I'm trying to remove the hours, minutes and seconds from a date using the following code :
TRUNC(column_date, 'YY')
But I get this : 01JAN2008:00:00:00, while I want this : 01JAN2008.
What should I do?
TRUNC() works as expected, and returns the original date truncated to year, as a date datatype. You want to format this date before displaying it (this actually means converting it to a string). For this, you can use the TO_CHAR() function.
You probably want:
TO_CHAR(TRUNC(column_date, 'YY'), 'ddmonyyyy')
Please note that this expression could be simplified to avoid the use of TRUNC(), as follows:
'01JAN' || TO_CHAR(column_date, 'yyyy')
I think you want to_char: https://docs.oracle.com/database/121/SQLRF/functions216.htm#SQLRF06129
Try using it in this way:
SELECT TO_CHAR(column_date, 'DD/MON/YYYY')
FROM x;
Where x is the table you are trying to query.
you only need to use
select to_char(column_date,'ddMONyyyy') FROM yourTable
Even you can invoke with
select to_char(column_date,'ddMONyyyy','nls_date_language=english') FROM yourTable
to guarantee to see the abbreviation JAN in the case your session/system date language value is different than english
to display as expected.
Related
When running
select processing_date from table;
i got this result "04-30-2020 20.12.49.978711"
what i want to change the format of the result to "30-APR-20"
is there a way i can do that ?
i tried select to_date(processing_date,'mm-dd-yyyy') from table; but it gives me errors
any help ?
You want to_char():
select to_char(processing_date, 'MM-DD-YYYY')
Dates are stored as an internal format, which you cannot change. If you want the date formatted in a particular way, then one solution is to convert to a string with the format you want.
EDIT:
The date appears to be a string. You can convert it to a date using:
select to_date(substr(processing_date, 1, 10), 'MM-DD-YYYY')
You can then either use as-is or use to_date() to get the format you really want.
I am not sure how to query for a date and I have tried it without the ' ' but it does not work. I was wonder if this is correct. Dateofemployment is a Date in the database and the date I put there is the date.
SELECT s
FROM Salesmen s
WHERE s.dateOfEmployment < '26-06-2012'
ORDER BY s.salepersonId ASC
Never assume there's a specific date format (dmy,ymd,mdy,etc.), always use the functions of your DBMS for writing dates instead of writing a string literal, e.g. TO_DATE in Oracle (and some others).
In best case you can use Standard SQL's date literals:
WHERE s.dateOfEmployment < DATE '2012-06-26'
Most DBMSes support it and there's no ambiguity because there's only one format allowed: yyyy-mm-dd
Your query is correct and you must put the two quotes since dateOfEmployment is a date. However, be careful with the position of the day and the month and make sure that your query does what you want.
When you leave out the quotes, you have a simple arithmetic expression: 26 - 06 - 2012. This is equal to something like -1992. That is an integer and not a date, so presumably the comparison will either generate an error or at least never return true.
When putting dates in queries, you should use ISO standard format: YYYY-MM-DD. Most databases will accept the following:
WHERE s.dateOfEmployment < '2012-06-26'
In Oracle, you need to add date before the constant.
I understand that querying a date will fail as its comparing a string to date and that can cause an issue.
Oracle 11.2 G
Unicode DB
NLS_DATE_FORMAT DD-MON-RR
select * from table where Q_date='16-Mar-09';
It can be solved by
select * from table where trunc(Q_date) = TO_DATE('16-MAR-09', 'DD-MON-YY');
What I don't get is why this works.
select* from table where Q_date='07-JAN-08';
If anyone can please elaborate or correct my mindset.
Thanks
Oracle does allow date literals, but they depend on the installation (particularly the value of NLS_DATE_FORMAT as explained here). Hence, there is not a universal format for interpreting a single string as a date (unless you use the DATE keyword).
The default format is DD-MM-YY, which seems to be the format for your server. So, your statement:
where Q_date = '07-JAN-08'
is interpreted using this format.
I prefer to use the DATE keyword with the ISO standard YYYY-MM-DD format:
where Q_Date = DATE '2008-01-07'
If this gets no rows returned:
select * from table where Q_date='16-Mar-09';
but this does see data:
select * from table where trunc(Q_date) = TO_DATE('16-MAR-09', 'DD-MON-YY');
then you have rows which have a time other than midnight. At this point in the century DD-MON-RR and DD-MON-YY are equivalent, and both will see 09 as 2009, so the date part is right. But the first will only find rows where the time is midnight, while the second is stripping the time off via the trunc, meaning the dates on both sides are at midnight, and therefore equal.
