How can I use IN in my "case expression"?
This is my query where I want count if any match like mumbai found then as mumbai:
select TYPEOFPRODUCT,
SUM(CASE(BRANCH) WHEN IN('Mumbai1' OR 'Mumbai2') THEN 1 ELSE 0 END) AS 'Mumbai'
SUM(CASE(BRANCH) WHEN IN('Delhi1' OR 'DelhiMain') THEN 1 ELSE 0 END) AS 'Delhi'
from los_ext
group by TYPEOFPRODUCT
You were close, you just need to comma separate values for IN rather than using OR, and there are two formats for CASE expressions, putting the field with the criteria after WHEN is more flexible, so I prefer to use it exclusively:
SELECT TYPEOFPRODUCT
,SUM( CASE WHEN BRANCH IN('Mumbai1','Mumbai2') THEN 1 ELSE 0 END) AS Mumbai
,SUM( CASE WHEN BRANCH IN('Delhi1', 'DelhiMain') THEN 1 ELSE 0 END) AS Delhi
FROM los_ext
GROUP BY TYPEOFPRODUCT
Its query select sum of individual branchs
select TYPEOFPRODUCT,
SUM(CASE WHEN (BRANCH = 'Mumbai1' OR BRANCH = 'Mumbai2' ) THEN 1 ELSE 0 END) AS 'Mumbai',
SUM(CASE WHEN (BRANCH = 'Delhi1' OR BRANCH = 'DelhiMain' ) THEN 1 ELSE 0 END) AS 'Delhi'
from los_ext
group by TYPEOFPRODUCT
Related
I have a bit of sql code that look similar to this:
select sum(case when latitude = '0' then 1 else 0 end) as count_zero,
sum(case when latitude is NULL then 1 else 0 end) as count_null,
sum((case when latitude = '0' then 1 else 0 end) +
(case when latitude is NULL then 1 else 0 end)
) as total_zero,
count(latitude) as count_not_nulls,
count(*) as total
from sites_database
Is there a "cleaner" way to write this same query. I have tried using the "sum" expression using the column alias, something like:
Sum(count_zero + count_null) as total_null
But this doesn't seem to work for some reason
You could use COUNT instead of SUM:
SELECT
COUNT(CASE WHEN latitude = '0' THEN 1 END) As count_zero,
COUNT(CASE WHEN latitude IS NULL THEN 1 END) AS count_null,
COUNT(CASE WHEN COALESCE(latitude, '0') = '0' THEN 1 END) AS total_zero,
COUNT(latitude) As count_not_nulls,
COUNT(*) as total
FROM sites_database;
Using COUNT here saves a bit of coding, because we don't have to provide an explicit ELSE condition (the default ELSE is NULL, which just isn't counted at all). Also note that for the total_zero conditional sum, I used COALESCE to merge the two counts into just one.
For the following query:
select count(distinct email_address)
from
(
select distinct email_address,
case when elq_activity_type='EmailSend' then 1 else 0 end 'Sends',
case when elq_activity_type='Bounceback' then 1 else 0 end 'Bounces',
case when elq_activity_type='EmailOpen' then 1 else 0 end 'Opens',
case when elq_activity_type='EmailClickthrough' then 1 else 0 end 'Clicks'
from elq_stg_activity
) a
having sum(sends-bounces)>0
The having clause doesn't seem to be doing anything. What am I doing wrong?
Need to get all unique emails that had an email delivered to them (send-bounce).
Thanks!
I think you want this:
select count(email_address)
from (select email_address,
sum(case when elq_activity_type = 'EmailSend' then 1 else 0 end) Sends,
sum(case when elq_activity_type = 'Bounceback' then 1 else 0 end) as Bounces,
sum(case when elq_activity_type = 'EmailOpen' then 1 else 0 end) as Opens,
sum(case when elq_activity_type = 'EmailClickthrough' then 1 else 0 end) as Clicks
from elq_stg_activity
group by email_address
) a
where sends = bounces;
There are numerous issues with your query. This is the only sensible interpretation I could think of.
I want to do a query like:
select
count(asterisk) where acción='a'/count(asterisk) where acción='b' * 100
from
same_table
grouped by day
but I don't want use subquery, is it possible with joins?
I`m not sure the syntax is correct, but you can use something like this:
SELECT day,
SUM(CASE WHEN "acción" = 'a' THEN 1 ELSE 0 END) AS SUM_A,
SUM(CASE WHEN "acción" = 'b' THEN 1 ELSE 0 END) AS SUM_B,
SUM(CASE WHEN "acción" = 'a' THEN 1 ELSE 0 END) AS SUM_A / SUM(CASE WHEN "acción" = 'b' THEN 1 ELSE 0 END) * 100 AS result
FROM your_table
GROUP BY day
The concept is to actually sum the the values that you need, instead of count.
I am getting a divide by zero error in my script.
Can anyone please help.
