Related
I am trying to use my query as the current day for my SQL query.
What I am trying below returns 0 records:
select *
from [TEST].[dbo].LIMIT
where endOfDay = GETDATE()
select *
from [TEST].[dbo].LIMIT
where endOfDay = dateadd(dd, datediff(dd, 0, getdate()), 0)
where endOfDay >= getdate() and endOfDay < getdate() + 1
An example date would be 2019-07-09 00:00:00.0
Also if there is no given date for today's date can I get a range of dates?
Any help would be appreciated, thanks.
First, you need to omit the quotes or else 'GETDATE()' is just a string.
Second, to match by "day", you need to strip the time part from the result of GETDATE(), which you can do by using CAST(GETDATE() as DATE) instead:
select *
from [TEST].[dbo].LIMIT
where endOfDay = CAST(GETDATE() as DATE)
For this to work best, the endOfDay column also needs to be of type DATE. If it is something else, you need to also CAST or CONVERT endOfDay to a DATE.
Using quotes makes it looking for a meaningless literal 'GETDATE()' to find nothing
You can use
with LIMIT(today, EndOfDay) as
(
select CONVERT(DATETIME, CONVERT(date, GETDATE())), GETDATE()
)
select EndOfDay
from LIMIT
where EndOfDay >= today and EndOfDay < today + 1;
Demo
Try this:
select *
from [TEST].[dbo].LIMIT
where cast(endOfDay as date) = cast(GETDATE() as date)
SQL Fiddle to see what the date will be compared with.
GETDATE() returns the server's current date and time. Unless you have any records that match that exactly, it doesn't make sense to use GETDATE. It doesn't look like you do based on the endOfDay column name.
The other criteria you show,
dateadd(dd,datediff(dd,0,getdate()),0) is essentially stripping the time off and returning midnight of the current date.
select getdate() 2019-07-11 15:10:09.287
select dateadd(dd,datediff(dd,0,getdate()),0) 2019-07-11 00:00:00.000
Assuming you don't care about time, convert both EndofDay and Getdate to a simple date for comparison.
select * from [TEST].[dbo].LIMIT where convert(date,EndOfDay) = convert(date,getdate())
Is there a way to use the Now() function in SQL to select values with today's date?
I was under the impression Now() would contain the time as well as date, but today's date would have the time set to 00:00:00 and therefore this would never match?
OK, lets do this properly. Select dates matching today, using indexes if available, with all the different date/time types present.
The principle here is the same in each case. We grab rows where the date column is on or after the most recent midnight (today's date with time 00:00:00), and before the next midnight (tomorrow's date with time 00:00:00, but excluding anything with that exact value).
For pure date types, we can do a simple comparison with today's date.
To keep things nice and fast, we're explicitly avoiding doing any manipulation on the dates stored in the DB (the LHS of the where clause in all the examples below). This would potentially trigger a full table scan as the date would have to be computed for every comparison. (This behaviour appears to vary by DBMS, YMMV).
MS SQL Server: (SQL Fiddle | db<>fiddle)
First, using DATE
select * from dates
where dte = CAST(CURRENT_TIMESTAMP AS DATE)
;
Now with DATETIME:
select * from datetimes
where dtm >= CAST(CURRENT_TIMESTAMP AS DATE)
and dtm < DATEADD(DD, 1, CAST(CURRENT_TIMESTAMP AS DATE))
;
Lastly with DATETIME2:
select * from datetimes2
where dtm2 >= CAST(CURRENT_TIMESTAMP AS DATE)
and dtm2 < DATEADD(DD, 1, CAST(CURRENT_TIMESTAMP AS DATE))
;
MySQL: (SQL Fiddle | db<>fiddle)
Using DATE:
select * from dates
where dte = cast(now() as date)
;
Using DATETIME:
select * from datetimes
where dtm >= cast((now()) as date)
and dtm < cast((now() + interval 1 day) as date)
;
PostgreSQL: (SQL Fiddle | db<>fiddle)
Using DATE:
select * from dates
where dte = current_date
;
Using TIMESTAMP WITHOUT TIME ZONE:
select * from timestamps
where ts >= 'today'
and ts < 'tomorrow'
;
Oracle: (SQL Fiddle)
Using DATE:
select to_char(dte, 'YYYY-MM-DD HH24:MI:SS') dte
from dates
where dte >= trunc(current_date)
and dte < trunc(current_date) + 1
