecutorService. See also ConnectionFactory.setSharedExecutor(...). You could set a Executors.newSingleThreadExecutor().
If you use one Consumer with a single queue, you can bind this queue using multiple bindingKeys (they may have wildcards). The messages will be placed into the queue in the same order that they were received by the message broker.
For example you have a single publisher that publishes messages where the order is important:
try (Connection connection2 = factory.newConnection();
Channel channel2 = connection.createChannel()) {
// publish messages alternating to two different topics
for (int i = 0; i < messageCount; i++) {
final String routingKey = i % 2 == 0 ? routingEven : routingOdd;
channel2.basicPublish(exchange, routingKey, null, ("Hello" + i).getBytes(UTF_8));
}
}
You now might want to receive messages from both topics in a queue in the same order that they were published:
// declare a queue for the consumer
final String queueName = channel.queueDeclare().getQueue();
// we bind to queue with the two different routingKeys
final String routingEven = "even";
final String routingOdd = "odd";
channel.queueBind(queueName, exchange, routingEven);
channel.queueBind(queueName, exchange, routingOdd);
channel.basicConsume(queueName, true, new DefaultConsumer(channel) { ... });
The Consumer will now receive the messages in the order that they were published, regardless of the fact that you used different topics.
There are some good 5-Minute Tutorials in the RabbitMQ documentation that might be helpful:
https://www.rabbitmq.com/tutorials/tutorial-five-java.html
I have a project that involves rabbitmq. The problem that I have is illustrated as follows:
So now, let me describe the scenario. I have n number of queues which subscribed to topic1.
Now my question is if I publish 3 messages in sequence, which are shown as 1, 2 and 3 into broker called Exchange, will rabbitmq Guarantee the sequence of those messages in all queues?
The only thing that I found was in rabbitmq documentation Message ordering guarantees which was taking about
Section 4.7 of the AMQP 0-9-1 core specification explains the conditions under which ordering is guaranteed: messages published in one channel, passing through one exchange and one queue and one outgoing channel will be received in the same order that they were sent. RabbitMQ offers stronger guarantees since release 2.7.0.
So can anyone help me out and point me to the right doc or example that shows whether it is guaranteed or not?
Thanks
As the other poster mentioned, your scenario should work fine assuming a simple/basic consumer setup. But here's some additional info that might explain why.
I wasn't sure quite what nuances might have been wrapped up in that section of the documentation either, until I looked up exactly what a Channel was. A connection to RabbitMQ can have multiple "mini-connections" within it called channels. Each of these channels are independent and thus you could send multiple messages to the broker via multiple channels.
So as long as the messages in your scenario are sent on a single channel (you'd have to explicitly try to use multiple channels), they'll arrive in the queue in the same order you sent them. As long as the messages are consumed via a single channel, they'd arrive on the consumer in the same order they arrived in the queue (also being the same order they were sent).
From: https://www.rabbitmq.com/tutorials/amqp-concepts.html
Some applications need multiple connections to an AMQP broker. However, it is undesirable to keep many TCP connections open at the same time because doing so consumes system resources and makes it more difficult to configure firewalls. AMQP 0-9-1 connections are multiplexed with channels that can be thought of as "lightweight connections that share a single TCP connection".
What you have quoted answers your question perfectly. The only question is what your consumer set up looks like. If you have each queue connected to its own channel and that consumer is running in its own thread, that thread will see each message in order as they were published.