Purpose: Take two fractions inputted on another platform and by user and evaluate them with IsNothing. If they aren't integers or strings that can be converted, run through Frac2Num (attached, I know this works, not the focus. Code created by Jeff Arms of Arecon Data).
It then checks to see if value A2 is greater than one. If so, then performs the math function (A2/2) - (A1/2) and then returns that value. Else, it returns 0.
So far I have only been able to return 0, so something with how it is reading the values or how its returning the value after the equation is messing it up, I think.
Main function:
Public Function MyFunction(ByVal A1 As String, ByVal A2 As String) As Integer
MyFunction= 0
Try
Dim B1 As Double
Dim B2 As Double
If IsNothing(A1) Then Return 0 'If the user provides no values, return 0.
If IsNothing(A2) Then Return 0 'If the user provides no values, return 0.
If IsNumeric(A1) = True Then
B1 = CDbl(A1)
Else
B1 = Frac2Num(A1)
End If 'If the value is an integer or convertible string, convert value to double. If not, run through Frac2Num function.
If IsNumeric(A2) = True Then
B2 = CDbl(A2)
Else
B2 = Frac2Num(A2)
End If
If A2 > 1 Then
MyFunction= (A2 / 2) - (A1 / 2)
Return MyFunction
Else MyFunction= 0
End If 'If A2 is greater than one, then MyFunction = value created by equation.
Catch ex As Exception
End Try
Frac2Num function:
Function Frac2Num(ByVal X As String) As Double
Dim P As Integer, N As Double, Num As Double, Den As Double
X = Trim$(X)
P = InStr(X, "/")
If P = 0 Then
N = Val(X)
Else
Den = Val(Mid$(X, P + 1))
If Den = 0 Then Error 11 ' Divide by zero
X = Trim$(Left$(X, P - 1))
P = InStr(X, " ")
If P = 0 Then
Num = Val(X)
Else
Num = Val(Mid$(X, P + 1))
N = Val(Left$(X, P - 1))
End If
End If
If Den <> 0 Then
N = N + Num / Den
End If
Frac2Num = N
End Function
Returning:
Sub Main()
Dim result As Integer
result = MyFunction("8 1/2", "8 5/8") 'Function called with example values.
Console.WriteLine(result)
Console.ReadLine()
End Sub
First of all, in the end of your code you are trying to convert a fraction string directly to a number, witch is causing your code to generate an exception and go to the Catch block
change it to
'You are using A1 and A2, change it to B1 and B#
If B2 > 1 Then
MyFunction = (B2 * 1.0 / 2) - (B1 * 1.0 / 2)
Return MyFunction
Else : MyFunction = 0
End If
also, you are returning an integer and assigning the result to an integer. Even if the result was computed properly in your example case it will not be evaluated correctly. Changing it to Double should solve it.
Public Function MyFunction(ByVal A1 As String, ByVal A2 As String) As Double
and
Dim result As Double
result = MyFunction("8 1/2", "8 5/8")
Related
Sub PrimePair()
Dim n As Integer
Dim count As Integer = 0
Console.WriteLine(count)
End Sub
Public Function PrimePairs(ByVal n As Integer, ByVal n2 As Long) As Integer
Dim count As Integer = 0
Console.ReadLine()
If n Mod 2 = 0 Then
For i = 1 To (n / 2) + 1
n2 = CLng(n - i)
If IsPrime(CLng(i)) And IsPrime(n2) = True Then
count += 1
End If
Next
Else
n2 = n - 2
If IsPrime(n2) = True Then
count = +1
End If
End If
Console.WriteLine(count)
Return n
End Function
End Module>
I can't run my code without sub. I created two functions, but the inputs I entered do not return in functions and do not print on the screen, I hope I can solve it, thanks for your attention. My project calculates how many different ways it prints the entered input value as a sum of prime numbers. About the Goldbach conjecture
I have a set which has an unknown number of objects. I want to associate a label to each one of these objects. Instead of labeling each object with a number I want to label them with letters.
For example the first object would be labeled A the second B and so on.
When I get to Z, the next object would be labeled AA
AZ? then BA, BB, BC.
ZZ? then AAA, AAB, AAC and so on.
I'm working using Mapbasic (similar to VBA), but I can't seem to wrap my head around a dynamic solution. My solution assumes that there will be a max number of objects that the set may or may not exceed.
label = pos1 & pos2
Once pos2 reaches ASCII "Z" then pos1 will be "A" and pos2 will be "A". However, if there is another object after "ZZ" this will fail.
How do I overcome this static solution?
Basically what I needed was a Base 26 Counter. The function takes a parameter like "A" or "AAA" and determines the next letter in the sequence.
Function IncrementAlpha(ByVal alpha As String) As String
Dim N As Integer
Dim num As Integer
Dim str As String
Do While Len(alpha)
num = num * 26 + (Asc(alpha) - Asc("A") + 1)
alpha = Mid$(alpha, 2,1)
Loop
N = num + 1
Do While N > 0
str = Chr$(Asc("A") + (N - 1) Mod 26) & str
N = (N - 1) \ 26
Loop
IncrementAlpha = str
End Function
If we need to convert numbers to a "letter format" where:
1 = A
26 = Z
27 = AA
702 = ZZ
703 = AAA etc
...and it needs to be in Excel VBA, then we're in luck. Excel's columns are "numbered" the same way!
Function numToLetters(num As Integer) As String
numToLetters = Split(Cells(1, num).Address(, 0), "$")(0)
End Function
Pass this function a number between 1 and 16384 and it will return a string between A and XFD.
