Select
(*)
From
MISC
WHERE
TO_DATE(TRANSACTION_TIME, YYYY-MM-DD HH24:MI:SS.FF6) Between
TO_DATE(:Variable1, 'YYYYMMDD') and TO_DATE(:Variable2, 'YYYYMMDD')
The transaction time column is CHAR(78) and returns 2017-06-12-12.35.37.444978 as and example. I have been struggling with this for awhile now and getting a variety of errors. With the current setup, I receive
Error Executing Query: ORA-01821: date format not recognized.
Variable1 = 20170612
Variable2 = 20170615
That's a timestamp not a date so you need to use to_timestamp() not to_date()
If you are only looking at the date, then perhaps a simpler version will work:
WHERE TO_DATE(SUBSTR(TRANSACTION_TIME, 10), 'YYYY-MM-DD') Between
TO_DATE(:Variable1, 'YYYYMMDD') and TO_DATE(:Variable2, 'YYYYMMDD')
Also, why not pass in the variables as dates rather than strings? That would get around the second conversion. If they are actually dates, then that might be where the conversion problem is.
Related
When running
select processing_date from table;
i got this result "04-30-2020 20.12.49.978711"
what i want to change the format of the result to "30-APR-20"
is there a way i can do that ?
i tried select to_date(processing_date,'mm-dd-yyyy') from table; but it gives me errors
any help ?
You want to_char():
select to_char(processing_date, 'MM-DD-YYYY')
Dates are stored as an internal format, which you cannot change. If you want the date formatted in a particular way, then one solution is to convert to a string with the format you want.
EDIT:
The date appears to be a string. You can convert it to a date using:
select to_date(substr(processing_date, 1, 10), 'MM-DD-YYYY')
You can then either use as-is or use to_date() to get the format you really want.
I'm trying to remove the hours, minutes and seconds from a date using the following code :
TRUNC(column_date, 'YY')
But I get this : 01JAN2008:00:00:00, while I want this : 01JAN2008.
What should I do?
TRUNC() works as expected, and returns the original date truncated to year, as a date datatype. You want to format this date before displaying it (this actually means converting it to a string). For this, you can use the TO_CHAR() function.
You probably want:
TO_CHAR(TRUNC(column_date, 'YY'), 'ddmonyyyy')
Please note that this expression could be simplified to avoid the use of TRUNC(), as follows:
'01JAN' || TO_CHAR(column_date, 'yyyy')
I think you want to_char: https://docs.oracle.com/database/121/SQLRF/functions216.htm#SQLRF06129
Try using it in this way:
SELECT TO_CHAR(column_date, 'DD/MON/YYYY')
FROM x;
Where x is the table you are trying to query.
you only need to use
select to_char(column_date,'ddMONyyyy') FROM yourTable
Even you can invoke with
select to_char(column_date,'ddMONyyyy','nls_date_language=english') FROM yourTable
to guarantee to see the abbreviation JAN in the case your session/system date language value is different than english
to display as expected.
Oracle SQL automatically converts my field D.START_DT to the following format:
TO_CHAR(D.START_DT,'YYYY-MM-DD')
Which makes it difficult for me to modify my own date format.
I've tried wrapping another TO_CHAR around it with no luck.
TO_CHAR(TO_CHAR(D.START_DT,'YYYY-MM-DD'), 'MM/DD')
And I've tried SUBSTR to select certain characters, with no luck. I think the hyphen is getting int he way.
SUBSTR(TO_CHAR(D.START_DT,'YYYY-MM-DD'), 6, 7) || '/' || SUBSTR(TO_CHAR(D.START_DT,'YYYY-MM-DD'), 9, 10)
What is the work around for this?
I agree with RMAN Express and see no problems converting dates to any format you need...
In case you still have problems try this (first to_char() in outer query is optional):
SELECT to_char(to_date(some_date, 'YYYY-MM-DD'), 'MM/DD') final_date
FROM
(
SELECT TO_CHAR(SYSDATE,'YYYY-MM-DD') some_date -- this is your "auto converted" date
FROM dual
)
/
A DATE datatype has no format. When you see a date printed on a screen, there was something that APPLIED the format you see. Could be a "default" in the program you are using (like SQL Developer) or your NLS setting, etc. But, a DATE datatype has no format. So, you have complete control over the format you see on screen.
The simplest is to use the TO_CHAR function:
select TO_CHAR(D.START_DT,'YYYY') from dual;
returns just the four digit year.
