I am working on a query, where I have to fill a table's column ([Result_DateTime]) with datetime values.
The datetime based on two columns, both integer. One contains the date and the other is the time, as it is.
As you can see from the picture, it is a bit difficult to merge and convert these values to an actual datetime, because of the way they are stored. Mainly the time value causing problems.
I concluded how to convert the date column:
CONVERT(DATETIME, LEFT(20200131, 8))
but then I got stuck - what to do with the time and how to merge the two into one datetime effectively?
Using function STUFF looks nasty...
Could you help me out please? I am using SQL Server 2014
Below is one method to do it:
SELECT CAST(Convert(DATE, LEFT(DATEUPDT, 8)) AS VARCHAR(10)) +' '+CAST (TIMEUPDT/100 AS VARCHAR(4)) + ':' + CAST(TIMEUPDT%(100 * (TIMEUPDT/100)) AS VARCHAR(10))+':00'
FROM TEST_TABLE_TIME;
I think I found one solution. What I tried is to avoid using varchar conversions because of how the time column's zeros are cut off. However, I am not convinced that this is the most effective way to do so:
DECLARE #DateInt int = 20200131
DECLARE #TimeInt int = 345 -- 03:45:00
SELECT CONVERT(DATETIME, LEFT(#DateInt, 8)) +
CAST(DATEADD(second, FLOOR(#TimeInt / 100) * 3600 + FLOOR(#TimeInt / 1) % 100 * 60, 0) as datetime)
I was testing it with various time values, it is working.
I want to query a subset from a dataset. Each row has a time stamp of the following format:
2014-04-25T17:25:14
2014-04-25T18:40:16
2014-04-25T18:44:57
2014-04-25T19:10:32
2014-04-25T20:22:12
...
Currently, I use the following query to select a time-based subset:
time LIKE '%2014-04-25T18%' OR time LIKE '%2014-04-25T19%'
This becomes quite complicated when you start to filter by mintutes or seconds.
Is there a way to run a query that such as ...
time > '%2014-04-25T18%' AND time < '%2014-04-25T19%'
A regular expression would be okay, too.
The database is a SpatiaLite database. The time column is of type VARCHAR.
If the date is being treated as a string and based on the example above:
time LIKE '%2014-04-25T18%' AND time <> '%2014-04-25T18:00:00:000'
Otherwise, you could convert the date to seconds since midnight and add 60 minutes to that to create the range part of the filter
DECLARE #test DATETIME = '2014-04-25T17:25:14'
SELECT #test
, CONVERT(DATE,#test) AS JustDate
, DATEDIFF(s,CONVERT(DATETIME,(CONVERT(DATE,#test))), #test) AS SecondsSinceMidnight
-- 60 seconds * 60 minutes * 24 hours = 86400
Thanks to your posts and this answer I came up with this solution:
SELECT * FROM data
WHERE DATETIME(
substr(time,1,4)||'-'||
substr(time,6,2)||'-'||
substr(time,9,2)||' '||
substr(time,12,8)
)
BETWEEN DATETIME('2014-04-25 18:00:00') AND DATETIME('2014-04-25 19:00:00');
I have a table which stores an amount of seconds as integer.
I want to display it and use it as Time or Date.
If I write this:
Select Cast(ColAmountofSeconds as Time) as ThisTime From MyTable;
same with:
Select Cast(ColAmountofSeconds as Date) as ThisTime From MyTable;
I get the following error:
Overflow occurred during data type conversion. conversion error from
string "14".
Note "14" is the value of the first row in the ColAmountofSeconds column.
This is so natural in SQL Server, that I can't believe the amount of time I've spent on figuring this out.
EDIT
I can't believe this is the answer:
Update MyTable
Set TIMESPENT = time '00:00:00' + ColAmountOfSeconds;
Firebird cast function does not support converting a numeric value to date, time or timestamp.
You can take advantage of the fact that Firebird supports arithmethic between dates and numeric values, so you can write your query like this:
select dateadd(second, ColAmountOfSeconds, cast('00:00:00' as time))
from myTable;
--or the equivalent:
select cast(cast('2013-01-01' as timestamp) + cast(ColAmountofSeconds as double precision) / 86400 as TIME)
from myTable;
I got a column called DateOfBirth in my csv file with Excel Date Serial Number Date
Example:
36464
37104
35412
When i formatted cells in excel these are converted as
36464 => 1/11/1999
37104 => 1/08/2001
35412 => 13/12/1996
I need to do this transformation in SSIS or in SQL. How can this be achieved?
