I have table as below:
Table Temp:
ID MAX MIN DATE_C
1 34 24 21-APR-17 02.41.38.520000 PM
2 32 26 20-APR-17 02.42.44.569000 PM
I execute the below SQL query to get temperature details on respective date:
SELECT *
FROM Temp t
WHERE t.date_c = TO_DATE( '2017-04-21', 'YYYY-MM-DD')
order by t.id
But it's returning empty records. Whats wrong with my query?
You need to remove the time component on the column. Here is one way:
SELECT *
FROM Temp t
WHERE TRUNC(t.date_c) = DATE '2017-04-21'
ORDER BY t.id;
However, I usually recommend using inequalities, rather than a function on the column:
SELECT *
FROM Temp t
WHERE t.date_c >= DATE '2017-04-21' AND
t.date_c < DATE '2017-04-22'
ORDER BY t.id;
This allows the query to use an index on date_c. I should add that the original version can use an index on (trunc(date_c, id).
21-APR-17 02.41.38.520000 PM is not a DATE; it has a fractional seconds component so it is a TIMESTAMP.
So, if you want to find items that are on a particular day (inputting the TIMESTAMP using an ISO/ANSI timestamp literal):
SELECT *
FROM Temp
WHERE date_c >= TIMESTAMP '2017-04-21 00:00:00' AND
date_c < TIMESTAMP '2017-04-21 00:00:00' + INTERVAL '1' DAY;
or
SELECT *
FROM Temp
WHERE date_c >= TO_TIMESTAMP( :your_date_string, 'YYYY-MM-DD' ) AND
date_c < TO_TIMESTAMP( :your_date_string, 'YYYY-MM-DD' ) + INTERVAL '1' DAY;
it's returning empty records. Whats wrong with my query?
date_c = TO_DATE( '2017-04-21', 'YYYY-MM-DD') matches all rows where the date_c value is exactly 2017-04-21 00:00:00.000000 (including the time component); if you do not have any rows with exactly that date and time then, as you noticed, it will return nothing. If you want to get records matching that day then you need to get values within a range of times between the start and end of the day.
You need to pass date on the column. Here is a way...
SELECT *
FROM Temp t
WHERE CAST(t.CREATED_ON as date)= N'2017-04-22'
ORDER BY t.id
Related
I wanted to get yesterday date from my Date column,
My logic is
SELECT MY_DATE,NAME,MONEY FROM MY_TABLE
WHERE MY_DATE-1
My records looks like this
MYDATE NAME MONEY
10/31/2019 BILLY 2000
11/1/2019 BILLY 3000
If today is 11/1/2019, i wanted to get the records on 10/31/2019.
The output of the select i wanted is
MYDATE NAME MONEY
10/31/2019 BILLY 2000
Since you want yesterday's date, I don't understand why you don't want to use SYSDATE.
Otherwise, it's quite easy:
WHERE my_date = TRUNC(SYSDATE-1);
In Oracle a DATE data type always has year, month, day, hour, minute and second components. Your user interface may not show the time components but they still exist.
If your time components are guaranteed to always be set to midnight then you can use:
SELECT MY_DATE,
NAME,
MONEY
FROM MY_TABLE
WHERE MY_DATE = TRUNC( SYSDATE ) - 1;
If you have non-midnight time values in the MY_DATE column then above method will not work and, instead, the best method is to compare on a range of values (since this allows Oracle to use an index on your column):
SELECT MY_DATE,
NAME,
MONEY
FROM MY_TABLE
WHERE MY_DATE >= TRUNC( SYSDATE ) - 1
AND MY_DATE < TRUNC( SYSDATE );
You could also truncate both sides of the comparison (however, Oracle would not use an index on the column and would need a separate function-based index):
SELECT MY_DATE,
NAME,
MONEY
FROM MY_TABLE
WHERE TRUNC( MY_DATE ) = TRUNC( SYSDATE ) - 1;
Oracle SQL:
I been trying to get this some snippet of query working. When you run it, it prompts you for an hour, and displays no records. I don’t want the query to have a static hour as it will need to be run 4 times a day.
So from the ‘&date’ input, I want it to show data for the past 24 hours. Is that possible?
dt_time = timestamp(6) field
select distinct to_char(dt_ time,'dd/mm/yyyy hh24'), fault_description
from order
where to_char(dt_time,'hh24') <= '&date' -24
order by to_char(dt_ time,'dd/mm/yyyy hh24');
Example, if you enter 10 (when query executed) it will show the data from 10(:00) through to 10(:00)next day
[Hope there is enough info for someone to answer, please]
Use a combination of between and interval:
where dt_time between
to_date(&date, 'ddmmyyyy hh24') and
to_date(&date, 'ddmmyyyy hh24') + interval '24' hour
You'll need to pass/parse the input date as a full date and not only the hour part, in order to prevent unexpected results.
