I am using SQL Server 2012 and T-SQL. I have a time column of 200 rows with different times (hh:mm:ss). I need to update it with random times. So all the data times I have now will be updated with new data times. Thank you!
Here is one method:
select cast(dateadd(second, rand(checksum(newid()))*60*60*24, 0) as time)
UPDATE <YOUR_TABLE> SET <TIME_COLUMN> = DATEADD(second, Rand(Cast(Newid() AS VARBINARY)) * datediff(second,'00:00:00', '23:59:59'), '00:00:00')
Assume you have the following 3 rows with a time column that contains different times:
CREATE TABLE table_with_times (timecolumn TIME);
INSERT INTO table_with_times VALUES ('20:00:00'),('05:00:59'),('22:30:50');
You can update each time column to new random time by computing random values for hour/minutes/seconds:
select * from table_with_times;
UPDATE table_with_times SET timecolumn = CAST(RIGHT('00' + CAST(ABS(CHECKSUM(NewId())) % 24 AS VARCHAR(2)),2)+':'+ RIGHT('00' + CAST(ABS(CHECKSUM(NewId())) % 60 AS VARCHAR(2)),2)+':'+ RIGHT('00' + CAST(ABS(CHECKSUM(NewId())) % 60 AS VARCHAR(2)),2) AS TIME);
select * from table_with_times;
Try it on http://sqlfiddle.com/
Related
I am trying to create a table in SQL which is about Music, it should contain songDuration. Which means I gotta hold minutes:seconds information in the table. But i have no idea what to use for the type. I am using SQL server.
Edit: I want to use the database for an ASP.NET Core web application. I was using a ready-to-use SQL database like northwnd. Now, I am trying to create one. So, I will not see the timing with SELECT function in SQL query. So, I need to use something that makes it mm:ss otomaticly. Is there is a type that I can decleare like that?
create table musics(
songDuration type,
...)
Why just don't you use int?
So you could calculate duration in the way you like.
E.g. minutes,hours, etc.
There's a datatype time which would be the logical choice, that stores it in format HH:mm:ss with an optional amount of fractional seconds determined by the size you declare the field (e.g. time(3) holds it to three decimal places)
If your source data is already in this notation it makes it getting it in the table easy and simple sorting/filtering operates as you expect. The downside to doing this is if you want to do certain operations such as SUM or AVG (because as a_horse_with_no_name pointed out in their comment) time technically represents a point in time not a duration and you'd have to do some workaround like so:
SELECT totalduration = SUM(DATEDIFF(SECOND, '0:00:00', duration))
FROM dbo.table
Alternatively you could store the number of (say) seconds in the duration using an int, but if you don't already have the information in that format you'd have to do some (light) conversion when inserting the data, and then back if you want to display in mm:ss
e.g:
SELECT CONVERT(varchar, DATEADD(SECOND, durationinseconds, 0), 8) FROM dbo.table
which would convert it back to hh:mm:ss format.
I do this by using an int column, and store the seconds there.
In your client you can calculate from the seconds howmany days, hours, minutes and seconds it is and display it like you want.
To display it in sql you can use this for example
declare #seconds int = 350
select right('00' + convert(varchar, datepart(hour, dateadd(s, #seconds, 0)) + ((#seconds / 86400) * 24)), 2)
+ ':' + right('00' + convert(varchar, datepart(minute, dateadd(s, #seconds, 0))), 2)
+ ':' + right('00' + convert(varchar, datepart(second, dateadd(s, #seconds, 0))), 2)
this will display
00:05:50
which is 0 hours, 5 minutes and 50 seconds
IF the value of seconds is larger than a day, this will be no problem. The number of hours will simply be greater
a value of 350000 will display 97:13:20
I have a Table in SQL server with a column "Time" having data type as time(7). Need to call the sum of this column, and when I use the following statement, it returns result as integer only.
Eg. If total time is 1:30:00,I expect result as 1.5. But the code I use doesn't get me this, it get me result as 1. Please check if you have a solution.
The code I used is
SELECT SUM(DATEPART(ss,Time) + DATEPART(mi,Time)*60 + DATEPART(hh,Time)*3600)/3600 AS TotalTime FROM dbo.Table
SELECT (
DATEPART(hh,Time) +
DATEPART(mi,Time) / 60.0 +
DATEPART(ss,Time) / 3600.0
) AS TotalTime
FROM dbo.Table
Try below - you don't need sum() function here and in your case, it is showing 1 because your result is 5400/3600 which is 1 but you need to add a float value as you are expecting float result
SELECT (DATEPART(ss,'1:30:00') + DATEPART(mi,'1:30:00')*60 +
DATEPART(hh,'1:30:00')*3600)/3600.00
AS TotalTime FROM dbo.Table
Try this, you can change the datepart argument based on your needs here is the full list
SELECT SUM(CAST(DATEDIFF(MINUTE, '00:00:00', [Time]) as float)/60) AS TotalHours FROM [dbo].[Table]
When you divide some value by int type, the result will be also int (the fraction is just dropped). Therefore, you need to convert a divider of 3600 from int to decimal:
SELECT SUM(DATEPART(ss,Time) + DATEPART(mi,Time)*60 + DATEPART(hh,Time)*3600)/CONVERT(DECIMAL(16,4), 3600) AS TotalTime FROM dbo.Table
If you want the difference in decimal hours, then do the following:
Convert the time values to seconds.
