I've below xml and would like to read it reverse order using for-each in xslt 1.0.
Input:
<Tokens>
<TokenNo>370021031939737</TokenNo>
<TokenNo>370021031939717</TokenNo>
<TokenNo>370021031939745</TokenNo>
<TokenNo>370021031939726</TokenNo>
</Tokens>
I want to read 370021031939726,370021031939745,370021031939717,370021031939737 using for-each. Can someone help.
Thanks
Related
This is regarding the common problem we face in Middleware( Oracle SOA 11g). We have one source value like "SEBẪSTIN" but while reading this value the final output value is appearing as "SEB�STIN"
yes..I know, I can use CDATA for not parsing the value. But it is not working.
I have referred to the following post. But no luck.
How to use <![CDATA[]]> in XSLT?
Could you please let me know the correct syntax using CDATA. My xslt tag looks like this
<ns2:Firstname>
<xsl:value-of select="imp1:FIRSTNAME"/>
</ns2:Firstname>
OR
do we have any other option to handle this character.
version details :
Oracle SOA 11g
Jdeveloper: 11.1.1.7.0
BPEL: 2.0
XSLT: 1.0
Any help would be appreciated.
Thanks,
Abhi
How to split xml file into multiple files based on a tag in xml file using mule
In xml we have <EOF> data based on <EOF> we need to chunk the xml.
You can do something similar to:
<splitter expression="#[xpath('//EOF')]" />
That would generate many messages one for each EOF tag in your XML. Depending on the structure you may need to fix the Xpath expression to be more precise.
Use splitter component in Mule
http://www.mulesoft.org/documentation/display/current/Splitter+Flow+Control+Reference
<healthcare>
<plans>
<plan1>
<planid>100</planid>
<planname>medical</planname>
<desc>medical</desc>
<offerprice>500</offerprice>
<area>texas</area>
</plan1>
<plan2>
<planid>101</planid>
<planname>dental</planname>
<desc>dental</desc>
<offerprice>1000</offerprice>
<area>texas</area>
</plan2>
</plans>
</healthcare>
<splitter evaluator="xpath" expression="/healthcare/plans" doc:name="Splitter"/>
<transformer ref="domToXml" doc:name="Transformer Reference"/>
<logger level="INFO" doc:name="Logger" message=" plans detils...#[message.payload]" />
i have input xml data as above. I want to replace offerprice value from the above xml data . I tried various ways. anyone can shed the light for my requirement in mule
in my requiremnet , hit external api based on the result value , I need to change the offerprice value in the input xml .
anyone help is highly valuable.I need this immediately in my work .please shed light
You can use XSLT to transform the XML file to another XML file (with or without the same schema). Here's a small example of how it would look in mule . . .
http://marcotello.com/mule-esb/using-the-xslt-transformer-in-mule-esb/
There are also a lot of resources for learning how to create XSLT files online / through google.
There are many ways to do it.
You can use Mule XSLT in your flow, which will change the value of offerprice from input xml and you will be getting the required Xml as output with the value you want.
Another way is to use Groovy, with XmlSlurper to parse your input Xml, replace the value, and rebuild the XML you want.
reference :- XML Mapping in Mule
and
Mule: Enriching an XML with additional information from DB
also refer
http://www.ibm.com/developerworks/library/j-pg05199/index.html
Hope this help
>> ? xml
No information on xml
There's parse-xml but it seems to me that it was for Rebol2.
I've searched for xml scripts in rebol.org and found xml-object.r that seemed to me like the most up to date from all searches.
I know about altxml, too, but the examples given are for html.
So, I'd like to ask about my choices if I want to parse and use information of +1GB of files of this simplified structure:
<?xml version="1.0" encoding="Windows-1252" standalone="yes"?>
<SalesFile xmlns="urn:StandardSalesFile-1.0">
<Header>
<SalesFileVersion>1.01</SalesFileVersion>
<DateCreation>2014-04-30</DateCreation>
</Header>
<SalesInvoices>
<Invoice>
<InvoiceNo>INV 1/1</InvoiceNo>
<DocumentStatus>
<InvoiceStatus>N</InvoiceStatus>
<InvoiceStatusDate>2014-01-03T17:57:59</InvoiceStatusDate>
</DocumentStatus>
</Invoice>
<Invoice>
<InvoiceNo>INV 2/1</InvoiceNo>
<DocumentStatus>
<InvoiceStatus>N</InvoiceStatus>
<InvoiceStatusDate>2014-01-03T17:59:12</InvoiceStatusDate>
</DocumentStatus>
</Invoice>
</SalesInvoices>
</SalesFile>
Is Rebol3 going to have a parse-xml tool? Should I use xml-object? If so how? Because it's still beyong my novice level of the language. Other option?
