Output year and month with a string - sql

Trying to output something like:
2016,11
Using this:
SELECT
CONVERT(VARCHAR(20),YEAR(GETDATE()) + ',' + MONTH(GETDATE())) AS YearMonth
Am I missing something in convert? Because I am getting this error:
Conversion failed when converting the varchar value ',' to data type
int.
Thanks

Try this.
SELECT
CONVERT(VARCHAR(20),YEAR(GETDATE())) + ',' + CONVERT(VARCHAR(20), MONTH(GETDATE())) AS YearMonth

You might use CONVERT with 112 to reach a string without delimiters ("20161110"). Converting this to VARCHAR(*6*) will implicitly cut the day. One (in most cases positiv) side-effect: You will get a low month zero padded (e.g. 2016,04). Then I use STUFF to insert the ,:
SELECT STUFF(CONVERT(VARCHAR(6),GETDATE(),112),5,0,',')
If you do not like the zero padded month, you could replace the 0 in STUFF like this:
DECLARE #d DATETIME={d'2016-04-05'};
SELECT STUFF(CONVERT(VARCHAR(6),#d,112),5,CASE WHEN MONTH(#d)<10 THEN 1 ELSE 0 END,',')

You are missing converting the output of MONTH() to a string. Here is one method:
select datename(year, getdate()) + ',' + cast(month(getdate()) as varchar(255)) as YearMonth
datename() is convenient because it returns a string. Unfortunately, for month it returns the name of the month, rather than the number.
You could also do:
select replace(convert(varchar(7), getdate(), 120), '-', ',')
Or use format() in SQL Server 2012+:
select format(getdate(), 'yyyy,MM')

Related

Looking to replace the year in SQL Server

I am converting a date using CONVERT(varchar,DateOfBirth,101) for birthdates.
I want to show these dates with the current year, I've tried REPLACE but you can't use wildcards with it and when I use DATEPART, it doesn't format with the right digits for month and day. I also can't add years because they are wildly different birthdates. Thanks.
If you want to display the date as a string in 101 format for current year, one option uses a direct format():
format(DateOfBirth, 'MM/dd/2020')
You can compute the current date dynamically:
format(DateOfBirth, concat('MM/dd/', year(getdate())))
On the other hand, if you want your result as a date, then you could use datefromparts():
datefromparts(year(getdate()), month(DateOfBirth), day(DateOfBirth))
If it is a datevalue, you can use FORMAT function. If it is a character value, you can use RIGHT and REPLACE.
DECLARE #dateValue DATETIME = '05/12/1999'
DECLARE #dateCharValue VARCHAR(12) = '05/12/1999'
SELECT FORMAT(#dateValue, 'MM/dd/2020')
SELECT REPLACE(#dateCharValue, RIGHT(#dateCharValue,4),2020)
--Result
05/12/2020
This could helped you:
The code CONVERT(varchar(5),GETDATE(),1) return this 05/27 and then just add the year of the date
SELECT CONVERT(varchar(5),GETDATE(),1) + '/' + cast(year(getdate()) as varchar)
Or
SELECT CONVERT(varchar(5),GETDATE(),1) + '/' + convert(varchar,year(getdate()))
The result of both:
05/27/2020 --(This is my current date n.n )
This work but if you use a string something like your example DateOfBirth will be the variable and if this is a string (DateOfBirth = '5/27/1987') you need to convert the string DateOfBirth to Date:
SELECT CONVERT(varchar(5),convert(date,DateOfBirth),1) + '/' + cast(year(GETDATE()) as varchar)
Or
SELECT CONVERT(varchar(5),convert(date,DateOfBirth),1) + '/' + convert(varchar,year(GETDATE()))
The Result of Both :
05/27/2020

Convert nvarchar date (DD/MM/YYYY) to Date Period (YYYY_MM)

