i have table like this :
school grade type
------ ----- -----
sc1 g1 t1
sc2 g2 t1
sc3 g4 t3
sc4 g3 t2
sc1 g2 t3
... etc
column grade has 4 distinct value g1,g2,g3,g4
column type has 3 distinct value t1,t2,t3
column school has 120 distinct value
and i shoud get Summary like this table :(for each distinct column 1-school-)
school g1 g2 g3 g4 sum(g1+g2+g3+g4) t1 t2 t3 sum(t1+t2+t3)
sc1 3 5 1 1 10 21 4 2 27
sc2 2 4 5 5 16 5 23 1 29
etc....
How can I write this query to give me the desired result I achieved part of this job by using report builder V6i
i get all number of distinct school in 1st level and order them ascending
i make query for each value (g1,g2,g3,g4,t1,t2,t3)
i want to get that table in sql query without using report
Conditional aggregation:
with
like_this ( school, grade, typ ) as (
select 'sc1', 'g1', 't1' from dual union all
select 'sc2', 'g2', 't1' from dual union all
select 'sc3', 'g4', 't3' from dual union all
select 'sc4', 'g3', 't2' from dual union all
select 'sc1', 'g2', 't3' from dual
)
-- end of test data; SQL query begins below this line
select school,
count(case when grade = 'g1' then 1 end) as g1,
count(case when grade = 'g2' then 1 end) as g2,
count(case when grade = 'g3' then 1 end) as g3,
count(case when grade = 'g4' then 1 end) as g4,
count(grade) as total_g,
count(case when grade = 't1' then 1 end) as t1,
count(case when grade = 't2' then 1 end) as t2,
count(case when grade = 't3' then 1 end) as t3,
count(typ) as total_t
from like_this
group by school
order by school -- optional
;
SCH G1 G2 G3 G4 TOTAL_G T1 T2 T3 TOTAL_T
--- ------- ------- ------- ------- ------- ------- ------- ------- -------
sc1 1 1 0 0 2 0 0 0 2
sc2 0 1 0 0 1 0 0 0 1
sc3 0 0 0 1 1 0 0 0 1
sc4 0 0 1 0 1 0 0 0 1
4 rows selected.
Related
I have this table
COL_A FROM TO
------------------
D1 1 3
D2 3 7
And also this other table
COL_A VALUE
-------------
D1 0
D1 2
D1 5
D2 2
D2 5
D2 6
I want to obtain this. For each row in the first table, count the rows in the second table whose value is less than, between and greater than the FROM and TO columns.
COL_A FROM TO LESS_THAN_FROM BETWEEN_FROM_TO GREATER_THAN_TO
-------------------------------------------------------------------
D1 1 3 1 1 1
D2 3 7 1 2 0
Use join and conditional aggregation:
select t.col_a, t.from, t.to,
sum(case when o.value < t.from then 1 else 0 end) as less_than,
sum(case when o.value between t.from and t.to then 1 else 0 end) as in_between,
sum(case when o.value > t.to then 1 else 0 end) as greater_than
from this_table t join
other_table o
on t.col_a = o.col_a
group by t.col_a, t.from, t.to;
I need to select/concat data from 2 tables in SQL Server I'm using Left Join, but the data is returned as multiple records.
Below are the sample tables
Table1
Id Name Age
1 Sk 20
2 Rb 30
Table2
ID Bike Price Table1Id
1 RX 200 1
2 CD 250 1
3 FZ 300 1
4 R1 400 2
The desired output is
ID Name Age Bike1 Price1 Bike2 Price2 Bike3 Price3
1 Sk 20 RX 200 CD 250 FZ 300
2 Rb 30 R1 400 NULL NULL NULL NULL
A sample format of the query I'm using
SELECT A.ID, A.Name, B.Bike, B.Price FROM Table1 A LEFT JOIN Table2 B ON
A.id = B.Table1Id order by A.id
The output I'm getting from the above query is
ID Name Age Bike Price
1 Sk 20 RX 200
1 Sk 20 CD 250
1 Sk 20 FZ 300
2 Rb 30 R1 400
I need the data as one record for a particular ID and not multiple records (As seen in the desired output). Tired using offset, but offset will return only limited result not the entire records.