;
Using TIMESTAMP:
select to_char(ts, 'YYYY-MM-DD HH24:MI:SS') ts
from timestamps
where ts >= trunc(current_date)
and ts < trunc(current_date) + 1
;
SQLite: (SQL Fiddle)
Using date strings:
select * from dates
where dte = (select date('now'))
;
Using date and time strings:
select dtm from datetimes
where dtm >= datetime(date('now'))
and dtm < datetime(date('now', '+1 day'))
;
Using unix timestamps:
select datetime(dtm, 'unixepoch', 'localtime') from datetimes
where dtm >= strftime('%s', date('now'))
and dtm < strftime('%s', date('now', '+1 day'))
;
Backup of SQL Fiddle code
There is no native Now() function in SQL Server so you should use:
select GETDATE() --2012-05-01 10:14:13.403
you can get day, month and year separately by doing:
select DAY(getdate()) --1
select month(getdate()) --5
select year(getdate()) --2012
if you are on sql server 2008, there is the DATE date time which has only the date part, not the time:
select cast (GETDATE() as DATE) --2012-05-01
Not sure what your asking!
However
SELECT GETDATE()
Will get you the current date and time
SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, GETDATE()))
Will get you just the date with time set to 00:00:00
Just zero off the time element of the date. e.g.
SELECT DATEADD(dd, DATEDIFF(dd, 0, getdate()), 0)
I've used GetDate as that's an MSSQL function, as you've tagged, but Now() is probably MySQL or you're using the ODBC function call, still should work if you just replace one with the other.
Not sure exactly what you're trying to do, but it sounds like GETDATE() is what you're after. GETDATE() returns a datetime, but if you're not interested in the time component then you can cast to a date.
SELECT GETDATE()
SELECT CAST(GETDATE() AS DATE)
Building on the previous answers, please note an important point, you also need to manipulate your table column to ensure it does not contain the time fragment of the datetime datatype.
Below is a small sample script demonstrating the above:
select getdate()
--2012-05-01 12:06:51.413
select cast(getdate() as date)
--2012-05-01
--we're using sysobjects for the example
create table test (id int)
select * from sysobjects where cast(crdate as date) = cast(getdate() as date)
--resultset contains only objects created today
drop table test
I hope this helps.
EDIT:
Following #dwurf comment (thanks) about the effect the above example may have on performance, I would like to suggest the following instead.
We create a date range between today at midnight (start of day) and the last millisecond of the day (SQL server count up to .997, that's why I'm reducing 3 milliseconds). In this manner we avoid manipulating the left side and avoid the performance impact.
select getdate()
--2012-05-01 12:06:51.413
select dateadd(millisecond, -3, cast(cast(getdate()+1 as date) as datetime))
--2012-05-01 23:59:59.997
select cast(getdate() as date)
--2012-05-01
create table test (id int)
select * from sysobjects where crdate between cast(getdate() as date) and dateadd(millisecond, -3, cast(cast(getdate()+1 as date) as datetime))
--resultset contains only objects created today
drop table test
If you have a table with just a stored date (no time) and want to get those by "now", then you can do this:
SELECT * FROM tbl WHERE DATEDIFF(d, yourdate, GETDATE())=0
This results in rows which day difference is 0 (so today).
For me the query that is working, if I want to compare with DrawDate for example is:
CAST(DrawDate AS DATE) = CAST (GETDATE() as DATE)
This is comparing results with today's date.
or the whole query:
SELECT TOP (1000) *
FROM test
where DrawName != 'NULL' and CAST(DrawDate AS DATE) = CAST (GETDATE() as DATE)
order by id desc
You can try this sql code;
SELECT [column_1], [column_1], ...
FROM (your_table)
where date_format(record_date, '%e%c%Y') = date_format(now(), '%e%c%Y')
You can try:
WHERE created_date BETWEEN CURRENT_TIMESTAMP-180 AND CURRENT_TIMESTAMP
This worked for me:
SELECT * FROM table where date(column_date) = curdate()
Hi guys hope you can help, I've done a search but can't seem to find what I'm looking for...
