I created the following table in hive.
CREATE TABLE IF NOT EXISTS employee (
eid int,
name String,
salary String,
destination String
)
COMMENT ‘Employee details’
ROW FORMAT DELIMITED
FIELDS TERMINATED BY ‘\t’
LINES TERMINATED BY ‘\n’
STORED AS TEXTFILE;
The table is created successfully. I am trying to do the following insert
insert into TABLE employee (eid,name,salary,destination) VALUES (1,'avi','100000','boston');
However, I am getting the following error messages.
NoViableAltException(283#[])
at org.apache.hadoop.hive.ql.parse.HiveParser.regularBody(HiveParser.java:39678)
at org.apache.hadoop.hive.ql.parse.HiveParser.queryStatementExpressionBody(HiveParser.java:38904)
at org.apache.hadoop.hive.ql.parse.HiveParser.queryStatementExpression(HiveParser.java:38780)
at org.apache.hadoop.hive.ql.parse.HiveParser.execStatement(HiveParser.java:1514)
at org.apache.hadoop.hive.ql.parse.HiveParser.statement(HiveParser.java:1052)
at org.apache.hadoop.hive.ql.parse.ParseDriver.parse(ParseDriver.java:199)
at org.apache.hadoop.hive.ql.parse.ParseDriver.parse(ParseDriver.java:166)
at org.apache.hadoop.hive.ql.Driver.compile(Driver.java:389)
at org.apache.hadoop.hive.ql.Driver.compile(Driver.java:303)
at org.apache.hadoop.hive.ql.Driver.compileInternal(Driver.java:1067)
at org.apache.hadoop.hive.ql.Driver.runInternal(Driver.java:1129)
at org.apache.hadoop.hive.ql.Driver.run(Driver.java:1004)
at org.apache.hadoop.hive.ql.Driver.run(Driver.java:994)
at org.apache.hadoop.hive.cli.CliDriver.processLocalCmd(CliDriver.java:201)
at org.apache.hadoop.hive.cli.CliDriver.processCmd(CliDriver.java:153)
at org.apache.hadoop.hive.cli.CliDriver.processLine(CliDriver.java:364)
at org.apache.hadoop.hive.cli.CliDriver.executeDriver(CliDriver.java:712)
at org.apache.hadoop.hive.cli.CliDriver.run(CliDriver.java:631)
at org.apache.hadoop.hive.cli.CliDriver.main(CliDriver.java:570)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:498)
at org.apache.hadoop.util.RunJar.run(RunJar.java:221)
at org.apache.hadoop.util.RunJar.main(RunJar.java:136)
FAILED: ParseException line 1:27 cannot recognize input near '(' 'eid' ',' in statement
How can I fix this?
INSERT INTO employee select 1, 'avi', '100000', 'boston';
It seems your version does not support insert columns list nor values.
P.s.
The error message is very clear.
You should focus on the last line.
Remember you need quotation marks as you are trying to insert Strings. Also, the field names are not necessary as you are inserting a value for all fields in your table. You might simply try the following:
INSERT INTO TABLE employee
VALUES (1, 'avi', '100000', 'boston');
You can't insert the data like this or insert command because insert command use in SQL.
For loading data into hive you have to create a one text file and you have to upload that file using load command.
For example
LOAD DATA LOCAL INPATH 'YOUR TXT FILE LOCATION' OVERWRITE INTO TABLE TABLENAME;
Related
I wanted to insert records having special character in snowflake.
