Laravel SQLSTATE[42000]: Syntax error or access violation: 1064 - sql

Question

Hi i want to create a foreign key but nothing work and i don't understand whyenter image description here
enter image description here

Answer 1

Please provide more info about table type, for now based on info that you type I can suggest you check are you using InnoDB tables? does FOREIGN KEY in table one corresponding to PK in table 2? are they have same types and length?

Answer 2

articles table
use Illuminate\Support\Facades\Schema;
use Illuminate\Database\Schema\Blueprint;
use Illuminate\Database\Migrations\Migration;
class CreateArticlesTable extends Migration
{
/**
* Run the migrations.
*
* #return void
*/
public function up()
{
Schema::create('articles', function (Blueprint $table) {
$table->increments('id');
$table->string('title' , 255);
$table->text('content');
$table->integer('user_id')->unsigned();
$table->foreign('user_id')->references('id')->on('users');
$table->timestamps();
});
}
/**
* Reverse the migrations.
*
* #return void
*/
public function down()
{
Schema::dropIfExists('articles');
}
}
category table
<?php
use Illuminate\Support\Facades\Schema;
use Illuminate\Database\Schema\Blueprint;
use Illuminate\Database\Migrations\Migration;
class CreateCategoryTable extends Migration
{
/**
* Run the migrations.
*
* #return void
*/
public function up()
{
Schema::create('category', function (Blueprint $table) {
$table->increments('id');
$table->string('name');
$table->timestamps();
});
}
/**
* Reverse the migrations.
*
* #return void
*/
public function down()
{
Schema::dropIfExists('category');
}
}