I'm trying to write a SQL query to show me all employees that have started 12 weeks or 84 days from the date of running the query (current date). I've got this so far but it's not returning the results I was expecting, I'm getting some records through where the start date is older than 84 days.
.... WHERE (EmployeeJobs.DateTo IS NULL or EmployeeJobs.DateTo = dateadd(d,datediff(d,0,getdate()),84))
I need a NULL statement included as unfortunately not all the records have a date in them.
Any help would be much appreciated
where
EmployeeJobs.DateTo IS NULL
or
datediff(d, EmployeeJobs.DateTo, getdate()) = 84
If you're using SQL Server 2008, then
where
EmployeeJobs.DateTo IS NULL
or
cast(EmployeeJobs.DateTo as date) = cast(getdate() - 84 as date)
Try it like this:
WHERE
(EmployeeJobs.DateTo IS NULL
or
convert(varchar, EmployeeJobs.DateTo, 112) = convert(varchar, DATEADD(day, -84, getdate(), 112)
)
Try this one, its suitable for all versions of Sql Server 2000+
....
WHERE
(EmployeeJobs.DateTo IS NULL
or
CONVERT(varchar, EmployeeJobs.DateTo, 112) = CONVERT(varchar, dateadd(d,-84,GETDATE()), 112)
)
BUT if you running it # sql server 2008+ you can simplify the work:
....
WHERE
(EmployeeJobs.DateTo IS NULL
or
cast(EmployeeJobs.DateTo as DATE) = CAST(dateadd(d,-84,GETDATE()) as DATE)
)
OR with the possibility of using index
....
WHERE
(EmployeeJobs.DateTo IS NULL
or
EmployeeJobs.DateTo >= CAST(dateadd(d,-84,GETDATE()) as DATE)
AND
EmployeeJobs.DateTo < CAST(dateadd(d,-83,GETDATE()) as DATE)
)
Do you have a DateFrom and a DateTo field? And the range of those two dates shows that they were employed between those two dates? Where a NULL DateTo means they have not yet left? And you want people who were employed 84 days ago?
WHERE
(EmployeeJobs.DateFrom <= dateadd(d, datediff(d,0,getdate()) - 84, 0))
AND (EmployeeJobs.DateTo >= dateadd(d, datediff(d,0,getdate()) - 84, 0) OR EmployeeJobs.DateTo IS NULL)
Alternatively (as functions are used already the impact on performance is there):
WHERE
-- get difference in days
DateDiff(dd,
-- lower date, replace Nulls
IsNull(EmployeeJobs.DateTo, GetDate()),
-- highest date
GetDate()
)
-- whatever the criteria, in this case equal to exact 84 days
= 84
I have a question. I have a SQL Server 2008 table with a field column. I have for example the Following dates:
1/1/2001
5/5/2004
8/5/2009
10/7/2011
5/5/2012
1/13/2014
Id like to be able to show all dates >= the current date (7/29/2011) as well as largest table date that is < current date. In this example, the result would be all dates >= 8/5/2009.
Can someone help guide me please??
select max(date) [date] from table where date < getdate()
union
select date from table where date >= getdate()
If I understand correctly, you want to include the date prior to the current date. GETDATE() will get the current date (with time). If you're alright with that, then this should work. Otherwise, you may have to parse out just the date from GETDATE()
SELECT TheDate
FROM DateTable
WHERE TheDate >= (SELECT MAX(TheDate) FROM DateTable WHERE TheDate < GETDATE())
This gets all dates greater than or equal to the most recent date before the current date.
I am not entirely sure I understand, but this looks like a BETWEEN the relevant dates. Or is there something more I am missing?
Assuming your table is called DateTable and your field is called TheDate, do it like this:
SELECT TheDate
FROM DateTable
WHERE TheDate >= DATEADD(d, -2, GETDATE())
Good luck!
It depends on the SQL server you're using. In postgres, for example, you need something like
SELECT fields FROM table WHERE date_field >= CURRENT_DATE - 1
But other SQL servers have different ways to specify "yesterday"
SELECT d1.*
FROM dates d1
LEFT JOIN dates d2 ON d1.Date < d2.Date AND d2.Date < GETDATE()
WHERE d2.Date IS NULL
Explanation:
Select every date for which there does not exist a date that is both earlier than today and later than the one being inspected.
