I just wanted to ask on how to notify a product on or before its expiry date in vb.net. I tried a lot of codes about it but still i am not able to solved this problem. I will really appreciate your help. Thank you
Since you didnt provide the table structure, I will try to help you understand the logic, which you can easily apply to your table.
SELECT Count(*)
FROM tbproducts
WHERE Datediff(d, now, tbproducts.expiarydate) > 0
Here you are simply saying, "please count for me how many products (rows) that passed their expiration day, when compared with right now"
Datediff(d, now, tbproducts.expiarydate) Will subtract today's date Now from the product's expiry date, and return the difference (in days d). This will return a long number.
So the difference between 12/7/2017 (now) and 12/5/2017 (expired 2 days ago), will be 7 (7th) - (minus) 5 (5th) = 2
And the difference between 12/7/2017 (now) and 12/10/2017 (not yet expired), will be 7 (7th) - (minus) 10 (10th) = -3
So as long as Datediff(d, now, tbproducts.expiarydate) returns a number over 0 then the product is expired
Related
I apologize, I am new at SQL. I am using BigQuery. I have a field called "last_engaged_date", this field is a datetime value (2021-12-12 00:00:00 UTC). I am trying to perform a count on the number of records that were "engaged" 12 months ago, 18 months ago, and 24 months ago based on this field. At first, to make it simple for myself, I was just trying to get a count of the number of records per year, something like:
Select count(id), year(last_engaged_date) as last_engaged_year
from xyz
group by last_engaged_year
order by last_engaged_year asc
I know that there are a lot of things wrong with this query but primarily, BQ says that "Year" is not a valid function? Either way, What I really need is something like:
Date() - last_engaged_date = int(# of months)
count if <= 12 months as "12_months_count" (# of records where now - last engaged date is less than or equal to 12 months)
count if <= 18 months as "18_months_count"
count if <= 24 months as "24_months_count"
So that I have a count of how many records for each last_engaged_date period there are.
I hope this makes sense. Thank you so much for any ideas
[How to] Return the number of months between now and datetime value [in BigQuery] SQL
The simples way is just to use DATE_DIFF function as in below example
date_diff(current_date(), date(last_engaged_date), month)
I need a WHERE statement where the date of the record is the previous day. I have the below code which will do this
WHERE DOC_DATE = dateadd(day,datediff(day,1,GETDATE()),0)
However I need this statement to get Friday's record when the current day is Monday. I have the below code but it will not work for me. No errors come back on SQL although no records results come back either. I have the below code for this
WHERE DOC_DATE = DATEADD(day, CASE WHEN datepart(dw,(GETDATE())) IN (2) then -3 ELSE -1 END ,0)
Important to add that this needs to be in a WHERE clause. This is for a Docuware administrative view I am creating. I have no control on how to write the SELECT statement, I only have access to edit the WHERE clause:
Here's a slightly "magical" way to compute the value that doesn't depend on any particular server settings such as datefirst. It's probably not immediately obvious how it works:
WHERE DOC_DATE = dateadd(day,datediff(day,'20150316',getdate()),
CASE WHEN DATEPART(weekday,getdate()) = DATEPART(weekday,'20150330')
THEN '20150313'
ELSE '20150315' END)
In the first line, we're computing the number of days which have elapsed since some arbitrary date. I picked a day in March 2015 to use as my base date.
The second line asks what today's day of the week is and if it's the same as some arbitrary "Known good" Monday. Just taking one value and comparing it to 2 depends on what your DATEFIRST setting is so I prefer not to write that.
In the third line, we decide what to do if it's a monday - I give a date that is 3 days before my arbitrary date above. If it wasn't a monday, we pick the day before.
Adding it all together, when we add the days difference from the arbitrary date back to one of these two dates from lines 3 and 4, it has the effect of shifting the date backwards 1 or 3 days.
It's can be an odd structure to see if you're not familiar with it - but combining dateadd/datediff and exploiting relationships between an arbitrary date and other dates computed from it can be useful for performing all kinds of calculations. A similar structure can be used for computing e.g. the last day of the month 15 months ago using just dateadd/datediff, an arbitrary date and another date with the right offset from the first:
SELECT DATEADD(month,DATEDIFF(month,'20010101',GETDATE()),'19991031')
As I said in a comment though, usually doing this sort of thing is only a short step away from needing to properly model your organisation's business days, at which point you'd typically want to introduce a calendar table. At one row per day, 20 years worth of pre-calculated calendar (adjusted as necessary as the business changes) is still less than 10000 rows.
You can try this.