Having record in source table :
order/date=2022-02-18/hour=12/85b3e2d8-0195-4238-b246-7ed6564ac464.json
I need to extract hour value i.e 12
I am able to extract the value using : cast(replace(substr(METADATA$FILENAME,28,2),'/','') as number)
But I need to create the insert script , I had tried :
'cast(replace(substr(METADATA$FILENAME,28,2),'/,'') as number)'
But getting error : FAILED CODE: 0 STATE: 22018 MESSAGE: Numeric value '5/' is not recognized
I tested your string in select and insert command as below:
select cast(replace(substr('order/date=2022-02-18/hour=12/85b3e2d8-0195-4238-b246-7ed6564ac464.json',28,2),'/','') as integer);
create table t1(c1 number);
insert into t1(c1) select cast(replace(substr('order/date=2022-02-18/hour=12/85b3e2d8-0195-4238-b246-7ed6564ac464.json',28,2),'/','') as integer);
If your issue is different, then share the exact command that you are executing and that's failing.
I got the solution :
Solution Snap shot
I wanted to insert this whole statement as string , I was facing issue due to special characters : / and '' .
Used backslash to resolve it.
I am trying to insert into Table Users from Person table.
However, The first_name column in the person table contains apostrophe in the name (Eg- Rus'sell) which is preventing me from successful insertion. How do I fix this?
INSERT INTO USERS VALUES (SELECT FIRST_NAME,.........FROM PERSON);
INSERT INTO USERS VALUES (SELECT FIRST_NAME,.........FROM PERSON);
First of all, your insert statement is syntactically incorrect. It will raise ORA-00936: missing expression. The correct syntax to insert multiple records from source table is:
INSERT INTO table_name SELECT columns_list FROM source_table;
The VALUES keyword is used to insert a single record into table using following syntax:
INSERT INTO table_name(columns_list) VALUES (expressions_list);
If you already have the value stored in another table, then simple INSERT INTO..SELECT FROM should work without any issues. However, if you are trying to INSERT INTO..VALUES having single quotation marks, then the best way is to use Quoting string literal technique The syntax is q'[...]', where the "[" and "]" characters can be any of the following as long as they do not already appear in the string.
!
[ ]
{ }
( )
< >
You don't have to worry about the single-quotation marks within the string.
create table t(name varchar2(100));
insert into t values (q'[Rus'sell]');
insert into t values (q'[There's a ' quote and here's some more ' ' ']');
select * from t;
NAME
-----------------------------------------------
Rus'sell
There's a ' quote and here's some more ' ' '
I don't think your question is showing the complete details, because I can execute the following statements without any problem:
create table person( first_name varchar2(100));
create table users( first_name varchar2(100));
insert into person values ('Rus''sell');
insert into users select first_name from person;
Apologies for the obscurity if any in the question. The query I was working with was a long insert query with multiple joins.
To sum it was a stored proc where I was doing an insert, for which the data is given by long select query with multiple joins. One of the column is the FIRST_NAME column which had some values with Apostrophe in it (Rus'sell, Sa'm).
The Insert statement values were being generated as below which was causing an 'ORA-00917: missing comma' error.
INSERT INTO TABLE_NAME values (314159,0,'Rus'sell','Parks','...........)
I fixed this by Replacing the column in the select from a single quote to two single quotes, before giving it to the insert statement which basically solved the issue.
REPLACE(FIRST_NAME,'''','''''') AS FIRST_NAME
Hope it helps.
I have a hive table created using the following query:
create table arraytbl (id string, model string, cost int, colors array <string>,size array <float>)
row format delimited fields terminated by ',' collection items terminated by '#';
Now , while trying to insert a row:
insert into mobilephones values
("AA","AAA",5600,colors("red","blue","green"),size(5.6,4.3));
I get the following error:
FAILED: SemanticException [Error 10293]: Unable to create temp file for insert values Expression of type TOK_FUNCTION not supported in insert/values
How can I resolve this issue?
The syantax to enter values in complex datatype if kinda bit weird, however this is my personal opinion.
You need a dummy table to insert values into hive table with complex datatype.
insert into arraytbl select "AA","AAA",5600, array("red","blue","green"), array(CAST(5.6 AS FLOAT),CAST(4.3 AS FLOAT)) from (select 'a') x;
And this is how it looks after insert.
hive> select * from arraytbl;
OK
AA AAA 5600 ["red","blue","green"] [5.6,4.3]
I wish to insert into an SQL table in a field whose data type is text. However I am informed of an error saying ' check datatype' my Name field is of type nvarchar and my job field is of type text.