There is also a Rebol 3 library by Christopher Ross-Gill called alt-xml.
http://www.ross-gill.com/page/XML_and_REBOL
This can translate the XML to either a block! or object! representation.
Your question states that these XML files are large and may not fit in main memory. I would suggest that creating 1GB XML files is not best practice as many parsers, including this one, do attempt to load the files into memory.
To support this you will have to chunk the files yourself by using open on the file and copy/part chunks out of the file. This is a bit messy, but it will work.
One way to make this cleaner is to use parse as per HostileFork's suggestion and modify the series as you parse it. Parse is very flexible in this regard.
Ideally parse would be able to work directly on port! objects, but this is only a future wish list item at the moment.
Do you really need to deal with the XML file as structure? If not, have you considered just using PARSE?
(Warning: the following is untested, I'm just presenting the concept.)
Invoices: copy []
parse my-doc [
<?xml version="1.0" encoding="Windows-1252" standalone="yes"?>
thru <SalesFile xmlns="urn:StandardSalesFile-1.0">
thru <Header>
thru <SalesFileVersion> copy SalesFileVersion to </SalesFileVersion>
</SalesFileVersion>
thru <DateCreation> copy DateCreation to </DateCreation>
</DateCreation>
thru </Header>
thru <SalesInvoices>
any [
thru <Invoice>
(Invoice: object [])
thru <InvoiceNo> copy InvoiceNo to </InvoiceNo>
</InvoiceNo>
(Invoice/No: InvoiceNo)
thru <DocumentStatus>
thru <InvoiceStatus> copy InvoiceStatus to </InvoiceStatus>
</InvoiceStatus>
(Invoice/Status: InvoiceStatus)
thru <InvoiceStatusDate> copy InvoiceStatusDate to </InvoiceStatusDate>
</InvoiceStatusDate>
(Invoice/StatusDate: InvoiceStatusDate)
thru </DocumentStatus>
thru </Invoice>
]
thru </SalesInvoices>
thru </SalesFile>
to end
]
If you know you have well-formed XML and don't want a dependency on a library for processing clunky-ol' XML, Rebol can get pretty far and clear with PARSE. As TAG! is just a subclass of string, you can make things look relatively literate. And it's much more lightweight to just work with the strings.
Though if structural manipulations are required, you'll need something that makes a DOM. Altxml is the go-to right now, AFAIK.
(Hmm...I had a name for the pattern copy x to <foo> <foo> that escapes me at the moment, but this is a good case for it.)
%Rebol-Dom.r or %rebol-dom-mdlparser.r,
If your willing to use rebol2 with parse to seek thru to the node-name, then copy a chunk of data, you could feed that to Rebol-Dom.r getnodename "salesInvoice" and append that node-element to a block repetitively.
I'm new to mule, working with Matamapper which converts csv file to xml. I'm able to convert csv to xml . But the final output response is not formatted with actual root element. Please find my final output xml structure. It doesnt have root element. Kindly guide me . If this is correct, help me how to insert root element. ( Bcz i tried Set payload to insert the root element) it is not working correclty.
<?xml version="1.0" encoding="UTF-8"?>
<employees>
<name>jothi</name>
<street>123, main</street>
</employees>
<employees>
<name>Jane </name>
<street>Main Street</street>
</employees>
Also referred : csv to xml: not sure the best way to do it in Mule ESB
http://www.mulesoft.org/documentation/display/current/DataMapper+Flat-to-Structured+and+Structured-to-Flat+Mapping - giving errors in datamapper
Thank you.
Upgrading MuleStudio to 3.5 cleaned up a lot of the errors I was seeing using the DataMapper