Any suggestions on how this can be achieved?
If you know the maximum number of bikes per person, you can use conditional aggregation:
SELECT ID, Name,
MAX(CASE WHEN seqnm = 1 THEN Bike END) as bike_1,
MAX(CASE WHEN seqnm = 1 THEN Price END) as price_1,
MAX(CASE WHEN seqnm = 2 THEN Bike END) as bike_2,
MAX(CASE WHEN seqnm = 2 THEN Price END) as price_2,
MAX(CASE WHEN seqnm = 3 THEN Bike END) as bike_3,
MAX(CASE WHEN seqnm = 3 THEN Price END) as price_3
FROM (SELECT A.ID, A.Name, B.Bike, B.Price,
ROW_NUMBER() OVER (PARTITION BY A.id ORDER BY B.Price) as seqnum
FROM Table1 A LEFT JOIN
Table2 B
ON A.id = B.Table1Id
) ab
GROUP BY ID, Name,
ORDER BY id
I have data in the below format
g_name amt flag
g1 0 0
g1 0 0
g1 10 1
g1 0 0
g1 15 2
g1 0 0
and I would require in the below format
n1 will have data starting from row where amt hits 1 and it keeps retaining it till the end, similarly n2 will have data starting from row where amt hits 2 and it keeps retaining it till the end, please help me with any window functions with out needing joins. please.
g_name amt flag n1 n2
g1 0 0 0 0
g1 0 0 0 0
g1 10 1 10 0
g1 0 0 10 0
g1 15 2 10 15
g1 0 0 10 15
I added a column for ordering - change as needed. I also added a few more rows with a different g_name, presumably this must be done "by g_name".
This is a good test case for the first_value() analytic function. It has the ability to ignore nulls - so we make the amt NULL when flag is not 1 (or 2, etc.) and then apply first_value() with the proper PARTITION BY and ORDER BY clauses.
with
test_data ( id, g_name, amt, flag ) as (
select 1, 'g1', 0, 0 from dual union all
select 2, 'g1', 0, 0 from dual union all
select 3, 'g1', 10, 1 from dual union all
select 4, 'g1', 0, 0 from dual union all
select 5, 'g1', 15, 2 from dual union all
select 6, 'g1', 0, 0 from dual union all
select 1, 'g2', 0, 0 from dual union all
select 2, 'g2', 4, 1 from dual union all
select 3, 'g2', 3, 2 from dual union all
select 4, 'g2', 0, 0 from dual
)
-- end of test data; solution (SQL query) begins below this line
select id, g_name, amt, flag,
coalesce (first_value(case when flag = 1 then amt end ignore nulls)
over (partition by g_name order by id), 0) as n1,
coalesce (first_value(case when flag = 2 then amt end ignore nulls)
over (partition by g_name order by id), 0) as n2
from test_data
order by g_name, id
;
ID G_NAME AMT FLAG N1 N2
--- ------ ---------- ---------- ---------- ----------
1 g1 0 0 0 0
2 g1 0 0 0 0
3 g1 10 1 10 0
4 g1 0 0 10 0
5 g1 15 2 10 15
6 g1 0 0 10 15
1 g2 0 0 0 0
2 g2 4 1 4 0
3 g2 3 2 4 3
4 g2 0 0 4 3
SQL tables represent unordered sets. There is no ordering, unless a column specifies that ordering. Let me assume that such a column exists.
If so, you can do this with analytic functions:
select t.*,
max(case when flag = 1 then amt else 0 end) over (order by ??) as n1,
max(case when flag = 2 then amt else 0 end) over (order by ??) as n2
from t;
The ?? specifies the ordering.
I have two tables as below. Caseid from first table is referenced in second table along with accidents. What I am trying to get total different accidents for a case type. Below two tables I documented sample data and expected result.