You can use NUMTODSINTERVAL in a CTE to get the hour as user input.
WITH t_hour( h ) AS
( SELECT NUMTODSINTERVAL(&d,'HOUR' ) h FROM DUAL
)
SELECT DISTINCT TO_CHAR(dt_time,'dd/mm/yyyy hh24'),
fault_description
FROM ORDER
CROSS JOIN t_hour
WHERE dt_time BETWEEN TRUNC(SYSDATE) + h AND TRUNC(SYSDATE) + 1 + h
ORDER BY 1;
You need to make use of SYSDATE as you are fetching last one day data.
Also if you add or subtract number with a date column the offset will be number of days, not number of hours. So you need to use &date/24
Try this:
select distinct to_char(dt_time,'dd/mm/yyyy hh24'), fault_description
from order
where dt_time - &date / 24 between TRUNC(sysdate-1) and TRUNC(sysdate)
order by to_char(dt_ time,'dd/mm/yyyy hh24');
Please comment.
WHERE DATEDIFF(SYSDATE,DT_TIME) * 24 < &DATE AND DT_TIME < SYSDATE
I want to select data where the operation_date between '01-Jan-2016' and yesterday. I used code as follows:
select *
where operation_date between '01-Jan-2016' and sysdate-1
from TABLE
But sysdate returns both date and time. Therefore, the above output includes all the data between '01-Jan-2016' and say, 14 Nov-2017 09:50:51. I only want the data before today. How to convert current time to date without time? Thanks.
Seems that you are looking for trunc().
Example
SELECT sysdate - 1 AS current_Date_Time
,trunc(sysdate) - 1 AS CURRENT_DATE1
,trunc(sysdate - 1) AS CURRENT_DATE2
FROM dual
Result
CURRENT_DATE_TIME CURRENT_DATE1 CURRENT_DATE2
----------------------------------------------------------
13.11.2017 18:08:41 13.11.2017 00:00:00 13.11.2017 00:00:00
DEMO
So the correct query will be as below.
SELECT *
WHERE operation_date BETWEEN DATE '2016-01-01' -- ANSI Date Literal
AND trunc(sysdate - 1)
FROM TABLE
OR
SELECT *
WHERE operation_date BETWEEN DATE '2016-01-01' -- ANSI Date Literal
AND trunc(sysdate) - 1
FROM TABLE
How do I select rows in the past starting from yesterday in Oracle DB where a field like created_date is a timestamp(6)?
I don't want to compare time, just date.
If you want exactly one day prior to the current time:
select *
from table t
where created_date < sysdate - 1;
If you want times before today:
select *
from table t
where created_date <= trunc(sysdate);
From the Oracle documentation on SELECT :
SELECT * FROM orders
WHERE created_date < TO_DATE('2014-04-28', 'YYYY-MM-DD');
I can pass this date format from my application, worked like a charm.
As you want to compare just date:
select *
from table t
where date(created_date) < DATE_SUB(CURRENT_DATE(), INTERVAL 1 DAY);
you can use cast function to deal with timestamp as date:
SELECT cast(SYSTIMESTAMP(6) as date)
FROM dual;
so you can select rows with "yesterdate" date by:
select ....
where cast(SYSTIMESTAMP(6) as date) like sysdate - 1
note: replace SYSTIMESTAMP(6) with column name which has timestamp type.
I have the following values in my table
Select * From TimeSheetLogs where InTimeStamp <= '1/22/2013'
when i execute the above query i get null value
but as you can see i have 3 data with datefield as 1/22/2013
Then what i am doing wrong?
Thanks
that is correct because
'1/22/2013 19:21' > '1/22/2013 00:00'
You probably need to truncate your dates first to remove the time portion. Then convert both sides to date datatype. The string '1/22/2013' is a string, not a date. By looking at data your InTimeStamp is timestamp datatype. You cannot compare date or timestamp to character w/out converting the char-s to date. I'm not sure what Database are you using. This is how you'd convert in Oracle using to_date function .
SELECT in_date, compare_date
FROM
(-- This is your InTimeStamp on the fly
SELECT trunc(to_timestamp('2013-01-22 16:21:19.273', 'yyyy-mm-dd hh24:mi:ss.ff')) in_date -- this is your InTimeStamp
, to_date('1/22/2013', 'mm/dd/yyyy') compare_date
FROM dual
)
WHERE in_date <= compare_date
/
Now you can compare two dates below - this is the output of above query:
in_date compare_date
---------- ------------
1/22/2013 1/22/2013
Select * From TimeSheetLogs
where InTimeStamp <= select convert(datetime,'1/22/2013',101)
As per my comment to #Zdravko's good answer, you just need to cast your date:
Select * From TimeSheetLogs where CAST(InTimeStamp as Date) <= '1/22/2013'