'MotorVehicles' Table
I ran a query to find 'AVG(Price) * 2' of attached table, then I ran another query where I substituted 'AVG(Price) * 2' with a hard number, I was able to get the two records in the result table, I have tried to use the aggregate functions in a 'Having' clause but my result table comes back empty. Need some help I would like to formulate a SELECT statement without a subquery to find all Motor vehicles whos price is more or equal to 'AVG(Price * 2)' in attached table.
thanks in advance
Many methods, this isn't nice, but it would work:
;with cte_a as
(
select avg(Price)*2 [Average]
from yourTable
-- or whatever your query to get average is as long as only 1 result
)
select *
from yourTable yt
inner join cte_a a on 1 = 1
where price >= a.Average
select * from MotorVehicles where price > (select avg(price) from t)*2;
I apologise if this is the subquery you want to avoid.
You can get something similar using a partitioned AVG().
DECLARE #T TABLE
(
X INT
)
INSERT #T SELECT 1
INSERT #T SELECT 10
INSERT #T SELECT 15
INSERT #T SELECT 20
SELECT X,XAVG=AVG(X) OVER(PARTITION BY 1 ) FROM #T
Resulting in:
X XAVG
1 11
10 11
15 11
20 11
Related
I am trying to write a sql statement that works something like a store. I have two queries and I want n records from the first query, but if there is less than n, I want the rest from the second.
I tried using TOP n and UNION
SELECT TOP 20 FROM (
(SELECT * FROM t1)
UNION
(SELECT * FROM t2))
but the results are from both tables regardless of how many are in t1. Basically, I want the first query to have precedence. If 5 records exist there and I want them and I want the rest from t2.
Add a column that identifies the query, so the first one have precedence.
SELECT TOP 20 *
FROM ((SELECT 1 as query, * FROM t1)
UNION
(SELECT 2 as query, * FROM t2))
ORDER BY query
you can use a CTE to place a sort order on the two tables and then use that in an order by clause
declare #foo1 table(
bar INT
)
insert into #foo1
values (1),(2),(3),(4),(5),(6),(7),(8),(9),(10)
--,(11),(12),(13),(14),(15),(16),(17),(18),(19),(20)
declare #foo2 table(
bar INT
)
insert into #foo2
values (101),(102),(103),(104),(105),(106),(107),(108),(109),(110),(111),(112),(113),(114),(115),(116),(117),(118),(119),(120)
;with base_data as (
select
0 as sort,
f1.bar
FROM #foo1 f1
UNION
SELECT
1 as sort,
f2.bar
FROM #foo2 f2
)
select top 20 bar
from base_data
order by sort, bar
I'll start directly by explaining with an example. Suppose I have a table which has 3 columns as shown.
Now what I am trying to achieve is, I want the first values of each individual column into a single column. So it would be something like this,
I have tried a few queries here including using TOP 1 and other incorrect ways. But I am still missing something here to achieve the exact output.
Need some guidance here on how to achieve this. Thank you.
SAMPLE TABLE
SELECT * INTO #TEMP
FROM
(
SELECT 1 BATCH_ID,'AAA' ASSIGNMENTTITLE,'FILE' ASSIGNMENTTYPE
UNION ALL
SELECT 1,'AAA1','FILE'
UNION ALL
SELECT 1,'AAA','FILE'
)TAB
If you need the second row specifically you can do the below
QUERY
;WITH CTE AS
(
-- Order row according to default format
SELECT ROW_NUMBER() OVER(ORDER BY (SELECT(0))) RNO,*
FROM #TEMP
)
SELECT CAST(BATCH_ID AS VARCHAR(20)) FROM CTE WHERE RNO=2
UNION ALL
SELECT ASSIGNMENTTITLE FROM CTE WHERE RNO=2
UNION ALL
SELECT ASSIGNMENTTYPE FROM CTE WHERE RNO=2
Click here to view result
UPDATE
Since there are 3 items in each record, it can be puzzled unless and otherwise an a column is for each items in a record.
;WITH CTE AS
(
-- Order row according to default format
SELECT ROW_NUMBER() OVER(ORDER BY (SELECT(0))) RNO,*
FROM #TEMP
)
SELECT CAST(BATCH_ID AS VARCHAR(20)),RNO
FROM CTE
UNION ALL
SELECT ASSIGNMENTTITLE,RNO
FROM CTE
UNION ALL
SELECT ASSIGNMENTTYPE,RNO
FROM CTE
ORDER BY RNO
Click here to view result
You can use the concat() function to create a column consisting of all the desired values
More info here
Simply you can try this. If want specific for a row use rowid. For all columns Use unpivot
create table #temp(id int, name varchar(100), title varchar(100))
insert into #temp values(1,'aaa','file')
insert into #temp values(1,'aaas','filef')
insert into #temp values(1,'aaaww','filefs')
select * from #temp
select top 1 cast(id as varchar) title from #temp
union
select top 1 name from #temp
union
select top 1 title from #temp
drop table #temp
This might help you
select top 1 convert(varchar(10), batch_id) ASSIGNMENTTITLE from table
union all
select top 1 ASSIGNMENTTITLE from table
union all
select top 1 ASSIGNMENTTYPE from table
If this is really what you want: "I want the first values of each individual column into a single column" it would be:
select ASSIGNMENTTITLE
from (
select min(convert(varchar(10), batch_id)) ASSIGNMENTTITLE,
1 ColOrder from table
union all
select min(ASSIGNMENTTITLE),
2 ColOrder from table
union all
select min(ASSIGNMENTTYPE),
3 ColOrder from table
) as data
order by ColOrder
I have a table that I'm trying to break out each row into one or more rows based on the second column value. Like this:
table (id, pcs):
ABC 3
DEF 1
GHJ 4
query result (id, pcs_num):
ABC 1
ABC 2
ABC 3
DEF 1
GHJ 1
GHJ 2
GHJ 3
GHJ 4
I'm writing this as a sproc in SQL server 2008. My best solution is to use a cursor and add [pcs] number of rows to a temp table for each row in the table. Is seems like there must be a simpler solution than this that I am missing. Thanks.
