I have table with column 1 same for client and column 2 has different value , if I find a column 2 with a value then all the records for the client should not show in my results
Column 1 Column2
1
2
3
In the above if I use where column2=1 then I should not have all the records
Basically I want to skip 123 if column 2 has 1
SELECT * FROM your_table WHERE Column1 <> '123' AND Column2 = 1
UPDATED with Join Condition
SELECT your_table.* FROM your_table
INNER JOIN clients ON your_table.Column1 = clients.NAME
WHERE your_table.Column2 = 1
AND clients.NAME <> 'abc'
Related
Tabel 1 :
ID1
ID2
ID3
MainID
Location
1
A
X
1AX
VIC
2
B
Y
2BY
SYD
3
C
W
3CW
TAS
4
D
Z
4DZ
TAS
Tabel 2 :
SALESID
QTY
AMT
DIFF
1AX
1
100
2
2BY
2
0
3
3CW
3
5
4DZ
3
12
2
Ignore other fields, I need to delete all raws in Tabel 1 where AMT in Tabel 2 has zero or no value for the SALESID.
For example, after the query, only raws containing 1AX & 4DZ should be remain in Tabel 1.
this can be done by subquery
get all MainID from table2 where amt is 0 or null
delete all rows that equal to previous fetched MainID
delete from table1 where MainID in (
select SALESID from table2 where AMT <=0 or AMT is null
)
You can use exists:
delete from table1
where exists (select 1
from table2 t2
where table1.mainid = t2.salesid and
(t2.amt = 0 or t2.amt is null)
);
Thinking an INNER JOIN would be much faster on larger data sets. Something like this:
DELETE
T1
FROM
Table1 T1
INNER JOIN
Table2 T2 ON T2.SalesID = T1.MainID
WHERE
IsNull(T2.Amt,0) = 0
Have a table like that. Let's pretend it is full table and we dont have any other rows:
ID Place
1 A
1 B
2 C
3 D
How can I perform such thing:
ID Place YesNo
1 A 1
1 B 1
1 C 0
1 D 0
2 A 0
2 B 0
2 C 1
2 D 0
3 A 0
3 B 0
3 C 0
3 D 1
For yes/no I need CASE statement but how to do the rest- full join table on itlself or some other options?
Thanks!
You can achieve that with two subqueries which each list the possible values of one of the columns. The two results should then be crossed to get all combinations. Finally outer join this with the original table to see which combinations actually occur:
SELECT first.ID,
second.Place,
CASE WHEN mytable.ID IS NULL THEN 0 ELSE 1 END AS YesNo
FROM (
SELECT DISTINCT ID
FROM mytable
) first
CROSS JOIN (
SELECT DISTINCT Place
FROM mytable
) second
LEFT JOIN mytable
ON mytable.ID = first.ID
AND mytable.Place = second.Place
ORDER BY first.ID,
second.Place
Here is an SQL fiddle
id idtest result
1 1 2
1 2 1
1 3 2
2 1 2
2 2 1
2 3 1
3 1 1
3 2 2
3 3 1
Would like to get all the rows with the same IDs that matches the condition.
For example: get all the rows with the same id where (idTest=2 and result=1) and (idTest=3 and result=2)
result:
id idtest result
1 1 2
1 2 1
1 3 2
What would be the query???
Thanks!
Do you mean this?
SELECT * FROM table WHERE id = 1 and (result = 1 OR result = 2)
How about his:
SELECT *
FROM table WHERE (idTest = 2 OR idTest = 3) AND (result=1 OR result=2)
ID test res
1 1 2
1 2 1
1 3 2
2 1 1
2 2 2
2 3 2
3 1 1
3 2 2
3 3 1
Sorry. This would be my table. and Would like to get all the rows with the same IDs that matches the condition. For example: get all the rows with the same id where (test=2 and res=1) and (test=3 and res=2)
Result:
ID test res
1 1 2
1 2 1
1 3 2
What would be the query in order to get the three rows ?? Thanks!
You can use EXISTS:
SELECT id, idTest, result
FROM dbo.TableName t
WHERE EXISTS
(
SELECT 1 FROM dbo.TableName t2
WHERE t.id = t2.id
AND(
( t2.idTest=2 AND t2.result=1 )
OR
( t2.idTest=3 AND t2.result=2 )
)
)
Demo
Update: result is different:
id idTest result
1 1 2
1 2 1 <-- satisfies your condition
1 3 2 <-- satisfies your condition
2 1 2
2 2 1 <-- satisfies your condition
2 3 1
So either my understanding was incorrect or your expected result. I have also all ID=2 because the second id-2 row matches the condition.
You seem to want all rows for id's that have rows with that particular combination. What about:
with ids as (
select id
from mytable
where (idTest=2 and result=1) or (idTest=3 and result=2)
group by id
having count(id) = 2
)
select mytable.* from mytable
inner join ids
on ids.id = mytable.id
This gets a list of id's where both conditions apply, and then gets all rows for those id's.