Edit:
I guess I misread; you're not using Excel. If you're using VBA you should still be able to do this will the help of an reference to an Excel Object Library.
This should get you going in terms of the logic. Haven't tested it completely, but you should be able to work from here.
Public Function GenerateLabel(ByVal Number As Long) As String
Const TOKENS As String = "ZABCDEFGHIJKLMNOPQRSTUVWXY"
Dim i As Long
Dim j As Long
Dim Prev As String
j = 1
Prev = ""
Do While Number > 0
i = (Number Mod 26) + 1
GenerateLabel = Prev & Mid(TOKENS, i, 1)
Number = Number - 26
If j > 0 Then Prev = Mid(TOKENS, j + 1, 1)
j = j + Abs(Number Mod 26 = 0)
Loop
End Function
I'm am using the code example below to represent an integer as an alphabetic string
Private Function GetExcelColumnName(columnNumber As Integer) As String
Dim dividend As Integer = columnNumber
Dim columnName As String = String.Empty
Dim modulo As Integer
While dividend > 0
modulo = (dividend - 1) Mod 26
columnName = Convert.ToChar(65 + modulo).ToString() & columnName
dividend = CInt((dividend - modulo) / 26)
End While
Return columnName
End Function
I found the above example here:
Converting Numbers to Excel Letter Column vb.net
How do I get the reverse, for example:
123 = DS -- Reverse -- DS = 123
35623789 = BYXUWS -- Reverse -- BYXUWS = 35623789
Is it possible to get the number from the alphabetic string without importing Excel?
I found an answer from another post. This function below will work to get the reverse
Public Function GetCol(c As String) As Long
Dim i As Long, t As Long
c = UCase(c)
For i = Len(c) To 1 Step -1
t = t + ((Asc(Mid(c, i, 1)) - 64) * (26 ^ (Len(c) - i)))
Next i
GetCol = t
End Function
I have this code below, and I'm getting an overflow error at the line:
s = s + (x Mod 10) [first line in the Do Loop]
Why? I declared x and s to be of type Double. Adding two doubles, why is this not working?
Thanks for your help.
Public Sub bidon1()
Dim i As Double, x As Double, s As Double, k As Byte, h As Byte
Dim y(1 To 6) As Double
For i = 1 To 1000000
x = i ^ 3
Do
s = s + (x Mod 10)
x = x \ 10
Loop Until x = 0
If s = x Then
k = k + 1
y(k) = x
If y(6) > 0 Then
For h = 1 To 6
Debug.Print y(h)
Next
Exit Sub
End If
End If
Next
End Sub
The problem is that the VBA mod operator coerces its arguments to be integers (if they are not already so). It is this implicit coercion which is causing the overflow. See this question: Mod with Doubles
On Edit:
Based on your comments, you want to be able to add together the digits in a largish integer. The following function might help:
Function DigitSum(num As Variant) As Long
'Takes a variant which represents an integer type
'such as Integer, Long or Decimal
'and returns the sum of its digits
Dim sum As Long, i As Long, s As String
s = CStr(num)
For i = 1 To Len(s)
sum = sum + Val(Mid(s, i, 1))
Next i
DigitSum = sum
End Function
The following test sub shows how it can be used to correctly get the sum of the digits in 999999^3:
Sub test()
Dim x As Variant, y As Variant
Debug.Print "Naive approach: " & DigitSum(999999 ^ 3)
y = CDec(999999)
x = y * y * y
Debug.Print "CDec approach: " & DigitSum(x)
End Sub
Output:
Naive approach: 63
CDec approach: 108
Since 999999^3 = 999997000002999999, only the second result is accurate. The first result is only the sum of the digits in the string representation of the double 999999^3 = 9.99997000003E+17
I would like to make CPU to calculate declared result from the given numbers that are also declared.
So far:
Dim ArrayOperators() As String = {"+", "-", "*", "/", "(", ")"}
Dim GlavniBroj As Integer = GBRnb() 'Number between 1 and 999 that CPU needs to get from the numbers given below:
Dim OsnovniBrojevi() As Integer = {OBRnb(), OBRnb(), OBRnb(), OBRnb()} '4 numbers from 1 to 9
Dim SrednjiBroj As Integer = SBRnb() '1 number, 10, 15 or 20 chosen randomly
Dim KrajnjiBroj As Integer = KBRnb() '25, 50, 75 or 100 are chosen randomly
Private Function GBRnb()
Randomize()
Dim value As Integer = CInt(Int((999 * Rnd()) + 1))
Return value
End Function
Private Function OBRnb()
Dim value As Integer = CInt(Int((9 * Rnd()) + 1))
Return value
End Function
Private Function SBRnb()
Dim value As Integer = CInt(Int((3 * Rnd()) + 1))
If value = 1 Then
Return 10
ElseIf value = 2 Then
Return 15
ElseIf value = 3 Then
Return 20
End If
Return 0
End Function
Private Function KBRnb()
Dim value As Integer = CInt(Int((4 * Rnd()) + 1))
If value = 1 Then
Return 25
ElseIf value = 2 Then
Return 50
ElseIf value = 3 Then
Return 75
ElseIf value = 4 Then
Return 100
End If
Return 0
End Function
Is there any way to make a program to calculate GlavniBroj(that is GBRnb declared) with the help of the other numbers (also without repeating), and with help of the given operators? Result should be displayed in the textbox, in a form of the whole procedure of how computer got that calculation with that numbers and operators. I tried to make it work by coding operations one by one, but that's a lot of writing... I'm not looking exactly for the code answer, but mainly for the coding algorithm. Any idea? Thanks! :)