INSERT INTO Table1 (Name, Job) VALUES ('John', 'Clerk')
In MS SQL Server, you wont be able to insert string values(with more than 1 characters) in table if the column of type nvarchar. You can only insert only one character using nvarchar.
If you wish to insert some text, please specify the some size with nvarchar.
For example in your case:
Create table Table1(Name nvarchar(5), Job Text)
Insert into Table1(Name, Job) values ('John','Clerk')
This will work.
Hope it will help you out.
I have the following:
hive> CREATE TABLE foo (bar timestamp) STORED AS ORC;
OK
Time taken: 0.041 seconds
hive> INSERT INTO TABLE foo VALUES ('2014-01-17 00:17:13');
NoViableAltException(26#[])
at org.apache.hadoop.hive.ql.parse.HiveParser_SelectClauseParser.selectClause(HiveParser_SelectClauseParser.java:742)
at org.apache.hadoop.hive.ql.parse.HiveParser.selectClause(HiveParser.java:40184)
at org.apache.hadoop.hive.ql.parse.HiveParser.singleSelectStatement(HiveParser.java:38048)
at org.apache.hadoop.hive.ql.parse.HiveParser.selectStatement(HiveParser.java:37754)
at org.apache.hadoop.hive.ql.parse.HiveParser.regularBody(HiveParser.java:37654)
at org.apache.hadoop.hive.ql.parse.HiveParser.queryStatementExpressionBody(HiveParser.java:36898)
at org.apache.hadoop.hive.ql.parse.HiveParser.queryStatementExpression(HiveParser.java:36774)
at org.apache.hadoop.hive.ql.parse.HiveParser.execStatement(HiveParser.java:1338)
at org.apache.hadoop.hive.ql.parse.HiveParser.statement(HiveParser.java:1036)
at org.apache.hadoop.hive.ql.parse.ParseDriver.parse(ParseDriver.java:199)
at org.apache.hadoop.hive.ql.parse.ParseDriver.parse(ParseDriver.java:166)
at org.apache.hadoop.hive.ql.Driver.compile(Driver.java:408)
at org.apache.hadoop.hive.ql.Driver.compile(Driver.java:322)
at org.apache.hadoop.hive.ql.Driver.compileInternal(Driver.java:976)
at org.apache.hadoop.hive.ql.Driver.runInternal(Driver.java:1041)
at org.apache.hadoop.hive.ql.Driver.run(Driver.java:912)
at org.apache.hadoop.hive.ql.Driver.run(Driver.java:902)
at org.apache.hadoop.hive.cli.CliDriver.processLocalCmd(CliDriver.java:268)
at org.apache.hadoop.hive.cli.CliDriver.processCmd(CliDriver.java:220)
at org.apache.hadoop.hive.cli.CliDriver.processLine(CliDriver.java:423)
at org.apache.hadoop.hive.cli.CliDriver.executeDriver(CliDriver.java:793)
at org.apache.hadoop.hive.cli.CliDriver.run(CliDriver.java:686)
at org.apache.hadoop.hive.cli.CliDriver.main(CliDriver.java:625)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:606)
at org.apache.hadoop.util.RunJar.main(RunJar.java:212)
FAILED: ParseException line 1:22 cannot recognize input near 'values' '(' ''2014-01-17 00:17:13'' in select clause
What is the correct way of inserting timestamps into a Hive table?
Hive version is: hive-0.13.0
According to Hive Language Manual "INSERT...VALUES is available starting in Hive 0.14".
So, you have only two options left:
Insert timestamp value from existing table or call a function to get it (e.g. from_unixtime(unix_timestamp()), see this answer for example)
Load data from a file.
This kind of writing is correct:
insert into table foo;
select '2014-01-17 00:17:13' as bar from foo