In SQL:
select dateadd(d,36464,'1899-12-30')
-- or thanks to rcdmk
select CAST(36464 - 2 as SmallDateTime)
In SSIS, see here
http://msdn.microsoft.com/en-us/library/ms141719.aspx
The marked answer is not working fine, please change the date to "1899-12-30" instead of "1899-12-31".
select dateadd(d,36464,'1899-12-30')
You can cast it to a SQL SMALLDATETIME:
CAST(36464 - 2 as SMALLDATETIME)
MS SQL Server counts its dates from 01/01/1900 and Excel from 12/30/1899 = 2 days less.
tldr:
select cast(#Input - 2e as datetime)
Explanation:
Excel stores datetimes as a floating point number that represents elapsed time since the beginning of the 20th century, and SQL Server can readily cast between floats and datetimes in the same manner. The difference between Excel and SQL server's conversion of this number to datetimes is 2 days (as of 1900-03-01, that is). Using a literal of 2e for this difference informs SQL Server to implicitly convert other datatypes to floats for very input-friendly and simple queries:
select
cast('43861.875433912' - 2e as datetime) as ExcelToSql, -- even varchar works!
cast(cast('2020-01-31 21:00:37.490' as datetime) + 2e as float) as SqlToExcel
-- Results:
-- ExcelToSql SqlToExcel
-- 2020-01-31 21:00:37.490 43861.875433912
this actually worked for me
dateadd(mi,CONVERT(numeric(17,5),41869.166666666664)*1440,'1899-12-30')
(minus 1 more day in the date)
referring to the negative commented post
SSIS Solution
The DT_DATE data type is implemented using an 8-byte floating-point number. Days are represented by whole number increments, starting with 30 December 1899, and midnight as time zero. Hour values are expressed as the absolute value of the fractional part of the number. However, a floating point value cannot represent all real values; therefore, there are limits on the range of dates that can be presented in DT_DATE. Read more
From the description above you can see that you can convert these values implicitly when mapping them to a DT_DATE Column after converting it to a 8-byte floating-point number DT_R8.
Use a derived column transformation to convert this column to 8-byte floating-point number:
(DT_R8)[dateColumn]
Then map it to a DT_DATE column
Or cast it twice:
(DT_DATE)(DT_R8)[dateColumn]
You can check my full answer here:
Is there a better way to parse [Integer].[Integer] style dates in SSIS?
Found this topic helpful so much so created a quick SQL UDF for it.
CREATE FUNCTION dbo.ConvertExcelSerialDateToSQL
(
#serial INT
)
RETURNS DATETIME
AS
BEGIN
DECLARE #dt AS DATETIME
SELECT #dt =
CASE
WHEN #serial is not null THEN CAST(#serial - 2 AS DATETIME)
ELSE NULL
END
RETURN #dt
END
GO
I had to take this to the next level because my Excel dates also had times, so I had values like this:
42039.46406 --> 02/04/2015 11:08 AM
42002.37709 --> 12/29/2014 09:03 AM
42032.61869 --> 01/28/2015 02:50 PM
(also, to complicate it a little more, my numeric value with decimal was saved as an NVARCHAR)
The SQL I used to make this conversion is:
SELECT DATEADD(SECOND, (
CONVERT(FLOAT, t.ColumnName) -
FLOOR(CONVERT(FLOAT, t.ColumnName))
) * 86400,
DATEADD(DAY, CONVERT(FLOAT, t.ColumnName), '1899-12-30')
)
In postgresql, you can use the following syntax:
SELECT ((DATE('1899-12-30') + INTERVAL '1 day' * FLOOR(38242.7711805556)) + (INTERVAL '1 sec' * (38242.7711805556 - FLOOR(38242.7711805556)) * 3600 * 24)) as date
In this case, 38242.7711805556 represents 2004-09-12 18:30:30 in excel format
In addition of #Nick.McDermaid answer I would like to post this solution, which convert not only the day but also the hours, minutes and seconds:
SELECT DATEADD(s, (42948.123 - FLOOR(42948.123))*3600*24, dateadd(d, FLOOR(42948.123),'1899-12-30'))
For example
42948.123 to 2017-08-01 02:57:07.000
42818.7166666667 to 2017-03-24 17:12:00.000
You can do this if you just need to display the date in a view:
CAST will be faster than CONVERT if you have a large amount of data, also remember to subtract (2) from the excel date:
CAST(CAST(CAST([Column_With_Date]-2 AS INT)AS smalldatetime) AS DATE)
If you need to update the column to show a date you can either update through a join (self join if necessary) or simply try the following:
You may not need to cast the excel date as INT but since the table I was working with was a varchar I had to do that manipulation first. I also did not want the "time" element so I needed to remove that element with the final cast as "date."
