I have a table in sql server 2008 like
Id Name Volume
1 Jack 20
2 John 20
3 White 40
... (23 more)
27 Jennifer 12
28 Brown 33
29 Brown 55
... (23 more)
53 Alex 67
53 Smith 15
53 Mary 73
What I want is to add a column to this table, which keeps unique letter(s) for each different id. Example output:
Id Name Volume LetterKey
1 Jack 20 A
2 John 20 B
3 White 40 C
... (23 more) (...Z)
27 Jennifer 12 AA
28 Brown 33 AB
29 Brown 55 AC
... (23 more) (...AZ)
53 Alex 67 BA
53 Smith 15 BB
53 Mary 73 BC
... (...BZ)
We do not need 3-digit letters, ZZ would be the last possible one. I could not find a proper way to add such a column to the table. I appreciate if someone helps me with it. Thanks.
With only a two character code, you can use row_number() and some character arithmetic:
with t as (
select t.*, row_number() over (order by id) as seqnum
from t
)
select ((case when seqnum > 26
then char(ascii('A') + seqnum / 26 - 1)
else ''
end) +
char(ascii('A') + seqnum % 26)
)
from t
Related
I need to Join two table with respective to two columns
Stu_id (Table 1) - Stu_id (Table 2)
Perf_yr(Table 1) - yr_month (Table 2)
perf_yr starts on every year Sept to Aug.
Perf_yr should match the yr_month based on Perf_yr start and end Month
Table 1
Stu_id Roll_No Avg_marks Perf_yr
1 100244 72 2017
2 200255 62 2018
3 100246 68 2019
Table 2
Stu_id Subject Marks yr_month
1 Maths 70 201609
1 Science 69 201701
1 Social 74 201712
2 Maths 60 201709
2 Science 61 201801
2 Social 62 201808
3 Maths 65 201810
3 Science 64 201912
3 Social 72 201902
Output
Stu_id Roll_No Avg_marks Perf_yr Subject Marks yr_month
1 100244 72 2017 Maths 70 201609
1 100244 72 2017 Science 70 201701
2 200255 62 2018 Maths 60 201709
2 200255 62 2018 Science 61 201801
2 200255 62 2018 Social 62 201808
3 100246 68 2019 Maths 65 201810
3 100246 68 2019 Science 64 201912
3 100246 68 2019 Social 72 201902
I TRIED :
SELECT A.*, B.* FROM
(SELECT * FROM TABLE1 )A
LEFT JOIN
(SELECT * FROM TABLE)B
ON
A.Stu_id = B.Stu_id
AND
A.Perf_yr = B.Yr_Month
BUT IT WONT GIVE THE DESIRED RESULT BECAUSE THE CONDITION IS NOT SATISFYING THE PERF YR START AND END DATE .
You need to parse eg 201609 as a date, add 4 months to it, then match it to the year from the other table. Adding 4 months converts a date range 201609-201708 into being 201701-201712 - we only care about the year part:
SELECT * FROM
t1
INNER JOIN t2
ON
t1.stu_id = t2.stu_id AND
t1.Perf_yr = EXTRACT(year FROM ADD_MONTHS(TO_DATE(t2.yr_month, 'YYYYMM'), 4))
This is oracle. The same logic will work for SQLS, you'll just need to adjust the functions used-
CONVERT(date, t2.yr_month+'01', 112) -- Convert yyyymmdd to a date
DATEADD(month, x, 4) -- add 4 months to x
YEAR(x) -- extract year from date x
I have a count of a top 2
My table has this data
Name Age price visited size
Jon 34 53 2018-01-01 9
Don 22 70 2018-03-01 15
Pete 76 12 2018-11-09 7
Jon 34 55 2018-09-13 9
Paul 90 64 2018-07-08 6
Pete 76 31 2018-03-25 7
Jon 75 34 2018-06-06 8
select top 2
name,
count(name) as cnt
from
tbl1
group by name
order by cnt desc
Which returns my top 2 names
Jon 3
Pete 2
This name will change dynamically as the query is run depending on who has made the most visits in total (this is very simplified the actual table has 1000's of entries).
What I would like to do is then use the result of that query to get the following all of which needs to be in a single query;
Name Age price visited size
Jon 34 53 2018-01-01 9
Jon 34 55 2018-09-13 9
Jon 75 34 2018-06-06 8
Pete 76 12 2018-11-09 7
Pete 76 31 2018-03-25 7
In summary, count who has visited the most and then display all the records under those names.