I am trying to divide two records and one of them has zero in it. I dont want to lose the row, please advise.
select DATEPART(Year,Request_date) as "Year",
DATEPART(Month,Request_date) as "Month",
COUNT([MONTH_OF_SUSPENSION]) as "Request" ,
sum(case when [PAYMENT_<=24HRS] = 'Y' then 1 else 0 end) as "Paid in 24hrs",
COUNT([MONTH_OF_SUSPENSION])/sum(case when [PAYMENT_<=24HRS] = 'Y' then 1 else 0 end) as "Achieved"
FROM suspension_br
where REQUEST_STATUS = 'OTHERS'
GROUP BY DATEPART(Year,Request_date),DATEPART(Month,Request_date)
You can introduce a second case to check the result of the sum:
case
when sum(case when [PAYMENT_<=24HRS] = 'Y' then 1 else 0 end) > 0
then COUNT([MONTH_OF_SUSPENSION])/sum(case when [PAYMENT_<=24HRS] = 'Y' then 1 else 0 end)
else 0 /* a default value that makes sense to you */
end as "Achieved"
Looking at your code I could assume you are using MSSQL and therefore you could use nullif which returns null if two arguments are equal. So for example your code could look like :
COUNT([MONTH_OF_SUSPENSION])/nullif(sum(case when [PAYMENT_<=24HRS] = 'Y' then 1 else 0 end),0) as "Achieved"
What it does is if the value of the sum operator is equal 0 then the divisor is turn from zero into null and that will result in the entire equation to become null.
use another case statement to check the result of your sum
select DATEPART(Year,Request_date) as "Year",
DATEPART(Month,Request_date) as "Month",
COUNT([MONTH_OF_SUSPENSION]) as "Request" ,
sum(case
when [PAYMENT_<=24HRS] = 'Y' then 1
else 0
end) as "Paid in 24hrs",
case
when sum(case
when [PAYMENT_<=24HRS] = 'Y' then 1
else 0
end) = 0 then 'whatever you want in this case'
else COUNT([MONTH_OF_SUSPENSION])/sum(case
when [PAYMENT_<=24HRS] = 'Y' then 1
else 0
end) as "Achieved"
FROM suspension_br
where REQUEST_STATUS = 'OTHERS'
GROUP BY DATEPART(Year,Request_date),DATEPART(Month,Request_date)
although this is pretty nasty looking, so you could tidy it up a bit with a sub-select:
select
year,
month,
request,
PaidIn24hrs,
case
when PaidIn24hrs = 0 then 'whatever you want in this case'
else request/PaidIn24hrs
end as "Achieved"
from
(
select DATEPART(Year,Request_date) as "Year",
DATEPART(Month,Request_date) as "Month",
COUNT([MONTH_OF_SUSPENSION]) as "Request" ,
sum(case
when [PAYMENT_<=24HRS] = 'Y' then 1
else 0
end) as "PaidIn24hrs"
FROM suspension_br
where REQUEST_STATUS = 'OTHERS'
GROUP BY DATEPART(Year,Request_date),DATEPART(Month,Request_date)
)
I created this select statement I will convert to a view. I need help with this. I need to be able to add the total of Minority that = Yes and No show total on report pages.
select
ps.BidPackage_ID,
ps.Project_ID,
SUM (case ps.Minority when 'Yes' then 1 else 0 end) MinorityTotal,
SUM (case ps.Gender when 'Female' then 1 else 0 end) FemaleTotal,
SUM(case ps.Cleveland_Resident when 1 then 1 else 0 end) ClevelandResidents,
ps.SubContractor
from
PersonnelSummary ps
group by
ps.BidPackage_ID,
ps.Project_ID,
ps.SubContractor
You nearly have it:
...
SUM (case ps.Minority when 'Yes' then 1 else 0 end) AS MinorityYes,
SUM (case ps.Minority when 'No' then 1 else 0 end) AS MinorityNo,
COUNT(*) AS Total,
...
With the Total I'm assuming that every row should be counted. This is what you want if:
The only values that exist in the column are 'Yes' and 'No' or
Values different from 'Yes' and 'No' should also be counted in the total.
You're forcing us to guess what you want. You have a count of the people who said that they were in a minority; do you want a count of the people who said No? Or do you want a count of the number who said 'either "Yes" or "No"' and excluding those who gave 'decline to say' or simply no answer at all?
select
ps.BidPackage_ID,
ps.Project_ID,
SUM (case ps.Minority when 'Yes' then 1 else 0 end) MinorityTotalYes,
SUM (case ps.Minority when 'No' then 1 else 0 end) MinorityTotalNo,
SUM (case ps.Minority when 'Yes' then 1 when 'No' then 1 else 0 end)
AS StatedMinorityTotal,
SUM (case ps.Gender when 'Female' then 1 else 0 end) FemaleTotal,
SUM(case ps.Cleveland_Resident when 1 then 1 else 0 end) ClevelandResidents,
ps.SubContractor
from
PersonnelSummary ps
group by
ps.BidPackage_ID,
ps.Project_ID,
ps.SubContractor