I am trying to convert this into a period format, so e.g. 2018_05 (YYYY_MM). currently the data is in DD/MM/YYYY format.
I tried a cast code but it returns me YYYY_DD.
SELECT
CASE WHEN RESERVED_FIELD_4 IS NULL THEN NULL
ELSE cast(year(RESERVED_FIELD_4) as Nvarchar (4))
+'_'+right('00'+cast(month(RESERVED_FIELD_4) as Nvarchar (2)),2)
END AS [DATAFEED_PERIOD]
I expect/want to see YYYY_MM.
Assuming RESERVED_FIELD_4 is a string type (char/nchar/varchar/nvarchar) the simplest solution would be to use substring:
CASE
WHEN RESERVED_FIELD_4 IS NULL THEN NULL
ELSE SUBSTRING(RESERVED_FIELD_4, 7, 4) + '_'+ SUBSTRING(RESERVED_FIELD_4, 4, 2)
END AS [DATAFEED_PERIOD]
If it's a date/datetime/datetime2 data type, the simplest solution would be to use format:
FORMAT(RESERVED_FIELD_4, 'yyyy_MM')
But for better performance you can use convert and stuff:
SELECT STUFF(CONVERT(char(6), RESERVED_FIELD_4, 112), 5, 0, '_')
In case your format is actually d/m/y the simplest option is to convert to date and than back to string:
SELECT STUFF(CONVERT(char(6), CONVERT(Date, RESERVED_FIELD_4, 103), 112), 5, 0, '_')
This is the common problem of storing a date with a VARCHAR column. You are guessing that the stored pattern is DD/MM/YYYY but the SQL engine doesn't know that and is currently assuming the MM/DD/YYYY pattern.
Please check these results:
-- MM/DD/YYYY
SELECT
DAY ('05/01/2019'), -- 1
MONTH('05/01/2019') -- 5
-- DD/MM/YYYY
SELECT
DAY ('25/05/2019'), -- Conversion failed when converting date and/or time from character string
MONTH('25/05/2019') -- Conversion failed when converting date and/or time from character string.
To display what you want correctly use string functions:
SELECT
RIGHT(RESERVED_FIELD_4, 4) + '_' + SUBSTRING(RESERVED_FIELD_4, 4, 2)
But you should actually fix the values on your VARCHAR column, cast them to DATE and store the values as DATE.
ALTER TABLE YourTable ADD ReservedField4Date DATE
UPDATE YourTable SET
ReservedField4Date = CONVERT(DATE,
RIGHT(RESERVED_FIELD_4, 4) -- Year
+ '-' + SUBSTRING(RESERVED_FIELD_4, 4, 2) -- Month
+ '-' + LEFT(RESERVED_FIELD_4, 2)) -- Day
ALTER TABLE YourTable DROP COLUMN RESERVED_FIELD_4
EXEC sp_rename 'SchemaName.YourTable.ReservedField4Date', 'RESERVED_FIELD_4', 'COLUMN'
Beware that changing the column type might affect other queries that assume this is a VARCHAR column.
If your data is in DD/MM/YYYY format, then it is being stored as a string. Hence, string functions come to mind:
select right(RESERVED_FIELD_4) + '_' + substrint(RESERVED_FIELD_4, 4, 2)
In SQL-SERVER you can use 'format'
format(dy,#your_date) as day_of_year
month(#your_date) as month
Try this:
Select concat(month(#your_date),'_'year(#your_date)) as your_period
this is a reference
Why not just do conversations ? :
SELECT REPLACE(CONVERT(VARCHAR(7), CONVERT(date, RESERVED_FIELD_4, 101), 102), '.', '_')
This assumes RESERVED_FIELD_4 is date type.

Strip year, month and date as int from a datetime field

I need to strip out part of a date (stored in my database table as a datetime field) in the form 'YYYYMMDD'. I would like the output to be an integer.
For example the datetime 2017-03-28 20:44:35.000 would convert to 20170328.
This is my attempt so far:
CAST(
CAST(DATEPART(year,transcriptCreationDateUTC) AS varchar(4))
+ CAST(DATEPART(month,transcriptCreationDateUTC) AS varchar(4))
+ CAST(DATEPART(day,transcriptCreationDateUTC) AS varchar(4))
AS int)
This is ugly to say the least, and also has the issue that it strips out leading zeros in the month and day fields, so for example 2017-03-28 20:44:35.000 converts to 2017328 not 20170328 as I would like.
There must be a better way, any help appreciated!
CONVERT with style 112 (which is YYYYMMDD format):
SELECT CONVERT(VARCHAR(8),transcriptCreationDateUTC,112)
If you really need the result as an INT, wrap in a CAST(... AS INT):
SELECT CAST(CONVERT(VARCHAR(8),transcriptCreationDateUTC,112) AS INT)
Huh? Just convert to a date:
select cast(transcriptCreationDateUTC as date)
If you want this as a string:
select format(transcriptCreationDateUTC, 'yyyyMMdd')
If you are using a pre-2012 version of SQL Server, you can do:
select convert(varchar(10), transcriptCreationDateUTC, 112)
If you want these as an integer (which is not obvious given that your query returns a string), just convert these to an integer:
select cast(format(transcriptCreationDateUTC, 'yyyyMMdd') as int)
Or, use this arithmetic:
select (year(transcriptCreationDateUTC) * 10000 +
month(transcriptCreationDateUTC) * 100 +
day(transcriptCreationDateUTC)
) as yyyymmdd