Table case:
caseId CaseType
1 AB
2 AB
3 AB
4 CD
5 CD
6 DE
Table CaseAccidents:
AccidentId caseID AccidentRating
1 1 High
2 1 High
3 1 Medium
4 1 LOW
5 2 High
6 2 Medium
7 2 LOW
8 5 High
9 5 High
10 5 Medium
11 5 LOW
Result should look like:
CaseType TotalHIghrating TotalMediumRating TotalLOWRating
AB 3 2 2
CD 2 1 1
DE 0 0 0
To get the sum of every rating, you can Use a SUM(CASE WHEN) clause, adding 1 by every record that match the rating.
In your question, you have pointed out that you want to see all distinct CaseType, you can get it by using a RIGHT JOIN, this will include all records of case table.
select case.CaseType,
sum(case when caseAccidents.AccidentRating = 'High' then 1 else 0 end) as TotalHighRating,
sum(case when caseAccidents.AccidentRating = 'Medium' then 1 else 0 end) as TotalMediumRating,
sum(case when caseAccidents.AccidentRating = 'LOW' then 1 else 0 end) as TotalLowRating
from caseAccidents
right join case on case.caseId = caseAccidents.caseID
group by case.CaseType;
+----------+-----------------+-------------------+----------------+
| CaseType | TotalHighRating | TotalMediumRating | TotalLowRating |
+----------+-----------------+-------------------+----------------+
| AB | 3 | 2 | 2 |
+----------+-----------------+-------------------+----------------+
| CD | 2 | 1 | 1 |
+----------+-----------------+-------------------+----------------+
| DE | 0 | 0 | 0 |
+----------+-----------------+-------------------+----------------+
Check it: http://rextester.com/MCGJA9193
Have you use case in a select clause before?
select C.CaseType,
sum(case when CA.AccidentRating = 'High' then 1 else 0 end)
from Case C join CaseAccidents CA on C.CaseId = CA.CaseId
group by C.CaseType
Please see this. Sample query of the table and also that result
create table #case(caseid int,casetype varchar(5))
insert into #case (caseid,casetype)
select 1,'AB' union all
select 2,'AB' union all
select 3,'AB' union all
select 4,'CD' union all
select 5,'CD' union all
select 6,'DE'
create table #CaseAccidents(AccidentId int, CaseId int,AccidentRating varchar(10))
insert into #CaseAccidents(AccidentId, CaseId, AccidentRating)
select 1,1,'High' union all
select 2,1,'High' union all
select 3,1,'Medium' union all
select 4,1,'Low' union all
select 5,2,'High' union all
select 6,2,'Medium' union all
select 7,2,'Low' union all
select 8,5,'High' union all
select 9,5,'High' union all
select 10,5,'Medium' union all
select 11,5,'Low'
My script
select c.casetype,
sum(case when ca.AccidentRating='High' then 1 else 0 end) as TotalHighRating,
sum(case when ca.AccidentRating='Medium' then 1 else 0 end) as TotalMediumRating,
sum(case when ca.AccidentRating='Low' then 1 else 0 end) as TotalLowRating
from #case c
Left join #CaseAccidents ca
on c.Caseid=ca.Caseid
group by c.casetype
Hope This could help!
Another approach using Pivot operator
SELECT casetype,
[High],
[Medium],
[Low]
FROM (SELECT c.casetype,
AccidentRating
FROM case c
LEFT JOIN CaseAccidents ca
ON ca.CaseId = c.caseid)a
PIVOT (Count(AccidentRating)
FOR AccidentRating IN ([High],
[Medium],
[Low]) ) p
Try This code once.
