Hello guys i need to use mutiple where clause in one sql query as follows but it can't work please help me.
select (select count(total) as 'studentMarks1' from School where total <60 ),
(select count(total) as 'studentMarks2' from School where total >80 )
from School
where Id = '8'
You rather need to use CASE statement like
select SUM(case when total < 60 then 1 else 0 end) as 'studentMarks1',
sum(case when total > 80 then 1 else 0 end) as 'studentMarks2'
from School
where Id = '8'
You cau usually do this with an appropriate CASE statement:
SELECT COUNT(CASE WHEN total < 60 then 1 else NULL END)
, COUNT(CASE WHEN total > 80 then 1 else NULL END)
FROM School
WHERE ID = '8'
Related
I have a bit of sql code that look similar to this:
select sum(case when latitude = '0' then 1 else 0 end) as count_zero,
sum(case when latitude is NULL then 1 else 0 end) as count_null,
sum((case when latitude = '0' then 1 else 0 end) +
(case when latitude is NULL then 1 else 0 end)
) as total_zero,
count(latitude) as count_not_nulls,
count(*) as total
from sites_database
Is there a "cleaner" way to write this same query. I have tried using the "sum" expression using the column alias, something like:
Sum(count_zero + count_null) as total_null
But this doesn't seem to work for some reason
You could use COUNT instead of SUM:
SELECT
COUNT(CASE WHEN latitude = '0' THEN 1 END) As count_zero,
COUNT(CASE WHEN latitude IS NULL THEN 1 END) AS count_null,
COUNT(CASE WHEN COALESCE(latitude, '0') = '0' THEN 1 END) AS total_zero,
COUNT(latitude) As count_not_nulls,
COUNT(*) as total
FROM sites_database;
Using COUNT here saves a bit of coding, because we don't have to provide an explicit ELSE condition (the default ELSE is NULL, which just isn't counted at all). Also note that for the total_zero conditional sum, I used COALESCE to merge the two counts into just one.
Have a tableA like this:
I wanna receive a tableИ like this (group by startTime and endTime, count of Severity in cnt column and count of every type of Severity in a distinct column):
The simple count (cnt column) works fine. But with the other I tired CASE WHEN THEN logics and it seems not working (line 10 for example). Can you please assist me with SQL query in this case.
You need conditional aggregation :
select starttime, endtime, count(*),
sum(case when severity = 'low' then 1 else 0 end),
sum(case when severity = 'med' then 1 else 0 end),
sum(case when severity = 'high' then 1 else 0 end)
from table t
group by starttime, endtime;
Try below query: with case when
select starttime, endtime, count(severity) as cnt, count(case when severity='LOW' then 1 end) cnt_low,count(case when severity='MED' then 1 end) cnt_med,count(case when severity='HIGH' then 1 end) as cnt_high
from tablename
group by starttime, endtime
use case when and aggregate function sum
select startTime , endTime,count(*) as Cnt,
sum( case when Severity='MED' then 1 else 0 end) as cntMed,
sum( case when Severity='LOW' then 1 else 0 end) as cntLow,
sum( case when Severity='HIGH' then 1 else 0 end) as cntHIGH from yourtable
group by startTime , endTime
I have this SQL query:
SELECT
COUNT(SDDOCO) AS Total
FROM
KAIPRDDTA.F4211LA, KAIPRDDTA.Dates
WHERE
SDDRQJ = Day10
which returns a count of all the orders for today.
I am trying to get a second column so that I have this:
To get orders that are not completed would be: SDNXTR < '562'. How would I add this to my sql query so that I can accomplish this goal? Let me know if you need anymore information and thanks in advance for your responses.
You have two options here:
SELECT
COUNT(SDDOCO) AS Total,
SUM(CASE WHEN SDNXTR < '562' THEN 1 ELSE 0 END) AS Not_Finished_Yet_With_SUM,
COUNT(CASE WHEN SDNXTR < '562' THEN 1 ELSE NULL END) AS Not_Finished_Yet_With_COUNT,
FROM
KAIPRDDTA.F4211LA, KAIPRDDTA.Dates
WHERE
SDDRQJ = Day10
You can use case statement to count that SDNXTR < '562' values like below:
SELECT count(SDDOCO) as Total,
sum(case when SDNXTR < '562' then 1 else 0 end) as not_yet_finished
FROM KAIPRDDTA.F4211LA, KAIPRDDTA.Dates
WHERE SDDRQJ = Day10
How can I use IN in my "case expression"?
This is my query where I want count if any match like mumbai found then as mumbai:
select TYPEOFPRODUCT,
SUM(CASE(BRANCH) WHEN IN('Mumbai1' OR 'Mumbai2') THEN 1 ELSE 0 END) AS 'Mumbai'
SUM(CASE(BRANCH) WHEN IN('Delhi1' OR 'DelhiMain') THEN 1 ELSE 0 END) AS 'Delhi'
from los_ext
group by TYPEOFPRODUCT
You were close, you just need to comma separate values for IN rather than using OR, and there are two formats for CASE expressions, putting the field with the criteria after WHEN is more flexible, so I prefer to use it exclusively:
SELECT TYPEOFPRODUCT
,SUM( CASE WHEN BRANCH IN('Mumbai1','Mumbai2') THEN 1 ELSE 0 END) AS Mumbai
,SUM( CASE WHEN BRANCH IN('Delhi1', 'DelhiMain') THEN 1 ELSE 0 END) AS Delhi
FROM los_ext
GROUP BY TYPEOFPRODUCT
Its query select sum of individual branchs
select TYPEOFPRODUCT,
SUM(CASE WHEN (BRANCH = 'Mumbai1' OR BRANCH = 'Mumbai2' ) THEN 1 ELSE 0 END) AS 'Mumbai',
SUM(CASE WHEN (BRANCH = 'Delhi1' OR BRANCH = 'DelhiMain' ) THEN 1 ELSE 0 END) AS 'Delhi'
from los_ext
group by TYPEOFPRODUCT
I want to do a query like:
select
count(asterisk) where acción='a'/count(asterisk) where acción='b' * 100
from
same_table
grouped by day
but I don't want use subquery, is it possible with joins?
I`m not sure the syntax is correct, but you can use something like this:
SELECT day,
SUM(CASE WHEN "acción" = 'a' THEN 1 ELSE 0 END) AS SUM_A,
SUM(CASE WHEN "acción" = 'b' THEN 1 ELSE 0 END) AS SUM_B,
SUM(CASE WHEN "acción" = 'a' THEN 1 ELSE 0 END) AS SUM_A / SUM(CASE WHEN "acción" = 'b' THEN 1 ELSE 0 END) * 100 AS result
FROM your_table
GROUP BY day
The concept is to actually sum the the values that you need, instead of count.