this my table
student_numbers
ROLL_NO NAME CLASS HINDI MATHS SCIENCE
2 amit 11 91 91 81
3 anirudh 11 88 87 81
4 akash 11 82 81 85
5 pratik 10 81 99 98
7 rekha 10 79 97 82
6 neha 10 89 91 90
8 kamal 10 66 68 69
1 ankit 11 97 98 87
i want to add last three columns and rank on that total partitioned by class
this is what i tried
select roll_no,name,class,total,
rank() over (partition by class order by total desc) as rank
from student_numbers,(select hindi+maths+science total from student_numbers)
;
but this is showing a very large table,with duplicate student name having different total .
I'm not exactly sure what you are trying to accomplish -- order the highest grades by class? If so, something like this should work:
SELECT SN.Roll_No,
SN.Class,
SN2.Total,
RANK() OVER (PARTITION BY SN.Class ORDER BY SN2.Total DESC) as rank
FROM Student_Numbers SN
JOIN (
SELECT
Roll_no, hindi+maths+science as Total
FROM Student_Numbers
) SN2 ON SN.Roll_No = SN2.Roll_No
Here is the SQL Fiddle.
Good luck.
Related
Table A
shop
amount
count
sameShopCount
shop5
100
1
1
shop2
99
2
1
shop3
98
3
1
shop4
97
4
1
shop1
96
5
1
shop2
95
6
2
shop4
94
7
2
shop5
93
8
2
shop5
92
9
3
shop1
91
10
2
shop5
90
11
4
shop3
89
12
2
Expected Result (order by amount desc):
shop
amount
expected result
shop5
100
1
shop2
99
2
shop3
98
3
shop4
97
4
shop1
96
5
shop2
95
2
shop4
94
4
shop5
93
1
shop5
92
1
shop1
91
5
shop5
90
1
shop3
89
3
I want to count shop column similar to count column in Table A. But also if shop exist more than 1 time it will reuse the first exist count number.
How can I achieved this with/without a temp table in SQL Server respectively? (SQL Server 2014 - build v12.0.6108.1)
I had tried something like:
ROW_NUMBER() OVER (ORDER BY amount DESC)
DENSE_RANK() OVER (PARTITION BY shop ORDER BY amount DESC)
Try using max and dense_rank window functions as the following:
with max_shop_amount as
(
select *,
max(amount) over (partition by shop) as mx
from table_name
)
select shop, amount,
dense_rank() over (order by mx desc) expected
from max_shop_amount
order by amount desc
See demo
I'm trying to retrieve top 5 marks from school database in databricks deltatable using SQL query. So I wrote following query
select
rs.State, rs.Year, rs.CW, rs.Country, rs.SchoolName,
rs.EducationSystem, rs.MarksS1, rs.MarksS2, rs.MarksS3, rs.MarksS4,
rs.TotalMarks, rs.group_rank
from
(select
State, Year, Country, SchoolName, EducationSystem,
MarksS1, MarksS2, MarksS3, MarksS4, TotalMarks,
row_number() over (partition by State, Year, Country, SchoolName, EducationSystem
order by TotalMarks DESC, MarksS1 ASC) as group_rank
from
nm_combined_historical_data_distinct) rs
where
group_rank < 6
I'm trying to get top 5 students based on marks. But if top 5 students have same marks, I want my output like this
State year Country School Name Education System MarksS1 MarksS2 MarksS3 MarksS4 Total
AZ 2020 US XYZ ABC 95 91 92 95 373
AZ 2020 US XYZ ABC 95 91 92 95 373
AZ 2020 US XYZ ABC 95 91 92 95 373
AZ 2020 US XYZ ABC 95 91 92 95 373
AZ 2020 US XYZ ABC 95 91 92 95 373
But my output is coming in this way
State year Country School Name Education System MarksS1 MarksS2 MarksS3 MarksS4 Total
AZ 2020 US XYZ ABC 95 91 92 95 373
Can you suggest me how do I get my desired output
Instead of row_number() use rank():
rank() over (partition by State, Year, Country, SchoolName, EducationSystem
order by TotalMarks DESC, MarksS1 ASC
) as group_rank
I have a count of a top 2
My table has this data
Name Age price visited size
Jon 34 53 2018-01-01 9
Don 22 70 2018-03-01 15
Pete 76 12 2018-11-09 7
Jon 34 55 2018-09-13 9
Paul 90 64 2018-07-08 6
Pete 76 31 2018-03-25 7
Jon 75 34 2018-06-06 8
select top 2
name,
count(name) as cnt
from
tbl1
group by name
order by cnt desc
Which returns my top 2 names
Jon 3
Pete 2
This name will change dynamically as the query is run depending on who has made the most visits in total (this is very simplified the actual table has 1000's of entries).
What I would like to do is then use the result of that query to get the following all of which needs to be in a single query;
Name Age price visited size
Jon 34 53 2018-01-01 9
Jon 34 55 2018-09-13 9
Jon 75 34 2018-06-06 8
Pete 76 12 2018-11-09 7
Pete 76 31 2018-03-25 7
In summary, count who has visited the most and then display all the records under those names.
Thanks in advance
Here's one option using in:
select *
from yourtable
where name in (
select top 2 name
from yourtable
group by name
order by count(*) desc
)
order by name
Online Demo
Here is our table
name math physics chemistry hindi english
pk 85 65 45 54 40
ashis 87 44 87 78 74
rohit 77 47 68 63 59
mayank 91 81 78 47 84
komal 47 51 73 61 55
we want to result show as (summing the grades essentially)
rank name total
1 mayank 381
2 ashis 370
3 rohit 314
4 pk 289
5 komal 287
SET #rank=0;
SELECT #rank:=#rank+1 AS rank,name,(math+physics+chemistry+hindi+english) as total
FROM tablename ORDER BY total DESC
this will produce your desired result as
rank | name | total
--------------------
1 | mayank | 381
2 | ashis | 370
for more details take a look mysql ranking results
Try this
SELECT #curRank := #curRank + 1 AS rank, name, (math + physics + chemistry + hindi + history) AS total FROM table, (SELECT #curRank := 0) r ORDER BY total DESC;
This will sum all the fields and sort them by descending order and add a rank.
By doing SELECT #curRank := 0 you can keep it all in one SQL statement without having to do a SET first.
id varname 1area 2area 3area 4area
------------------------------------
1 abc 345 3.7 34 87
1 pqr 46 67 78 55
1 lmn 67 99 33 44
2 xyz 78 78 33 32
I need to calculate SUM of column query.
Is it possible to get column count using while loop?
You probably want to do a SUM() of the Narea column group by your id column like
select id, sum(1area),
sum(2area), sum(3area), sum(4area)
from tbl1
group by id;