SQL Varchar convert to Date - Sybase

I am using Sybase IQ and have the following stored as a varchar:
01October 2010
I want to convert this from varchar to date datatype with the following format:
yyyy-mm-dd eg.2010-10-01
How would I write this SQL statement? Thanks in advance.
With difficulty. There's a reason you should never store dates and times as strings.
It's been awhile since I've used Sybase, but what we need to do is get the field into YYYY-MM-DD format, and then pass it to the DATE() or DATETIME() function.
Let's assume the first two characters are always the day of the month, and the last 4 characters are the year. That means everything in between is the month. Let's also assume that there are no leading or trailing spaces. If either of these assumptions fails, then the query will fail.
Then you can do something like this:
SELECT DATE (
RIGHT(UnnamedField,4) + '-' +
CASE LTRIM(RTRIM(SUBSTRING(Unnamed,3,LEN(Unnamed) - 6)))
WHEN 'January' THEN '01'
WHEN 'February' THEN '02'
WHEN 'March' THEN '03'
.
.
.
WHEN 'December' THEN '12'
END + '-' + LEFT(UnnamedField,2)
)
FROM UnnamedTable
Note that, as others have mentioned, the date data type is not a formatted datatype. If possible you should format it in your application. If you must do it in the query, use the CONVERT() function.
Sybase is able to convert a string to a date. So if you use substring to extract the date into a format that IQ can convert, then you can just use the convert() function.
Here's an example of how to do it:
Sample data:
create table #tmp1 (col1 varchar(100))
insert #tmp1 values ('01October 2010')
Query to convert the value to a date:
select
convert
(
date,
(
substring(col1, 3, charindex(' ', col1) - 2) -- Month
+ substring(col1, 1, 2) -- Day
+ substring(col1, charindex(' ', col1), 5) -- Year (include the leading space)
)
)
from #tmp1
Now that the value is in a date format, you can use the convert function to convert the date datatype to string, using your specified format. The default output for a date datatype is yyyy-mm-dd already.
Edit: After taking a look at #BaconBits' answer, I've realized that I could simplify the query a bit by using the substring function wrappers left, right, and the convert wrapper of date. It's the same logic; but using the simplified wrappers might make it easier to understand.
select
date
(
substring(col1, 3, charindex(' ', col1) - 2) -- Month
+ left(col1, 2) -- Day
+ ' ' + right(col1, 4) -- Year (include the leading space)
)
from #tmp1

DATENAME and DATEPART in SQL

I'm trying to get my EntryDate column in this format 'YYYY_m' for example '2013_04'.
This code has been unsuccessful
DATENAME (YYYY, EntryDate) + '_' + DATEPART (M, EntryDate)
Attempts using DATEFORMAT have also been unsuccessful, stating there was syntax error at ',' after the M. What code would work instead?
Thank you.
How about date_format()?
select date_format(EntryDate, '%&Y_%m')
This is the MySQL way. Your code looks like an attempt to do this in SQL Server.
EDIT:
The following should work in SQL Server:
select DATENAME(year, EntryDate) + '_' + RIGHT('00' + DATEPART(month, EntryDate), 2)
Personally, I might use convert():
select replace(convert(varchar(7), EntryDate, 121), '-', '_')
select DATENAME (YYYY, EntryDate)
+ '_'
+ right('0' + convert(varchar(2),datepart (MM, EntryDate)), 2)
You have to convert the result of DATEPART() to a character string in order for the + to perform an append.
FYI - in the future "unsuccessful" doesn't mean anything. Next time post the actual error you are receiving.
For example:
SELECT concat(EXTRACT(YEAR FROM '2015/1/1'), '_',
LPAD(extract(month from '2014/1/1'),2,'0')) AS OrderYear
This uses
concat to combine strings
lpad to place a leading 0 if month is one digit
and uses extract to pick of the part of date needed.
working fiddle
http://sqlfiddle.com/#!2/63b24/8
DATEPART
It is a Datetime function which extract information from date. This function always returns result as integer type.
SELECT DATEPART(month, '2009-01-01 00:00:00:000') as month
it is return "1" as an integer:
DATENAME
It is also another Datetime function which to extract information from date. This function always returns result as varchar
SELECT DATENAME(month, '2009-01-01 00:00:00:000') as month
it is return "January".