See TO_CHAR date format options.
http://docs.oracle.com/cd/E11882_01/server.112/e26088/sql_elements004.htm#CDEHIFJA
You should always supply the format in your code and not rely on some other "default" to supply it.
I have the following in my SQL where clause. This is running against an Oracle database. The sc_dt field is defined in the db as a date field.
sc_dt = TO_DATE('2011-11-03 00:00:00.0', 'YYYY-MM-DD')
produces the following error "date format picture ends before converting entire input string"
When I try to account for the fractional seconds (.0 in this case) with the following, I get the following error.
sc_dt = TO_DATE('2011-11-03 00:00:00.0', 'YYYY-MM-DD HH24:MI:SS.FF')
produces the following error "date format not recognized"
I'm really just assuming that I need the .FF to account for the .0 in the "from" string. I've also tried .FF1, .FF2, ..., .FF9 with the same results (I'm grasping at straws at this point).
As far as I can see, the sc_dt field always has the month/day/year portion populated (and not the hour/minute/second portion).
I'm debugging a java program which is executing the above SQL as a prepared statement with the 2011-11-03 00:00:00.0 value.
How can I get around this?
You need to use the seconds past midnight option. Something like:
select TO_DATE('2011-11-03 00:00:01.1', 'YYYY-MM-DD HH24:MI:SS.SSSSS') from dual
Or This:
select TO_TIMESTAMP('2011-11-03 00:00:00.1', 'YYYY-MM-DD HH24:MI:SS.FF') from dual
An Oracle DATE column like sc_dt will always have a day and a time component down to the second. Depending on your query tool and how it is configured (generally the session's NLS_DATE_FORMAT), it is possible that the time component isn't being displayed by default. You can, however, see the time component by doing an explicit TO_CHAR
SELECT to_char( sc_dt, 'YYYY-MM-DD HH24:MI:SS' )
FROM table_name
Because a DATE only stores the time to the second, however, you cannot use fractional seconds in your format mask. So you would need to do something like this to extract just the portion of the string up to the fractional seconds. If you're not guaranteed that the string will always be 19 characters before the decimal point, you could use INSTR as well to look for the decimal point and take everything before that.
TO_DATE( substr('2011-11-03 00:00:00.0', 1, 19), 'YYYY-MM-DD HH24:MI:SS')
Since this is coming from a Java application, however, you're much better off using the correct data type. If you bind a Java date (java.sql.Date) using the setDate method on the prepared statement rather than binding a string, then you won't have to deal with the string format in your SQL statement.
I realize this thread is more than a year old but...
Another option just to throw it in might be:
src_dt=select TO_DATE('2011-11-03 00:00:01.1234', 'YYYY-MM-DD HH24:MI:SS.?????') from dual;
Note: there is an extra '?' thrown in to illustrate that you can even stick in a few extra '?'s. There is no complaint from Oracle if the digits represented by the '?'s do NOT have any corresponding character in the source time string. This might be helpful if you aren't sure of the precision of seconds you are receiving.
This option gives some flexibility to the format of "fractional seconds" from your source time.
I do not know that this is actually documented anywhere.
I did this :
ALTER SESSION
SET NLS_DATE_FORMAT = 'YYYY-MM-DD HH24:MI:SS.?';
--Change the decimal
ALTER SESSION
SET NLS_NUMERIC_CHARACTERS = ',.';
And it worked for me
src_dt=select TO_DATE('2011-11-03 00:00:01.1', 'YYYY-MM-DD HH24:MI:SS.SSSSS') from dual
I guess the above one should work if you just need a date output.
I have a column which is of "DATE" type and I want to run a query on it comparing it with sysdate.
But I am getting following error, Can someone please let me know what I am missing here?
SQL> select distinct file_name as r
from table_1
where view_day >= TO_DATE(SYSDATE-10, 'YYYY/MM/DD');
ERROR at line 1:
ORA-01858: a non-numeric character was found where a numeric was expected
You shouldn't use to_date on a date, To_date is for casting a varchar to date, not a date.
If you do use the function to_date on a date, then oracle will refer to it as a string according to nls_date_format which may vary in different environments.
As #jonearles said, if you want to remove the time in sysdate then use TRUNC
USE:
select distinct file_name as r
from table_1
where view_day >= TRUNC(SYSDATE-10)
Error shows that a VIEW_DAY column is varchar so you need to convert DATE to String. Use TO_CHAR or convert VIEW_DAY to date type.