WHERE DOC_DATE = DATEADD(DAY, CASE WHEN datepart(dw, GETDATE()) = 2 THEN -3 ELSE -1 END, CAST(GETDATE() AS DATE))
I need some help in this my case is
1-two parameters date from , date to
2-number of team parameter that manually enter by user for later on use in some calculation
rquirement
count only working days (6days per week ) without Friday based on filtered period (date from and date to)
Code
=(COUNT(IIF(Fields!Job_Status.Value="Closed",1,Nothing))) /
((DateDiff(DateInterval.day,Parameters!DateFrom.Value,Parameters!ToDate.Value
)) * (Parameters!Number_of_teams.Value))
Note
this code is working fine but it calculate all days
thanks in advance
Try this:
=(DATEDIFF(DateInterval.Day, CDATE("2016-02-14"), CDATE("2016-02-17")) + 1)
-(DATEDIFF(DateInterval.WeekOfYear, CDATE("2016-02-14"), CDATE("2016-02-17")) * 2)
-(IIF(WeekdayName(DatePart(DateInterval.Weekday,CDATE("2016-02-14"),FirstDayOfWeek.System))="sunday",1,0)
-(IIF(WeekdayName(DatePart(DateInterval.Weekday,CDATE("2016-02-17"),FirstDayOfWeek.System))="saturday",1,0)
))
It will ruturn count of monday to friday between the given range in the above case it returns 3. For StartDate = 2016-02-14 and EndDate = 2016-02-21 it returns 5.
UPDATE: Expression to exclude friday from the count.
=(DATEDIFF(DateInterval.Day, Parameters!DateFrom.Value, Parameters!ToDate.Value) + 1)
-(DATEDIFF(DateInterval.WeekOfYear, Parameters!DateFrom.Value, Parameters!ToDate.Value) * 1)
-(IIF(WeekdayName(DatePart(DateInterval.Weekday,Parameters!ToDate.Value,FirstDayOfWeek.System))="friday",1,0))
Tested with:
DateFrom ToDate Result
2016-02-12 2016-02-19 6
2016-02-12 2016-02-18 6
2016-02-12 2016-02-15 3
It is very strange to me see a saturday and sunday as working days instead of friday.
Let me know if this helps you.
The most sustainable solution for this kind of question, in the long term, is to create a "date dimension" aka "calendar table". That way any quirks in the classification of dates that don't conform to some neat mathematical pattern can be accommodated. If your government decides to declare date X a public holiday starting from next year, just add it to your public holidays column (attribute). If you want to group by say "work days, weekends, and public holidays" no need to reinvent the wheel, just add that classification to the calendar table and everyone has the benefit of it and you don't need to worry about inconsistency in calculation/classification. You might want the first or last working day of the month. Easy, filter by that column in the calendar table.
USERS
ID TIMEMODIFIED
1 1400481271
2 1400481489
3 1400486453
4 1400486525
5 1401777484
I have timemodified field, From timemodified, I need to get the rows of last 4 weeks by taking from today's date.
SELECT id FROM USERS
WHERE FROM_UNIXTIME(timemodified,'%d-%m-%Y') >= curdate()
AND FROM_UNIXTIME(timemodified,'%d-%m-%Y') < curdate()-1
Your times are already in Unix timestamp format. Bear in mind that it'll be far more efficient to compare [TIMEMODIFIED] against the current date converted to a Unix timestamp. In addition, you don't need to check any upper bound unless [TIMEMODIFIED] can be in the future.
Try:
-- 60x60x24x7x4 = 2419200 seconds in four weeks
SET #unix_four_weeks_ago = UNIX_TIMESTAMP(curdate()) - 2419200;
SELECT id FROM USERS
WHERE timemodified >= #unix_four_weeks_ago;
NB. Four weeks ago (i.e. today – 28 days) was 1,437,696,000 (24th July) at the time of this answer. The latest record in the sample you provided has a timestamp going back to the 3rd June 2014, and so none of these records will be returned by the query.
How can I create a stored procedure that accepts a start and end date.(e.g April 1 - April 30
1.) Get the business days including Saturdays x (a value). +
2.) Get Holidays x (a value)
and return the total.
I'm new to this, I guess it would be a tsql function. hmm.
any help would be appreciated.
Thanks
The simplest solution to this problem is to create a Calendar table that contains a value for every day you might want to consider. You could then add columns that indicate whether it is a business day or a holiday. With that, the problem becomes trivial:
Select ..
From Calendar
Where IsBusinessDay = 1
And Calendar.[Date] Between '2010-04-01' And '2010-04-30'
If you wanted the count of days, you could then do:
Select Sum( Case When IsBusinessDay = 1 Then 1 Else 0 End ) As BusinessDayCount
, Sum( Case When IsHoliday = 1 Then 1 Else 0 End ) As HolidayCount
From Calendar
Where Calendar.[Date] Between '2010-04-01' And '2010-04-30'
http://classicasp.aspfaq.com/date-time-routines-manipulation/how-do-i-count-the-number-of-business-days-between-two-dates.html
First, you will need to store all of the holidays into an independant table (Christmas, Easter, New Year Day, etc. with their respective dates (normally timed at midnight));
Second, you will have to generate, into a temporary table maybe, the dates of the office days, it then excludes the dates contained in the Holidays table.
Third, you may set the office hours to these dates depending on what day it is, if you have different working hours on different day.
That is the algorithm for you to find the appropriate code implementation.
Let me know if this helps!