UPDATE [Table_with_Date]
SET [Column_With_Excel_Date] = CAST(CAST(CAST([Column_With_Excel_Date]-2 AS INT)AS smalldatetime) AS DATE)
If you are unsure of what you would like to do with this test and re-test! Make a copy of your table if you need. You can always create a view!
Google BigQuery solution
Standard SQL
Select Date, DATETIME_ADD(DATETIME(xy, xm, xd, 0, 0, 0), INTERVAL xonlyseconds SECOND) xaxsa
from (
Select Date, EXTRACT(YEAR FROM xonlydate) xy, EXTRACT(MONTH FROM xonlydate) xm, EXTRACT(DAY FROM xonlydate) xd, xonlyseconds
From (
Select Date
, DATE_ADD(DATE '1899-12-30', INTERVAL cast(FLOOR(cast(Date as FLOAT64)) as INT64) DAY ) xonlydate
, cast(FLOOR( ( cast(Date as FLOAT64) - cast(FLOOR( cast(Date as FLOAT64)) as INT64) ) * 86400 ) as INT64) xonlyseconds
FROM (Select '43168.682974537034' Date) -- 09.03.2018 16:23:28
) xx1
)
For those looking how to do this in excel (outside of formatting to a date field) you can do this by using the Text function https://exceljet.net/excel-functions/excel-text-function
i.e.
A1 = 132134
=Text(A1,"MM-DD-YYYY") will result in a date
This worked for me because sometimes the field was a numeric to get the time portion.
Command:
dateadd(mi,CONVERT(numeric(17,5),41869.166666666664)*1440,'1899-12-31')
I'm trying to query a table that has a varchar(100) "VALUE" column. This column can hold anything from a letter, a number or, in this case, a date.
The date will always be entered in the table as 'YYYY-mm-dd'. However, when I run the following query:
select * from myTable
where VALUE = '2009-12-11' (Date, Format 'yyyy-mm-dd')
I receive the following error:
Invalid date supplied for myTable.VALUE.
Example of the value table:
(1,'122')
(2,'red')
(3,'2009-12-11')
Any ideas as to what might be causing this?
Thanks!
if the data type is declared as varchar, it should just treat it like a string.
try not specifying anything about the date format, like
select * from myTable
where VALUE = '2009-12-11'
If you run an explain on the query, you can see that it's casting value to date before comparing against your supplied value. If you have another column that accurately records the type of what's in VALUE, you can add that to the where clause and you will no longer get the error (see below). Otherwise, go with Beth's recommendation.
select * from myTable
where VALUE = '2009-12-11' (Date, Format 'yyyy-mm-dd')
and VALUE_TYPE = 'DATE';
Teradata internal date calculation is (year - 1900) * 10000 + (month * 100) + day.
So if date is 02/11/2009 (2nd November 2010) then
=(2009-1900) * 10000 + (11 * 100) + 2
=109 * 10000 + 1100 + 2
=1090000 + 1100 + 2
=1090000
1100
2
----------
1091102
----------
So 2nd november 2009 is stored in Teradata as 1091102.
You can extract it in required format by casting (as u have it in varchar). Hope this helps.
Is it possible that VALUE is a reserved word in Teradata?
If so, you need to put that into double quotes:
select *
from myTable
where "VALUE" = '2009-12-11'