SQL order by 100% not ordering first - sql

Question

I have a query that shows my counter's accuracy and I'm doing a simple order by accuracy. But, what is happening it is ordering correctly BUT 100% appears at the bottom and not in correct order. I have moved the order by, but I may be missing something?
QUERY:
select counted_by_user_id, total, defects, trunc((total-defects)/total*100,2)||'%' as accuracy from
(
select counted_by_user_id, sum(locations) as total, sum(numberOfDefectBins) as defects from
(
select counted_by_user_id, locations, numberOfDefectBins from
(
select trunc(ical.last_updated_date_utc) as CountDate,ip.process_name,ipl.icqa_process_id,ical.counted_by_user_id,count(*) as locations, (
SELECT COUNT(iid.icqa_ical_detail_id)
FROM icqa_process_locations ipl1, icqa_count_attempt_logs ical1, icqa_ical_details iid
WHERE ipl1.icqa_process_id = ipl.icqa_process_id
AND ical1.icqa_count_attempt_id = ipl1.icqa_count_attempt_id
AND ical1.counted_by_user_id = ical.counted_by_user_id
AND iid.icqa_count_attempt_log_id = ical1.icqa_count_attempt_log_id
AND iid.is_defective = 'Y' and trunc(ipl1.last_updated_date_utc) = trunc(sysdate)) as numberOfDefectBins
from icqa_count_attempt_logs ical left join icqa_process_locations ipl
on ical.icqa_count_attempt_id = ipl.icqa_count_attempt_id
left join ICQA_PROCESSES ip on ipl.icqa_process_id= ip.icqa_process_id
where trunc(ical.last_updated_date_utc) = trunc(sysdate)
AND ical.counted_by_user_id IS NOT NULL
group by trunc(ical.last_updated_date_utc), ip.process_name, ipl.icqa_process_id, ical.counted_by_user_id
order by ical.counted_by_user_id
))
group by counted_by_user_id
)
order by accuracy desc;
RESULT:
counted_by_user_id total defects accuracy
dggonza 346 1 99.71%
giermanc 225 1 99.55%
kylecoll 659 4 99.39%
manansal 71 1 98.59%
jssuarez 271 5 98.15%
jhheredi 464 10 97.84%
tabilinl 185 4 97.83%
darinc 102 3 97.05%
tostab 484 18 96.28%
alicmena 25 1 96%
reyesk 733 31 95.77%
genej 478 22 95.39%
yadirac 73 4 94.52%
lhherold 505 28 94.45%
anamarih 465 30 93.54%
pineiror 380 25 93.42%
nallelys 349 31 91.11%
almquij 112 12 89.28%
kustance 357 50 85.99%
arteagaa 54 12 77.77%
gardne 848 0 100%
willij 5 0 100%
castnera 21 0 100%
pbarbara 43 0 100%
caudilr 493 0 100%
jennifei 27 0 100%

Answer 1

Of course. Because you are sorting a string not a number.
There are multiple solutions:
order by length(accuracy) desc, accuracy;
is probably the easiest.
Some others:
order by cast(replace(accuracy, '%', '') as float);
order by (total-defects)/total;
order by (case when accuracy = '100%' then 1
when accuracy >= '10%' then 2
else 3
end), accuracy desc