select casetype,
sum(case when ca.AccidentRating='High' then 1 else 0 end ) as TotalHIghrating,
sum(case when ca.AccidentRating='Medium' then 1 else 0 end ) as TotalMediumRating ,
sum(case when ca.AccidentRating='Low' then 1 else 0 end ) as TotalLOWRating
from #case c
left join #CaseAccidents ca on c.caseid=ca.CaseId
group by casetype
I'm trying to do a full join on two SQL queries, below:
1st Query:
SELECT
ID
,SUM(CASE WHEN reason = 4 THEN 0 ELSE quantity*price END) AS TValue
,COUNT(*) AS CountAll
FROM table1
WHERE Date>=#StartDate AND Date<=#EndDate
GROUP BY ID
2nd Query:
SELECT
ID
,SUM(CASE WHEN reason = 1 THEN 1 ELSE 0 END) AS New
,SUM(CASE WHEN reason = 6 THEN 1 ELSE 0 END) AS Amend
,SUM(CASE WHEN reason = 5 THEN 1 ELSE 0 END) AS Cancel
FROM Table2
WHERE Date2 >=#StartDate AND Date2<= #EndDate
GROUP BY ID
Result from query1
ID CountAll TValue
-------------------------
id1 24 1020
id2 13 2030
id3 4 120
Result from query 2:
ID New Amend Cancel
--------------------------------
id1 12 4 6
id2 7 6 1
id4 2 1 2
Needed output:
ID TValue CountAll New Amend Cancel Total(countall+new+amend+cancel)
----------------------------------------------------------------------------------------
Id1 1020 24 12 4 6 46
Id2 2030 13 7 6 1 27
id3 120 4 0 0 0 4
Id4 0 0 2 1 2 5
I'll post my current solution if requested, but it is pretty far from working.
I've been doing a bit of research and I think I need to either make a union to join the ID'S, or just do a Full Join. (Second day ever doing sql)
Try this,
SELECT *
FROM
(
SELECT ID ,
SUM(CASE WHEN reason = 4 THEN 0 ELSE quantity*price END) AS TValue,
COUNT(*) AS CountAll
FROM table1
WHERE Date>=#StartDate AND Date<=#EndDate
GROUP BY ID
) a FULL JOIN
(
SELECT ID ,
SUM(CASE WHEN reason = 1 THEN 1 ELSE 0 END) AS New ,
SUM(CASE WHEN reason = 6 THEN 1 ELSE 0 END) AS Amend ,
SUM(CASE WHEN reason = 5 THEN 1 ELSE 0 END) AS Cancel
FROM Table2
WHERE Date2 >=#StartDate AND Date2<= #EndDate
GROUP BY ID
) b ON a.ID = b.ID
I would write something like below:
select decode (a.id, null, b.id, a.id) as ID, a.TValue, CountAll, b.new, b.Amend, b.cancel
from (SELECT ID ,SUM(CASE WHEN reason = 4 THEN 0 ELSE quantity*price END)
AS TValue ,COUNT(*) AS CountAll
FROM table1
WHERE Date>=#StartDate AND Date<=#EndDate GROUP BY ID
) a FULL OUTER JOIN
(SELECT ID , SUM(CASE WHEN reason = 1 THEN 1 ELSE 0 END)
AS New ,SUM(CASE WHEN reason = 6
THEN 1 ELSE 0 END) AS Amend ,
SUM(CASE WHEN reason = 5 THEN 1 ELSE 0 END) AS Cancel
FROM Table2 WHERE Date2 >=#StartDate AND Date2<= #EndDate GROUP BY ID
) b
on a.id = b.id
have you tried this...
select isnull (a.id,b.id) as ID, a.TValue, CountAll, b.new, b.Amend, b.cancel
from (SELECT ID ,SUM(CASE WHEN reason = 4 THEN 0 ELSE quantity*price END) AS TValue ,COUNT(*) AS CountAll
FROM table1
WHERE Date>=#StartDate AND Date<=#EndDate GROUP BY ID ) a
FULL OUTER JOIN (SELECT ID , SUM(CASE WHEN reason = 1 THEN 1 ELSE 0 END) AS New ,SUM(CASE WHEN reason = 6 THEN 1 ELSE 0 END) AS Amend , SUM(CASE WHEN reason = 5 THEN 1 ELSE 0 END) AS Cancel
FROM Table2 WHERE Date2 >=#StartDate AND Date2<= #EndDate GROUP BY ID ) b on a.id = b.id