SqlFiddle
SELECT *
FROM table t1
WHERE EXISTS (SELECT 1 FROM table WHERE id = t1.id AND idtest = 2 AND result = 1)
AND EXISTS (SELECT 1 FROM table WHERE id = t1.id AND idtest = 3 AND result = 2)
Just keep adding more AND EXISTS if you need more
Or you can use IN if it makes more sense to you
SELECT *
FROM table
WHERE id IN (SELECT id from table where idtest = 2 and result = 1)
AND id IN (SELECT id from table where idtest = 3 and result = 2)
do you need a method that treats the condition(s) in a generic way, like if they're values in another table? Or do you only need a way to pull results of two independent conditions?
If the latter, then this should work:
SELECT
id
FROM
(SELECT id
FROM tbl
WHERE idTest=2 AND RESULT=1) cond1 INNER JOIN
(SELECT id
FROM tbl
WHERE idTest=3 AND RESULT=2) cond2 ON
cond1.id = cond2.id
otherwise, if your conditions are generic and stored in a table, you'd need something like:
SELECT
id
FROM
(SELECT id
FROM tbl FULL OUTER JOIN conditions c
WHERE c.isUseMe = 1 AND c.SEQ = 1 AND idTest=c.idTestVal AND result=c.resultVal) cond1 INNER JOIN
(SELECT id
FROM tbl FULL OUTER JOIN conditions c
WHERE c.isUseMe = 1 AND c.SEQ = 2 AND idTest=c.idTestVal AND result=c.resultVal) cond2 ON
cond1.id = cond2.id
if the 4 values are passed in as parameters, you'd need something like:
SELECT
id
FROM
(SELECT id
FROM tbl
WHERE idTest=#idTestVal1 AND result=#resultVal1) cond1 INNER JOIN
(SELECT id
FROM tbl
WHERE idTest=#idTestVal2 AND result=#resultVal2) cond2 ON
cond1.id = cond2.id
I have a question on SQL join which involve multiple condition in second joined table. Below is the table details
Table 1
pId status keyVal
---- ------- ------
100 1 45
101 1 46
Table 2
pId mode modeVal
100 2 5
100 3 6
101 2 7
101 3 8
I have above two tables and I am trying to join based on below condition to get pId's
pId's which has keyVal = 45 and status = 1 joined with table2 which has mode = 2 and modeVal 5 and mode =3 and modeVal = 6
the result I am expecting is to return pid = 100
Can you please help me with a join query ?
One way is to use GROUP BY with HAVING to count that the number of rows found is 2, of which 2 are matching the condition;
WITH cte AS (SELECT DISTINCT * FROM Table2)
SELECT t1."pId"
FROM Table1 t1 JOIN cte t2 ON t1."pId" = t2."pId"
WHERE t1."status" = 1 AND t1."keyVal" = 45
GROUP BY t1."pId"
HAVING SUM(
CASE WHEN t2."mode"=2 AND t2."modeVal"=5 OR t2."mode"=3 AND t2."modeVal"=6
THEN 1 END) = 2 AND COUNT(*)=2
If the values in t2 are already distinct, you can just remove the cte and select directly from Table2.
An SQLfiddle to test with.
SELECT columns
FROM table1 a, table2 B
WHERE a.pid = B.pid
AND a.keyval = 45
AND a.status = 1
AND (
(B.mode = 2 AND B.modeval = 5)
OR
(B.mode = 3 AND B.modeval = 6)
)
Below query should work for you perfectly
select distinct table1.pid FROM table1 JOIN table2
on table1.pid = table2.pid
WHERE table2.modeValue IN (5,6) AND table2.mode IN (2,3) AND table1.keyVal=45 and table1.status=1;
I have this table:
id type otherid
1 4 1234
2 5 1234
3 4 4321
As you can see there are 3 records, 2 of them belongs to otherid "1234" and got type of 4 and 5.
Last record belongs to otherid of "4321" and has only a type of 4.
I need to select all otherid that got only the type 4 and not the type5.
Example: after this select on that table the query shuould return only the record 3
Thanks
add1:
Please consider the TYPE can be any number from 1 up to 20.
I only need otherid that got type 4 but not type 5 ( except than that they can have any other type )
add2:
using mysql 5.1
This is kind of a workaround
SELECT * FROM (
SELECT GROUP_CONCAT('|',type,'|') type,other_id FROM table GROUP BY otherid
) t WHERE type LIKE '%|4|%' AND type NOT LIKE '%|5|%'
You could use a not exists subquery:
select distinct otherid
from YourTable as yt1
where yt1.type = 4
and not exists
(
select *
from YourTable as yt2
where yt1.otherid = yt2.otherid
and yt1.type <> yt2.type -- use this line for any difference
and yt2.type = 5 -- or this line to just exclude 5
)
Another way is by using a left join from where you exclude rows that have both type 4 and 5:
select a.*
from table1 a
left join table1 b on b.otherid = a.otherid and b.type = 5
where a.type = 4 and b.id is null