You can use a recursive CTE:
;WITH CTE AS
(
SELECT *
FROM YourTable
UNION ALL
SELECT id, pcs-1
FROM CTE
WHERE pcs-1 >= 1
)
SELECT *
FROM CTE
ORDER BY id, pcs
OPTION(MAXRECURSION 0)
Here is a demo for you to try.
Here is my approach. Extremely easy with a Tally Table (A table that only has a column with a value 1 -> X). No need for recursion, and this will be much faster over larger tables.
Notice we are only making a Tally Table of 100 rows, feel free to expand that as large as you'd like. If you get too crazy, you might need another cross join in sys.sysobjects to accomdate. The real query is at the bottom, as you can see it's extremely easy.
SELECT TOP 100
IDENTITY( INT,1,1 ) AS N
INTO #Tally
FROM sys.sysobjects sc1 ,
sys.sysobjects sc2
CREATE TABLE #Test
(
Id char(3),
pcs int
)
INSERT INTO #Test
SELECT 'ABC', 3 UNION ALL
SELECT 'DEF', 1 UNION ALL
SELECT 'GHJ', 4
SELECT #Test.Id, #Tally.N FROM #Tally
JOIN #Test ON #Tally.N <= #Test.pcs
ORDER BY #Test.Id
SELECT
id
,pcs_num
FROM MyTable
CROSS APPLY (
SELECT TOP (pcs)
ROW_NUMBER() OVER(ORDER BY (SELECT 1)) pcs_num
FROM master.dbo.spt_values
) t
I have the following query that returns rows based on a comma seperated list
Select * from Table where RecordID in (22,15,105,1,65,32)
I would like the results of this query to return to in the order of the ID's in the list. Is that possible with SQL?
Thanks in advance
select * from Table
where RecordID in (22,15,105,1,65,32)
order by (
case RecordID
when 22 then 1
when 15 then 2
when 105 then 3
when 1 then 4
when 65 then 5
when 32 then 6 end)
If you need the output to appear in a particular order, then you need to specify that order, using something the server can sort. Not knowing which engine you're working against, the general scheme would be to create a temp table or use rowset constructors to pair each record ID with its desired sort order.
E.g. (SQL Server)
declare #T table (RecordID int,Position int)
insert into #T (RecordID,Position)
select 22,1 union all
select 15,2 union all
select 105,3 union all
select 1,4 union all
select 65,5 union all
select 32,6
select * from Table t inner join #T t2 on t.RecordID = t2.RecordID order by t2.Position
I'd to the ordering in the client, but if you really want to do it in SQL, do it like this:
declare #T table (id int identity(1,1), RecordID int)
insert into #T (RecordID)
values (22), (15), (105), (1), (65), (32)
select * from
[table] t
inner join #t s on t.id=s.recordid
where t.id in (22, 15, 105, 1, 65, 32)
order by s.id
(works in SQL Server 2008)
Yes. You add the ORDER BY recordedid clause at the end.
The last time I had to do this I ended up doing a union all and generating a select statement for each id, i.e.
select * from Table where RecordID = 22
union all
select * from table where recordid = 15
etc.
It was a pain but it worked.
Use ORDER BY against the RecordID
Select * from Table where RecordID in (22,15,105,1,65,32) ORDER BY RecordID
I'm trying to write a query that will return all QUERY_ID values alongside all matching TABLE_ID values, where QUERY_ID is not specified in any table, and I can't create tables, so have to specify it in the query itself:
QUERY_ID TABLE_ID
1 1
2 NULL
3 3
4 4
5 NULL
I feel like there ought to be a simple way to do this, but I can't think of it for the life of me. Any help would be wonderful. Thanks!
select q.QUERY_ID, t.TABLE_ID
from (
select 1 as QUERY_ID
union all
select 2
union all
select 3
union all
select 4
union all
select 5
) q
left outer join MyTable t on q.QUERY_ID = t.TABLE_ID
one way by using the built in master..spt_values table
SELECT number AS QUERY_ID,TABLE_ID
FROM master..spt_values v
LEFT JOIN YourTable y ON y.QUERY_ID = y.TABLE_ID
WHERE TYPE = 'p'
AND number > 0
AND number <= (SELECT COUNT(*) FROM YourTable)
order by QUERY_ID
are you able to create #temp tables...can you do this?
create table #temp(QUERY_ID int identity,TABLE_ID varchar(200))
insert #temp(TABLE_ID)
select TABLE_ID
from YourTable
select * from #temp
order by QUERY_ID
drop table #temp
or like this
select identity(int,1,1) as QUERY_ID,TABLE_ID
into #temp
from YourTable
select * from #temp
order by QUERY_ID
On sql server 2005 and up there is the row_number function so maybe a reason to upgrade :-)