I have this requirement: There is a field of 8-byte length and I want to extract the last 4 bytes using SQL.
Example: There is date 01012017 so I want only 2017. How can I achieve this using WHERE clause.
You should select the data in full flesh, then use
LOOP AS it_fulldate ASSIGNING <ls_fulldate>.
<ls_fulldate>-date = <ls_fulldate>-date+4(4).
ENDLOOP.
But usually, date time data type is YYYYMMDD so the correct might be <ls_fulldate>-date+0(4)
Related
In Table have a Date field of type date and I get 2 date from and to as String.
I want to filter the recodrs that exist between these 2 dates.
What will be the best way to select
The best is to transform the string dates into dates using your DBMS provided transformation functions,
Using Oracle for instance, i would write :
where
your_date_field
between to_date(from,format_of_from) and to_date(to,format_of_to)
Having some issues deleting rows from a data set. They need to be deleted by a date criteria, but the variable is in e8601dt. format. One thing I noticed about the variable is that its a number type variable, but left aligned (not sure if that has relevance or not), so I attempted to substring, and some additional attempts (below)...no success -
PROC SQL;
DELETE *
FROM DATASETS.BATCH_REPORT
WHERE datepart(BATCH_DATE) > '2015-10-01'
;
QUIT;
PROC SQL;
DELETE *
FROM DATASETS.BATCH_REPORT
WHERE BATCH_DATE > '11oct2015'd
;
QUIT;
Assuming there has to be an easy way to call out a value in this format...or will I need to convert this variable to a more compliable format, then do my processing?
OK...did some research. Apparently (and some one please correct me if I am wrong)...to use the e8601dt. format, a date value needs to be multiplied by 86400, then you can apply the format. So.....dividing by 86400 brought me back to the SAS data as an integer. This did the trick :
PROC SQL;
DELETE *
FROM SETS
WHERE ID >= 20372
;
QUIT;
You're close! Date conversions are a pain between systems. The representation of the values depends on the environment configuration.
Within proc SQL, I think you have to specify oracle functions (not the SAS datepart) Looks like you've figured out that Oracle's 'DATE' datatype stores both date&time within the same value. The DATE datatype stores the year (including the century), the month, the day, the hours, the minutes, and the seconds (after midnight). SAS has 2 different date types: date and datetime.
I'd suggest using the oracle to_date() function to compare against a character date, i.e.
WHERE BATCH_DATE > to_date('2015-10-01','yyyy-mm-dd')
If desired, you could use the oracle to_char(BATCH_DATE,'mm-dd-yyyy') to cast the date variable to a text value and then compare on the text value. But you loose some of the comparison power.
....edited due to new info about ...ew... db2 ..... :-)
I'm way NOT a DB2 guy, but maybe something like this?
First, set the date as in: (the date passed to DB2 needs the double quotes):
CALL SYMPUT('INT_DATE',"'"||PUT(sas_date,YYMMDDD10.)||"'");
Then use in the SQL as in:
PROC SQL ;
WHERE BATCH_DATE >= &INT_DATE
https://communities.sas.com/t5/SAS-Procedures/DB2-Date9-format-To-SAS-Serial-Date/td-p/32436
i'm new to MS Access..
one of my Access table CHECKOUT having a column name CHECK-TIME with Date/time data type
values in that column are like 7/15/2013 10:56:22 AM,9/19/2013 6:54:37 PM....
i want to select the data based on date like `7/15/2013'
how to write the query for this task ???
thanks in advance..
First off, the way to specify date literals is with hash (#) not any form of quote or backtick.
Secondly, you can't do LIKE comparisons with dates, not that I've ever seen anyway.
Thirdly, it's always best to specify dates in yyyy-mm-dd format because it's an unambiguous format.
This example should give you what you need:
SELECT
*
FROM
CHECKOUT
WHERE
datevalue([CHECK-TIME]) = #2013-07-15#
The datevalue() function takes a parameter, usually a string but in this case a datetime, and converts it to a date, thus stripping off the time. This allows us to check for equality against a date literal.
I have to run column checks for data consistency and the only thing that is throwing off my code is checking for character lengths for dates between certain parameters.
SEL
sum(case when ( A.date is null or (character_length(A.date) >8)) then 1 else 0 end ) as Date
from
table A
;
The date format of the column is YYYY-MM-DD, and the type is DA. When I run the script in SQL Assistant, I get an error 3580 "Illegal use of CHARACTERS, MCHARACTERS, or OCTET_LENGTH functions."
Preliminary research suggests that SQL Assistant has issues with the character_length function, but I don't know how to adjust the code to make it run.
with chareter length are you trying to get the memory used? Becuase if so that is constant for a date field. If you are trying to get the length of the string representation i think LENGTH(A.date) will suffice. Unfortanatly since teradata will pad zeros on conversions to string, I think this might always return 10.
UPDATE :
Okay so if you want a date in a special 'form' when you output it you need to select it properly. In teradata as with most DBs Date are not store in strings, but rather as ints, counting days from a given 'epoch' date for the database (for example the epoch might be 01/01/0000). Each date type in teradata has a format parameter, which places in the record header instructions on how to format the output on select. By default a date format is set to this DATE FROMAT 'MM/DD/YYYY' I believe. You can change that by casting.
Try SELECT cast(cast(A.date as DATE FORMAT 'MM-DD-YYYY') as CHAR(10)) FROM A. and see what happens. There should be no need to validate the form of the dates past a small sample to see if the format is correct. The second cast forces the database to perform the conversion and use the format header specified. Other wise what you might see is the database will pass the date in a date form to SQL Assitant and sql assitant will perform the conversion on the application level, using the format specified in its own setting rather then the one set in the database.
I have two columns. ColA and ColB contains char(10) with data "20090520" and "20090521".
I want to select and get the date difference in days. I have tried using Format() and CDate()
but MS Access always display as #ERROR.
Access prefers its dates in this format:
#2009-12-01#
You can convert your date to something Access understands with:
CDate(Format([ColA], "0000-00-00"))
Or alternatively:
DateSerial(Left([ColA],4),Mid([ColA],5,2),Right([ColA],2))
And to display the result in your preferred format:
Format(<date here>, "dd-mm-yyyy")
Try using DateSerial() to convert the dates:
DateSerial(Left([FieldName],4),Mid([FieldName],5,2),Right([FieldName],2))
If at all possible, change the datatype to a date datatype. You should not store dates as character data.
I am connecting to another database which I have no control on. That is why this problem occurred. Thanks for the feedback.