Thanks in advance
Here's one option using in:
select *
from yourtable
where name in (
select top 2 name
from yourtable
group by name
order by count(*) desc
)
order by name
Online Demo
Lets say I have a table which holds all exports for some time back in Microsoft SQL database:
Name:
ExportTable
Columns:
id - numeric(18)
exportdate - datetime
In order to get the number of exports per week I can run the following query:
SELECT DATEPART(ISO_WEEK,[exportdate]) as 'exportdate', count(exportdate) as 'totalExports'
FROM [ExportTable]
Group By DATEPART(ISO_WEEK,[exportdate])
order by exportdate;
Returns:
exportdate totalExports
---------- ------------
27 13
28 12
29 15
30 8
31 17
32 10
33 7
34 15
35 4
36 18
37 10
38 14
39 14
40 21
41 19
Would it be possible to aggregate the week results by quarter so the output becomes something like the bellow?
UPDATE
Sorry for not being crystal clear, I would like the current result to add upp with previous result up to a new quarter.
Note week 41 contains 21+19 = 40
Week 39 contains 157 (13+12+15+8+17+10+7+15+4+18+10+14+14)
exportdate totalExports Quarter
---------- ------------ -------
27 13 3
28 25 3
29 40 3
30 48 3
31 65 3
32 75 3
33 82 3
34 97 3
35 101 3
36 119 3
37 129 3
38 143 3
39 157 3 -- Sum of 3 Quarter values.
40 21 4 -- New Quarter show current week value
41 40 4 -- (21+19)
You can use this.
SELECT
DATEPART(ISO_WEEK,[exportdate]) as 'exportdate'
, SUM( count(exportdate) ) OVER ( PARTITION BY DATEPART(QUARTER,MIN([exportdate])) ORDER BY DATEPART(ISO_WEEK,[exportdate]) ROWS UNBOUNDED PRECEDING ) as 'totalExports'
, DATEPART(QUARTER,MIN([exportdate])) [Quarter]
FROM [ExportTable]
Group By DATEPART(ISO_WEEK,[exportdate])
order by exportdate;
You could use a case statement to separate the dates into quarters.
e.g.
CASE
WHEN EXPORT_DATE BETWEEN '1' AND '4' THEN 1
WHEN Export_Date BETWEEN '5' and '9' THEN 2
ELSE 0 AS [Quarter]
END
Its just an example but you get the idea.
You could then use the alias from the case
SELECT DATEPART(ISO_WEEK,[exportdate]) as 'exportdate', count(exportdate) as 'totalExports', DATEPART(quarter,[exportdate]) as quarter FROM [ExportTable] Group By DATEPART(ISO_WEEK,[exportdate]), DATEPART(quarter,[exportdate]) order by exportdate;
Here is our table
name math physics chemistry hindi english
pk 85 65 45 54 40
ashis 87 44 87 78 74
rohit 77 47 68 63 59
mayank 91 81 78 47 84
komal 47 51 73 61 55
we want to result show as (summing the grades essentially)
rank name total
1 mayank 381
2 ashis 370
3 rohit 314
4 pk 289
5 komal 287
SET #rank=0;
SELECT #rank:=#rank+1 AS rank,name,(math+physics+chemistry+hindi+english) as total
FROM tablename ORDER BY total DESC
this will produce your desired result as
rank | name | total
--------------------
1 | mayank | 381
2 | ashis | 370
for more details take a look mysql ranking results
Try this
SELECT #curRank := #curRank + 1 AS rank, name, (math + physics + chemistry + hindi + history) AS total FROM table, (SELECT #curRank := 0) r ORDER BY total DESC;
This will sum all the fields and sort them by descending order and add a rank.
By doing SELECT #curRank := 0 you can keep it all in one SQL statement without having to do a SET first.
this my table
student_numbers
ROLL_NO NAME CLASS HINDI MATHS SCIENCE
2 amit 11 91 91 81
3 anirudh 11 88 87 81
4 akash 11 82 81 85
5 pratik 10 81 99 98
7 rekha 10 79 97 82
6 neha 10 89 91 90
8 kamal 10 66 68 69
1 ankit 11 97 98 87
i want to add last three columns and rank on that total partitioned by class
this is what i tried
select roll_no,name,class,total,
rank() over (partition by class order by total desc) as rank
from student_numbers,(select hindi+maths+science total from student_numbers)
;
but this is showing a very large table,with duplicate student name having different total .
I'm not exactly sure what you are trying to accomplish -- order the highest grades by class? If so, something like this should work:
SELECT SN.Roll_No,
SN.Class,
SN2.Total,
RANK() OVER (PARTITION BY SN.Class ORDER BY SN2.Total DESC) as rank
FROM Student_Numbers SN
JOIN (
SELECT
Roll_no, hindi+maths+science as Total
FROM Student_Numbers
) SN2 ON SN.Roll_No = SN2.Roll_No
Here is the SQL Fiddle.
Good luck.