Here is our table
name math physics chemistry hindi english
pk 85 65 45 54 40
ashis 87 44 87 78 74
rohit 77 47 68 63 59
mayank 91 81 78 47 84
komal 47 51 73 61 55
we want to result show as (summing the grades essentially)
rank name total
1 mayank 381
2 ashis 370
3 rohit 314
4 pk 289
5 komal 287
SET #rank=0;
SELECT #rank:=#rank+1 AS rank,name,(math+physics+chemistry+hindi+english) as total
FROM tablename ORDER BY total DESC
this will produce your desired result as
rank | name | total
--------------------
1 | mayank | 381
2 | ashis | 370
for more details take a look mysql ranking results
Try this
SELECT #curRank := #curRank + 1 AS rank, name, (math + physics + chemistry + hindi + history) AS total FROM table, (SELECT #curRank := 0) r ORDER BY total DESC;
This will sum all the fields and sort them by descending order and add a rank.
By doing SELECT #curRank := 0 you can keep it all in one SQL statement without having to do a SET first.
Related
I have a table in sql server 2008 like
Id Name Volume
1 Jack 20
2 John 20
3 White 40
... (23 more)
27 Jennifer 12
28 Brown 33
29 Brown 55
... (23 more)
53 Alex 67
53 Smith 15
53 Mary 73
What I want is to add a column to this table, which keeps unique letter(s) for each different id. Example output:
Id Name Volume LetterKey
1 Jack 20 A
2 John 20 B
3 White 40 C
... (23 more) (...Z)
27 Jennifer 12 AA
28 Brown 33 AB
29 Brown 55 AC
... (23 more) (...AZ)
53 Alex 67 BA
53 Smith 15 BB
53 Mary 73 BC
... (...BZ)
We do not need 3-digit letters, ZZ would be the last possible one. I could not find a proper way to add such a column to the table. I appreciate if someone helps me with it. Thanks.
With only a two character code, you can use row_number() and some character arithmetic:
with t as (
select t.*, row_number() over (order by id) as seqnum
from t
)
select ((case when seqnum > 26
then char(ascii('A') + seqnum / 26 - 1)
else ''
end) +
char(ascii('A') + seqnum % 26)
)
from t
id varname 1area 2area 3area 4area
------------------------------------
1 abc 345 3.7 34 87
1 pqr 46 67 78 55
1 lmn 67 99 33 44
2 xyz 78 78 33 32
I need to calculate SUM of column query.
Is it possible to get column count using while loop?
You probably want to do a SUM() of the Narea column group by your id column like
select id, sum(1area),
sum(2area), sum(3area), sum(4area)
from tbl1
group by id;
I have one table : SCORE
name score
mike 97
tom 86
lucy 44
and another table : RANK
low up rank
90 100 A
80 90 B
70 80 C
60 70 D
0 60 E
and I want the result like that
name score rank
mike 97 A
tom 86 B
lucy 44 E
How to write sql
Try the below query, JOIN two table with condition of rank between low and up
SELECT name,score,rank
FROM score
JOIN rank ON score > low AND score<=up
What is difference between PERCENTILE_DISC and PERCENTILE_CONT,
I have a table ### select * from childstat
FIRSTNAME GENDER BIRTHDATE HEIGHT WEIGHT
-------------------------------------------------- ------ --------- ---------- ----------
lauren f 10-JUN-00 54 876
rosemary f 08-MAY-00 35 123
Albert m 02-AUG-00 15 923
buddy m 02-OCT-00 15 150
furkar m 05-JAN-00 76 198
simon m 03-JAN-00 87 256
tommy m 11-DEC-00 78 167
And I am trying differentiate between those percentile
select firstname,height,
percentile_cont(.50) within group (order by height) over() as pctcont_50_ht,
percentile_cont(.72) within group (order by height) over() as pctcont_72_ht,
percentile_disc(.50) within group (order by height) over () as pctdisc_50_ht,
percentile_disc(.72) within group (order by height) over () as pctdisc_72_ht
from childstat order by height
FIRSTNAME HEIGHT PCTCONT_50_HT PCTCONT_72_HT PCTDISC_50_HT PCTDISC_72_HT
-------------------------------------------------- ---------- ------------- ------------- ------------- -------------
buddy 15 54 76.64 54 78
Albert 15 54 76.64 54 78
rosemary 35 54 76.64 54 78
lauren 54 54 76.64 54 78
furkar 76 54 76.64 54 78
tommy 78 54 76.64 54 78
simon 87 54 76.64 54 78
But still can't understand how this two and what is use of those two functions..
PERCENTILE_DISC returns a value in your set/window, whereas PERCENTILE_CONT will interpolate;
In your query, when you use .72, PERCENTILE_CONT interpolates between 76 and 78, since 72% is neither one of them; PERCENTILE_DISC chooses 76 (the lowest of the ones)
I found this explanation very helpful
http://mfzahirdba.blogspot.com/2012/09/difference-between-percentilecont-and.html
ITEM REGION WK FORECASTQTY
---- ---------- ---------- -----------
TEST E 3 137
TEST E 2 190
TEST E 1 232
TEST E 4 400
SELECT
t.* ,
PERCENTILE_CONT(0.5)
WITHIN GROUP ( ORDER BY forecastqty)
OVER (PARTITION BY ITEM , region ) AS PERCENTILE_CONT ,
MEDIAN(forecastqty)
OVER (PARTITION BY ITEM , region ) AS MEDIAN ,
PERCENTILE_DISC(0.5)
WITHIN GROUP ( ORDER BY forecastqty)
OVER (PARTITION BY ITEM , region ) AS PERCENTILE_DISC
FROM
t ;
ITEM REGION WK FORECASTQTY PERCENTILE_CONT MEDIAN PERCENTILE_DISC
---- ---------- ---------- ----------- --------------- ---------- ---------------
TEST E 3 137 211 211 190
TEST E 2 190 211 211 190
TEST E 1 232 211 211 190
TEST E 4 400 211 211 190
this my table
student_numbers
ROLL_NO NAME CLASS HINDI MATHS SCIENCE
2 amit 11 91 91 81
3 anirudh 11 88 87 81
4 akash 11 82 81 85
5 pratik 10 81 99 98
7 rekha 10 79 97 82
6 neha 10 89 91 90
8 kamal 10 66 68 69
1 ankit 11 97 98 87
i want to add last three columns and rank on that total partitioned by class
this is what i tried
select roll_no,name,class,total,
rank() over (partition by class order by total desc) as rank
from student_numbers,(select hindi+maths+science total from student_numbers)
;
but this is showing a very large table,with duplicate student name having different total .
I'm not exactly sure what you are trying to accomplish -- order the highest grades by class? If so, something like this should work:
SELECT SN.Roll_No,
SN.Class,
SN2.Total,
RANK() OVER (PARTITION BY SN.Class ORDER BY SN2.Total DESC) as rank
FROM Student_Numbers SN
JOIN (
SELECT
Roll_no, hindi+maths+science as Total
FROM Student_Numbers
) SN2 ON SN.Roll_No = SN2.Roll_No
Here is the SQL Fiddle.
Good luck.