And since this also finds data:
select* from table where Q_date='07-JAN-08';
... then you have rows at midnight on that date. You might also have rows with other times, so checking the count with the trunc version might be useful.
You can check the times you actually have with:
select to_char(q_date, 'YYYY-MM-DD HH24:MI:SS') from table;
If you do want to make sure you catch all times within the day you can use a range:
select * from table where
q_date >= date '2009-03-16'
and q_date < date '2009-03-17';
Quick SQL Fiddle demo.
Although it sounds like you're expecting all the times to be midnight, which might indicate a data problem.
Oracle SQL automatically converts my field D.START_DT to the following format:
TO_CHAR(D.START_DT,'YYYY-MM-DD')
Which makes it difficult for me to modify my own date format.
I've tried wrapping another TO_CHAR around it with no luck.
TO_CHAR(TO_CHAR(D.START_DT,'YYYY-MM-DD'), 'MM/DD')
And I've tried SUBSTR to select certain characters, with no luck. I think the hyphen is getting int he way.
SUBSTR(TO_CHAR(D.START_DT,'YYYY-MM-DD'), 6, 7) || '/' || SUBSTR(TO_CHAR(D.START_DT,'YYYY-MM-DD'), 9, 10)
What is the work around for this?
I agree with RMAN Express and see no problems converting dates to any format you need...
In case you still have problems try this (first to_char() in outer query is optional):
SELECT to_char(to_date(some_date, 'YYYY-MM-DD'), 'MM/DD') final_date
FROM
(
SELECT TO_CHAR(SYSDATE,'YYYY-MM-DD') some_date -- this is your "auto converted" date
FROM dual
)
/
A DATE datatype has no format. When you see a date printed on a screen, there was something that APPLIED the format you see. Could be a "default" in the program you are using (like SQL Developer) or your NLS setting, etc. But, a DATE datatype has no format. So, you have complete control over the format you see on screen.
The simplest is to use the TO_CHAR function:
select TO_CHAR(D.START_DT,'YYYY') from dual;
returns just the four digit year.
See TO_CHAR date format options.
http://docs.oracle.com/cd/E11882_01/server.112/e26088/sql_elements004.htm#CDEHIFJA
You should always supply the format in your code and not rely on some other "default" to supply it.
Thanks for your help. I am not able to make out the type/format of the "Value" in a Date column.I guess its in Julian Date format.
The Column is paid_month and the values are below.
200901
200902
So,please help in writing SQL query to convert the above values(Mostly in Julian Format) in the Date Column to normal date (MM/DD/YYYY) .
Thanks
Rohit
Hi,
I am sorry for missing in giving the whole information.
1)Its a Oracle Database.
2)The column given is Paid_Month with values 200901,200902
3)I am also confused that the above value gives month & year.Day isnt given if my guess is right.
4)If its not in Julian format ,then also please help me the SQL to get at least mm/yyyy
I am using a Oracle DB and running the query
THANKS i GOT THE ANSWER.
**Now,i have to do the reverse meaning converting a date 01/09/2010 to a String which has 6 digits.
Pls help with syntax-
select to_char(01/01/2010,**
It looks like YYYYMM - depending on your database variant, try STR_TO_DATE(paid_month, 'YYYYMM'), then format that.
Note: MM/DD/YYYY is not "normal" format - only Americans use it. The rest of the world uses DD/MM/YYYY
For MySQL check
http://dev.mysql.com/doc/refman/5.1/en/date-and-time-functions.html#function_date-format
Example:
SELECT DATE_FORMAT(NOW(), '%d/%m/%Y')
For MySQL, you would use the STR_TO_DATE function, see http://dev.mysql.com/doc/refman/5.0/en/date-and-time-functions.html#function_str-to-date
SELECT STR_TO_DATE(paid_month,'%Y%m');
Sounds like the column contains some normal dates and some YYYYMM dates. If the goal is to update the entire column, you can attempt to isolate the YYYYMM dates and update only those. Something like:
UPDATE YourTable
SET paid_month = DATE_FORMAT(STR_TO_DATE(paid_month, '%Y%m'), '%m/%d/%Y')
WHERE LENGTH(paid_month) = 6
SELECT (paid_month % 100) + "/01/" + (paid_month/100) AS paid_day
FROM tbl;
I'm not sure about how oracle concatenates strings. Often, you see || in SQL:
SELECT foo || bar FROM ...
or functions:
SELECT cat (foo, bar) FROM ...