function with loop for urls won't return all of them - beautifulsoup

Question

I am working on a project to pull details from state reports on restaurant inspections. Each inspection has its own url. I am able to gather the values into a dictionary, but only return one at a time. In the call to the function, if I don't specify a specific library entry, I get an error: ''list' object has no attribute 'timeout'' If it ask for a specific entry, I get a good return. How can I get them all?
# loop through the url list to gather inspection details
detailsLib = {}
def get_inspect_detail(urlList):
html = urlopen(urlList)
soup = bs4.BeautifulSoup(html.read(), 'lxml')
details = soup.find_all('font', {'face': 'verdana'})[10:]
result = []
for detail in details:
siteName = details[0].text
licNum = details[2].text
siteRank = details[4].text
detailsLib = {
'Restaurant': siteName,
'License': licNum,
'Rank': siteRank,
}
result.append(detailsLib)
return result
get_inspect_detail(urlList[21])
So I can get the 21st restaurant on the list, repeating 36 times, but not all of them.
Another question for another day is where to do the clean-up. The details will need some regex work but I'm unsure whether to do that inside the function (one at a time), or outside the function by calling all values from a specific key in the library.

Answer 1

Call get_inspect_detail() once per item in urlList, and save all the results.
all_results = []
for url in urlList:
details = get_inspect_detail(url)
all_results.extend(details)