Sum the seconds.
Divide by 60 * 60
So:
select sum(datediff(second, 0, v.t)) / (60.0 * 60)
from (values (convert(time, '00:10:01')),
(convert(time, '01:00:03'))
) v(t)
There is no reason to break the value in to component parts. That just seems unnecessarily complicated.
I want to fetch only month and year from a date column in SQL Server.
Example: if today's date is 02/03/2019, then I want 0319.
Note: I want the result in same order (2 digit month and 2 digit year). Zero should not be removed from month.
As an alternative approach, you could go for:
RIGHT(REPLACE(CONVERT(varchar(8),DateColumn,3),'/',''),4)
You can create a number using:
select month(datecol) * 100 + (year(datecol) % 100)
Prepending the zeros requires a bit more work:
select right('0' + convert(varchar(255), month(datecol) * 100 + (year(datecol) % 100)), 4)
Or, you can use format():
select format(datecol, 'MMyy')
You can try this
substring(convert(nvarchar,#date,12),3,2) + left(convert(nvarchar,#date,12),2)
You can create an user defined function, and then apply to your column/s
create function udf_Getmonthyear(#date as date)
RETURNS nchar(4)
BEGIN
DECLARE #d_format nchar(6) = (select convert(nvarchar,#date,12))
RETURN (select SUBSTRING(#d_format,3,2) + left(#d_format,2))
end
go
Use function DATEPART in TSQL to get any part of a DateTime value. e.g:
DATEPART(yy,datecol) gives you 4 digit year part of a DateTime column (e.g: datecol), using the % (modulus) operator you can get 2 digit year DATEPART(yy,datecol)%100.
DATEPART(mm,datecol) gives you month part of the datecol field.
select Right('0'+cast(DATEPART(mm,datecol) as varchar(2)),2) +
Right('0'+cast(DATEPART(yy,datecol)%100 as varchar(2)),2) MonthYearPart
from MyTable
Regards
We have in our table, in SQL Server 2008, the datetime is only holding the date.
There is also an hour col and a minute col, there are for the appointment. the are both columns defined as number.
The hour is typically like this:
12.00
and minute is like 40.00. I tried adding them but it gives a total rather than
12:40 which is what we need. How can I get this to show 12:40. With the : would be better.
Well... taking a shot here, for SQL Server
declare #table table (d datetime,h decimal(4,2), m decimal(4,2))
insert into #table
values
('20170113',12.00,40.00),
('20170113',9.00,8.00)
select
d + cast(left(h,len(floor(h))) + ':' + cast(left(m,len(floor(m))) as varchar(2)) + ':' + '00' as datetime)
from
#table
Prepend 00. to minutes - please note that dot there.
Convert both to times.
Add them.
Convert result back to string.
This way You will also corectly handle situation like 12.40 + 00.30.00 = 13.10
There is a column in my Table. In which we are storing string value in format 'HH:MM'.During fetching records with this table every things works ok with
DATEDIFF(MINUTE, '00:00', ColumnName)
Problem is when we have Value greater than 23:59.
Its showing error like
Conversion failed when converting date and/or time from character string.
Can anybody suggest me the right approach for achieving this scenario.
If you are storing the value as something other than a time, why not just store the number of minutes and convert to whatever format you want on output?
Otherwise, I would suggest that you simply convert the value to minutes:
select (cast(left(ColumnName, 2) as int) * 60 +
cast(right(ColumnName, 2) as int)
) as Minutes
If you are not using date/time values, there is no requirement for using the functions specifically designed for them.
EDIT:
To handle hours longer than 99, use charindex():
select (cast(left(ColumnName, charindex(':', ColumnName) - 1) as int) * 60 +
cast(right(ColumnName, 2) as int)
) as Minutes
So it sounds like your saving the length of a time period. Try storing it in minutes. My query can handle numbers of different lengths since it's based on the colon.
DECLARE #yourTable TABLE (ColumnName VARCHAR(10));
INSERT INTO #yourTable
VALUES ('100:00'),
('24:20');
SELECT ColumnName,
(hr * 60) + minut AS time_period_in_minutes
FROM #yourTable
CROSS APPLY (SELECT CAST(SUBSTRING(ColumnName,0,CHARINDEX(':',ColumnName)) AS INT),
CAST(SUBSTRING(ColumnName,CHARINDEX(':',ColumnName) + 1,LEN(ColumnName)) AS INT)) CA(hr,minut)
Results:
ColumnName time_period_in_minutes
---------- ----------------------
100:00 6000
24:20 1460
Try to this
select DATEDIFF(MINUTE, '00:00', case when ISDATE(ColumnName)=0 then '00:00' else ColumnName end )