Lots of guessing here based on loose narrative and unknown data types.
DECLARE #t TABLE(d DATE);
INSERT #t SELECT '20010101'
UNION ALL SELECT '20040505'
UNION ALL SELECT '20090805'
UNION ALL SELECT '20111007'
UNION ALL SELECT '20120505'
UNION ALL SELECT '20140113';
DECLARE #now DATE = SYSDATETIME();
WITH t AS
(
SELECT d, rn = ROW_NUMBER() OVER (ORDER BY d)
FROM #t
)
SELECT t.d
FROM t LEFT OUTER JOIN t AS x
ON t.rn = x.rn - 1
WHERE COALESCE(x.d, #now) >= #now
ORDER BY t.d;
I am looking for a good SQL Statement to select all rows from the previous day from one table. The table holds one datetime column. I am using SQL Server 2005.
get today no time:
SELECT dateadd(day,datediff(day,0,GETDATE()),0)
get yestersday no time:
SELECT dateadd(day,datediff(day,1,GETDATE()),0)
query for all of rows from only yesterday:
select
*
from yourTable
WHERE YourDate >= dateadd(day,datediff(day,1,GETDATE()),0)
AND YourDate < dateadd(day,datediff(day,0,GETDATE()),0)
To get the "today" value in SQL:
convert(date, GETDATE())
To get "yesterday":
DATEADD(day, -1, convert(date, GETDATE()))
To get "today minus X days": change the -1 into -X.
So for all yesterday's rows, you get:
select * from tablename
where date >= DATEADD(day, -1, convert(date, GETDATE()))
and date < convert(date, GETDATE())
It's seems the obvious answer was missing. To get all data from a table (Ttable) where the column (DatetimeColumn) is a datetime with a timestamp the following query can be used:
SELECT * FROM Ttable
WHERE DATEDIFF(day,Ttable.DatetimeColumn ,GETDATE()) = 1 -- yesterday
This can easily be changed to today, last month, last year, etc.
SELECT * from table_name where date_field = DATE_SUB(CURRENT_DATE(),INTERVAL 1 DAY);
Its a really old thread, but here is my take on it.
Rather than 2 different clauses, one greater than and less than. I use this below syntax for selecting records from A date. If you want a date range then previous answers are the way to go.
SELECT * FROM TABLE_NAME WHERE
DATEDIFF(DAY, DATEADD(DAY, X , CURRENT_TIMESTAMP), <column_name>) = 0
In the above case X will be -1 for yesterday's records
This should do it:
WHERE `date` = CURDATE() - INTERVAL 1 DAY
Can't test it right now, but:
select * from tablename where date >= dateadd(day, datediff(day, 1, getdate()), 0) and date < dateadd(day, datediff(day, 0, getdate()), 0)
In SQL Server do like this:
where cast(columnName as date) = cast(getdate() -1 as date)
You should cast both sides of the expression to date to avoid issues with time formatting.
If you need to control interval in more detail, then you should try something like:
declare #start datetime = cast(getdate() - 1 as date)
declare #end datetime = cast(getdate() - 1 as date)
set #end = dateadd(second, 86399, #end)
Another way to tell it "Yesterday"...
Select * from TABLE
where Day(DateField) = (Day(GetDate())-1)
and Month(DateField) = (Month(GetDate()))
and Year(DateField) = (Year(getdate()))
This conceivably won't work well on January 1, as well as the first day of every month. But on the fly it's effective.
Well, its easier to cast the datetime column to date and than compare.
SELECT * FROM TABLE_NAME WHERE cast(COLUMN_NAME as date) =
dateadd(day,0, convert(date, getdate(), 105))
A simple alternative
Select GETDATE() - 1
Change 1 to go back that many number of days
PS : This gives you timestamp accuracy.
This worked a charm:
SELECT * FROM mytable WHERE date(mydate) = DATE_SUB(CURDATE(), INTERVAL 1 DAY);
subdate(now(),1) will return yesterdays timestamp
The below code will select all rows with yesterday's timestamp
Select * FROM `login` WHERE `dattime` <= subdate(now(),1) AND `dattime` > subdate(now(),2)