SQL Server group by date - sql

Question

SELECT [DATE], [AMOUNT], SUM(AMOUNT) OVER (ORDER BY DATE) AS 'Running Total'
FROM PeopleActi
WHERE INSTANCE = 'Bank'
AND DATE IS NOT NULL
GROUP BY [DATE], [AMOUNT];
In the code above I selecting a user's date, amount and the "SUM(AMOUNT) OVER (ORDER BY DATE) AS 'Running Total'" is the running total of their costs over a period of dates. When I run this code I get the following results:
DATE AMOUNT Running Total
2018-10-05 100 100
2018-10-06 1000 1100
2018-10-07 5000 6100
2018-10-08 2000 8100
2018-10-09 1000 9100
2018-10-10 5000 14100
2018-10-11 3000 25100
2018-10-11 8000 25100
This works nicely but my issue is the last two rows. I wanted them to be grouped by their date and have the total amount for both same days, so it should be:
Date Amount Running Total
2018-10-11 11000 25100
Does anyone have an idea of how this can achieved? My [DATE] is of type DATE.
UPDATE!!!!
I've seen some of your solutions and they are good but its important I display the AMOUNT and the Running Total amount as well, so the final result should be...
DATE AMOUNT Running Total
2018-10-05 100 100
2018-10-06 1000 1100
2018-10-07 5000 6100
2018-10-08 2000 8100
2018-10-09 1000 9100
2018-10-10 5000 14100
2018-10-11 11000 25100
Thank you everyone for the help so far!

Answer 1

Group up the amounts and then do your cumulative total
WITH CTE
AS
(
SELECT A.Dt,
SUM(A.Amount) AS Amount
FROM (
VALUES ('2018-10-05',100),
('2018-10-06',1000),
('2018-10-07',5000),
('2018-10-08',2000),
('2018-10-09',1000),
('2018-10-10',5000),
('2018-10-11',3000),
('2018-10-11',8000)
) AS A(Dt,Amount)
GROUP BY A.Dt
)
SELECT C.Dt,
C.Amount,
SUM(C.Amount) OVER (ORDER BY C.Dt) AS CumTotal
FROM CTE AS C;

Answer 2

Try like below
SELECT [DATE],sum( [AMOUNT]), SUM(AMOUNT) OVER (ORDER BY DATE) AS 'Running Total'
FROM PeopleActi
WHERE INSTANCE = 'Bank'
AND DATE IS NOT NULL
GROUP BY [DATE]

Answer 3

If you need groping sum then why you are using window function, only aggregation is enough :
SELECT [DATE], SUM([AMOUNT])
FROM PeopleActi
WHERE INSTANCE = 'Bank' AND DATE IS NOT NULL
GROUP BY [DATE];

Answer 4

Try this
;WITH CTe([DATE],AMOUNT)
AS
(
SELECT '2018-10-05', 100 UNION ALL
SELECT '2018-10-06', 1000 UNION ALL
SELECT '2018-10-07', 5000 UNION ALL
SELECT '2018-10-08', 2000 UNION ALL
SELECT '2018-10-09', 1000 UNION ALL
SELECT '2018-10-10', 5000 UNION ALL
SELECT '2018-10-11', 3000 UNION ALL
SELECT '2018-10-11', 8000
)
SELECT DISTINCT [DATE],SUM(AMOUNT)OVER(PARTITION BY [DATE] ORDER BY [DATE]) AMOUNT , SUM(AMOUNT)OVER( ORDER BY [DATE]) AS RuningTot FROM CTe
Script
SELECT DISTINCT [DATE],
SUM(AMOUNT)OVER(PARTITION BY [DATE] ORDER BY [DATE]) AS AMOUNT,
SUM(AMOUNT) OVER (ORDER BY DATE) AS 'Running Total'
FROM PeopleActi
WHERE INSTANCE = 'Bank'
AND DATE IS NOT NULL

Answer 5

I would use a CTE to first group by Date, and then do your running total ..
So something like
with myAmounts AS
(
SELECT [DATE], SUM([AMOUNT]) AS Amount
FROM PeopleActi
WHERE INSTANCE = 'Bank'
AND DATE IS NOT NULL
GROUP BY [DATE]
)
SELECT [DATE], [AMOUNT], SUM(AMOUNT) OVER (ORDER BY DATE) AS 'Running Total'
FROM myAmounts
GROUP BY [DATE], [AMOUNT]
;
HTH,
B
ps; just saw that its the same answer as another .. democoding in action

Answer 6

Every field in a group by is going to cause it to potentially create new lines. If you SUM the amount field and remove it from your grouping, that should solve the issue. EDIT: I see the issue, I provided a fully stand alone example of the query below that you can adapt.
DECLARE #PeopleActi TABLE ([DATE] DATE,[AMOUNT] MONEY)
INSERT INTO #PeopleActi SELECT '2018-10-05',100
INSERT INTO #PeopleActi SELECT '2018-10-06',1000
INSERT INTO #PeopleActi SELECT '2018-10-07',5000
INSERT INTO #PeopleActi SELECT '2018-10-08',2000
INSERT INTO #PeopleActi SELECT '2018-10-09',1000
INSERT INTO #PeopleActi SELECT '2018-10-10',5000
INSERT INTO #PeopleActi SELECT '2018-10-11',3000
INSERT INTO #PeopleActi SELECT '2018-10-11',8000
SELECT *, SUM(AMOUNT) OVER (ORDER BY DATE) AS 'Running Total'
FROM (
SELECT [DATE], SUM([AMOUNT]) AS AMOUNT
FROM #PeopleActi
WHERE DATE IS NOT NULL
GROUP BY [DATE]
) a
GROUP BY [DATE],Amount

Answer 7

Try Subselect:
SELECT p.[DATE], p.[AMOUNT], SUM(AMOUNT) OVER (ORDER BY DATE) AS 'Running Total'
FROM
(
select [date], sum([amount]) as Amount from PeopleActi
WHERE INSTANCE = 'Bank'
AND DATE IS NOT NULL
group by [date]
) p
GROUP BY p.[DATE], p.[AMOUNT]